When water is added to a mixture Na_2O_2(s) and S(s), a redox reaction occurs, as represented by the equation below.
2NaO_2(s) + 2 H_2O(l) rightarrow 4 NaOH (aq) + SO_2(aq) Delta H_298 degree = -610 kJ/mol_rxn; Delta S_298 degree = -73 J/(K mol_rxn)
Which of the following statements about the thermodynamic favorability of the reaction at 298 K is correct?
(A) It is thermodynamically unfavorable
(B) It is thermodynamically favorable and is driven by Delta S degree only.
(C) It is favorable and is driven by Delta H degree only.
(D) It is thermodynamically favorable and is driven by both Delta H degree and Delta S degree
Answer:
(C) It is favorable and is driven by ΔH° only.
Explanation:
Let's consider the following balanced equation.
2 Na₂O₂ + S + 2 H₂O → 4 NaOH + SO₂
To determine whether it will be favorable or not at 298 K, we need to calculate the standard Gibbs free energy (ΔG°).
If ΔG° < 0, the reaction will be favorable.If ΔG° > 0, the reaction will be unfavorable.We can calculate ΔG° using the following expression.
ΔG° = ΔH° - T.ΔS°
As we can see from the expression above, the favorability will be driven if ΔH° < 0 and if ΔS° < 0. Since ΔH° = -610 kJ/mol and ΔS° = -73 J/K.mol, the favorability will be driven by ΔH°. Now, let's calculate the overall favorability.
ΔG° = ΔH° - T.ΔS°
ΔG° = -610 kJ/mol - 298 K.(-0.073 kJ/K.mol) = -588 kJ/mol
The reaction is favorable and is driven by ΔH° only.
What type of a liquid will have a pH value equal to 12?
Basic
Neutral
Strong acid
Weak acid
Answer:
weak acid
Explanation:
Answer: Basic is correct!!!!!
Explanation:
Given the molecular formulas, write the empirical formulas in the spaces provided.
C6H4Cl2
C6H5Cl
N2O5
Answer:
1. C3H2Cl
2. C6H5Cl
3. N2O5
Explanation:
One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) technique. As corn photosynthesizes, it concentrates the isotope carbon-13, whereas most other plants concentrate carbon-12. Over-reliance on corn consumption can then be correlated with certain diseases, because corn lacks the essential amino acid lysine. Archaeologists use a mass spectrometer to separate the C12 and C 13 isotopes in samples of humans remains. Suppose you use a velocity selector to obtain single ionized (missing one electron) atoms of speed 8.50 km/s and what to bend them within a uniform magnetic field in a semicircle of diameter 25.0 cm for the C12 . The measured masses of these isotopes are 1.99 × 10^-26 kg ( C12 ) and 2.16 × 10^-26 kg ( C13).
Required:
a. What strength of magnetic field is required? (b) What is the diameter of the 13C semicircle?
b. What is the separation of the C12 and C13 ions at the detector at the end of the semicircle? Is this distance large enough to be easily observed?
Answer:
a. i. 8.447 × 10⁻³ T ii. 27.14 cm
b. i. 2.14 cm ii. It is easily detectable.
Explanation:
a.
i. What strength of magnetic field is required?
Since the magnetic force F = Bqv equals the centripetal force F' = mv²/r on the C12 charge, we have
F = F'
Bqv = mv²/r
B = mv/re where B = strength of magnetic field, m = mass of C12 isotope = 1.99 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q = charge on C 12 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron)and r = radius of semicircle = 25.0 cm/2 = 12.5 cm = 12.5 × 10⁻² m
So,
B = mv/rq
B = 1.99 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (12.5 × 10⁻² m × 1.602 × 10⁻¹⁹ C)
B = 16.915 × 10⁻²³ kgm/s ÷ (20.025 × 10⁻²¹ mC)
B = 0.8447 × 10⁻² kg/sC)
B = 8.447 × 10⁻³ T
(ii) What is the diameter of the 13C semicircle?
Since the magnetic force F = Bq'v equals the centripetal force F' = mv²/r' on the C13 charge, we have
F = F'
Bq'v = mv²/r'
r' = mv/Be where r = radius of semicircle, B = strength of magnetic field = 8.447 × 10⁻³ T, m = mass of C12 isotope = 2.16 × 10⁻²⁶ kg, v = speed of C 12 isotope = 8.50 km/s = 8.50 × 10³ m/s, q' = charge on C 13 isotope = e = electron charge = 1.602 × 10⁻¹⁹ C (since the isotope loses one electron) and = d/2 = 12.5 cm = 12.5 × 10⁻² m
So, r' = mv/Be
r' = 2.16 × 10⁻²⁶ kg × 8.50 × 10³ m/s ÷ (8.447 × 10⁻³ T × 1.602 × 10⁻¹⁹ C)
r' = 18.36 × 10⁻²³ kgm/s ÷ 13.5321 × 10⁻²² TC)
r' = 1.357 × 10⁻¹ kgm/TC)
r' = 0.1357 m
r' = 13.57 cm
Since diameter d' = 2r', d' = 2(13.57 cm) = 27.14 cm
b.
i. What is the separation of the C12 and C13 ions at the detector at the end of the semicircle?
Since the diameter of the C12 isotope is 25.0 cm and that of the C 13 isotope is 27.14 cm, their separation at the end of the semicircle is 27.14 cm - 25.0 cm = 2.14 cm
ii. Is this distance large enough to be easily observed?
This distance of 2.14 cm easily detectable since it is in the centimeter range.
To take liquid on a plane, they must be in a container with a maximum volume of 100ml select the item that cannot be taken on the plane
0.12 litres bottle of aftershave
75ml of sun cream
0.1 litre of mouthwash
0.095ml of shampoo
Answer:
The answer is 0.12 liters bottle of aftershave.
Explanation:
In order to fit into the container, the volume of the liquid has to be lesser than or equal to 100ml. 0.12 liter is the only option which is more than 100ml. That's why it is the answer.
Zack has noticed a lot of changes in his body. He has gained muscle mass and started to grow facial hair. His voice is also getting deeper.
In which stage of development is he?
childhood
adolescence
early adulthood
late adulthood
Answer:
b
Explanation:
Sample A: 300 mL of 1M sodium chloride
Sample B: 145 mL of 1.5 M sodium chloride
Which sample contains the larger concentration of sodium chloride?
Answer:
Sample A
Explanation:
Molarity of a solution can be calculated using the formula:
Molarity = number of moles (mol) ÷ volume (vol)
For Sample A:
V = 300ml = 300/1000 = 0.3 L
Molarity = 1M
n = number of moles (mol)
1 = n/0.3
n = 0.3moles
For Sample B:
V = 145 mL = 145/1000 = 0.145L
Molarity = 1.5 M
n = number of moles
1.5 = n/0.145
n = 1.5 × 0.145
n = 0.22 moles
Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.
Molecular complexes in the cristae contain electron transport carriers that move _________ into the intermembrane space. The first electron transport carrier accepts an ________ from _________ . A second carrier accepts an ___________ from _________ . After the ________have travelled through the chain they are finally accepted by ________ and 2 __________ to produce water. Going from high to low concentration, _________ flow through ATP synthase like a water wheel to produce ~32 ________ molecules.
Answer:
a.) Hydrogen
b.) electron
c.) NADH⁺ + H⁺
d.) electron
e.) FADH₂
f.) electron
g.) hydrogen ions
h.) oxygen
i.) hydrogen ions
j.) ATP
Explanation:
Molecular complexes in the cristae contain electron transport carriers that move Hydrogen into the intermembrane space.
The first electron transport carrier accepts an electron from NADH⁺ + H⁺
A second carrier accepts an electron from FADH₂ .
After the electron have travelled through the chain they are finally accepted by hydrogen ions and oxygen to produce water.
Going from high to low concentration, hydrogen ions flow through ATP synthase like a water wheel to produce ~32 ATP molecules.
The elements in the periodic table are not always represented by
the first one or two letters in their names. What are some examples of
this (list three)?
Unnillium (101)
Unnilbium (102)
Unniltrium (103)
Unnilquadium (104)
Unnilpentium (105)
Unnilhexium (106)
Unnilseptium (107)
Unniloctium (108)
Unnilennium (109)
Ununnillium (110)
What is matter?
O A. Anything that has energy and motion
B. Anything that takes up space and has mass
C. Anything that can be seen
D. Anything that can be measured
Answer:
B.Anything that takes up space and has mass
Someone please help anyone who steals points will be reported
Answer:
ecosystem i think
A gas mixture contains each of the following gases at the indicated partial pressures: N2, 231 torr ; O2, 101 torr; and He, 155 torr .
What is the total pressure of the mixture?
What mass of each gas is present in a 1.00 -L sample of this mixture at 25.0 degrees Celsius?
Enter your answers numerically separated by commas.
Answer:
P = 487 Torr
mN₂ = 0.347 g
mO₂ = 0.174 g
mHe = 0.0333 g
Explanation:
Step 1: Calculate the total pressure of the mixture
The total pressure of the mixture (P) is equal to the sum of the partial pressures of the gases.
P = pN₂ + pO₂ + pHe
P = 231 Torr + 101 Torr + 155 Torr = 487 Torr
Step 2: Calculate the moles of each gas
We have 3 gases in a 1.00 L container at 25.0 °C (298.2 K). We can calculate the number of moles using the ideal gas equation: P × V = n × R × T.
nN₂ = pN₂ × V / R × T
nN₂ = 231 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.0124 mol
nO₂ = pO₂ × V / R × T
nO₂ = 101 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00543 mol
nHe = pHe × V / R × T
nHe = 155 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00833 mol
Step 3: Calculate the mass of each gas
The molar mass of N₂ is 28.01 g/mol.
mN₂ = 0.0124 mol × 28.01 g/mol = 0.347 g
The molar mass of O₂ is 32.00 g/mol.
mO₂ = 0.00543 mol × 32.00 g/mol = 0.174 g
The molar mass of He is 4.00 g/mol.
mHe = 0.00833 mol × 4.00 g/mol = 0.0333 g
The line notation, Pt
| H2(g) | H (aq) || Cu2 (aq) | Cu(s),
indicates that
copper metal is a product of the cell reaction.
hydrogen gas (H2) is a product of the cell reaction.
Cu is the anode.
Pt is the cathode.
Answer:
copper metal is a product of the cell reaction.
Explanation:
In writing the line notation of a cell reaction, we ought to recall that the anode is placed at the left hand side of the notation while the cathode is placed at the right hand side of the notation.
If we look at the line notation shown in the question, we will realize that the Cu2+ (aq) | Cu(s) half cell is the cathode and that copper metal is the product of the reaction as shown by the notation.
4. Eggs are present in the ovaries when people are born, and after they go
through puberty. *
OTrue
OFalse
2. How many calories are needed to raise 50 g of iron from 55°C to 200°C? (c = 0.110 cal/g °C)
Answer:
Q = 797.5 cal
Explanation:
Given that,
Mass of iron, m = 50 g
The temperature rises from 55°C to 200°C.
We need to find the heat needed to raise the temperature. The heat raised is given by :
[tex]Q=mc\Delta T[/tex]
Put all the values,
[tex]Q=50\times 0.11\times (200-55)\\\\Q=797.5\ cal[/tex]
So, 797.5 calories of heat is needed.
If a medicine ball in a gym has a mass of 4.0 Kg, what is its weight?
Answer:
Weight = 0.4Explanation:
Given Information :
Mass = 4.0kg
Acceleration due to gravity = 10 m/s
Weight= ?
[tex]Weight = \frac{mass}{acceleration\: due \:to \:gravity} \\\\W= \frac{4.0}{10} \\\\W= \frac{2}{5} \\\\W=0.4[/tex]
Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.
Answer:
50 g Sucrose
Explanation:
Step 1: Given data
Mass of solution: 2000 gConcentration of the solution: 2.5%Step 2: Calculate the mass of sucrose needed to prepare the solution
The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:
2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose
Civic participation is best described as the act of
avoiding harming other community members.
meeting one's legal responsibilities.
voting in every type of election.
going above and beyond one's legal duties.
Which is one of Edwin Hubble’s findings that supports the big bang theory?
Answer:
meeting ones legal responsibility
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes?
-Molecules in both the metal and the surrounding air will start moving at lower speeds. -Molecules in both the metal and the surrounding air will start moving at higher speeds. -The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
-The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
until the next harvest, and seed must be held for the next season's ... successful grain storage is the moisture content of the crop. ... or both. If ambient temperatures are low, then air alone may cool the ... allow some of the drying to take place naturally while the crop ... employed to cool grain that has been placed in storage.
The celestial bodies in space move about in predictable paths called blank . As a result, a planet is able to blank around the Sun. Other objects in the solar system also orbit the Sun. These objects include blank and comets.
Answer:
Gravity
Explanation:
All matter exerts a force, which is called , that pulls all other matter towards its center. The strength of the force depends on the mass of the object: the Sun has more gravity than Earth, which in turn has more gravity than an apple. Also, the force weakens with distance. Objects far from the Sun won’t be influenced by its gravity.
A or B or C or D, fassst plzzz
Answer:
a.option is the correct answer
When liquid water freezes into solid ice in the freezer,
Answer:
What about it? I don't get the question
Question 6
4 pts
6) Chromium crystallizes in a body-centered cubic unit cell. If the length of an edge of the unit cell
is 289 pm, what is the density (in g/cm3) of chromium?
Show your work on a paper and upload it here.
Upload
Choose a File
Answer:
7.15g/cm³
Explanation:
To solve this question we must know that a body-centered cubic unit cell contains 2 atoms.
The volume of the unit cell is:
289pm = (289x10⁻¹²m)³ =
2.414x10⁻²⁹m³ * (1cm³ / 1x10⁻⁶m³) = 2.414x10⁻²³cm³
And the mass is -Molar mass Chromium = 51.9961g/mol:
2atoms * (1mol / 6.022x10²³atoms) * (51.9961g / mol) =
1.727x10⁻²²g
The density is:
1.727x10⁻²²g / 2.414x10⁻²³cm³ =
7.15g/cm³a change in an objects position is called
Answer: are there any answer choices? If not I think MOTION
Explanation: hope that’s right, have a great day!! :)
What is the usable form of nitrogen that is found in the ground?
In each pair of compounds, pick the one with the higher vapor pressure at a given temperature. Explain your reasoning.
a. CH4 or CH3CI
b. CH3CH2CH2OH or CH3OH
c. CH3OH or H2CO
Answer:
The answer is:
[tex]PART \ A: CH_4\\\\PART \ B: CH_30H\\\\PART \ C: H_2CO[/tex]
Explanation:
Parts A:
The vapor pressure is higher in [tex]CH_4[/tex] because it is non-polar, while [tex]CH_3Cl[/tex] is polar. [tex]CH_4[/tex] has a lower molar weight as well.
Part B:
Although hydrogen bonding is found in both commodities, the vapor pressure is higher because of the smaller molar mass of [tex]CH_30H[/tex].
Part C:
[tex]H_2CO[/tex] does not show hydrogen due to the increased vapor pressure
[tex]CH_3OH[/tex] bonding.
How much energy (in J) is lost when a sample of iron with a mass of 28.3 g cools from 66.0 degrees celsius to 24.0 degrees celsius.
Answer:
Q = -535 J.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:
[tex]Q=mC(T_F-T_i)[/tex]
Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:
[tex]Q=28.3g*0.450\frac{J}{g\°C} (24.0\°C-66.0\°C)\\\\Q=-535J[/tex]
Regards
Solid lead acetate is slowly added to 75.0 mL of a 0.0492 M sodium sulfate solution. What is the concentration of lead ion required to just initiate precipitation?
Answer:
The concentration of lead ion required to just initiate precipitation is -[tex]2.37\times10^-^5 M[/tex]
Explanation:
Lets calculate -:
Solubility equilibrium -: [tex]PbI_2(s)[/tex] ⇄ [tex]Pb^2^+ (aq) + 2I^- (aq)[/tex]
Solubility product of [tex]PbI_2[/tex] ,[tex]Q=[Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex][I^-]^2_i_n_i_t_i_a_l[/tex] [tex]=9.8\times10^-^9[/tex]
Concentration of [tex]I^-[/tex][tex]=[KI]=0.0492M[/tex]
When the ionic product exceeds the solubility product , precipitation of salt takes place .
[tex]Q_s_p\geq K_s_p[/tex]
[tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex][I^-]^2_i_n_i_t_i_a_l[/tex] [tex]\geq 9.8\times10^-^9[/tex]
[tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex][0.0492]^2[/tex] [tex]\geq 9.8\times10^-^9[/tex]
[tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq \frac{9.8\times10^-^9}{[0.0492]^2}[/tex]
[tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq[/tex] [tex]\frac{9.8\times10^-^9}{2.42\times10^-^3}[/tex]
[tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq[/tex] [tex]2.37\times10^-^5 M[/tex]
Thus , [tex]PbI_2[/tex] will start precipitating when [tex][Pb^2^+]_i_n_i_t_i_a_l[/tex] [tex]\geq 2.37\times10^-^5 M[/tex].
a sample of mg(hco3)2 contains 1.8 moles of oxygen atom find the number of carbon atoms in the given sample
please solve fast very much urgent
Answer:
0.60 moles of atoms of carbon
Explanation:
Step 1: Given data
Chemical formula of the compound: Mg(HCO₃)₂Moles of oxygen atoms: 1.8 molesStep 2: Calculate the number of carbon atoms in the given sample
According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:
1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C
What does a velocity measurement include that a speed measurement does not?
time
direction
distance
acceleration