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Actually Welcome to the Concept of the Power and Energy.
As a pendulum swings from the bottom position to the top position, it gains a height which means it gains the Potential energy.
hence we can say that, kinetic energy is changed into potential energy.
So, the Option A.) is correct.
Answer:
I think it's A)
Explanation:
it could be wrong i don't know hope it's not good luck!
[O.04H]The table below shows the use of some energy production methods over time.
Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500
Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.
I think The coastal areas were highly polluted
Answer:
i think its greenhouse gases may increase
Explanation:
A voltage is applied to a resistor,
which creates a 1.50 A current. If
you double the resistance, keeping
the voltage the same, what will the
new current be?
(Unit = A)
Answer:
Explanation:
By Ohms Law, Voltage = Current * Resistance
Keeping the voltage the same and doubling the resistance, the current will be halved.
So the new current = 1.5/2 = 0.75A
By using Ohms law, the current will be 0.75A.
What is Ohm's law?Ohm's law states that the current flowing through a resistance is proportional to potential difference across the resistance under constant temperature and pressure conditions. Ohm's law can be expressed as:
V =IR
Here, I = 1.50 AR = R Ωso, V = 1.50 R Now Voltage is same but resistance is doubled so new resistance is
Now, put the values of given data in ohms law formula:
2RI = 1.50 R/ 2R = 0.75A
Hence current is 0.75A
To know more about Ohms law here
https://brainly.com/question/14796314.
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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in
(a) watts
(b) horsepower.
Answer:
A. 10023.75 Watts
B. 13.44 horse power
Explanation:
A. Determination of the power in Watts.
We'll begin by calculating the energy of the cheetah. This can be obtained as follow
Velocity (v) = 27 m/s
Mass (m) = 110 kg
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 110 × 27²
KE = 55 × 729
KE = 40095 J
Finally, we shall determine the power in Watts. This can be obtained as follow:
Kinetic energy (KE) = 40095 J
Time (t) = 4 s
Power (P) =?
Power = Energy /time
Power = 40095 / 4
Power = 10023.75 Watts
B. Determination of the power in horse power.
Power in Watts = 10023.75 Watts
Power in horse power =?
Recall:
746 Watts = 1 hp
Therefore,
10023.75 Watts = 10023.75 / 746
10023.75 Watts = 13.44 hp
Therefore, the power in horse power is 13.44 hp
Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
write any three utilities of plastics
Explanation:
container, bottles, boxes, cups
a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?
Answer:
L = 2 J.s
Explanation:
The angular momentum of an object travelling in a horizontal circle is given by the following formula:
[tex]L = mvr[/tex]
where,
L = Angular momentum = ?
m = mass = 0.8 kg
v = linear speed = rω
r = radius of circular path = length of rope = 0.5 m
ω = Angular Speed = 10 rad/s
therefore,
[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]
L = 2 J.s
In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?