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Answer:

The most cost effective company will be Painting USA that charge $700 to paint Paul house .

As given

Paul is going to have the exterior of his home painted.

Painting USA charges $75.00 to come out and evaluate the house plus $25.00 per hour of labor.

If it takes 25 hours to paint Paul’s house.

Total amount charge by Painting USA = Painting USA charges for come out  and evaluate the house + Cost of per hour of labor × Total hours take to paint Paul house .

Total amount charge by Painting USA = 75 + 25 × 25

                                                               = 75 + 625

                                                               = $ 700

As given

Upscale Home Painting does not charge to evaluate the house. However, they charge $40.00 per hour.

Total amount charge by Upscale Home Painting = Cost of per hour of labor × Total hours take to paint Paul house

                                                                                = 40 × 25

                                                                                = $ 1000

Therefore  the most cost effective company will be Painting USA  that charge $700 to paint Paul house .

Step-by-step explanation:

Answer:

for the first one, because its tan of D and also tan formula is opp/adj it should be tanD=80/18

for the second one, because sin(A) and cos(B) is the same thing, if one increases the other would increase as well

Step-by-step explanation:

Answer:

[tex]2\sqrt{10}[/tex] units

Step-by-step explanation:

Use the distance formula [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\[/tex] to find the distance between the two points. Substitute the x and y values of the points (-1,-3) and (1,3) into the formula and simplify:

[tex]d =\sqrt{(3-(-3))^2+(1-(-1))^2} \\d =\sqrt{(3+3)^2+(1+1)^2} \\d = \sqrt{(6)^2+(2)^2} \\d = \sqrt{36+4} \\d = \sqrt{40} \\d = 2\sqrt{10}[/tex]

So, the distance is [tex]2\sqrt{10}[/tex] units.

Answer:

its 9

the other ans is scam :))))))

Answer:

Notice that 99 players need to be eliminated for there to be declared a winner. Notice also that every match eliminates exactly one person. Therefore, 99 matches are needed to eliminate 99 people and therefore declare a winner. The rest of the information is irrelevant. Therefore, the total number of matches is text divisible by 11.

Answer: charity activity trivia señora Sonia de warrior Gloria Delaware 853

Step-by-step explanation:

Answer:

x = 04

Step-by-step explanation:

7x-2(x-10)=40

7x-2x+20=40

5x=20

therefore x=20/5

that is 4

Answer:

p=Mv

p=(80)(8)

p=640kgms-1

The required momentum of the basketball is 640 kgm/s.

Given that,

Mass of the basketball = 80kg

The velocity of the basketball = 8m/s

We have to determine,

The momentum of the basketball.

According to the question,

The momentum center of an object is equivalent to the mass of the object times the velocity of the object.

[tex]P = MV[/tex]

Where M is the mass of basketball= 80kg

And v is the velocity = 8m/s.

Substitute all the values in the given equation.

[tex]P = MV \\\\P = 80 \times 8 \\\\P = 640[/tex]

Hence, The required momentum of the basketball is 640 kgm/s.

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Answer:

0.5

Step-by-step explanation:

Sample mean, x = 6 points greater than population mean ;

Population mean, m = 16

Standard deviation, s = 12

Zscore = (sample mean - population mean) / standard deviation

Zscore = (x - m) / s

x = 16 + 6 = 22

Zscore = (22 - 16) / 12

Zscore = 6 /12

Zscore = 0.5

Answer:

D

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

Because when you

Answer:

X=3

Step-by-step explanation:

Rearrange terms

6+3=15

3+6=15

Subtract from both sides of the equation

3+6=15

3+6−6=15−6

Simplify

Subtract the numbers

Subtract the numbers

3=9

x=3

X = 3.

Step-by-step explanation:

1) Subtract 6 from both sides.

[tex]3x = 15 - 6[/tex]

2) Simplify 15 - 6 to 9.

[tex]3x = 9[/tex]

3) Divide both sides by 3.

[tex]x = \frac{9}{3} [/tex]

4) Simplify 9/3 to 3.

[tex]x = 3[/tex]

So, therefor, 5he answer is x=3.

Answer:

[tex]f(125) = log_{5}(125 ) \\ = log_{5}( {5}^{3} ) = 3 log_{5}(5 ) = 3(1) = 3[/tex]

Answer:

8 times 5 on each side

Step-by-step explanation:

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Trigonometry.

Here, as the given figure.

We will use the tan ratio to get the value of 'y'.

hence, tan(30°) = 5/y

[tex]since \: \: \tan(30) = \frac{1}{ \sqrt{3} } [/tex]

so we use it here,

y = 5/tan(30)

===> hence,

[tex]y \: \: = 5 \sqrt{3} [/tex]

Answer:

formulae : 1/3 × area of base × height

= 1/3 × 6 × 8

= 1×2×8

=16

Answer:

The ratio to compare would be C) 5 to 3 because there are 5 red amrbels and 3 blue ones

Answer:

312-170=142

142÷2=71

170+71=241

241+71=312

train A weighs 241 tons

The amount of radioactive lead remaining after 3 years is 545gm.

The amount of radioactive lead remaining after 8 years is 464gm.

The amount of radioactive lead remaining after 15 years is 371gm.

The half-tie for radio active lead is 21.66 years.

Given that,

A sample of 600 g of radioactive​ lead-210 decays to​ polonium-210,

According to the function A(t) = 600e ^-0.032t, ​

Where, t is time in years.

We have to find,

Find the amount of radioactive lead remaining after.

According to the question,

Function [tex]A(t) = 600e^{(-0.032t)}[/tex]

[tex]A(3) = 600\times e^{(-0.032t)} \\\\A (3) = 600 \times \dfrac{1}{e^{0.032\times 3} } \\\\e^{0.096} = 1.10075\\\\A (3) = 600 \times \dfrac{1}{e^{0.096} } \\\\A (3) = 600 \times \dfrac{1}{1.10075} } \\\\A(3) = \dfrac{600}{1.10075}\\\\A(3) = 545gm[/tex]

The amount of radioactive lead remaining after 3 years is 545gm.

[tex]A(8) = 600\times e^{(-0.032t)} \\\\A (8) = 600 \times \dfrac{1}{e^{0.032\times 8} } \\\\e^{0.0256} = 1.129175\\\\A (8) = 600 \times \dfrac{1}{e^{0.0256} } \\\\A (8) = 600 \times \dfrac{1}{1.129175} } \\\\A(8) = \dfrac{600}{1.129175}\\\\A(8) = 464gm[/tex]

The amount of radioactive lead remaining after 8 years is 464gm.

[tex]A(15) = 600\times e^{(-0.032t)} \\\\A (15) = 600 \times \dfrac{1}{e^{0.032\times 15} } \\\\e^{0.48} = 1.61607\\\\A (8) = 600 \times \dfrac{1}{e^{0.48} } \\\\A (8) = 600 \times \dfrac{1}{1.61607} } \\\\A(8) = \dfrac{600}{1.61607}\\\\A(8) = 371gm[/tex]

The amount of radioactive lead remaining after 15 years is 371gm.

[tex]A(15) = 600\times \dfrac{1}{2} = 600e^{-0.032t} \\\\= e^{(-0.032t)} = \dfrac{1}{2}\\\\Taking \ log \ on \ both \ sides\\\\= -0.032t = ln2\\\\= t = \dfrac{ln2}{-0.032}\\\\= t = 21.660\\\\= t = 21.66 years[/tex]

The half-tie for radio active lead is 21.66 years.

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Answer:

no

Step-by-step explanation:

Use the following formula to find the height

3V/πr² = h

Answer:

827

Step-by-step explanation:

Answer:

Step-by-step explanation:

I think c ..................

...........

Answer:

x -6, y 0,

x 0, y -1,

x 0, y -2,

x 2, y 0

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{3w - 2h + -5w + 6h}[/tex]

[tex]\large\text{COMBINE the LIKE TERMS}[/tex]

[tex]\large\text{(3w + (-5w)) + (-2h + 6h)}[/tex]

[tex]\large\text{(-2h + 6h) = 4h}[/tex]

[tex]\large\text{(3w - 5w) = -2w}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \bf4h - 2w}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]