asteak at a restaurant actually weighs 17 ounces (the true value),but the menu claims that it is a 15-ounce steak. Find the values ofabsolute and relative errors.

Redundant bits are additional bits added to the data bits to achieve this purpose.

The number of redundant bits necessary for a code is related to the number of data bits to ensure error detection and correction in transmitted data. In general, redundant bits are additional bits added to the data bits to achieve this purpose.

To determine the number of redundant bits (r) needed for a specific number of data bits (k), you can use the following inequality:

[tex]2^r ≥ k + r + 1[/tex]

Here, r is the number of redundant bits, and k is the number of data bits.

Step-by-step explanation:

1. Identify the number of data bits (k) in the code.
2. Use the inequality[tex]2^r ≥ k + r + 1[/tex]to find the minimum value of r (redundant bits) that satisfies the inequality.
3. The value of r obtained will be the number of redundant bits necessary for the code.

By adding redundant bits to the data, it helps in detecting and correcting errors during data transmission, thereby ensuring the accuracy and reliability of the information being communicated.

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To find all distinct eigenvalues of A and their corresponding basic eigenvectors, follow these steps. For each eigenvalue λ, solve the equation (A - λI)x = 0, where x is the eigenvector.

Step 1: Find the characteristic equation of matrix A.
Write down the equation |A - λI| = 0, where λ represents the eigenvalues and I is the identity matrix.
Step 2: Solve the characteristic equation.
Find the values of λ that satisfy the equation obtained in Step 1. These values are the eigenvalues of matrix A.
Step 3: Find eigenvectors corresponding to each eigenvalue.
For each eigenvalue λ, solve the equation (A - λI)x = 0, where x is the eigenvector. Find the null space of (A - λI) to determine the basic eigenvectors.
Step 4: State the eigenvalue followed by the basic eigenvectors.
For each eigenvalue, specify the number of basic eigenvectors and list the eigenvectors corresponding to that eigenvalue.
Please note that I cannot provide a specific solution without the matrix A. If you provide the matrix A, I would be happy to walk you through the process with actual calculations.

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(a) To find the optimal decision surface, we need to find the equation that satisfies P(Y = 1|x) = P(Y = 0|x). In this problem, we are given that each class-conditional distribution is defined as a two-dimensional Gaussian distribution with mean mi and covariance matrix Σi:

P(x|Y = i) = (2π|Σi|)^(-1/2) exp[-1/2 (x - mi)ᵀΣi^(-1)(x - mi)] where i ∈ {0,1}, mi = (1,2) for Y = 0 and mi = (6,3) for Y = 1, and Σi = Σ for i ∈ {0,1}. We are also given that P(Y = 0) = P(Y = 1) = 1/2.

Using Bayes' rule, we can find the posterior probability of Y = 1 given x:

P(Y = 1|x) = P(x|Y = 1)P(Y = 1) / [P(x|Y = 0)P(Y = 0) + P(x|Y = 1)P(Y = 1)]

Substituting the Gaussian distributions and simplifying, we get:

P(Y = 1|x) = [1 + exp(-q(x))]^(-1)

where q(x) = (1/2)[(x - m1)ᵀΣ^(-1)(x - m1) - (x - m0)ᵀΣ^(-1)(x - m0) + 2log(π/2)]

The decision surface is the set of points x such that P(Y = 1|x) = P(Y = 0|x), or equivalently, q(x) = 0.

Solving for q(x) = 0, we get:

(x - m1)ᵀΣ^(-1)(x - m1) - (x - m0)ᵀΣ^(-1)(x - m0) + 2log(π/2) = 0

Expanding and simplifying, we get:

xᵀΣ^(-1)(m1 - m0) - 1/2(m1ᵀΣ^(-1)m1 - m0ᵀΣ^(-1)m0) = 0

Plugging in the given values, we get:

x₁ + 5x₂ = 13.5

Therefore, the optimal decision surface is the line x₁ + 5x₂ = 13.5.

(b) To generalize the solution to arbitrary covariance matrices Σ0 and Σ1, we can derive the decision surface equation by following the same steps as in part (a), but using the general expressions for the Gaussian distributions:

P(x|Y = i) = (2π|Σi|)^(-1/2) exp[-1/2 (x - mi)ᵀΣi^(-1)(x - mi)]

where Σi is the covariance matrix for class i, and mi is the mean vector for class i.

Using Bayes' rule and simplifying, we get:

P(Y = 1|x) = [1 + exp(-q(x))]^(-1)

where q(x) = (1/2)[(x - m1)ᵀΣ1^(-1)(x - m1) - (x - m0)ᵀΣ0^(-1)(x - m0) + log(|Σ0|/|Σ1

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The person will need approximately 0.55 gallons of paint to paint the room.

To calculate the amount of paint needed, we need to first calculate the surface area that will be painted. The person will paint four walls and the ceiling of the room.

To calculate the surface area of the walls, we need to find the area of each wall and add them together. Since the room is rectangular, each wall has the same height of 8 ft. The width and length of each wall are:

- Wall 1: 9 ft x 8 ft = 72 ft²
- Wall 2: 9 ft x 8 ft = 72 ft²
- Wall 3: 2 ft x 8 ft = 16 ft²
- Wall 4: 2 ft x 8 ft = 16 ft²

The total surface area of the walls is: 72 ft² + 72 ft² + 16 ft² + 16 ft² = 176 ft²

To calculate the surface area of the ceiling, we need to find the area of the rectangle that represents the ceiling. The length and width of the ceiling are:

- Ceiling: 9 ft x 2 ft = 18 ft²

Therefore, the total surface area that will be painted is: 176 ft² + 18 ft² = 194 ft²

Since we know the surface area that will be painted, we can now calculate the amount of paint needed. The amount of paint needed depends on the type of paint and the manufacturer's instructions. Generally, paint coverage is measured in square feet per gallon. If we assume a coverage of 350 square feet per gallon, then the person will need:

- 194 ft² / 350 ft²/gal = 0.55 gallons of paint

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The student government should survey 640 students to estimate the percentage of the student body that supports the proposed change in the academic calendar with a 99% confidence level and a margin of error of 8%.

To determine the sample size needed for the survey, we can use the following formula:
n = (z^2 * p * q) / E^2
Where:
n = sample size
z = z-score for the desired confidence level (99%)
p = estimated proportion of the population supporting the change (unknown, so we'll use 0.5 for a conservative estimate)
q = 1 - p
E = margin of error (0.08)
Plugging in the values, we get:
n = (2.576^2 * 0.5 * 0.5) / 0.08^2
n = 639.53
Since we can't have a fractional number of students, we should round up to the nearest integer:
n = 640

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Answer:

For the given information, let's solve the following:

a. Do you know that the period of a function is the time taken for one complete cycle of the function? In this case, the Ferris wheel takes one rotation every 80 seconds, which means it completes one cycle in 80 seconds. Therefore, the period of the function is 80 seconds.

b. To write f(t) in the form of f(t) = a sin b(t-h) + k, we first need to determine the amplitude, period, and phase shift of the function. The amplitude is half the distance between the highest and lowest points of the function, which is (102-94)/2 = 4 feet. The period is 80 seconds, which we found in part a. The phase shift is 0 since the ride starts at the highest point. Therefore, the function can be written as f(t) = 4 sin (2π/80)t + 102.

c. To graph the function, we can plot the height of the car (y-axis) against time (x-axis), using the function obtained in part b.

d. To find the value of f(15), we simply substitute t = 15 in the function obtained in part b. f(15) = 4 sin (2π/80)(15) + 102 = 98.28 feet. This makes sense because after 15 seconds, the car would have traveled a quarter of a cycle and would be descending from the highest point.

e. To find f(180), we can use the fact that the Ferris wheel takes one rotation every 80 seconds. Therefore, after 180 seconds, the wheel would have completed two full cycles and would be back at the highest point. Therefore, f(180) = 102 feet.

I hope this helps! Let me know if you have any further questions or if there's anything else I can assist you with.

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Distance and recession velocity the Hubble relation links two characteristics of distant objects in the universe:

their redshift and their distance from Earth. This relationship is crucial for understanding the expansion of the universe, as it helps us measure the distances to faraway celestial objects and study their motion relative to us.

What are Distance Sensors?

Distance sensors, as the name implies, are used to determine the distance of an object from another object or barrier without the use of physical touch (unlike a measuring tape, for example).

What is the sensor equation?

The sensor size may be estimated by multiplying the pixel size by the resolution along each of the two dimensions. The focal length may be computed using the formula: Focal Length x FOV = Sensor Size x Working Distance.

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Therefore, the correct option is (b) 46 that is the number of students who like Twix and Reese's peanut butter cups only (region D) by principle of inclusion-exclusion, we need to subtract the number of students who like Snickers, as well as the number of students who like all three kinds of candy, from the number of students who like Twix and Reese's peanut butter cups along with one or both of the other kinds of candy.

We can start by using the principle of inclusion-exclusion, which tells us that:

|A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C|

where |X| denotes the number of elements in set X.

Using the numbers given in the problem, we have:

|A| = 129

|B| = 118

|C| = 145

|A ∩ B| = 22

|B ∩ C| = 54

|A ∩ C| = 55

|A ∩ B ∩ C| = 8

Substituting these values into the formula, we get:

|A ∪ B ∪ C| = 129 + 118 + 145 - 22 - 55 - 54 + 8 = 269

This tells us that 269 students like at least one of the three kinds of chocolate candy.

To find the number of students who like Twix and Reese's peanut butter cups only (region D), we need to subtract the number of students who like Snickers, as well as the number of students who like all three kinds of candy, from the number of students who like Twix and Reese's peanut butter cups along with one or both of the other kinds of candy:

|D| = |B ∩ C| - |A ∩ B ∩ C|

= 54 - 8

= 46

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An equation of the line in point-slope form include the following: y + 3 = -3(x + 1).

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

At data point (-1, -3) and a slope of -3, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - (-3) = -3(x - (-1))  

y + 3 = -3(x + 1)

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To find the height of the building, we need to use trigonometry. Let's call the height of the building "h" and the distance from point a to the building "x". From point a, the angle of elevation to the top of the building is given. Let's call this angle "θ".

Using trigonometry, we can write:

tan(θ) = h/x

We can rearrange this equation to solve for h:

h = x * tan(θ)

Now let's move to point b. We know that it is ft closer to the building than point a, so the distance from point b to the building is (x - ft). We also know the angle of elevation from point b, which we'll call "α".

Using the same equation as before, but with the new values, we get:

h = (x - ft) * tan(α)

Now we can set these two expressions for h equal to each other:

x * tan(θ) = (x - ft) * tan(α)

We can solve this equation for h:

h = x(tan(θ) - tan(α)) / (1 - tan(θ)tan(α))

This gives us the height of the building. We just need to plug in the values we were given for x, ft, θ, and α.

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The radical expression is simplified to 7√10. Option D

A radical expression can simply be described as an expression that is made up of or consists of a radical.

A radical is made up of a square root sign that is used to represent surd forms.

It is also important to note that surds are described as values that can no longer be simplified

From the information given, we have the radical expression as;

√490

Find the pair factors of 490 that has on perfect square.

We get;

√49 × 10

Find the square root of the values, we have;

7× √10

Multiply the values

7√10

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a. Therefore, the value of X, xo, that satisfies P(41 ≤ X ≤ xo) = 0.8630 is xo = 8.15. We can illustrate this on a graph of the standard normal distribution by shading the area between the z-scores of 0 and 1.05. b. Therefore, the 10th percentile is x10 = 1.16. We can illustrate this on a graph of the standard normal distribution by shading the area to the left of the z-score of -1.28.

a. Using the standard normal probability table, we find that the z-score associated with a probability of 0.8630 is 1.05. Therefore, we can use the formula z = (X - μ) / σ to solve for X:
1.05 = (xo - 5) / 3
Multiplying both sides by 3, we get:
xo - 5 = 3.15
Adding 5 to both sides, we get:
xo = 8.15
b. To calculate the 10th percentile, we need to find the value of X, call it x10, which corresponds to a cumulative probability of 0.1. Using the standard normal probability table, we find that the z-score associated with a cumulative probability of 0.1 is -1.28. Therefore, we can use the formula z = (X - μ) / σ to solve for X:
-1.28 = (x10 - 5) / 3
Multiplying both sides by 3, we get:
x10 - 5 = -3.84
Adding 5 to both sides, we get:
x10 = 1.16

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The classification of the shapes have been done below based on 2D and 3D.

None of the given terms are three-dimensional figures

Non-polygon:

None of the given terms are non-polygons

A quadrilateral is a polygon with four sides. A rectangle is a specific type of quadrilateral with four right angles. Both quadrilaterals and rectangles are two-dimensional figures.

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The vertex is (3,-37) and the direction of the opening is upwards. To determine the vertex and direction of the opening of the parabola for the quadratic equation y = 3x^2 - 18x - 10, we first need to put it in vertex form.

Completing the square, we have:

[tex]y = 3(x^2 - 6x) - 10[/tex]
y = 3(x^2 - 6x + 9) - 10 - 27

(adding and subtracting 27, which is 3 times 9, inside the parentheses)

[tex]y = 3(x - 3)^2 - 37[/tex]

Now we can see that the vertex is (3,-37), since the equation is in the

form y = a(x - h)^2 + k, where (h,k) is the vertex.

We can also see that the parabola opens upwards, since the coefficient of x^2 is positive.

Therefore, the vertex is (3,-37) and the direction of opening is upwards.

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A significant deviation from the expected value of 425 grams for the bag filling machine. The manufacturer should investigate and adjust the machine to ensure that it is distributing the correct amount of chocolate chips in each bag.

Based on the information provided, the manufacturer of chocolate chips is interested in determining if there is a deviation from the expected value of 425 grams for the bag filling machine. They have collected a sample of 18 bags and calculated a mean of 416 grams with a standard deviation of 19. Assuming a normal distribution, they would like to determine the p-value of the test statistic with a significance level of 0.01.

To do this, they would conduct a one-sample t-test using the formula:

t = (x - μ) / (s / √n)

where x is the sample mean, μ is the population mean (expected value), s is the sample standard deviation, and n is the sample size.

Plugging in the values, we get:

t = (416 - 425) / (19 / √18) = -2.21

Using a t-distribution table or calculator with 17 degrees of freedom (n-1), we can find the p-value associated with a t-score of -2.21 and a one-tailed test (since we are interested in whether the bags are underfilled). The p-value is approximately 0.0212, which is less than the significance level of 0.01. Therefore, we reject the null hypothesis and conclude that the bags are likely being underfilled by the bag filling machine at the 425-gram setting.

In summary, the p-value of the test statistic is approximately 0.0212, indicating a significant deviation from the expected value of 425 grams for the bag filling machine. The manufacturer should investigate and adjust the machine to ensure that it is distributing the correct amount of chocolate chips in each bag.

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A significant deviation from the expected value of 425 grams for the bag filling machine. The manufacturer should investigate and adjust the machine to ensure that it is distributing the correct amount of chocolate chips in each bag.

Based on the information provided, the manufacturer of chocolate chips is interested in determining if there is a deviation from the expected value of 425 grams for the bag filling machine. They have collected a sample of 18 bags and calculated a mean of 416 grams with a standard deviation of 19. Assuming a normal distribution, they would like to determine the p-value of the test statistic with a significance level of 0.01.

To do this, they would conduct a one-sample t-test using the formula:

t = (x - μ) / (s / √n)

where x is the sample mean, μ is the population mean (expected value), s is the sample standard deviation, and n is the sample size.

Plugging in the values, we get:

t = (416 - 425) / (19 / √18) = -2.21

Using a t-distribution table or calculator with 17 degrees of freedom (n-1), we can find the p-value associated with a t-score of -2.21 and a one-tailed test (since we are interested in whether the bags are underfilled). The p-value is approximately 0.0212, which is less than the significance level of 0.01. Therefore, we reject the null hypothesis and conclude that the bags are likely being underfilled by the bag filling machine at the 425-gram setting.

In summary, the p-value of the test statistic is approximately 0.0212, indicating a significant deviation from the expected value of 425 grams for the bag filling machine. The manufacturer should investigate and adjust the machine to ensure that it is distributing the correct amount of chocolate chips in each bag.

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The value of a in the figure is 25⁰

Recall that an isosceles triangle is a triangle that has at least two sides of equal length and two angles that are equal

Given that >MPO = < MNP = 25  isosceles triangle

Also, <POM = 180 - (25+25) = 180-50 = 130

Let the centre be x

<OXN =90

But 130 +25 = 155

Therefore the value of a is 180-155 = 25⁰

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The amount for each category is given as:

Initially, we must determine how much of each crop is present:

By now, we are able to construct the circle graph by knowing that a circle comprises of 360 degrees, assorted degrees can aid us in identifying every classification of crops:

To find out the amount for each category, we need to compute each percentage share:

Given this information, we can proceed and develop the circle graph.

Make use of a clean and circular diagram and divide it into three proportional parts using their corresponding degree values, then label every section with its matching crop name alongside the respective percentage owned.

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The farmer has the following distribution of crops:

Corn - 40%

Wheat - 35%

Cotton - 25%

A farmer uses his land to grow soybeans, corn, wheat, and cotton. He has a total of 500 crops consisting of corn, wheat, and cotton. The distribution of these crops is 40% corn, 35% wheat, and 25% cotton. Sketch a circle graph and label it with percentages.

We can start by finding Jerry's pay rate per second:

Pay rate per second = $10,000 / 114 seconds = $87.72 per second

Then, we can calculate Jerry's earnings for 30 minutes (1800 seconds):

Earnings for 30 minutes = $87.72 per second x 1800 seconds = $157,896

Therefore, Jerry will make $157,896 in 30 minutes based on his pay rate of $10,000 in 114 seconds.

Consider three random variables, U, V, and W. The answer is E(W) = 2.

To solve for E(W), we need to use the fact that U is equal to both 3V+2 and 5W-23. We can set these two expressions equal to each other:

3V + 2 = 5W - 23

Solving for V in terms of W, we get:

V = (5W - 25) / 3

Now we can use the formula for the expected value of a linear function of a random variable:

E(aX + b) = aE(X) + b

In this case, we have:

V = (5W - 25) / 3

So:

E(V) = E((5W - 25) / 3) = (5/3)E(W) - 25/3

We know that E(V) = -5, so we can substitute that in:

-5 = (5/3)E(W) - 25/3

Solving for E(W), we get:

E(W) = (-5 + 25/3) / (5/3) = 2

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A graph of the line whose x-intercept is 8 and whose y-intercept is 7 is shown below.

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical expression;

y = mx + c

Where:

Mathematically, an intercept form of the equation of a standard line is given b;

x/a + y/b = 1

Where:

a and b are x-intercept and y-intercept respectively.

By substituting, we have:

x/8 + y/7 = 1

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Answer:

To create the cylindrical travel case, we need approximately 588.75 square inches of leather.

To compare the quantitative responses to the two conditions in a paired design, the differences between the response within each pair are used. These paired differences can be compared to the appropriate statistical procedures to determine the significance of the results.

For paired designs, the appropriate statistical procedure is the one-sample t procedure. This procedure is used to compare the mean of the paired differences to a hypothesized value, such as zero. The null hypothesis is that the mean difference is equal to zero, indicating no significant difference between the two conditions. If the calculated t-value is greater than the critical value, the null hypothesis can be rejected, indicating a significant difference between the two conditions.

In cases where the sample size is large and the population standard deviation is known, the two-sample z procedure can also be used. This procedure compares the difference between the means of the two samples to a hypothesized value. However, this procedure is less commonly used for paired designs.

The two-sample t procedure is used for independent designs, where two samples are selected from different populations. This procedure compares the means of the two samples to each other, rather than comparing the paired differences within each sample.

In summary, for paired designs, the appropriate statistical procedure is the one-sample t procedure, while the two-sample z procedures and the two-sample t procedures are used for independent designs.

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The area of the given composite figure is 6256 square cm.

The area of the composite figure will be the sum of the area of the three semicircles and the rectangle.

First, the area of the two semicircles which make one full circle is,

Area = πr²

Area = πx 16²

Area = 804 square cm

The area of the other semicircle is,

Area = (1/2) πr²

Area = (1/2) π(36)²

Area = 2035 square cm

The area of this rectangle is,

Area = L x W

Area = 16 x 36

Area = 576 square cm

The total area is,

Area = 804 + 2035 + 576

Area = 3415 square cm

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Answer: To find the magnitude and direction of vector RS, we first need to find the components of the vector, which are given by the differences in the x- and y-coordinates of R and S:

v = RS = <(-14) - (-2), 8 - 11> = <-12, -3>

The magnitude of v is given by the formula ||v|| = sqrt(a^2 + b^2), where a and b are the x- and y-components of v:

||v|| = sqrt((-12)^2 + (-3)^2) = sqrt(144 + 9) = sqrt(153) = 12.37

The direction of v is given by the angle that it makes with the positive x-axis, measured counterclockwise. We can find this angle using the formula theta = arctan(b/a), where a and b are the x- and y-components of v:

theta = arctan(-3/-12) = arctan(0.25) = -14.04 degrees (rounded to the nearest hundredth)

Therefore, the magnitude of RS is 12.37, and the direction of RS is 14.04 degrees below the negative x-axis.

Step-by-step explanation:

Answer:

3 months

Step-by-step explanation:

To find the amount of months, m, we will have to solve the equation given. If you don't have any experience solving equations, this could be tricky, but hopefully my work below will be helpful.

15m + 35 = 10(m + 5)

15m + 35 = 10m + 50

15m - 10m + 35 = 10m - 10m + 50

5m + 35 = 50

5m + 35 - 35 = 50 - 35

5m = 15

5m/5 = 15/5

m = 3

After 3 months the cost of the gyms will be the same. Let me know if you need more clarification or were confused by my work. :)

The length of the hypotenuse of the right triangle is given as follows:

[tex]h = 3\sqrt{2}[/tex]

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

The side lengths for this problem are given as follows:

Hence the hypotenuse length is obtained as follows:

[tex]h^2 = (\sqrt{8} + 1)^2 + (\sqrt{8} - 1)^2[/tex]

[tex]h^2 = 8 + 2\sqrt{8} + 1 + 8 - 2\sqrt{8} + 1[/tex]

[tex]h^2 = 18[/tex]

[tex]h = \sqrt{2 \times 9}[/tex]

[tex]h = 3\sqrt{2}[/tex]

As the hypotenuse contains a term with a square root, it is in surd form.

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The mean of ^p can be calculated using the formula: ^p = x/n, where x is the number of minority applicants in the sample and n is the sample size. Since we do not know the sample size, we cannot calculate the exact value of ^p.

However, we can assume that the sample size is large enough for the Central Limit Theorem to apply, which means that the mean of ^p is equal to the proportion of minority applicants in the population, which is 0.1 (10%).

The standard deviation of ^p can be calculated using the formula: σ(^p) = sqrt((p(1-p))/n), where p is the proportion of minority applicants in the population and n is the sample size. Substituting p = 0.1 and using the information that the bank filled 9% of open positions with minority candidates, we can estimate the sample size as

[tex]n = 0.09/0.1 = 0.9. Therefore, σ(^p) = sqrt((0.1*0.9)/0.9) = sqrt(0.1) = 0.316.[/tex]

To compute an approximation for p(^p < or is equal to 0.09), we need to standardize the variable ^p using the formula:

[tex]z = (^p - p)/σ(^p).[/tex]

Substituting the values of ^p, p, and σ(^p), we get: z = (0.09 - 0.1)/0.316 = -0.316.

The probability of ^p being less than or equal to 0.09 can be found by looking up the area under the standard normal distribution curve to the left of z = -0.316. Using a standard normal table or a calculator, we find that this probability is approximately 0.376.

Therefore, there is a 37.6% chance that the sample will have fewer minority applicants than were hired by the bank.

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The weight of one green triangle is equal to: D. -2.

In this scenario and exercise, you are required to write a system of equations that represents the balance by using the balance shown in the image attached below and then determine the weight of one green triangle.

Since it is a balance, we can reasonably infer and logically deduce that all of the pink squares (s) and green triangles (t) on the left-hand side must be equal to the all of the parameters (numerical values) on the right-hand side of the balance as follows;

3s + 2t = 5    ......equation 1

2s + 5t = -4    ......equation 2

By solving the system of equations simultaneously using the elimination method and multiplying equation 2 by 3/2, we have:

3s + 2t = 5

3s + 7.5t = -6

(3s - 3s) + (2t - 7.5t) = (5 + 6)

-5.5t = 11

t = -11/5.5

t = -2.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The IQR(Inter Quartile Range) is the best measure of variability and equals 4.

The length of ribbons found at a seamstress are listed as the data set below.

5, 8, 10, 12, 12, 19

Here, Mean and median cannot be the best measure since it not even a measure of variability. They are the measures of central tendency.

The measures of variability are Range and IQR.

Range is the difference of the highest value and the lowest value. It will be affected by outliers.

So, range = 19 - 5 = 14

IQR is the difference of the third quartile and the first quartile.

Third quartile is the middle value of the second half which is 12 and the first quartile  = 8

IQR = 12 - 8 = 4

Hence the appropriate measure is IQR.

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