ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.

The correct answer is C) The initial population at the time of the estimation

Explanation:

A mathematical function represents the relationship between two variables by showing how one increases or decreases as the other changes. In the case presented, the variables are the time in years represented by x and the population represented by f (x). In this context, the value 160.000 in column f(x) represents the population on the year 0, this means the current population or initial population when the function or estimation is created. On the other hand, other values represent the population in the future, for example, the value 173189 represents the population in 4 years.

Answer:

yes the 3ed answer in correct on ENG 2022

Answer:

Ones: 91

Hundredths: 91.20

Step-by-step explanation:

All numbers that comprises the digits, 91.20, have place value.

The 9 in the digit has a place value of tens, i.e. 9*10 = 90.

The 1 has a place value of one's, i.e. 1*1 = 1

The 2, after the decimal point to the right, has a place value of tenth, i.e. 1*10-¹ = ⅒ = 0.1

While the zero has a place value of hundredth.

Therefore, the digits, in the ones place = 91

In the hundredths place = 91.20

Answer:

If x=7 that means that if 7 substitute r which is 7^2 and 7*7=49 and 49/4

=12 1/4

So the remainder is 1

Step-by-step explanation:

Answer:

(5, 11) and (2, 2)

Step-by-step explanation:

y = (x-2)² + 2

y + 4 = 3x

(x-2)² + 2 + 4 = 3x

x² - 4x + 4 + 6 = 3x

x² - 7x + 10 = 0

(x - 5)(x - 2) = 0

x - 5 = 0, x = 5

x - 2 = 0, x = 2

y = (5-2)² + 2 = 11

(5, 11)

y = (2-2)² + 2 = 2

(2, 2)

Answer:

[tex]\large \boxed{\sf \bf \ \text{ The solutions are } x=2, y=2 \text{ and } x=5, y=11.} \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

We want to solve this system of equations.

[tex]\begin{cases}&y=(x-2)^2+2\\&y+4=3x\end{cases}[/tex]

This is equivalent to (subtract 4 from the second equation).

[tex]\begin{cases}&y=(x-2)^2+2\\&y=3x-4\end{cases}[/tex]

Then, we can write y = y, meaning:

[tex](x-2)^2+2=3x-4\\\\\text{*** We develop the left side. ***}\\\\x^2-4x+4+2=3x-4 \\\\\text{*** We simplify. *** }\\\\x^2-4x+6=3x-4\\\\\text{*** We subtract 3x-4 from both sides. ***}\\\\x^2-4x+6-3x+4=0\\\\\text{*** We simplify. *** }\\\\x^2-7x+10=0[/tex]

[tex]\text{*** The sum of the zeroes is 7 and the product 10 = 5 x 2 ***}\\\\\text{*** We can factorise. ***}\\\\x^2-5x-2x+10=x(x-5)-2(x-5)=(x-2)(x-5)=0\\\\x-2 = 0 \ \ or \ \ x-5 = 0\\\\x= 2 \ \ or \ \ x=5[/tex]

For x = 2, y =0+2=2 (from the first equation) and for x = 5 y=3*5-4=15-4=11 (from the second equation)

So the solutions are (2,2) and (5,11)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

It's 144 square units

Step-by-step explanation:

The pyramid has a square base with 8 sides and a slant height of 5

a=8

l=5

The total are of the square base pyramid is

A= [tex]a^{2}[/tex]+2al

a is side length of square and l is slant height

A= [tex](8)^{2}+2[/tex] x 8 x 5

A=64+80

A=144

Answer:

All real values of x such that x ≥-3

Step-by-step explanation:

g(x) = sqrt(x+3)

A sqrt must be greater than or equal to zero

sqrt (x+3) ≥ 0

Square each side

x+3≥ 0

Subtract 3 from each side

x ≥-3

The restrictions on x are x ≥-3

That means the domain is x ≥-3

All real values of x such that x ≥-3

Answer:

[tex]\boxed{\mathrm{B}}[/tex]

Step-by-step explanation:

[tex]g(x)=\sqrt{x+3}[/tex]

A square root must have a value of greater than or equal to 0.

[tex]\sqrt{x+3}\geq 0[/tex]

Square both sides.

[tex]x+3\geq 0[/tex]

Subtract 3 from both sides.

[tex]x\geq -3[/tex]

Answer:

Step-by-step explanation:

7x² - 4x - 3 = 0

Rewrite - 4x as a difference

That's

7x² - 7x + 3x - 3 = 0

Factorize the expression

7x( x - 1) + 3 ( x - 1) = 0

(7x + 3)( x - 1 ) = 0

7x + 3 = 0 x - 1 = 0

7x = - 3 x = 1

x = -3/7

The solutions are

x = - 3/7 or x = 1

Hope this helps you

Answer:

3/4

Step-by-step explanation:

Explanation:

List out the total number of outcomes = {1,2,3,4,5,6,7,8,9,10,11,12}

We have 12 items in this list.

From this list, highlight the outcomes that are less than 9. So we will have this smaller list of {1,2,3,4,5,6,7,8} which has 8 items in it.

There are 8 ways to get what we want (a number less than 9) out of 12 outcomes total

The probability is therefore 8/12 = 2/3

Answer: The number of possibilities = 380

Step-by-step explanation:

Given, There are 20 players on a soccer team. From them, a captain and an alternate captain have to be chosen.

Since, captain and alternate captain comes in order.

Number of ways to choose r things out of n things (when order matters) :

[tex]^nP_r=\dfrac{n!}{(n-r)!}[/tex]

Number of ways to choose 2 players ( for  captain and alternate captain ) from 20 players :

[tex]^{20}P_2=\dfrac{20!}{18!}=20\times19=380[/tex]

Hence, the number of possibilities = 380

Answer:

6

Step-by-step explanation:

Well first we need to tfraph the following equation,

2y - x = -6

Look at the image below

Thus,

by looking at the graph we can tell that the x-intercept is 6.

Hope this helps :)

Answer:

Step-by-step explanation:

Method 1

[tex]2y -x = -6\\Let ; y =0\\2(0) -x =-6\\-x =-6\\x = 6\\\\ (6 , 0 )[/tex]

Method 2

[tex]x - interept = -c/a\\a = -1\\b =2\\c = 6\\\\x - intercept =\frac{ -(6)}{-1} \\\\x - intercept = 6[/tex]

Answer:  19)  117°                    20) 53°

               21)  229°                   22) 119°

               23) 155°                    24) 323°

Step-by-step explanation:

Use Pythagorean Theorem to find r:     x² + y² = r²

19) x = [tex]-\sqrt{17}[/tex] ,  y = 8,    r = 9

     [tex]\cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{-\sqrt{17}}{9} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{-\sqrt{17}}{9}\bigg)\rightarrow \quad \theta = \large\boxed{117^o}[/tex]

20) x = 3,   y = 4,   r = 5

      [tex]\cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{3}{5} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{53^o}[/tex]

21) x = [tex]-\sqrt7[/tex],   y = -3,   r = 4

    [tex]\sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{4} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{4}\bigg)\rightarrow \quad \theta = \large\boxed{229^o}[/tex]    

22) x = [tex]-\sqrt{15}[/tex],   y = 7,   r = 8

     [tex]\tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{7}{-\sqrt{15}} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{7}{-\sqrt{15}}\bigg)\rightarrow \quad \theta = \large\boxed{119^o}[/tex]

23) x = -13,   y = 6,   r = [tex]\sqrt{205}[/tex]

     [tex]\tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{6}{-13} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{6}{-13}\bigg)\rightarrow \quad \theta = \large\boxed{155^o}[/tex]

24) x = 4,    y = -3,   r = 5

     [tex]\sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{5} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{323^o}[/tex]

For the point [tex](-\sqrt{17},8)[/tex], [tex]cos\theta=0.4581[/tex]

For the point [tex](3,4)[/tex], [tex]cos\theta=0.6[/tex]

For the point [tex](-\sqrt7,-3)[/tex], [tex]sin\theta=-0.75[/tex]

For the point [tex](-\sqrt{15},7)[/tex], [tex]tan\theta=-1.807[/tex]

For the point [tex](-13,6)[/tex], [tex]tan\theta=-0.4615[/tex]

For the point [tex](4,-3)[/tex], [tex]sin\theta=-0.6[/tex]

For ratios [tex]sin\theta[/tex] and [tex]cos\theta[/tex], we need to calculate the hypotenuse of the right-angled triangle. For the ratio [tex]tan\theta[/tex], we can directly make use of the coordinate points.

For the point [tex](-\sqrt{17},8)[/tex]

[tex]r=\sqrt{17+8^2}=9[/tex]

[tex]cos\theta=\dfrac{x}{r}\\\\=-\dfrac{\sqrt{17}}{9}\approx0.4581[/tex]

For the point [tex](3,4)[/tex]

[tex]r=\sqrt{3^2+4^2}=5[/tex]

[tex]cos\theta=\dfrac{x}{r}\\\\=\dfrac{3}{5}=0.6[/tex]

For the point [tex](-\sqrt7,-3)[/tex]

[tex]r=\sqrt{7+(-3)^2}=4[/tex]

[tex]sin\theta=\dfrac{y}{r}\\=-\dfrac{3}{4}=-0.75[/tex]

For the point [tex](-\sqrt{15},7)[/tex]

[tex]tan\theta=\dfrac{y}{x}\\=-\dfrac{7}{\sqrt{15}}=-1.807[/tex]

For the point [tex](-13,6)[/tex]

[tex]tan\theta=\dfrac{y}{x}\\=-\dfrac{6}{13}=-0.4615[/tex]

For the point [tex](4,-3)[/tex]

[tex]r=\sqrt{4^2+(-3)^2}=5[/tex]

[tex]sin\theta=\dfrac{y}{r}\\=-\dfrac{3}{5}=-0.6[/tex]

Learn more about trigonometry here: https://brainly.com/question/23686339

Answer:

A, B, D, and E

Step-by-step explanation:

recall that the inverse functions verify the identity rule that one function applied on the other will render the identity "x". It is like launching a function from a value x, and then taking the trip back to the value that originated it.

Such also implies that the domain where you started becomes the Range of the function that makes the trip back. And of course, its reciprocal: The Range of the starting function becomes the Domain of the function that gets back.

Therefore, andswers A, B, D and E are correct answers

Answer:

The salary of the governor of state A is $171,575 and the salary of the governor of state B is $117,830.

Step-by-step explanation:

If the governor of state A's salary is "x" and the governor of state B's salary is "y", then:

[tex]x = y + 53,745[/tex]

If the total of their salaries is $289,405, then the sum of x and y should be equal to that number.

[tex]x + y = 289,405\\[/tex]

Applying the first expression on the second allows us to solve for y as shown below.

[tex]y + 53745 + y = 289405\\2y = 289405 - 53745\\2y = 235660\\y = 117830[/tex]

Using this data on the first expression allows us to solve for the first governo's salary.

[tex]x = 117830 + 53745 = 171575[/tex]

The salary of the governor of state A is $171,575 and the salary of the governor of state B is $117,830.

Answer:

B

Step-by-step explanation:

C is too little and D is too much

To solve this system of equations by addition, our first goal is to cancel

out one of the variables by adding the two equations together.

However, if we add these two equations together right away, nothing

will cancel so we need to set things up so a variable will cancel.

Notice that we have an 2x in our second equation.

If we had a -2x in our first equation, then the x's would cancel out.

In order to create a -2x in the first equation, we simply

multiply both sides of the first equation by -2.

So we have (-2)(x - 2y) = (-4)(-2) which can be rewritten as -2x + 4y = 8.

Now rewrite both equations, as shown below.

Now when we add the equations together, the x terms

will cancel out and we're left with 5y = 15.

Dividing both sides by 5, y = 3.

To solve for x, plug a 3 in for y in either one of our 2 original equations.

So let's go with our second equation.

Plugging a 3 in for y, we get 2x + (3) = 7.

Now subtract 4 from both sides to get 2x = 4.

Dividing both sides by 2, we fid that x = 2.

Since x = 2 and y = 3, our answer is the ordered pair (2, 3).

Answer:

You get 12$ per B and 15$ per A.  Thus, the answer is A) $282

Step-by-step explanation:

4A+4B=108

Divide by 4

A+B=27

Subtract B

A = 27 - B

3A+5B=105

Substitution

3(27-B)+5B = 105

Distribute

81-3B+5B=105

Combine like terms

81+2B=105

Subtract 81

2B=24

Divide by 2

B = 12

A = 15

14(15)+6(12)=x

210+72=x

282=x

Hope it helps <3

Answer: l = 60 ft and w = 30 ft

P = 2(l + w)

180 = 2(l + w)

Let x = width of his yard

Let 2x = length of his yard

[tex]180=2(2x+x)[/tex]

[tex]\frac{180}{2}=\frac{2(2x+x)}{2}[/tex]

[tex]90=3x[/tex]

[tex]\frac{90}{3} =\frac{3x}{3}[/tex]

[tex]x=30ft[/tex]

l = 2x = 30(2) = 60 ft

Check:

180 = 2(l + w)

180 = 2(60 + 30)

180 = 2(90)

180 = 180

LS = RS

Answer: A) 21.25 ≤ x ≤ 22.75

Step-by-step explanation:

Given, Average weight of basketballs = 22 ounces

It is possible for its weight to vary at most 0.75 ounces from this average.

Let x denotes the weight of the basket ball.

Then, the required range  for a basketball's weight:

Average-0.75 ≤ x ≤ Average+0.75

⇒22-0.75 ≤ x ≤ 22+0.75

⇒21.25 ≤ x ≤ 22.75

Hence, the range for a basketball's weight: 21.25 ≤ x ≤ 22.75 .

Correct option: A) 21.25 ≤ x ≤ 22.75

Answer:

1/4

1/2

3/4

Step-by-step explanation:

Given:

Types of colors in the spinner

Yellow 1

Red 2

Blue 1

Total:4

Successful outcome of Yellow:1

Successful outcome of Red:2

Successful outcome of Blue:1

Required:

Probability of the

Formula:

Probability= successful outcome ÷ possible outcome

Solution

Probability=1 ÷ 4

Probability= 2÷4

Probability= 3÷4

Hope this helps ;) ❤❤❤

Answer:

D

Step-by-step explanation:

Apply rule : [tex]-(-a)=+a[/tex]

Negative times negative is positive.

The expression turns into a sum of fractions.

Answer:3.82

Step-by-step explanation: Find 80% of 4.50 (4.50 x 0.8=3.60) then find 6% of 3.6 (0.06 x 3.6= 0.216) add 0.216 + 3.6= 3.816 but in money you have to round so the answer is 3.82

Answer:

1.8

Step-by-step explanation:

$4.50-%20=3.6

3.6- %9=1.8

Step-by-step explanation:

I would suggest that she studies or do a cost analysis of what it will cost her to transport to the library to request for the book and return it, if it is not expensive as compared to the cost of the book she should travel down to request for it. else she should purchase the book

Or

Fareeda can simply check if the second library has a distant library services so that the book can be either

1. Sent to her home or placement address, or

2.Scans of book chapters and articles be emailed to her.

Answer:

Hey I know!

1.10 euro

Answer:

397.5 :)

Step-by-step explanation:

Answer:

Construction II

Step-by-step explanation:

Construct 3 perpendicular bisectors of the triangles sides; where they intersect is the point of concurrency. The distance from the point of concurrency to one of the vertices is the radius.

Answer:

-9.6

Step-by-step explanation:

[tex]2\frac{2}{5} =2.40\\-\frac{1}{4} =-0.25[/tex]

If change them into decimals it looks like that.

Then all you have to do is use standard calculator to find the answer.

[tex]\frac{2.40 }{-0.25} =-9.6[/tex]

Answer:9 and 3/8  

Step-by-step explanation:

you have to make 2 and 2/5 into an improper fraction then make the -1/4 into a -4/1 then multiply across to make 48/5 then you have to reduce down to 8 and 8/5. but that cant happen so you reduce again and get 9 and 3/8.

Answer:

The data that we have is:

f(x) = x + 5

g(x) = x^2 + 1

p(x) = g(x) + f(x) = (x^2 + 1) + (x + 5) = x^2 + x + 6.

q(x) = g(x) - f(x) =  (x^2 + 1) - (x + 5) = x^2 - x - 4

We want to find  p(x)*q(x)

well, we can replace:

p(x)*g(x) = (g(x) + f(x))*(g(x) - f(x))

Now, you can recall the relationship:

a^2 - b^2 = (a + b)*(a - b)

then we have that:

(g(x) + f(x))*(g(x) - f(x)) = g(x)^2 - f(x)^2

now we can replace g(x) and f(x) by the expressions that we know:

g(x)^2 - f(x)^2 = (x^2 + 1)^2 - (x + 5)^2

now we can simplify this:

(x^2 + 1)^2 - (x + 5)^2 = (x^4 + 2*1*x + 1^2) - (x^2 + 2*5*x +5^2)

= x^4 + 2*x + 1 - x^2 - 10x - 25

= x^4 - x^2 - 8*x - 24

p(x)*q(x) = x^4 - x^2 - 8*x - 24

Answer:

x^4+x^2-10x-24

Step-by-step explanation:

Answer: 40 inches

Step-by-step explanation:

The woman weight and the seat will be: 145lb + 5lb = 150lb,

her son weight and the seat will be: 95lb + 5lb = 100lb

her daughter weight and the seat will be: 70lb + 5lb = 75lb

Given that the woman is on the left side of the seesaw, 60 inches from the fulcrum. The moment of the woman will be 150 × 60 = 9000

The daughter and son both get on the right side.

If the son sits 60 inches from the fulcrum, his moment will be:

100 × 60 = 6000

The sum of the moment of the son and daughter must be equal to the moment of their mother.

Let the position of the daughter = X

The moment of the daughter will be:

75 × X = 75X

Equate the moment of the mother to the sum of the moment of her children

9000 = 6000 + 75X

Collect the like terms

75X = 9000 - 6000

75X = 3000

X = 3000/75

X = 40

The position the daughter should sit to balance the seesaw is 40 inches away from seasaw to the right.

Answer:

0.73

Step-by-step explanation:

Data obtained from the question include the following:

Length (L) of square = x

Base (b) of triangle = (3x – 2)

Height (h) of triangle = (2x + 4)

Area of square = L²

Area of square = x²

Area of triangle = ½bh

Area of triangle = ½(3x – 2) (2x + 4)

Expand

½ [3x(2x + 4) –2(2x + 4)]

½[6x² + 12x – 4x – 8]

½[6x² + 8x – 8]

3x² + 4x – 4

Area of triangle = 3x² + 4x – 4

Now, to find the value of x which makes the area of the two figures the same, we simply equate both areas as shown below:

Area of triangle = area of square

Area of triangle = 3x² + 4x – 4

Area of square = x²

Area of triangle = area of square

3x² + 4x – 4 = x²

Rearrange

3x² – x² + 4x – 4 = 0

2x² + 4x – 4 = 0

Solving by formula method

a = 2, b = 4, c = –4

x = – b ± √(b² – 4ac) / 2a

x = – 4 ± √(4² – 4×2×–4) / 2×2

x = – 4 ± √(16 + 32) / 4

x = – 4 ± √(48) / 4

x = (– 4 ± 6.93)4

x = (– 4 + 6.93)4 or (– 4 – 6.93)4

x = 0.73 or –2.73

Since the measurement can not be negative, the value of x is 0.73.

Answer:

[tex]$\arcsin\left(\frac{129\sqrt{2}}{250}\right)\approx 0.8179$[/tex]

Step-by-step explanation:

[tex]\alpha \text{ and } \beta \text{ in Quadrant I}[/tex]

[tex]$\tan(\alpha)=\frac{1}{7} \text{ and } \sin(\beta)=\frac{1}{\sqrt{10}}=\frac{\sqrt{10} }{10} $[/tex]

Using Pythagorean Identities:

[tex]\boxed{\sin^2(\theta)+\cos^2(\theta)=1} \text{ and } \boxed{1+\tan^2(\theta)=\sec^2(\theta)}[/tex]

[tex]$\left(\frac{\sqrt{10} }{10} \right)^2+\cos^2(\beta)=1 \Longrightarrow \cos(\beta)=\sqrt{1-\frac{10}{100}} =\sqrt{\frac{90}{100}}=\frac{3\sqrt{10}}{10}$[/tex]

[tex]\text{Note: } \cos(\beta) \text{ is positive because the angle is in the first qudrant}[/tex]

[tex]$1+\left(\frac{1 }{7} \right)^2=\frac{1}{\cos^2(\alpha)} \Longrightarrow 1+\frac{1}{49}=\frac{1}{\cos^2(\alpha)} \Longrightarrow \frac{50}{49} =\frac{1}{\cos^2(\alpha)} $[/tex]

[tex]$\Longrightarrow \frac{49}{50}=\cos^2(\alpha) \Longrightarrow \cos(\alpha)=\sqrt{\frac{49}{50} } =\frac{7\sqrt{2}}{10}$[/tex]

[tex]\text{Now let's find }\sin(\alpha)[/tex]

[tex]$\sin^2(\alpha)+\left(\frac{7\sqrt{2} }{10}\right)^2=1 \Longrightarrow \sin^2(\alpha) +\frac{49}{50}=1 \Longrightarrow \sin(\alpha)=\sqrt{1-\frac{49}{50}} = \frac{\sqrt{2}}{10}$[/tex]

The sum Identity is:

[tex]\sin(\alpha + \beta)=\sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)[/tex]

I will just follow what the question asks.

[tex]\text{Find the value of }\alpha+2\beta[/tex]

[tex]\sin(\alpha + 2\beta)=\sin(\alpha)\cos(2\beta)+\sin(2\beta)\cos(\alpha)[/tex]

[tex]\text{I will first calculate }\cos(2\beta)[/tex]

[tex]$\cos(2\beta)=\frac{1-\tan^2(\beta)}{1+\tan^2(\beta)} =\frac{1-(\frac{1}{7})^2 }{1+(\frac{1}{7})^2}=\frac{24}{25}$[/tex]

[tex]\text{Now }\sin(2\beta)[/tex]

[tex]$\sin(2\beta)=2\sin(\beta)\cos(\beta)=2 \cdot \frac{\sqrt{10} }{10}\cdot \frac{3\sqrt{10} }{10} = \frac{3}{5} $[/tex]

Now we can perform the sum identity:

[tex]\sin(\alpha + 2\beta)=\sin(\alpha)\cos(2\beta)+\sin(2\beta)\cos(\alpha)[/tex]

[tex]$\sin(\alpha + 2\beta)=\frac{\sqrt{2}}{10}\cdot \frac{24}{25} +\frac{3}{5} \cdot \frac{7\sqrt{2} }{10} = \frac{129\sqrt{2}}{250}$[/tex]

But we are not done yet! You want

[tex]\alpha + 2\beta[/tex] and not [tex]\sin(\alpha + 2\beta)[/tex]

You actually want the

[tex]$\arcsin\left(\frac{129\sqrt{2}}{250}\right)\approx 0.8179$[/tex]

Answer:

ok bye guy................

Answer:

isosceles

Step-by-step explanation: