Pls i need this !!!!

The high temperature on Tuesday was -5°F.

Given that,

On Monday, the high temperature in Sheboygan, Wisconsin, was –12°F.

The high temperature on Tuesday was 7 degrees warmer than the high temperature on Monday.

Let T be the high temperature on Tuesday and M be the high temperature on Monday.

By the given statement,

T = M + (7°F)

We have, M = -12°F

Substituting,

T = -12°F + 7°F

  = -5°F

Hence the required temperature is -5°F.

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The correct answer is B) II only.

The condition that checks that the sampling distribution of the sample proportion is approximately normal is II only, which is np0≥10 and n(1−p0)≥10 for sample size n.

Option I is not sufficient by itself to ensure normality of the sampling distribution. While random sampling is important for reducing bias in the sample, it does not guarantee that the sample proportion will have a normal distribution.

Option III is not relevant to the normality of the sampling distribution, as it pertains to the sample size relative to the population size and not the distribution of the sample proportion.

Therefore, the correct answer is B) II only.

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1. The people in the survey are 32

2. The problem is that there should not be a row for 57

3. There is nothing wrong with the vfrequency table

4. The teacher displays class testscores ion stem and leaf plot woyl give the most  valid conclusion

Count the frequency

8 + 10 + 12 + 2

= 32

A statistical instrument, termed as a frequency table, tabulates and illustrates how often particular elements or values belonging to numerous classifications crop up in a dataset.

In other words, it streamlines the procedure of managing and examining data, ultimately simplifying the identification of patterns and trends that may be present within the information at hand.

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When designing a logic circuit from a description of the problem, there are several necessary steps that must be taken.

When designing a logic circuit from a description of the problem, the necessary steps you should take are:
1. Understand the problem: Carefully read and analyze the problem description to determine the input and output requirements.
2. Identify inputs and outputs: List down all the required inputs and outputs based on the problem description.
3. Define truth table: Create a truth table that represents the relationship between the inputs and outputs of the circuit.
4. Simplify the Boolean expression: Use Boolean algebra or Karnaugh maps to simplify the Boolean expression derived from the truth table. This will minimize the number of gates required in the circuit.
5. Select appropriate logic gates: Based on the simplified Boolean expression, select the necessary logic gates (AND, OR, NOT, etc.) to build the circuit.
6. Design the circuit: Connect the selected logic gates to create the desired logic circuit, ensuring proper connections between inputs, gates, and outputs.
7. Verify the design: Test the designed circuit using various input combinations and ensure it produces the correct output as per the problem description.
By following these steps, you can successfully design a logic circuit that meets the requirements of the given problem.

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The base and height of the rectangle are 80 and 60 feet.

A rectangle has a diagonal of 100 feet. The length that could be the base and height of the rectangle is as follows:

Therefore, let's use Pythagoras's theorem to find the base and the height of the triangle.

c² = a² + b²

where

Therefore,

80² + 60² = 100²

6400 + 3600 = 10000

10000 = 10000

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Answer:

1) b. 3

2) a. 5

3) c. 4

4) d. 6

Step-by-step explanation:

Let's go through the process step-by-step to find the Standard Error of the Mean (SEM) for a 93% confidence interval for the proportion of newspapers with a non-conforming attribute.

Step 1: Define the variable of interest
The variable of interest here is whether the newspaper has a non-conforming attribute, which includes excessive ruboff, improper page setup, missing pages, or duplicate pages.

Step 2: Collect the data
You have already collected the data by selecting a random sample of n = 200 newspapers from all the newspapers printed during a single day.

Step 3: Organize the data
You have organized the results, which show that 35 newspapers contain some type of non-conformance, in a worksheet.

Step 4: Calculate the proportion
Now, we need to calculate the proportion of non-conforming newspapers:
Proportion (p) = (Number of non-conforming newspapers) / (Total number of newspapers in the sample)
p = 35 / 200 = 0.175

Step 5: Calculate the Standard Error of the Mean (SEM)
The formula for the SEM is:
SEM = sqrt[p * (1 - p) / n]
where p is the proportion of non-conforming newspapers and n is the sample size.
SEM = sqrt[0.175 * (1 - 0.175) / 200]
SEM ≈ 0.0283

So, the Standard Error of the Mean (SEM) for a 93% confidence interval for the proportion of newspapers with a non-conforming attribute is approximately 0.0283.

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The missing sides are represented as;

AC =  4√2    O.

AB = 4    M

DE =  6√2    L

DF =  6√2   L

To determine the value of the missing sides, we need to note the following trigonometric identities and their ratios;

sin θ = opposite/hypotenuse

cos θ = adjacent/hypotenuse

tan θ = opposite/adjacent

From the information given, we have that;

cos 45 = 4/AC

cross multiply the values

AC = 4÷ 1√2

Multiply the values

AC = 4× √2/1

Multiply the values

AC = 4√2

tan 45 = AB/4

AB = 4

To determine the values

sin 45 = DE/6

DE = 6√2

Then,

DF = 6√2

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The total area of Cedarville is in the shaded area that is both east of the river and north of Main Street is 6/10. Option C

We know that a fraction can be seen as a part of the whole. Thus when we talk about a fraction, we mean the part that we have taken out of the whole.

If we want to get the fraction of the total area of Cedarville is in the shaded area that is both east of the river and north of Main Street, then we have to count all the boxes and this would give us ten.

Six out of this ten are shaded thus the fraction of the total area of Cedarville is in the shaded area that is both east of the river and north of Main Street is 6/10.

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The scale factor used in the dilation of the triangles is 3

From the question, we have the following parameters that can be used in our computation:

The scale factor is calculated as

Scale factor  = A'/A

Substitute the known values in the above equation, so, we have the following representation

Scale factor  = (-3, -3)/(-1, -1)

Evaluate

Scale factor  = 3

Hence, the scale factor is 3

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The correct option is (c). t (1) = C1, and t(n) = 2t(2n/3) + C2, C1 and C2 are positive constants. Here's a step-by-step explanation:

1. When n = 1, the algorithm computes a function g (M [0])) and returns an integer value, which takes constant time, represented by C1.
2. For larger values of n, the algorithm divides the input array into two subarrays starting at positions i = 0 and [n/3 - 1], each containing [2n/3] elements.
3. It runs the algorithm recursively on each subarray, returning two integers x and y, and computes g(x, y).
4. Counting all the operations for each step, we can see that there are two recursive calls with inputs of size 2n/3, and one operation for computing g(x, y).

Therefore, the recurrence relation for the running time of this algorithm is:
t(1) = C1 (base case)
t(n) = 2t(2n/3) + C2 (recursive case)

C1 and C2 are positive constants.

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The best statistic to use to describe each variable will depend on the specific characteristics of the data distribution and the research question of interest. However, in general:

LOS (length of stay): The most appropriate statistic to use to describe LOS would be the median, as it is less affected by outliers and skewed distributions than the mean. The median represents the central value of the distribution, i.e., the value that separates the top 50% from the bottom 50% of observations. This is useful in understanding the typical or average length of stay, without being overly influenced by unusually long or short stays that may be present in the data.

Charge: The most appropriate statistic to use to describe charges would be the mean, as it is a measure of central tendency that reflects the total amount charged divided by the total number of cases. The mean is sensitive to outliers and extreme values, so if the distribution is heavily skewed or contains extreme values, the median may be a more appropriate measure.

Admission source: The most appropriate statistic to use to describe admission source would be the mode, as it is a categorical variable that represents the most common source of admission. The mode provides insight into the most frequent route of admission for patients, which can be useful in identifying patterns and trends in patient flow.

Gender: The most appropriate statistic to use to describe gender would be the frequency or count of males and females in the dataset, as it is a binary categorical variable. The frequency provides insight into the distribution of males and females in the sample, which can be useful in identifying gender-related disparities or trends in healthcare utilization.

Discharge status: The most appropriate statistic to use to describe discharge status would be the frequency or count of each category of discharge status, such as home, skilled nursing facility, hospice, etc. This provides insight into the distribution of patients' discharge destinations, which can be useful in understanding the healthcare needs and outcomes of different patient populations.

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The time that it would take Justin to charge the batter to 100% on both devices will be 111.67 minutes

It takes about 36.67 minutes to charge the Nintendo Switch entirely.

The iPad has a residual battery life of 40%, which means it must gain an additional 60% percent increase in energy.

Since we understand that the tablet powers up by approximately 12 percentage points every quarter of an hour, the estimated duration for one hundred percent charging is close to 75 minutes.

Consequently, Justin must energize both gadgets and will need nearly 111.67 minutes or almost two hours to accomplish this task completely.

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To determine the minimum number of people at a party so that at least one of the three scenarios occurs, we can use the pigeonhole principle.

If we consider each person as a pigeon and each scenario as a hole, we need to determine the minimum number of pigeons (people) such that at least one hole (scenario) has three pigeons (people) in it.

For the first scenario, we need to find three people who are f2f friends. This means that each person needs to have two f2f friends (excluding themselves). So, if we have two people at the party, they cannot be f2f friends, and if we have three people, they can all be f2f friends. Therefore, the minimum number of people needed for this scenario is three.

For the second scenario, we need to find three people who have met online but not f2f. This means that each person needs to have two online friends (excluding themselves). If we have two people at the party, they cannot have any online friends, and if we have three people, it is possible that one person has two online friends while the other two have none. Therefore, the minimum number of people needed for this scenario is three.

For the third scenario, we need to find three people who are mutual strangers, having never met before. This means that each person needs to be a stranger to the other two people. If we have two people at the party, they cannot be strangers, and if we have three people, it is possible that all three are strangers to each other. Therefore, the minimum number of people needed for this scenario is three.

Therefore, the minimum number of people needed at the party so that at least one of the three scenarios occurs is three.
Using the pigeonhole principle, let's consider three categories for party attendees: face-to-face friends, online friends, and mutual strangers.

To ensure at least one of the given scenarios occurs, we need to apply the pigeonhole principle to each category, considering a group of three people. This means we will have three pigeonholes and need to find the minimum number of attendees to guarantee that one of the pigeonholes will have at least three people.

If there are two people in each category, there's no guarantee that any of the given scenarios will occur. Therefore, we need at least three people in one category. When we distribute three attendees across each category (2 f2f friends, 2 online friends, and 2 strangers), the next person attending the party will force at least one category to have three people.

Thus, the minimum number of people at the party to ensure one of the given scenarios occurs is 2+2+2+1 = 7 people.

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There are 50,257 permutations of the 10 digits that either begin with the three digits 987, contain the digits 45 in the fifth and sixth positions, or end with the three digits 123.

To find the number of permutations that meet the given criteria, we can break the problem into three cases:

Case 1: Permutations that begin with the three digits 987.
For these permutations, we have 7 digits remaining that can be arranged in any order. Therefore, there are 7! = 5040 permutations that begin with 987.

Case 2: Permutations that contain the digits 45 in the fifth and sixth positions.
For these permutations, we can first place the digits 45 in the fifth and sixth positions, leaving us with 8 digits remaining. These 8 digits can be arranged in any order, so there are 8! = 40,320 permutations that contain the digits 45 in the fifth and sixth positions.

Case 3: Permutations that end with the three digits 123.
For these permutations, we have 7 digits remaining that can be arranged in any order before the final three digits. Therefore, there are 7! = 5040 permutations that end with 123.

To find the total number of permutations that meet at least one of these criteria, we can use the principle of inclusion-exclusion.

First, we add the number of permutations from each case:

5040 + 40,320 + 5040 = 50,400

Next, we subtract the number of permutations that meet two of the criteria. There are two pairs of criteria that overlap:

- Permutations that begin with 987 and contain 45 in the fifth and sixth positions
- Permutations that contain 45 in the fifth and sixth positions and end with 123

To count the number of permutations that meet both of these criteria, we can first place the digits 987 at the beginning, followed by the digits 45 in the fifth and sixth positions, and then the remaining 5 digits can be arranged in any order before the final 123. Therefore, there are 5! = 120 permutations that meet both criteria.

We can do the same for the other pair of overlapping criteria:

- Permutations that begin with 987 and end with 123
- Permutations that contain 45 in the fifth and sixth positions and end with 123

To count the number of permutations that meet both of these criteria, we can first place the digits 987 at the beginning, followed by the remaining 4 digits which can be arranged in any order before the final 123. Therefore, there are 4! = 24 permutations that meet both criteria.

Now we can subtract the total number of permutations that meet two criteria:

120 + 24 = 144

Finally, we add back in the number of permutations that meet all three criteria:

There is only one permutation that meets all three criteria: 98745*****123

Therefore, the total number of permutations that meet at least one of the given criteria is:

50,400 - 144 + 1 = 50,257

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Answer:96

Step-by-step explanation:

(4x4)+(4x4)+(4x4)+(4x4)+(4x4)+(4x4)

16+16+16+16+16+16

48+48

96

The equations of the graph from the figure are y = 4 and y = -2

From the question, we have the following parameters that can be used in our computation:

The graph

On the graph, we can see that

We have two horizontal lines that pass through the points y = 4 and y = -2

This means that the equations represented on the graph are y = 4 and y = -2

So, we can conclude that none of the options are true from the options

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Answer: Average speed is given by the formula:

speed = distance ÷ time

Given that Darlene rode her bike 8 2/5 miles in 3/4 of an hour. We need to convert the mixed number 8 2/5 to an improper fraction.

8 2/5 = (8 x 5 + 2) / 5 = 42/5

So, Darlene rode her bike a distance of 42/5 miles in a time of 3/4 hours.

Substitute speed = distance ÷ time

speed = (42/5) ÷ (3/4)

To divide by a fraction, we invert and multiply:

speed = (42/5) x (4/3)

speed = 56/5

So, Darlene's average speed was 56/5 miles per hour (mph).

To simplify this fraction, we can divide both the numerator and denominator by 1:

speed = 11/1

The equation of the quadratic function in standard form is -6/25(x - 7)(x + 2) = 0 and the factored form is (x - 7)(x + 2) = 0.

To find the equation of the quadratic function, we need to use the x-intercepts to write the equation in factored form, which is (x - r)(x - s) = 0, where r and s are the roots of the equation. In this case, the roots are -2 and 7, so the factored form of the equation is (x + 2)(x - 7) = 0.

To find the value of a in the standard form equation, we need to use the point (5,-42). We substitute x = 5 and y = -42 into the standard form equation and solve for a. This gives us the equation -2a + 15b + c = -42.

We can also find the value of c by substituting one of the x-intercepts into the factored form equation. If we substitute x = -2, we get (-2 + 2)(-2 - 7) = 0, which simplifies to -18 = c.

Substituting this value of c into the equation -2a + 15b + c = -42 gives us -2a + 15b - 18 = -42, which simplifies to -2a + 15b = -24.

Finally, we can use the factored form equation to solve for b. Expanding the equation (x + 2)(x - 7) = 0 gives us x² - 5x - 14 = 0. Using the quadratic formula or factoring, we find that the roots are -2 and 7, which are the same as the x-intercepts.

We can therefore write the equation in standard form as a(x - 7)(x + 2) = 0. To find the value of a, we use the equation -2a + 15b - 18 = -42 and the value of b = -1 to get a = -6/25.

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The value of the constant c that makes the probability statement P(-esz Sc) = 0.252 correct is 0.68. To determine the value of the constant c that makes the probability statement P(-esz Sc) = 0.252 correct, we need to use the complement rule, which states that P(A) = 1 - P(A').

In this case, we can rewrite the statement as P(-esz Sc)' = 0.748 (since the complement of the event "-esz Sc" is "esz Sc'").

Next, we need to use the standard normal distribution table or calculator to find the z-score that corresponds to a probability of 0.748. The closest value we can find is 0.7464, which corresponds to a z-score of -0.68 (rounded to two decimal places).

Now we can use the standard normal distribution formula

[tex]z = (x - mu) / sigma,[/tex]

where mu is the mean (which is 0 for the standard normal distribution) and sigma is the standard deviation (which is 1 for the standard normal distribution).

Plugging in the values we have, we get -0.68 = (-c - 0) / 1, which simplifies to -0.68 = -c. Solving for c, we get c = 0.68 (rounded to two decimal places).

Therefore, the value of the constant c that makes the probability statement P(-esz Sc) = 0.252 correct is 0.68.

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(a) 50% of the packages will weigh more than 1 pound.

(b) 24.64% of the packages will weigh between .95 and 1.05 pounds.

(c) The probability that a randomly selected package of ground beef will weigh less than .80 pound is 9.18%.

(d) It would be unusual to find a package of ground beef that weighs 1.45 pounds. Such a large package could be explained by either an error in the packaging process or a deliberate attempt to provide larger packages to some customers.

a. To find the proportion of packages that weigh more than 1 pound, we need to calculate the area under the normal curve to the right of 1 pound. Using a standard normal table or calculator, we can find this probability to be:

P(Z > (1-1)/0.15) = P(Z > 0) = 0.5000

Therefore, 50% of the packages will weigh more than 1 pound.

b. To find the proportion of packages that weigh between .95 and 1.05 pounds, we need to calculate the area under the normal curve between these two values. Using a standard normal table or calculator, we can find this probability to be:

P((.95-1)/0.15 < Z < (1.05-1)/0.15) = P(-0.33 < Z < 0.33) = 0.3482

Therefore, 34.82% of the packages will weigh between .95 and 1.05 pounds.

c. To find the probability that a randomly selected package of ground beef will weigh less than .80 pound, we need to calculate the area under the normal curve to the left of .80 pound. Using a standard normal table or calculator, we can find this probability to be:

P(Z < (.80-1)/0.15) = P(Z < -1.33) = 0.0912

Therefore, there is a 9.12% chance that a randomly selected package of ground beef will weigh less than .80 pound.

d. It would be quite unusual to find a package of ground beef that weighs 1.45 pounds, as this is more than three standard deviations above the mean. The probability of finding a package that weighs 1.45 pounds or more can be calculated as:

P(Z > (1.45-1)/0.15) = P(Z > 2.67) = 0.0038

This is a very small probability, suggesting that such a large package is an outlier in the distribution. It could be due to a mistake in packaging or an intentional oversized package for a special order.

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To determine the critical value z alpha for alpha equals 0.04, we need to find the z value at which the standard normal distribution has a right-tailed area of 0.04.

First, we need to find the area in the left tail of the standard normal distribution that corresponds to 1 - alpha. Since alpha is 0.04, 1 - alpha is 0.96. Using a standard normal distribution table or calculator, we can find that the z value corresponding to a left-tailed area of 0.96 is approximately 1.75.

Next, we need to find the z value that corresponds to a right-tailed area of 0.04. This is simply the negative of the z value we found above since the standard normal distribution is symmetric at about 0. Therefore, the critical value z alpha for alpha equals 0.04 is approximately -1.75.

Note that the critical value is also sometimes referred to as the z-score, and is used in hypothesis testing to determine whether a sample mean is significantly different from a population mean. The critical value represents the boundary beyond which we reject the null hypothesis.
To determine the critical value zα for α=0.04, follow these steps:

Step 1: Identify the given values
- Right-tailed area (α) = 0.04

Step 2: Convert the right-tailed area to the left-tailed area
Since the standard normal distribution is symmetrical, you can find the left-tailed area by subtracting α from 1:
Left-tailed area = 1 - α = 1 - 0.04 = 0.96

Step 3: Find the z value corresponding to the left-tailed area
Using a z-table or an online calculator, look up the z-value corresponding to a left-tailed area of 0.96. This z value will be your critical value (zα).

The critical value zα corresponding to a right-tailed area of 0.04 (left-tailed area of 0.96) is approximately 1.75.

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The dimensions of the rectangle are length = 21 meters and width = 18 meters.

To find the dimensions of the rectangle meeting these conditions, we first need to set up an equation based on the given information. We know that the perimeter is 78 meters, so we can use the formula for the perimeter of a rectangle:

Perimeter = 2(length + width)

Substituting in the given information, we get:

78 = 2(3 + width + width)

Simplifying, we can combine like terms:

78 = 2(3 + 2width)

78 = 6 + 4width

Subtracting 6 from both sides:

72 = 4width

Dividing by 4:

width = 18

So we know the width of the rectangle is 18 meters. We also know that the length is 3 meters greater than the width, so:

length = width + 3 = 18 + 3 = 21

Therefore, the dimensions of the rectangle meeting the specified conditions are:

width = 18 meters

length = 21 meters

To find the dimensions of the rectangle meeting the specified conditions, we'll use the information given: the perimeter is 78 meters and the length is 3 meters greater than the width.

Step 1: Write down the formula for the perimeter of a rectangle.
Perimeter (P) = 2(Length (L) + Width (W))

Step 2: Substitute the given values and conditions into the formula.
78 = 2(L + W)
Given that the length is 3 meters greater than the width, we can write L = W + 3.

Step 3: Substitute the expression for L in terms of W into the perimeter formula.
78 = 2((W + 3) + W)

Step 4: Solve the equation for W.
78 = 2(2W + 3)
39 = 2W + 3
36 = 2W
W = 18 meters

Step 5: Find the length (L) using the expression L = W + 3.
L = 18 + 3
L = 21 meters

So, the dimensions of the rectangle are length = 21 meters and width = 18 meters.

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Answer: I don't know, sorry!

Step-by-step explanation:

Answer:

Step-by-step explanation: soz cn't help

The equivalent fractions for 1/5 and 3/4 with a common denominator of 20 are:

1/5 = 4/20

3/4 = 15/20

To write equivalent fractions for 1/5 and 3/4 using 20 as the common denominator

we need to multiply the numerator and denominator of each fraction by the same number such that the denominator becomes 20.

For 1/5:

1/5 = (1 x 4)/(5 x 4) = 4/20

Therefore, an equivalent fraction for 1/5 with a denominator of 20 is 4/20.

For 3/4:

3/4 = (3 x 5)/(4 x 5) = 15/20

An equivalent fraction for 3/4 with a denominator of 20 is 15/20.

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The correct statement regarding the data-sets is given as follows:

A. A girl is 10% more likely to work after school than a boy.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

Out of 30 boys, 18 work after school, hence the probability is given as follows:

18/30 = 0.6 = 60%.

Out of 20 girls, 14 work after school, hence the probability is given as follows:

14/20 = 0.7 = 70%.

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