Any help please and thank you (picture included)

Answer:

  0.00000002119188

Step-by-step explanation:

If you enter this number into a spreadsheet (with a single E), you can set the display format to show you the value in standard form. The exponent (E) of -8 indicates the most-significant digit (2) is in the 8th place to the right of the decimal point:

  = 2.119188×10^-8

  = 0.00000002119188

Answer:

Step-by-step explanation:

The question is in complete. Here is the complete question.

"The dimensions of a triangular pyramid are shown below. The height of

the pyramid is 6 inches. What is the volume in cubic inches?

Base of triangle = 1in

height of triangle = 5in"

Given the dimension of the triangular base of base 1 inch and height 5inches with the height of the pyramid to be 6inches, the volume of the triangular pyramid is expressed as [tex]V = \frac{1}{3}BH[/tex] where;\

B = Base area

H = Height of the pyramid

Base area  B = area of the triangular base = [tex]\frac{1}{2}bh[/tex]

b = base of the triangle

h = height of the triangle

B = [tex]\frac{1}{2} * 5 * 1\\[/tex]

[tex]B = 2.5in^{2}[/tex]

Since H = 6inches

Volume of the triangular pyramid = [tex]\frac{1}{3} * 2.5 * 6\\[/tex]

[tex]V = 2.5*2\\V =5in^{3}[/tex]

Answer:

each bag of candy is $6.00

Step-by-step explanation:

1 bag would cost $6.00

1×$6.00=$6.00

6 bags × $6.00 = $36.00

Answer:

the constant of proportionally is 6

the prices of 6 bags of candy is 36

Step-by-step explanation:

to find the constant u divide 6 by 1 to find how they multiplying it by

the prices for six bags is 36 bc u can do 6 times 6 or look at the graph and see that it lands on 36

hope this helps

Answer:

1. distance = 275 ft

2. rate = 55 miles/hour

Step-by-step explanation:

April travels at the rate of 25 ft per seconds and the time she spent traveling is 11 seconds. How far she traveled is the distance she covered. The rate or the speed unit is given as ft per seconds. Therefore, the distance covered can be expressed as follows.

rate = distance/time

where

rate = 25 ft/sec

time = 11 secs

rate = distance/time

25 = distance/11

cross multiply

distance = 25 × 11

distance = 275 ft

Isaac drove for 3 hours and he covered a distance of 165 miles. The rate of travel can be expressed as follows

rate = distance/time

distance = 165 miles

time = 3 hours

rate = 165/3

rate = 55 miles/hour

Answer:

5 is solution

Step-by-step explanation:

hello,

I am not sure what is expected for this kind of question.

we can notice that 5 is a solution as

[tex]\sqrt{4*5+5}-\sqrt{5-1}=\sqrt{25}-\sqrt{4}=5-2=3\\and\\\sqrt{5+4}=\sqrt{9}=3[/tex]

hope this helps

Answer:

no

Step-by-step explanation:

No, it is not a random sample of the students in school.

Answer:

No

Step-by-step explanation:

A random sample is a sample that is taken from a larger set. Molly specifically chose to interview the youngest students, so the sample is not random.

Answer:

  a(1) = 10

  a(n) = a(n-1)·0.6

Step-by-step explanation:

The first term of the sequence is the one listed first: 10. That means a(1) = 10.

The next term of the geometric sequence will be the first term multiplied by the common ratio. That ratio can be found as the ratio of the second term to the first:

  r = 6/10 = 0.6

So, the recursive formula is ...

  a(n) = a(n-1)·r

  a(n) = a(n-1)·0.6

Answer:

 a(1) = 10

 a(n) = a(n-1)·0.6

Answer:

The correct option is (C).

Step-by-step explanation:

Missing information:

According to a university of wildlife ecology and conservation researcher, the average level of mercury uptake in wading birds in a region has declined over the past several years. Five years ago, the average level was 16 parts per million. Give the null and alternative hypotheses for testing whether the average level today is less than 16 ppm.

The hypothesis can be defined as follows:

H₀: The average level of mercury uptake in wading birds in a region is 16 ppm, i.e. μ = 16.

Hₐ: The average level of mercury uptake in wading birds in a region is less than 16 ppm, i.e. μ < 16.

A Type I error is the rejection of a null hypothesis (H₀) when indeed the null hypothesis is true. It is symbolized by α.

In this case the type I error can be defined as:

Concluding that the average level of mercury uptake in wading birds in a region today is less than 16 parts per​ million, when in​ fact, the average level of mercury uptake in wading birds in a region today is equal to 16 parts per million.

The correct option is (C).

Answer:

[tex]\boxed{\sf \ \ \ k = 1 \ \ \ }[/tex]

Step-by-step explanation:

hello,

saying that p-1 is a factor of [tex]p^4+p^2-p-k[/tex]

means that 1 is a root of this expression, so it comes

1+1-1-k=0

<=> 1-k=0

<=> k = 1

Answer:

[tex]t=\frac{595-600}{\frac{20}{\sqrt{65}}}=-2.016[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=65-1=64[/tex]  

The p value would be given by:

[tex]p_v =2*P(t_{(64)}<-2.016)=0.048[/tex]  

And for this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mena is different from 600 mg

Step-by-step explanation:

Information given

[tex]\bar X=595[/tex] represent the sample mean

[tex]s=20[/tex] represent the sample standard deviation

[tex]n=65[/tex] sample size  

[tex]\mu_o =600[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

System of hypothesis

We want to test if the true mean is different from 600 mg, the system of hypothesis would be:  

Null hypothesis:[tex]\mu = 600[/tex]  

Alternative hypothesis:[tex]\mu \neq 600[/tex]  

The statistic would be given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing the info we got:

[tex]t=\frac{595-600}{\frac{20}{\sqrt{65}}}=-2.016[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=65-1=64[/tex]  

The p value would be given by:

[tex]p_v =2*P(t_{(64)}<-2.016)=0.048[/tex]  

And for this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mena is different from 600 mg

Answer :

I have solved for the points.

Explanation :

Just get a protractor and plot out the angles into a circle. Starting with the largest angle.

Answer:

See Below

Step-by-step explanation:

x(2x) - 4(2x) + x(3) - 4(3)

= 2x² - 8x + 3x -12

= 2x²-5x-12

Answer:

3 miles per hour

Step-by-step explanation:

Jessica is walking home from a friend's house.

After 2 minutes she is 0.8 miles from the home and after 12 minutes she is 0.3 miles away fro her house.

Her rate will be = (change in distance)/change in time

= (0.8-0.3)/(12-2)

= 0.5/10

= 0.05 miles per minute

Now we will convert timings from minutes to hour.

Or  = 0.05×60  

= 3 miles per hour

Answer:

m < ACO = 90 degrees.

Step-by-step explanation:

The line joining the center O of the circle to the point of contact of the tangent is a right angle.

Answer: 90 degrees

Step-by-step explanation: Khan academy

Answer:

[tex]x=2$\pm$\sqrt{42}[/tex]

Step-by-step explanation:

The given equation is:

[tex]x^{2} -4x-9=29\\\Rightarrow x^{2} -4x-9-29=0\\\Rightarrow x^{2} -4x-38=0[/tex]

Formula:

A quadratic equation [tex]ax^{2} +bx+c=0[/tex] has the following roots:

[tex]x=\dfrac{-b+\sqrt D}{2a}\ and\\x=\dfrac{-b-\sqrt D}{2a}[/tex]

Where [tex]D= b^{2} -4ac[/tex]

Comparing the equation with [tex]ax^{2} +bx+c=0[/tex]

a = 1

b = -4

c= -38

Calculating D,

[tex]D= (-4)^{2} -4(1)(-38)\\\Rightarrow D = 16+152 = 168[/tex]

Now, finding the roots:

[tex]x=\dfrac{-(-4)+\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4+2\sqrt {42}}{2}\\\Rightarrow x=2+\sqrt {42}\\and\\x=\dfrac{-(-4)-\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4-2\sqrt {42}}{2}\\\Rightarrow x=2-\sqrt {42}[/tex]

So, the solution is:

[tex]x=2$\pm$\sqrt{42}[/tex]

Answer is A or the first one

Answer:  55.6 days

Step-by-step explanation:

[tex]P=P_oe^{kt}\\\\\bullet \quad P=\dfrac{1}{2}P_0\\\bullet \quad k=-0.1247\\\bullet \quad t = unknown\\\\\\\dfrac{1}{2}P_o=P_oe^{-0.1247t}\\\\\\\dfrac{1}{2}=e^{-0.1247t}\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=-0.1247t\\\\\\\dfrac{ln\dfrac{1}{2}}{-0.1247}= t\\\\\\\large\boxed{55.6=t}[/tex]

Answer:

13-n=4

Subtract both sides by 13

-n=-9

n=9

Step-by-step explanation:

13 less means - and a number means n that you don’t know. is means = sign. And so we get the answer that I gave you. Thank you

Answer:

It  was gained 4 1/4 points.

Step-by-step explanation:

- 7 1/8 - 1 5/8 + 13 = - 8 6/8 + 13 = - 8 3/4 + 13 = - 8 - 3/4 + 12 + 4/4 =  4 1/4

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

[tex]A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}[/tex]

[tex]B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}[/tex]

[tex]C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}[/tex]

AX + B = C

AX = C - B

C - B = [tex]\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}[/tex] = [tex]\begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}[/tex]

C - B = [tex]\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}[/tex]

Let  [tex]X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}[/tex]

AX = [tex]\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}[/tex]

     = [tex]\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}[/tex]

Since AX = C - B

[tex]\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}[/tex]

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = [tex]\begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix}[/tex] will be the answer.

Answer:

the second option is your answer

Step-by-step explanation:

Answer:

Graphing Linear Inequalities

This is a graph of a linear inequality:

linear inequality y <= x +2

The inequality y ≤ x + 2

You can see the y = x + 2 line, and the shaded area is where y is less than or equal to x + 2

Linear Inequality

A Linear Inequality is like a Linear Equation (such as y = 2x+1) ...

... but it will have an Inequality like <, >, ≤, or ≥ instead of an =.

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

Rearrange the equation so "y" is on the left and everything else on the right.

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

Shade above the line for a "greater than" (y> or y≥)

or below the line for a "less than" (y< or y≤).

Let us try some examples:

Example: y≤2x-1

1. The inequality already has "y" on the left and everything else on the right, so no need to rearrange

2. Plot y=2x-1 (as a solid line because y≤ includes equal to)

Answer

value of x is 34 degrees  

Step-by-step explanation:

Answer:

[tex]t=\frac{2567-2564}{\frac{11}{\sqrt{21}}}=1.250[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=21-1=20[/tex]  

the p value for this case would be given by:

[tex]p_v =2*P(t_{(20)}>1.250)=0.2113[/tex]  

For this case we see that the p value is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 2564 mm

Step-by-step explanation:

Information given

[tex]\bar X=2567[/tex] represent the mean height for the sample  

[tex]s=\sqrt{121}= 11[/tex] represent the sample standard deviation

[tex]n=21[/tex] sample size  

[tex]\mu_o =2564[/tex] represent the value that we want to test

[tex]\alpha=0.1[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to check if the true mean is equal to 2564 mm, the system of hypothesis would be:  

Null hypothesis:[tex]\mu = 2564[/tex]  

Alternative hypothesis:[tex]\mu \neq 2564[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing we got:

[tex]t=\frac{2567-2564}{\frac{11}{\sqrt{21}}}=1.250[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=21-1=20[/tex]  

the p value for this case would be given by:

[tex]p_v =2*P(t_{(20)}>1.250)=0.2113[/tex]  

For this case we see that the p value is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 2564 mm

Answer:  4.4 seconds

Step-by-step explanation:

h(t) = -16t² + 315

Since we want to find the total time the baseball is in the air, we need to find the time (t) when the ball lands on the ground --> h(t) = 0

  0  = -16t² + 315

-315 = -16t²

[tex]\dfrac{315}{16}=t^2\\\\\\\sqrt{\dfrac{315}{16}}=t\\\\\\\dfrac{\sqrt{315}}{4}=t\\\\\\\large\boxed{4.4=t}[/tex]

Answer:

≈ 4.44 sec

Step-by-step explanation:

h= 315 ft

h= 16t²

315 = 16t²

t²=315/16

t=√315/16 ≈ 4.44 sec

Answer: -1

Step-by-step explanation:

to calculate f(-1), you know that x = -1. so all you have to do is substitute:

f(-1) = (-1)2 + 1

f(-1) = -2 + 1

f(-1) = -1

Answer:

0

Step-by-step explanation:

Answer:

$23161.10

Step-by-step explanation:

Assuming this is compounded annually, we use our simple interest rate formula: A = P(1 + r)^t

Step 1: Convert months to years

60 months/12 month/year = 5 years

Step 2: Plug in known variables

A = 18400(1 + 0.0471)^5

Step 3: Solve

When you plug step 2 into your calc you should get 23161.1 as your answer. I am assuming that this isn't compounded quarterly or monthly, but just yearly.

Answer:

Cash, Bonds, Stocks and Mutual funds

Step-by-step explanation:

The four major categories of securities are:  

These 4  major categories are evaluated as given below:  

Answer:

  Annuity C:  Deposit $72,000 one lump sum

Step-by-step explanation:

The yield is improved when the money is on deposit for a longer period.

If the $2400 annual deposit is made at the first of the year, then it will yield more than $600 deposits made at the first of each quarter.

If the $72,000 deposit is made at the beginning of the period, the entire amount is earning interest for the entire period.

  Annuity C will provide the largest yield.

Answer:

The instantaneous rate is 36.

Step-by-step explanation:

Given the cost of producing a commodity,

[tex]C(x) = 7000 + 6x + 0.15x^{2}[/tex]

Now calculate the average rate of change in cost of producing commodity.  

Use below formula to calculate average rate of change when (i) x = 103 $ per unit:

[tex]\text{Average rate of change} = \frac{C(103) – C(100) }{103 - 100} \\C(x) = 7000 + 6x + 0.15x^{2} \\C(100) = 7000 + 6 \times 100 + 0.15 (100)^{2} = 9100 \\C(103) = 7000 + 6 \times 103 + 0.15 (103)^{2} = 9209.35 \\\text{Average rate of change} = \frac{9209.35 - 9100}{103 - 100} = 36.45[/tex]

Now calculate average rate of change when (ii) x = 101 $ per unit:

[tex]\text{Average rate of change} = \frac{C(101) – C(100) }{101 - 100} \\C(x) = 7000 + 6x + 0.15x^{2} \\C(100) = 7000 + 6 \times 100 + 0.15 (100)^{2} = 9100 \\C(101) = 7000 + 6 \times 101 + 0.15 (101)^{2} = 9136.15 \\\text{Average rate of change} = \frac{9136.15 - 9100}{101 - 100} = 36.15[/tex]

Now to find the Instantaneous Rate of Change we just need to find the differentiation of given function.

[tex]C(x) = 7000 + 6x + 0.15x^{2} \\C’(x) = 6 + 0.3x \\[/tex]

Instantaneous Rate of Change when x = 100

[tex]= 6 + 0.3 \times (100) \\= 36[/tex]