ANSWER FAST: Which pair of activities will accomplish the most vigorous physical activity outside of school?

Answers

Answer 1

Answer:

running

Explanation:

it really gets your heart pumping in blood flowing


Related Questions

A car company is performing brake tests on one of its cars. The car reaches a speed of 160 km/h and then hits the brakes to slow down at a rate of 11.0 m/s2 . A) How long does it take for the car to stop b) How far does the car travel when braking? A rate of 11.0 m/s2 .

Answers

Answer:

a)  t = 4.04 s , b)  x = 89.77 m

Explanation:

This is a one-dimensional kinematics exercise.

a) Let's use caution to find the time, the vehicle speed when stopped is zero

         v = v₀ - at

let's reduce the magnitudes to the SI system

      v₀ = 160 km /h (1000m / 1km) (1h / 3600s) = 44.44 m / s

       0 = v₀ - at

        t = v₀ / a

        t = 44.44 / 11

        t = 4.04 s

b) to calculate the distance traveled we use

         x = v₀t - ½ a t²

         x = 44.44   4.04 - ½ 11.0 4.04²

          x = 179.54 - 89.77

         x = 89.77 m

Do action and reaction act on the same
body or on different bodies?
plochlain
answer with Khe help of bocample. How Core
they related in magnitude and direction?

Answers

Explanation:

action and reaction forces act on the same body since these are forces that oppose that are opposite

A car starts from rest, then accelerates at 1.20 m/s^2 for 7.00 s. It hits the brakes, slowing to stop at a rate of -4.25 m/s^2. What is the total time for the problem? (Unit = s) PLEASE HELP!!

Answers

Answer:

8.98 secs

Explanation:

First part of the journey;

If the car starts from rest, then accelerates at 1.20 m/s^2 for 7.00 s, the total time taken during this period is 7.0s.

But then  lets get the velocity v of the car during its first part of the journey.

Using the formula v1 = u1+ at1

v = 0+1.2(7)

v = 8.4m/s

Second part of the journey is when the driver hits the brake and slowing to stop at a rate of -4.25 m/s^2. To calculate the time it takes by the body to decelerates, we will use the equation of motion v2 = u2 + at2

v = final velocity of the car during the second part of the journey

u = initial velocity of the car during the second part of the journey

a = deceleration

t = time taken

Given v2 = 0m/s, u2 = 8.4m/s, a = -4.25m/s²

0 = 8.4-4.25t2

4.25t2 = 8.4

t2 = 8.4/4.25

t2 = 1.98secs

Total time taken for the journey = t1+t2

= 7.0s + 1.98s

= 8.98secs

Plzz answer this questions
will mark as brainlist ​

Answers

Answer:

1. 19.28 secs

2. 154.22 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

Force (F) = 1000 N

Mass (m) = 1200 Kg

Time (t) =..?

Distance (s) =...?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Force (F) = 1000 N

Mass (m) = 1200 Kg

Acceleration (a) =.?

Force (F) = mass (m) x acceleration (a)

F = ma

1000 = 1200 x a

Divide both side by 1200

a = 1000/1200

a = 0.83 m/s²

Since the car is coming to rest, it means it is decelerating. Therefore, the acceleration is – 0.83 m/s²

1. Determination of time taken for the car to halt i.e stop. This can be obtained as follow:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

acceleration (a) = – 0.83 m/s²

Time (t) =.?

v = u + at

0 = 16 + (–0.83 x t)

0 = 16 – 0.83t

Rearrange

0.83t = 16

Divide both side by 0.83

t = 16/0.83

t = 19.28 secs.

Therefore, the time taken for the car to halt is 19.28 secs.

2. Determination of the distance travelled by the car before coming to rest. This can be obtained as follow:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

acceleration (a) = – 0.83 m/s²

Distance (s) =..?

v² = u² + 2as

0 = 16² + (2 x –0.83 x s)

0 = 256 – 1.66s

Rearrange

1.66s = 256

Divide both side by 1.66

s = 256/1.66

s = 154.22 m

Therefore, the distance travelled by the car before coming to rest is 154.22 m.


A man can walk three blocks east and four blocks north in 20 min. He can drive 12 times that distance in the same amount of time. How far can the man
drive in 20 min? Assume that each block is 0.3 kilometers.

Answers

Answer:  25.2 km

Explanation:

3 blocks east and four blocks east = 7 blocks

1 block = 0.3 km  --> 7 blocks = 2.1 km

12 times 2.1 km = 25.2 km

how to calculate displacement

Answers

Displacement is a vector quantity, and thus has both magnitude and direction. Displacement = (final position) - (initial position) = change in position. D = Xf -Xi.
Velocity = displacement/time
Using the formula above
Displacement = velocity•time

. What happens to the polarity of an electromagnet when the direction of the current passing through it is reversed?

Answers

Answer:

The polarity of electromagnet also gets reversed when the direction of current is reversed. The current flows from negative terminal to positive terminal in an electromagnet due to the flow of electrons so polarity is also established in the electromagnet. As, the current direction is reversed, the polarity of magnet also gets reversed because the polarity of magnet depends on the direction of the current.

Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6 N. ¿Cuál es el nuevo alargamiento?

Answers

Answer:

[tex]k=784 N/m[/tex]

[tex]\Delta x=8,8 cm[/tex]

Explanation:

Usando la ley de Hook tenemos:

[tex]F=k\Delta x[/tex]

Solving it for k we have:

[tex]k=\frac{F}{\Delta x}[/tex]

[tex]k=\frac{39,2}{0,05}[/tex]

[tex]k=784 N/m[/tex]

Usando la misma ecuación y sabiendo k tenemos:

[tex]\Delta x=\frac{F}{k}[/tex]

[tex]\Delta x=\frac{68,6}{784}[/tex]

[tex]\Delta x=8,8 cm[/tex]

Espero esto te ayude!

A gas occupies a volume of 1.0 m3 in a cylinder at a pressure of 120kPa. A piston compresses the gas until the volume is 0.25m3, the temperature remaining constant. What is the new pressure of the gas?

Answers

Answer:

Approximately [tex]480\; \rm kPa[/tex], assuming that this gas is an ideal gas.

Explanation:

Let [tex]V(\text{Initial})[/tex] and [tex]P(\text{Initial})[/tex] denote the volume and pressure of this gas before the compression. Let [tex]V(\text{Final})[/tex] and [tex]P(\text{Final})[/tex] denote the volume and pressure of this gas after the compression.

By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:

[tex]\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}[/tex].

Note that in Boyle's Law, [tex]P[/tex] is inversely proportional to [tex]V[/tex]. Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.

For this particular question:

[tex]V(\text{initial}) = 1.0\; \rm m^3[/tex].[tex]P(\text{Initial}) = 120\; \rm kPa[/tex].[tex]V(\text{final}) = 0.25\; \rm m^3[/tex].The pressure after compression, [tex]P(\text{Final})[/tex], needs to be found.

Rearrange the equation to obtain:

[tex]\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})[/tex].

Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.

[tex]\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}[/tex].

I NEED HELP PLEASE, THANKS! :)
Generate an explanation for the following formula: P = I²R . Explain.

Answers

Answer:

P = VI = (IR)I = I2R

Explanation:

What the equation means is that if you double the current you end up with 4 times the power loss. It's like the area of carpet you need for a room - if you make the room twice as long and twice as wide you need 4x as much carpet. The physical explanation is that the voltage difference along a wire depends on the current - more current flowing with a resistance means more voltage (pressure of electricity if you like) is built up.

This extra voltage means more power. So if you double the current your would double the power, but you also double the voltage which doubles the power again = 4x as much power. P = VI = (IR)I = I2R

I hope this helps you out, if I'm wrong, just tell me.

As I mentioned earlier, Ohm's law gives us the formula P = IV, where V is the voltage ( also known as the electrical potential difference ) and I is the current. It is confusing that P = I²R and P = IV are one in the same - so I want to go a bit deeper on that.

We have three formulas, P = IV, P = I²R, and P = V² / R. Each are considered the same. The two formulas P = I²R, and P = V² / R are derived from the statement that P = IV, under the condition V = IR. Substitute the value of V from this second condition V = IR into P = IV. You would get the following -

P = I( IR ),

P = I²R

That is how one can derive the formula P = I²R, and how P = IV and P = I²R are thought to be one in the same. If you would like, take a look at how to get the formula " P = V² / R, "

V = IR, P = IV

I = V / R, P = IV

P = ( V / R )V,

P = V² / R

Hope that helps!

[03.02]
In order to change power, what else must be changed? (1 point)​

Answers

Answer:

Current or voltage should also be changed.

Explanation:

Please i need a Brainliest.

How far away from the surface of earth does the acceleration due to gravity will be inclined by 36% of its value on the surface of earth? Radius of earth is 6400 km

Answers

Answer:

1,600 km

Explanation:

since the acceleration due to gravity reduces by 36%, it means that (1 - 36%) of acceleration still remains:

g' = 64g/100

using the acceleration formula:

g' = g x [R² / (R + height)²]

64g/100 = g x [R² / (R + height)²]

64/100 = R² / (R + height)²

√(64/100) = √[R² / (R + height)²]

8/10 = R / (R + height)

8 (R + height) = 10R

8R + 8height = 10R

8height = 2R

height = 2R / 8 = R / 4

R = 6,400 km

height = 6,400 km / 4 = 1,600 km

Answer:

The acceleration due to gravity will be inclined 1600 KM by 36% of its value on the surface of earth

Identify one simple machine used at your home and explain how it makes your work easier​

Answers

Answer:

they are,

1. scissor = they are very useful for cutting papers, clothes, etc. if there wouldn't be sicssor than we would not be able to cut various things . it has made easier to cut tgings.

2. nailcutter= it is also one type of simple machine. it is used to trim our nails. if there would be no nailcutter then our nail would be so dirty and long.

hope it helps..

Newton’s third law of motion says that for every action there is a(n) and opposite reaction.

Answers

Answer:

for every action thete is an equal and opposite reaction

Answer:

Newton’s third law of motion says that for every action there is a(n)

equal and opposite reaction.

Explanation:

just got it right edg 1928

In this graph, what is the displacement of the particle in the last teo seconds?
A. 0.2 meters
B. 2 meters
C. 4 meters
D. 6 meters​

Answers

Answer: B

Explanation:

Displacement is a vector quantity. it is the distance covered in a specific direction.

Whereas, Velocity = displacement/time

Make displacement the subject of formula

Displacement = velocity × time

From the graph, velocity is constant which is equal to 1 m/s

Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,

Displacement = 1 × 2 = 2 m

So, the particle displacement in the last two seconds will be 2 metres

What does the use of the phrase "the lucky ones"
convey about the author's viewpoint?
What does the phrase "But we never ate enough to
satisfy our hunger" demonstrate about the author?

Answers

Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Elie Weisel's memoir "Night" is about the persecution of the jews by the Germans during the worst genocide in world history. The events leading up to the Holocaust and the resulting after-effects through his personal experience provides one of the most prominent witness accounts of the crime.

When Weisel states that "lying down wasn't an option", he reveals how congested space was in the cabin. The "lucky ones" were able to breathe in the fresh air from the window, while the rest have to be satisfied with wherever they are. This reveals his realization of the grim situation inside the over-packed cabin, where there is hardly any space to move.

And when he said that they "never ate enough to satisfy our hunger", he presents the realization and understanding of the grim situation in the train's cabin where eating is not a luxury, but a necessity to stay alive. And for that, they know they have to "economize, to save for tomorrow" rather than just stay full once.  

Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Holiday lights are often connected in series and use special lamps that short out when the potential difference across a lamp increases to the line voltage. Generate an explanation why and explain why these light sets might blow their fuses after many bulbs have failed.

Answers

Answer:

If there isn't this type of mechanism, the whole setup will blow even if only one lamp burns out. Doing this mechanism is to decrease the overall resistance resulting in an increased current (Since resistance and current are inversely related) which is the best to blast the fuse.

Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate
resultant and its direction. ​

Answers

Answer:

the following image will make you understand

Explanation:

Which of these is an example of overcoming static friction?

A. Speeding up on a bike
B. Starting to pedal a bike that is stationary
C. Slowing down on a bike
D. Trying to stop a bike while pedaling

Answers

Answer:

Option B. is the best choice.

Explanation:

Static friction is a force that keeps an object at rest. It must be overcome to start moving the object. Once an object is in motion, it experiences kinetic friction.

B. Starting to pedal a bike that is stationary

Best Regards!

Answer:

I think that the answer is option B)

Explanation:

if spiderman runs and jumps horizontally from the top of a 200m high building, what does he need his velocity to be to land on a building 100m high, 10m away from him?

Answers

Answer:

v = 2.22 m/s

Explanation:

First we apply the second equation of motion to the vertical motion of the body:

s = Vi t + (1/2)gt²

where,

s = y = vertical distance covered = 200 m - 100 m = 100 m

Vi = V₀y = Vertical Component of Initial Velocity = 0 m/s  (because spider man jumps horizontally, thus his velocity has no vertical component initially)

t = Time Taken to Land on 100 m high building = ?

g = 9.8 m/s²

Therefore,

100 m = (0 m/s)t + (0.5)(9.8 m/s²)t²

t² = (100 m)/(4.9 m/s²)

t = √(20.4 s²)

t = 4.5 s

Now, we analyze the horizontal motion. Neglecting air friction, the horizontal motion is uniform with uniform velocity. Therefore,

s = vt

where,

s = x = horizontal distance covered = 10 m

v = V₀ₓ = Horizontal Component of Initial Velocity = Initial Velocity = ?

Therefore,

10 m = v(4.5 s)

v = 10 m/4.5 s

v = 2.22 m/s

A man weighing 80kg is standing on a trolley weighing
320kg. The trolley resting on smooth horizontal rails. If
the man starts walking on the trolley along the rails with
a speed of 1ms", then his displacement relative to the
ground after 4 second is
1) 4.8 m 2) 4 m 3) 3.2 m 4) 2.8 m​

Answers

Answer:

Net displacement = 3.2 m

Explanation:

Given:

Mass of man = 80 kg

Mass of trolley = 320 kg

Speed = 1 m/s

Time = 4 sec

Computation:

Displacement by man = 1 m/s × 4 sec

Displacement by man = 4 m

Net ext force (trolley) = com at rest

So,

320 × X = 80(4 - X)

32X = 32 - 8X

40X = 32

X = 0.8 m

Net displacement = 4 m - 0.8 m

Net displacement = 3.2 m

Answer:

3) 3.2 m

Explanation:

The computation of the displacement relative to the ground after 4 seconds is shown below:

Let us assume the following

Starting x coordinate is at the origin

As it does not involve any external force so x coordinated would remain unchanged

Now the separation between the man and the trolley is

[tex]= 4 \times 1[/tex]

= 4 m

And, we assume the displacement of man be x

So, for trolley it would be (4 -x)

Now we develop the equation which is

[tex]80 \times x = 320 \times (4 - x)[/tex]

x = 16 - 4x

Therefore x = 3.2 m

Determine the amount of time for polonium-210 to decay to one fourth its original quantity. The half-life of polonium-210 is 138 days. Explain.

Answers

Answer:

276 days

Explanation:

1/4 th of the original means 2 half lives

1 half life = 138 days

So,

2 half lives = 276 days

A train starting from rest picks up a speed of 20 m/s in 20 s while travelling on a straight path. It continues to move at the same speed for the next 50 s. It is then brought to rest in the next 10 s.
a. Plot the speed-time graph for the train..

e. How much distance did the train cover during this entire journey?

Answers

Answer:

[tex]1300 m[/tex]

Explanation:

As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from [tex]20 s[/tex] to [tex]70 s[/tex] is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.

The total distance covered by the train during the entire journey is the area of the speed-time graph.

Area[tex]=\frac{1}{2}(20\times 20)+ 50\times 20+\frac{1}{2}(20\times 10)[/tex]

[tex]=200+1000+100[/tex]

[tex]=1300[/tex]

As velocity is in [tex]m/s[/tex] and time is in [tex]s[/tex] so the unit of area is [tex]m[/tex]

Hence, the total distance is  [tex]1300m[/tex].

How is mercury barometer constructed ?

Answers

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

A mercury barometer requires a tube which has one close end, and one open end.Tube is placed upside down in a beaker in such a way so that one end open in the beaker and the other remain outside of the beaker. The barometric liquid (mercury) is then filled in the tube by pouring mercury liquid in the beaker.

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

a body starts from rest and gains the velocity of 5 metre per second into second is it of uniform velocity explain​

Answers

Answer:

It is not a uniform velocity, because his velocity increases for 5 m every second (acceleration = 5m/s2), meaning his velocity always changes.

When he starts at rest, his velocity is 0 m/s. But in 1 second later, his velocity is already 5m/s. At 2 seconds, his velocity will be 10 m/s.

A baboon steals an apple and runs to a nearby boulder 10.0\,\text m10.0m10, point, 0, start text, m, end text to its left. The baboon reaches the boulder in 1.0\,\text s1.0s1, point, 0, start text, s, end text with a constant acceleration of 20.0\,\dfrac{\text m}{\text s^2}20.0 s 2 m ​ 20, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction leftward. What was the baboon's initial velocity when it started running to the boulder?

Answers

Given that,

Distance = 10 m

Time = 1.0 sec

Acceleration a =20 m/s²

We need to calculate the baboon's initial velocity

Using equation of motion

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Where, s = distance

t = time

a = acceleration

Put the value in to the formula

[tex]10=u\times1+\dfrac{1}{2}\times20\times1^2[/tex]

[tex]u=10-10[/tex]

[tex]u=0\ m/s[/tex]

Hence, The baboon's initial velocity is zero.

The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the half-life of the source?

Answers

Answer:

[tex]t_{1/2}=6 h[/tex]

Explanation:

Let's use the decay equation.

[tex]A=A_{0}e^{-\lambda t}[/tex]

Where:

A is the activity at t timeA₀ is the initial activityλ is the decay constant

We know that [tex]\lambda=\frac{ln(2)}{t_{1/2}}[/tex]

So we have:

[tex]\lambda=\frac{ln(A/A_{0})}{t}[/tex]

[tex]\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}[/tex]

[tex]t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}[/tex]

[tex]t_{1/2}=6 h[/tex]

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

A body is thrown vertically upward and the height travelled by it is 200m , find the initial velocity and time required to reach maximum height ?

Answers

Answer:

Initial velocity(u)=62.6 m/s^2Time(t)=6.39 seconds

Solution,

Displacement(s)=200 m

Initial velocity (u)=?

Final velocity(v)=0 m/s^2

acceleration due to gravity(g)=-9.8 m/s^2

now,

[tex] {v}^{2} = {u}^{2} + 2as \\ {(0)}^{2} = {u}^{2} + 2 \times ( - 9.8) \times 200 \\ {u}^{2} = 2 \times 9.8 \times 200 \\ {u}^{2} = 3920 \\ u = \sqrt{3920} \\ u = \sqrt{ {62.6}^{2} } \\ u = 62.6 \: metre \: per \: second[/tex]

Again,

Finding time taken,

[tex]v = u + at \\ t = \frac{v - u}{a} \\ = \frac{0 - 62.6}{ - 9.8} \\ = \frac{ - 62.6}{ - 9.8} \\ = 6.39 \: seconds[/tex]

Hope this helps...

Good luck on your assignment...

1. How much heat energy is required to raise the temperature of a 5 kg aluminium bar
from 28°C to 68°C ?
( Specific heat capacity of aluminium = 900 J kg C)​

Answers

Answer:

180 kJ

Explanation:

Given that:

Mass (m) = 5 kg

Initial temperature (T1) = 28°C

Final temperature (T2) = 68°C

The change in temperature (ΔT) = T2 - T1 = 68°C - 28°C = 40°C

Specific heat capacity of aluminium (c) = 900 J/kg°C

The quantity of heat energy required (q) is given by:

q = mcΔT

q = 5 kg × 900 J/kg°C × 40°C

q =  180000 Joules

q = 180 kJ

Therefore 180 kJ is required to raise the temperature of aluminium from 28°C to 68°C.

A 0.3-m-radius automobile tire rotates how many revolutions after starting from rest and accelerating at a constant 2.13 rad/s2 over a 23.2-s interval?

Answers

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

[tex]\theta = \omega_i \ + \frac{1}{2} \alpha t^2[/tex]

the initial angular velocity is zero,

[tex]\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad[/tex]

Find how many revolutions that are in 573.2256 Rad

[tex]N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions[/tex]

Therefore, the automobile tire rotates 91 revolutions

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