Anyone know this problem

If 8% of students were absent on Tuesday no. of students that were absent was 50.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, There are 625 students at Median middle school and 8% of the students were absent on Tuesday.

∴ No. of students that were absent on Tuesday is 8% of 625 which is,

= (8/100)×625.

= 50.

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Answer:

1. 0.333 No

2. 0.3 or 0.300 Yes

3. 0.667 No

Step-by-step explanation:

Answer:

r = 5y/8

Step-by-step explanation:

isolate the variable by dividing each side by factors that contain the variable.

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\[/tex]

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)[/tex]  [as x+y=14]

[tex]\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\[/tex]

[tex]\Rightarrow x =(25 \times 14)/32=10.9375[/tex] grams

and [tex]y = 14-x= 14-10.9375=3.0625[/tex] grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\[/tex]

[tex]\Rightarrow x =(50 \times 14)/57=12.28[/tex] grams

and [tex]y = 14-x= 14-12.28=1.72[/tex] grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

Answer:

5 m

Step-by-step explanation:

V = l × w × h

480 = 12 × 8 × h

h = 480 ÷ 96 = 5 m

Answer:

5m

Step-by-step explanation:

Well volume is V=Bh. So you do 12 times 8= 96 thats your base. So you need to them do 480 divided by 96 which equals 5 so therefore 5 is your answer. Also just to make sure that's the right answer, do 12 times 8 times 5. That equals 480.

Answer:

Y equals -1/5

Answer:

y = -0.2

General Formulas and Concepts:

Pre-Algebra

Step-by-step explanation:

Step 1: Define equation

[tex]\frac{3.6}{0.2(6y + 1)} =\frac{9}{0.5y}[/tex]

Step 2: Solve for y

Step 3: Check

Plug in y to verify it's a solution.

Here we see that -90 does indeed equal -90. ∴ y = -0.2 is indeed a solution of the equation.

Answer:

542

Step-by-step explanation:

divide it I hope it helps

Answer:

241.20 dollars

Step-by-step explanation:

Use the equation I=prt, where I is the interest and p is the percentage of simple interest, which is 6% or 0.06. T is the rate of time in years. R is the amount Felix deposited. Our equation would be:

I=(0.06)(1340)(3)

I=(0.18)(1340)

I=$241.20

Step-by-step explanation:

the regular form of r=8

Answer:

Step-by-step explanation:

Y= -6

X=-2

Answer:

900 cubic inches.

Step-by-step explanation:

Given the following data

Volume of right circular cone = 300in³

We know that the volume of a right circular cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]

Where;

The volume of a right circular cylinder is given by the formula;

[tex] V = \pi r^{2}h[/tex]

Thus, multiplying the volume of the right circular cone by 3 would give us the volume of the right circular cylinder.

[tex] V = \frac{1}{3} \pi r^{2}h * 3[/tex]

Substituting into the equation, we have;

V = 300 * 3

V = 900in³

Therefore, the volume of a right cylinder that has the same base and height as the cone is 900 cubic inches.

Answer:-1/2

Step-by-step explanation:

Look at the points

Answer:

3

Step-by-step explanation:

13 ÷ 4 = 3.25

but you wont by .25 of a shirt so he can only buy 3 shirts

Answer:

number of $20 bill = 4

Number of $5 bill = 5

Step-by-step explanation:

Given that:

Total number of $5 and $20 bills = 9

Let :

Number of $5 bills = x

Number of $20 bills = y

Combined worth of all bills = $105

x + y = 9 - - - (1)

5x + 20y = 105 - - - (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

5(9 - y) + 20y = 105

45 - 5y + 20y = 105

15y = 105 - 45

15y = 60

y = 60/15

y = 4

x = 9 - y

x = 9 - 4 = 5

Hence,

number of $20 bill = 4

Number of $5 bill = 5

Answer:y=x+3

Step-by-step explanation:

Answer:

C) (5, ∞)

General Formulas and Concepts:

Alg I

Step-by-step explanation:

According to the graph, we have a horizontal asymptote at y = 5. Therefore, the graph never actually touches/reaches the y-value 5. Therefore, 5 is not included in our range:

(5, ∞) or y ≥ 5

Answer:

(C).  AB←→⊥PQ←→

Step-by-step explanation:

This is the only suitable answer to produce a triangle △CMR which is a right triangle.

When we will draw Line AB And PQ which they are intersecting And to produce a right triangle by taking two random points ( C on AB and  P on PQ).

Then AB and PQ must be Perpendicular to each other, only then a triangle CMR will be right angled at M.

Answer:

A

Step-by-step explanation:

Point slope form

x, y

[tex](y-x)= (slope)(x-y)[/tex]

So its

[tex]y-6=\frac{1}{2}(x+3)[/tex]

So option 1.

Hope this helps plz hit the crown :D

Answer:

B

Step-by-step explanation:

y=mx +b

y= 1/2x = b

y intercept (0,-6)

Answer:

Step-by-step explanation:

So initially you have a square piece of metal, 15" x 15". You cut out squares from the corners of each side with side length x.

So you'll have a sheet that looks something like this now (assuming the formatting works):

   _____

__|       |__

|               |

|__        __|

   |____|

Your original side length was 15, but it has now been reduced by x on each side, so you're now going to have a new side length of 15 - 2x

When you fold the box up, the box will have a height of just x.

So you have a base with lengths (15 - 2x) and (15 - 2x), and a height which is just x.

V = l*w*h

So

V = (15 - 2x)(15 - 2x)(x)

= 225x - 60x^2 + 4x^3

Hope this helps

Answer:

0.65

Step-by-step explanation:

a coin has 2 sides so there is two outcomes

1-0.35=0.65

Answer:

option D is the answer

Step-by-step explanation:

3n + 5

_______

n² + 5

Answer:

A, C, D are true.

Step-by-step explanation:

Answer: A,B,C,D

Step-by-step explanation:

ALL ARE TRUE I JUST TOOK THE TEST A P E X

Answer:

The solution is too long. So, I included them in the explanation

Step-by-step explanation:

This question has missing details. However, I've corrected each question before solving them

Required: Determine the inverse

1:

[tex]f(x) = 25x - 18[/tex]

Replace f(x) with y

[tex]y = 25x - 18[/tex]

Swap y & x

[tex]x = 25y - 18[/tex]

[tex]x + 18 = 25y - 18 + 18[/tex]

[tex]x + 18 = 25y[/tex]

Divide through by 25

[tex]\frac{x + 18}{25} = y[/tex]

[tex]y = \frac{x + 18}{25}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{x + 18}{25}[/tex]

2. [tex]g(x) = \frac{12x - 1}{7}[/tex]

Replace g(x) with y

[tex]y = \frac{12x - 1}{7}[/tex]

Swap y & x

[tex]x = \frac{12y - 1}{7}[/tex]

[tex]7x = 12y - 1[/tex]

Add 1 to both sides

[tex]7x +1 = 12y - 1 + 1[/tex]

[tex]7x +1 = 12y[/tex]

Make y the subject

[tex]y = \frac{7x + 1}{12}[/tex]

[tex]g'(x) = \frac{7x + 1}{12}[/tex]

3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]

Replace h(x) with y

[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]

Swap y & x

[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]

Add [tex]\frac{1}{3}[/tex] to both sides

[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]

[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]

Multiply through by -4

[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]

[tex]-4x - \frac{4}{3}= 9y[/tex]

Divide through by 9

[tex](-4x - \frac{4}{3})/9= y[/tex]

[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]

[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]

[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]

[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]

4:

[tex]f(x) = x^9[/tex]

Replace f(x) with y

[tex]y = x^9[/tex]

Swap y with x

[tex]x = y^9[/tex]

Take 9th root

[tex]x^{\frac{1}{9}} = y[/tex]

[tex]y = x^{\frac{1}{9}}[/tex]

Replace y with f'(x)

[tex]f'(x) = x^{\frac{1}{9}}[/tex]

5:

[tex]f(a) = a^3 + 8[/tex]

Replace f(a) with y

[tex]y = a^3 + 8[/tex]

Swap a with y

[tex]a = y^3 + 8[/tex]

Subtract 8

[tex]a - 8 = y^3 + 8 - 8[/tex]

[tex]a - 8 = y^3[/tex]

Take cube root

[tex]\sqrt[3]{a-8} = y[/tex]

[tex]y = \sqrt[3]{a-8}[/tex]

Replace y with f'(a)

[tex]f'(a) = \sqrt[3]{a-8}[/tex]

6:

[tex]g(a) = a^2 + 8a- 7[/tex]

Replace g(a) with y

[tex]y = a^2 + 8a - 7[/tex]

Swap positions of y and a

[tex]a = y^2 + 8y - 7[/tex]

[tex]y^2 + 8y - 7 - a = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]

Factorize

[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]

[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]

[tex]y = -4 \±\sqrt{(23 + a)}[/tex]

[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]

7:

[tex]f(b) = (b + 6)(b - 2)[/tex]

Replace f(b) with y

[tex]y = (b + 6)(b - 2)[/tex]

Swap y and b

[tex]b = (y + 6)(y - 2)[/tex]

Open Brackets

[tex]b = y^2 + 6y - 2y - 12[/tex]

[tex]b = y^2 + 4y - 12[/tex]

[tex]y^2 + 4y - 12 - b = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]

[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]

Factorize:

[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]

[tex]y = -2\±\sqrt{16+b}[/tex]

Replace y with f'(b)

[tex]f'(b) = -2\±\sqrt{16+b}[/tex]

8:

[tex]h(x) = \frac{2x+17}{3x+1}[/tex]

Replace h(x) with y

[tex]y = \frac{2x+17}{3x+1}[/tex]

Swap x and y

[tex]x = \frac{2y+17}{3y+1}[/tex]

Cross Multiply

[tex](3y + 1)x = 2y + 17[/tex]

[tex]3yx + x = 2y + 17[/tex]

Subtract x from both sides:

[tex]3yx + x -x= 2y + 17-x[/tex]

[tex]3yx = 2y + 17-x[/tex]

Subtract 2y from both sides

[tex]3yx-2y =17-x[/tex]

Factorize:

[tex]y(3x-2) =17-x[/tex]

Make y the subject

[tex]y = \frac{17 - x}{3x - 2}[/tex]

Replace y with h'(x)

[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]

9:

[tex]h(c) = \sqrt{2c + 2}[/tex]

Replace h(c) with y

[tex]y = \sqrt{2c + 2}[/tex]

Swap positions of y and c

[tex]c = \sqrt{2y + 2}[/tex]

Square both sides

[tex]c^2 = 2y + 2[/tex]

Subtract 2 from both sides

[tex]c^2 - 2= 2y[/tex]

Make y the subject

[tex]y = \frac{c^2 - 2}{2}[/tex]

[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]

10:

[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]

Replace f(x) with y

[tex]y = \frac{x + 10}{9x - 1}[/tex]

Swap positions of x and y

[tex]x = \frac{y + 10}{9y - 1}[/tex]

Cross Multiply

[tex]x(9y - 1) = y + 10[/tex]

[tex]9xy - x = y + 10[/tex]

Subtract y from both sides

[tex]9xy - y - x = y - y+ 10[/tex]

[tex]9xy - y - x = 10[/tex]

Add x to both sides

[tex]9xy - y - x + x= 10 + x[/tex]

[tex]9xy - y = 10 + x[/tex]

Factorize

[tex]y(9x - 1) = 10 + x[/tex]

Make y the subject

[tex]y = \frac{10 + x}{9x - 1}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]

Answer:c

Step-by-step explanation:

math

Answer:

5/8

Step-by-step explanation:

1/4=2/8

7/8-2/8=5/8

Answer:

Step-by-step explanation:

1. use the slope formula --> (y2-y1)/(x2-x1)

2. (8 - 4)/(13 -(-3))

3. 4/16

4. m = 1/4

102 is 60% 170. Divide 102 by 0.6, which results in 102. Hope this helps! Have an amazing rest of your day and please mark brainliest! xx

Answer:

? = 130°

Step-by-step explanation:

The sum of all angles inside a triangle is always 180°.

180 - 20 - 30 = 130°

130° is vertical to the ?, therefore, the ? = 130°

hope this helps :)

To get the answer to this question we would have to calculate how much each DVD costs in each scenario.

To do this we will divide each cost by the total number of CDS:

[tex]\frac{2.30}{10} = .23[/tex]

[tex]\frac{10.50}{50} = .21[/tex]

For the pack of 10 CDS each CD costs 23 cents. On the contrary, for the pack of 50 CDs each CD costs 21 cents. Therefore to get a better deal, you would want to go with the 50 CDs.

Hope this helps!

- Kay

The cost per CD is lower when buying the package of 50 CDs, it is the better buy. You would save money by purchasing the package of 50 CDs for $10.50.

To determine which is the better buy, we need to compare the cost per CD in both scenarios.

Let's first calculate the cost per CD when buying 10 CDs:

Cost for 10 CDs = $2.30

Cost per CD = $2.30 / 10 CDs = $0.23 per CD

Now, let's calculate the cost per CD when buying a package of 50 CDs:

Cost for 50 CDs = $10.50

Cost per CD = $10.50 / 50 CDs = $0.21 per CD

Comparing the two options:

- Buying 10 CDs individually costs $0.23 per CD.

- Buying a package of 50 CDs costs $0.21 per CD.

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Answer:

55 push ups

Step-by-step explanation:

Given that:

Starting count = 10

Additional count = 3

Starting count + (additional count * number of days)

Exactly on the 3rd week = on the 15th day

10 + (3 * 15)

10 + 45

= 55 push ups

Answer:

Step-by-step explanation:

area of a triangle = 1/2 * base * height

                             = 1/2 * 12 * 17

                             = 102 cm²