Answer:
Explanation:
we have to make charge inside the conductor zero because we know that electric field inside the conductor should be zero
so, the outer surface of the conductor should contain + 10 uC of charge and the inner surface contains -10 uC
Death Valley holds the record for the highest recorded temperature in the United States. On July 10, 1913, at a place called Furnace Creek Ranch, the temperature rose to Th = 134°F. The lowest U.S. temperature ever recorded occurred at Prospect Creek Camp in Alaska on January 23, 1971, when the temperature plummeted to Tc = −79.8°F.
A) Convert these temperatures to the Celsius scale.
B) Convert the Celsius temperatures in part (a) to Kelvin.
Answer:
A) The formula used to convert from degrees fahrenheit to degrees celsius is °C = 5/9 (° F - 32)
Thus, 5/9 (134°F-32)
5/9=0,55
=0,555 * 102°F
=56,66 °C
B) 5/9 (-79.8°F-32)
=0,555 * -111,8
=-62.11 °C
A) The formula used to convert from degrees Celcius to degrees Kelvin is °K = °C + 273.15
56,66 °C + 273.15
= 329.81 °K
B) K = -62.11 °C + 273.15
=211.04 °K
You are a passenger in a car and not wearing your seat belt. Without increasing or decreasing its speed, the car makes a sharp left turn, and you find yourself colliding with the right-hand door. Which is the correct analysis of the situation?a. During the turn, there is a rightward force pushing you into the door. b. During the turn, the door exerts a leftward force on you. c. both of the above. d. neither of the above
Answer:
b) During the turn, the door exerts a leftward force on you.
Explanation:
Although at the curve the car makes a turn without deceleration or accelerating, we must consider the fact that the direction of the instantaneous velocity of the car, which is always pointing tangentially away from the curve, is changing, producing a centripetal acceleration (acceleration is the rate of change of velocity) towards the center of the curve. The result is that a force inwards towards the center of the curve from the door, is exerted on you in the leftwards direction when your body collides with the door.
what dangers higher voltages have for humans whose resistance changes depending on hand lotion, rubber gloves, other types of gloves etc.
Answer:
Higher voltages pose huge dangers to humans with changes in resistance however, the use of hand lotion and rubber gloves help to reduce the amount of current flowing through the human. Notwithstanding higher currents can lead to death by stopping blood flow to the heart causing a heart attack. Best way to survive voltages above 120 volts is to use a rubber glove and avoid touching bare wires.
Explanation:
Other classes of gloves that can be used include: Class 1 gloves which can be used for current up to 7,500 volts of AC, Class 2 up to 17,000 volts AC, Class 3 up to 26,500 volts AC, and Class 4 up to 36,000 volts AC. However, cotton gloves can be used inside to absorb perspiration and to improve the comfort of the user.
define limitations in the operation conditions of a pn junction
Answer:
Such limitations are given below.
Explanation:
Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance. In connector operation, the maximum inversion voltage seems to be of significant importance.Blue light (λ = 475 nm) is sent through a single slit with a width of 2.1 µm. What is the maximum possible number of bright fringes, including the central maximum, produced on the screen? (Hint: What is the largest angle that can be used?)
Answer:
m = 4
Explanation:
The expression that explains the constructive interference of a diffraction pattern is
a sin θ = m λ
where a is the width of the slit and λ the wavelength
sin θ = m λ / a
The maximum value is for when the sine is 1, let's substitute
1 = m λ/a
m = a /λ
let's reduce the magnitudes to the SI system
a = 2.1 um = 2.1 10⁻⁶
lam = 475 nm = 475 10⁻⁹ m
let's calculate
m = 2.1 10⁻⁶ / 475 10⁻⁹
m = 4.42
with m must be an integer the highest value is
m = 4
A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simple pendulum, which she hangs down the center of a spiral staircase of the tower. The period of oscillation is 9.79 s. The acceleration of gravity is 9.8 m/s 2 . What is the height of the tower
Answer:
The height of the tower is 23.786 m
Explanation:
Given;
period of oscillation, t = 9.79 s
acceleration of gravity, g = 9.8 m/s²
The period of oscillation is calculated as follows;
[tex]t = 2\pi \sqrt{\frac{h}{g} } \\\\[/tex]
where;
h represents the height of the tower
g is the acceleration of gravity
[tex]t = 2\pi \sqrt{\frac{h}{g} } \\\\\sqrt{\frac{h}{g} } = \frac{t}{2\pi} \\\\[/tex]
square both sides of the equation;
[tex](\sqrt{\frac{h}{g} })^2 = (\frac{t}{2\pi} )^2\\\\ \frac{h}{g} = \frac{t^2}{4\pi ^2} \\\\h = \frac{gt^2}{4\pi ^2} \\\\h = \frac{9.8*(9.79)^2}{4\pi ^2}\\\\h = 23.786 \ m[/tex]
Therefore, the height of the tower is 23.786 m
11. A sandbag is released from a rising air balloon and hits the ground 7.00 seconds later. From what height was the sandbag dropped from if at the moment of release the balloon was traveling upward at 3.00 m/s
Answer:
The initial height of the sandbox before being released is 219.272 meters.
Explanation:
The sandbag is accelerated until hitting the ground due to the effect of gravitation, since height is too small with respect to the radius of Earth, then gravity acceleration can be considered constant and due to this, the following kinematic equation is applied to determine the initial height as a function of time:
[tex]y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot a \cdot t^{2}[/tex]
Where:
[tex]y[/tex] - Final height, measured in meters.
[tex]y_{o}[/tex] - Initial height, measured in meters.
[tex]v_{o}[/tex] - Initial speed, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]a[/tex] - Acceleration, measured in meters per square second.
Now, the initial height is cleared:
[tex]y_{o} = y - v_{o}\cdot t - \frac{1}{2}\cdot a \cdot t^{2}[/tex]
Given that [tex]y = 0\,m[/tex], [tex]v_{o} = 3\,\frac{m}{s}[/tex], [tex]t = 7\,s[/tex] and [tex]a = -9.807\,\frac{m}{s^{2}}[/tex], the initial height of the sandbox is:
[tex]y_{o} = 0\,m - \left(3\,\frac{m}{s} \right)\cdot (7\,s) - \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (7\,s)^{2}[/tex]
[tex]y_{o} = 219.272\,m[/tex]
The initial height of the sandbox before being released is 219.272 meters.
Your 64-cm-diameter car tire is rotating at 3.4 rev/s when suddenly you press down hard on the accelerator. After traveling 260 m, the tire's rotation has increased to 5.5 rev/s.
What is the tires angular acceleration?
Answer:
The angular acceleration of the tire is 0.454 rad/s²
Explanation:
Given;
initial velocity, u = 3.4 rev/s = 3.4 rev/s x 2π rad/rev
u = 21.3656 rad/sec
final velocity, v = 5.5 rev/s = 5.5 rev/s x 2π rad/rev
v = 34.562 rad/sec
Calculate the value of angular rotation, θ, of the tire
θ = Number of revolutions x 2π rad/rev
θ = [tex]\frac{260}{2 \pi r} *\frac{2 \pi \ rad}{rev}[/tex]
θ = (260 / r)
r is the radius of the tire = 64 / 2 = 32cm = 0.32 m
θ = (260 / 0.32)
θ = 812.5 rad
Apply the following kinematic equation, to determine angular acceleration of the tire;
[tex]v^2 = u^2 + 2 \alpha \theta\\\\2 \alpha \theta = v^2 - u^2\\\\\alpha = \frac{v^2-u^2}{2 \theta} \\\\\alpha = \frac{(34.562)^2-(21.3656)^2}{2 (812.5)}\\\\\alpha = \frac{738.043}{1625} \\\\\alpha = 0.454 \ rad/s^2[/tex]
Therefore, the angular acceleration of the tire is 0.454 rad/s²
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displaced from its equilibrium position and undergoes simple harmonic oscillations. What is the period of the oscillations
Answer:
The period is [tex]T = 0.700 \ s[/tex]
Explanation:
From the question we are told that
The mass is [tex]m = 0.350 \ kg[/tex]
The extension of the spring is [tex]x = 12.0 \ cm = 0.12 \ m[/tex]
The spring constant for this is mathematically represented as
[tex]k = \frac{F}{x}[/tex]
Where F is the force on the spring which is mathematically evaluated as
[tex]F = mg = 0.350 * 9.8[/tex]
[tex]F =3.43 \ N[/tex]
So
[tex]k = \frac{3.43 }{ 0.12}[/tex]
[tex]k = 28.583 \ N/m[/tex]
The period of oscillation is mathematically evaluated as
[tex]T = 2 \pi \sqrt{\frac{m}{k} }[/tex]
substituting values
[tex]T = 2 * 3.142* \sqrt{\frac{0.35 }{28.583} }[/tex]
[tex]T = 0.700 \ s[/tex]
A 2.0-kg object moving 5.0 m/s collides with and sticks to an 8.0-kg object initially at rest. Determine the kinetic energy lost by the system as a result of this collision.
Answer:
20J
Explanation:
In a collision, whether elastic or inelastic, momentum is always conserved. Therefore, using the principle of conservation of momentum we can first get the final velocity of the two bodies after collision. This is given by;
m₁u₁ + m₂u₂ = (m₁ + m₂)v ---------------(i)
Where;
m₁ and m₂ are the masses of first and second objects respectively
u₁ and u₂ are the initial velocities of the first and second objects respectively
v is the final velocity of the two objects after collision;
From the question;
m₁ = 2.0kg
m₂ = 8.0kg
u₁ = 5.0m/s
u₂ = 0 (since the object is initially at rest)
Substitute these values into equation (i) as follows;
(2.0 x 5.0) + (8.0 x 0) = (2.0 + 8.0)v
(10.0) + (0) = (10.0)v
10.0 = 10.0v
v = 1m/s
The two bodies stick together and move off with a velocity of 1m/s after collision.
The kinetic energy(KE₁) of the objects before collision is given by
KE₁ = [tex]\frac{1}{2}[/tex]m₁u₁² + [tex]\frac{1}{2}[/tex]m₂u₂² ---------------(ii)
Substitute the appropriate values into equation (ii)
KE₁ = ([tex]\frac{1}{2}[/tex] x 2.0 x 5.0²) + ([tex]\frac{1}{2}[/tex] x 8.0 x 0²)
KE₁ = 25.0J
Also, the kinetic energy(KE₂) of the objects after collision is given by
KE₂ = [tex]\frac{1}{2}[/tex](m₁ + m₂)v² ---------------(iii)
Substitute the appropriate values into equation (iii)
KE₂ = [tex]\frac{1}{2}[/tex] ( 2.0 + 8.0) x 1²
KE₂ = 5J
The kinetic energy lost (K) by the system is therefore the difference between the kinetic energy before collision and kinetic energy after collision
K = KE₂ - KE₁
K = 5 - 25
K = -20J
The negative sign shows that energy was lost. The kinetic energy lost by the system is 20J
A stream of water emerging from a faucet narrows as fails. The cross-sectional area of the soutis As -6.40 cm. water comes out of the spout at a speed of 33.2 cm/s, and the waterfalls h = 7.05 cm before iting the bottom of sink What is the cross-sectional area of the water stream just before it is the sink? a. 0.162 cm3 b. 1.74 cm3c. 6.21cm3d. 0.943cm3
Answer:
The area of the water stream will be 1.74 cm^2
Explanation:
initial velocity of water u = 33.2 cm/s
initial area = 6.4 cm^2
height of fall = 7.05 cm
final area before hitting the sink = ?
as the water falls down the height, it accelerates under gravity; causing the speed to increase, and the area to decrease.
first we find the velocity before hitting the sink
using
[tex]v^{2} = u^{2} + 2gh[/tex] -----Newton's equation of motion
where v is the velocity of the water stream at the sink
u is the initial speed of the water at the spout
h is the height of fall
g is acceleration due to gravity, and it is positive downwards.
g = 981 cm/s^2
imputing relevant values, we have
[tex]v^{2} = 33.2^{2} + (2 * 981 * 7.05)[/tex]
[tex]v^{2} = 1102.24 + 13832.1 = 14934.34[/tex]
[tex]v = \sqrt{14934.34}[/tex] = 122.206 cm/s
according to continuity equation,
A1v1 = A2v2
where A1 is the initial area
V1 = initial velocity
A2 = final area
V2 = final velocity
6.4 x 33.2 = 122.206 x A2
212.48 = 122.206 x A2
A2 = 212.48 ÷ 122.206 ≅ 1.74 cm^2
A water-balloon launcher with mass 5 kg fires a 1 kg balloon with a velocity of
8 m/s to the east. What is the recoil velocity of the launcher?
Answer:
1.6 m/s west
Explanation:
The recoil velocity of the launcher is 1.6 m/s west.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
A water-balloon launcher with mass 5 kg fires a 1 kg balloon with a velocity of 8 m/s to the east.
Final momentum will be zero, so
m₁u₁ +m₂u₂ =0
Substitute the values for m₁ = 5kg, m₂ =1kg and u₂ =8 m/s, then the recoil velocity will be
5 x v +1x8 = 0
v = - 1.6 m/s
Thus, the recoil velocity of the launcher is 1.6 m/s (West)
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Kinetic energy is the energy an object has due to its
Kinetic energy is the energy an object has due to its Motion.
Kinetic energy is a characteristic of a moving particle. It is a type of energy that a matter or particle possesses due to its motion.
It is expressed:
[tex]K_E = \frac{1}{2}mv^2[/tex]
Where m is the mass of the particle and v is velocity.
Hence, Kinetic energy is the energy an object has due to its Motion.
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A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you at 13.0 m/s. The maximum force you apply in catching the water balloon is twice the average force. How long must the interaction time of your catch be to make sure the water balloon doesn't soak you
Answer:
t = 0.029s
Explanation:
In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:
[tex]F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}[/tex] (1)
m: mass of the water balloon = 1.20kg
Δv: change in the speed of the balloon = v2 - v1
v2: final speed = 0m/s (the balloon stops in my hands)
v1: initial speed = 13.0m/s
Δt: interaction time = ?
The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:
[tex]|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s[/tex]
The interaction time to avoid that the water balloon breaks is 0.029s
Complete the following statement:
Bimetallic strips used as adjustable switches in electric appliances consist of metallic strips that must have different:_____
a. volume.
b. specific heat capacities.
c. expansion coefficients.
d. mass.
e. length.
Answer: c. expansion coefficients.
Explanation: Bimetallic strips used as adjustable switches in electric appliances consist of metallic strips that must have different expansion coefficients.
I found the answer on Quizlet. :)
Bimetallic strips used as adjustable switches in electric appliances consist of metallic strips that must have different expansion coefficients. The correct option is c.
What is the expansion coefficient?The coefficient of thermal expansion (CTE) is the rate at which a material expands as its temperature rises. This coefficient is determined at constant pressure and without a phase change, i.e. the material is expected to remain solid or fluid.
Bimetallic strips, which are utilized as adjustable switches in electric appliances, are made up of metallic strips with differing expansion coefficients. The coefficient of thermal expansion indicates how the size of an object varies as temperature changes.
Therefore, the correct option is c. expansion coefficients.
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Two mirrors are touching so they have an angle of 35.4 degrees with one another. A light ray is incident on the first at an angle of 55.7 degrees with respect to the normal to the surface. What is the angle of reflection from the second surface
Answer:
54.6°
Explanation:
From law of reflection i=r.
So, construct the reflected ray at 55.7°degrees from the normal and let it fall on the other mirror.
Now draw the second normal at the point of incidence and again measure the angle of incidence, and draw the angle of reflection.
If you consider triangle AOB, one angle is ∠AOB=90°
and ∠OAB is 54.6°
From angle sum property third angle ie ∠ABO=180°-90°-54.6°=35.4°
So, the second incident angle will be 54.6°
Hence, the second reflected angle will be 54.6 degrees.
Find the average power Pavg created by the force F in terms of the average speed vavg of the sled.
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The power created is [tex]P_{avg} = F * v_{avg}[/tex]
Explanation:
From the question we are told that
The that the average power is mathematically represented as
[tex]P_{avg} = \frac{W }{\Delta t }[/tex]
Where W is is the Workdone which is mathematically represented as
[tex]W = F * s[/tex]
Where F is the applies force and s is the displacement due to the force
So
[tex]P_{avg} = \frac{F *s }{\Delta t }[/tex]
Now this displacement can be represented mathematically as
[tex]s = v_{avg} * \Delta t[/tex]
Where [tex]v_{avg }[/tex] is the average velocity and [tex]\Delta t[/tex] is the time taken
So
[tex]P_{avg} = \frac{F *v_{avg} * \Delta t }{\Delta t }[/tex]
=> [tex]P_{avg} = F * v_{avg}[/tex]
Answer:
Pavg = Fvavg
Explanation:
Since the P (power) done by the F (force) is:
P = Fs/t
and we are looking for the velocity, so then it would be:
P = Fv
with the average velocity the answer is:
Pavg = Favg
If an object is moving at a constant speed, and the force F is also constant, this formula can be used to find the average power. If v is changing, the formula can be used to find the instantaneous power at any given moment (with the quantity v in this case meaning the instantaneous velocity, of course).
solenoid is .3 m long and is wound with 2 layers of wire. the inner layer consists of 300 turns, the outer alyter of 250 turns. if the current in both layers are 3 A and in the same direction what is the magnetic field at the center of the solonoid?
Answer:
Explanation:
Magnetic field due to a solenoid
B = μ₀ nI where n is no of turns per unit length and I is current
for outer layer of turns
B = μ₀ x (250 / .3) x 3
= 4π x 10⁻⁷ x (250 / .3) x 3
= 3.14 x 10⁻³ T
for inner layer of turns
B = μ₀ x (300 / .3) x 3
= 4π x 10⁻⁷ x (300 / .3) x 3
= 3.77 x 10⁻³ T
Total magnetic field
= (3.14 + 3.77 ) x 10⁻³ T
= 6.91 x 10⁻³ T .
A 40 cm ruler with non-uniform mass is hung from its center of mass, at 21 cm. A force is applied at the 40 cm mark of the ruler. The length of the moment arm is _____. 40 19 21 None of the above
Answer:
The length of the moment arm is 19 cm
Explanation:
Given;
The total length of the ruler, L = 40 cm
a mass is hung from its center mass, at 21 cm
a force, F is applied at 40 cm
The length of the moment arm is calculated as;
the center mass of the ruler is at 20 cm mark
0 21cm 40cm
--------------------------------------------------------------------
↓ r ↓
M F
Moment about F, = Fr
The length of the moment arm is = r
r = 40 cm - 21 cm
r = 19 cm
Therefore, the length of the moment arm is 19 cm
A solid sphere is rolling smoothly with a speed of 6.0 m/s on a horizontal surface. It then rolls up a ramp to a maximum height of h and stops. Calculate this maximum height. (The moment of inertia of a solid sphere is I
Answer:
Explanation:
This exercise we will work using energy conservation, let's use two points
lower. Ramp starting point
Em₀ = K = ½ m v² + ½ I w²
more height. Point where e stops
[tex]Em_{f}[/tex] = m g h
at the starting point the sphere is spinning let's look for the relationship between the angular and linear variables
v = w r
the moment of inertia of a sphere is tabulated
I = 2/5 M R2
let's use that energy is conserved
Em₀ = Em_{f}
½ m v² + ½ (2/5 m r²) (v / r)² = m g h
½ v² + 1/5 v2 = g h
h= 7/10 v² / g
Two nearly equal wavelengths of light are incident on an N slit grating. The two wavelengths are not resolvable. When N is increased they become resolvable. This is because:
Answer:
the lines become more narrow
Explanation: Two nearly equal wavelengths of light are incident on an N slit grating. The two wavelengths are not resolvable. When N is increased they become resolvable. This is because:
The lines become more narrow.
A straw has an outer diameter of 14 mm, inner diameter of 11 mm, and length of 21 cm. It is made of glass with a Young's modulus of 68 GPa and tensile strength of 7 MPa. a. What is the effective spring constant of the straw with respect to elongation in N/m? b. When you hold either end you can stretch the straw with up to 90 N. How much does the straw elongate in mm? c. By how much can you extend the length of the straw before it breaks?
Given that,
Outer diameter = 14 mm
Inner diameter = 11 mm
Length = 21 cm
Young's modulus = 68 GPa
Tensile strength = 7 Mpa
(a). We need to calculate the effective spring constant of the straw with respect to elongation
Using formula of effective spring constant
[tex]\dfrac{Y}{\Delta l}=\dfrac{YA}{l}[/tex]
[tex]k=\dfrac{YA}{l}[/tex]
Where, k = effective spring constant
Y= Young's modulus
A = area
l = length
Put the value into the formula
[tex]k=\dfrac{68\times10^{9}\times\dfrac{\pi}{4}(0.014^2-0.011^2)}{21\times10^{-2}}[/tex]
[tex]k=1.90\times10^{7}\ N/m[/tex]
(b). Force = 90 N
We need to calculate the stretch the straw
Using formula of stretch
[tex]\Delta l=\dfrac{F}{k}[/tex]
Where, F = force
k = effective spring constant
Put the value into the formula
[tex]\Delta l=\dfrac{90}{1.90\times10^{7}}[/tex]
[tex]\Delta l=0.0000047\ m[/tex]
[tex]\Delta l=4.7\times10^{-6}\ m[/tex]
(c). We need to calculate the extend the length of the straw before it breaks
Using formula of extend length
[tex]E_{max}=\dfrac{Y\Delta l}{l}[/tex]
[tex]\Delta l=\dfrac{E_{max}l}{Y}[/tex]
Put the value into the formula
[tex]\Delta l=\dfrac{7\times10^6\times21\times10^{-2}}{68\times10^{9}}[/tex]
[tex]\Delta l=0.0000216\ m[/tex]
[tex]\Delta l=0.0216\times10^{-3}\ m[/tex]
[tex]\Delta l=0.0216\ mm[/tex]
Hence, (a). The effective spring constant of the straw with respect to elongation is [tex]1.90\times10^{7}\ N/m[/tex]
(b). The stretch the straw is [tex]4.7\times10^{-6}\ m[/tex]
(c). The extend length of the straw before it breaks is 0.0216 mm.
A proud new Jaguar owner drives her car at a speed of 25 m/s into a corner. The coefficients of friction between the road and the tires are 0.70 (static) and 0.40 (kinetic) assuming the car is not skidding while traveling along the curve, what is the magnitude of the centripetal acceleration of the car
Answer:
ac = 3.92 m/s²
Explanation:
In this case the frictional force must balance the centripetal force for the car not to skid. Therefore,
Frictional Force = Centripetal Force
where,
Frictional Force = μ(Normal Force) = μ(weight) = μmg
Centripetal Force = (m)(ac)
Therefore,
μmg = (m)(ac)
ac = μg
where,
ac = magnitude of centripetal acceleration of car = ?
μ = coefficient of friction of tires (kinetic) = 0.4
g = 9.8 m/s²
Therefore,
ac = (0.4)(9.8 m/s²)
ac = 3.92 m/s²
Based on the data provided, the centripetal acceleration is 3.92 m/s²
What is centripetal acceleration?Centripetal acceleration is the acceleration of a body moving in a circular path which is directed toward the center of the circle.
In the given question, the frictional force must balance the centripetal force for the car not to skid.
Frictional Force = Centripetal Forcewhere,
Frictional Force = μR
R = mg
F = μmg
Centripetal Force = m
Then
μmg = ma
a = μg
ac = 0.4 * 9.8 m/s²
ac = 3.92 m/s²
Therefore, the centripetal acceleration is 3.92 m/s².
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3. A body moves along a semicircular path. The ratio of distance to displacement is
Answer:
Ratio of distance to displacement is pi/2
Explanation:
Pls see attached file for diagram and explanation
what is the maximum torque on a coil 5 cm x 12 cm, composed of 600 turns, when it is carrying a current of 10^-5 A in a uniform field of .1 T
Answer:
3.6×10⁻⁶ Nm
Explanation:
From the question,
The expression for maximum torque is given as
τ = BANI.................Equation 1
where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.
Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.
Substitute these values into equation 1
τ = 0.1(0.006)(600)(10⁻⁵)
τ = 3.6×10⁻⁶ Nm
An arrow is launched vertically upward at a speed of 50 m/s. What is the arrow’s speed at the highest point? Ignore air resistance
Answer:
depending on how high it goes at 100m it has taken 2 secondes
Explanation:
At the highest point, the arrow is changing from moving up to moving down. At that exact point, its speed AND its velocity are both ZERO.
And air resistance actually makes no difference.
What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 2.5 × 10−4 mm and a crack length of 2.5 × 10−2 mm when a tensile stress of 170 MPa is applied (in MPa)
Answer:
2404 MPa
Explanation:
See attachment for solution
The maximum stress that exists at the tip of the internal crack is 3,400 Mpa.
The given parameters;
radius of the internal crack, r = 2.5 x 10⁻⁴ mmcrack length, l = 2.5 x 10⁻²tensile stress, σ = 170 MPa = 170 x 10⁶ N/m²The maximum stress that exists at the tip of the internal crack is calculated as follows;
[tex]\sigma _{max} = 2\sigma \times \sqrt{(\frac{l}{r} )} \\\\\sigma _{max} = 2 \times 170 \times 10^6 \times \sqrt{(\frac{2.5\times 10^{-2}}{2.5 \times 10^{-4}})} \\\\\sigma _{max} = 3.4 \times 10^{9} \ Pa\\\\\sigma _{max} = 3,400\ Mpa[/tex]
Thus, the maximum stress that exists at the tip of the internal crack is 3,400 Mpa.
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We observe that a small sample of material placed in a non-uniform magnetic field accelerates toward a region of stronger field. What can we say about the material?
Answer:
C) It is either ferromagnetic or paramagnetic
Explanation:
The complete question is given below
We observe that a small sample of material placed in a non-uniform magnetic field accelerates toward a region of stronger field. What can we say about the material?
A) It must be ferromagnetic.
B) It must be paramagnetic.
C) It is either ferromagnetic or paramagnetic.
D) It must be diamagnetic.
A ferromagnetic material will respond towards a magnetic field. They are those materials that are attracted to a magnet. Ferromagnetism is associated with our everyday magnets and is the strongest form of magnetism in nature. Iron and its alloys is very good example of a material that readily demonstrate ferromagnetism.
Paramagnetic materials are weakly attracted to an externally applied magnetic field. They usually accelerate towards an electric field, and form internal induced magnetic field in the direction of the external magnetic field.
The difference is that ferromagnetic materials can retain their magnetization when the externally applied magnetic field is removed, unlike paramagnetic materials that do not retain their magnetization.
In contrast, a diamagnetic material is repelled away from an externally applied magnetic field.
If the heating curve is reversed, what would best describe the boiling point?
Answer:
point of condensation
Explanation:
During a snowball fight, two snowball with masses of 0.30 kg and 0.70 kg, respectively, are thrown in such a manner that they meet head-on (traveling opposite directions) and combine to form a single mass. The magnitude of initial velocity for each is 10.4 m/s. What is the speed of the 1.0 kg mass immediately after the collision
Answer:
10.4 m/s
Explanation:
Given that
mass of the first snowball, m1 = 0.3 kg
mass of the second snowball, m2 = 0.7 kg
Magnitude of initial velocity for both masses, u = 10.4 m/s
To start with, we use the formula of conservation of linear momentum which states that
magnitude of initial momentum is equal to magnitude of final momentum.
m1u1 + m2u2 = V(m1 + m2)
0.3 * 10.4 + 0.7 * 10.4 = V(0.3 + 0.7)
3.12 + 7.28 = V(1)
10.4 = V
The 1 kg mass is an addition Of the 0.3 mass & 0.7 kg mass.
Thus, the speed of the 1 kg mass is 10.4 m/s