an inductive argument guarantees its conclusion

True

False

Answers

Answer 1

Answer:

False

Explanation:

inductive arguments have some evidence but do not have full assurance of truth of the conclusion

Answer 2
I think the answer is true

Related Questions

Catching a wave, a 77 kg surfer starts with a speed of 1.3 m/s, drops through a height of 1.65 m, and ends with a speed of 8.2 m/s. How much non-conservative work was done on the surfer?

Answers

Answer:

Explanation:

The total work done by the wave is expressed as;

Workdone = Potential energy + Kinetic energy

Workdone = mgh + 1/2mv²

m is the mass = 77kg

g is the acceleration due to gravity = 9.8m/s²

v is the velocity = 8.2m/s

h is the height = 1.65m

Substitute into the formula;

Workdone = 77(9.8)(1.65) + 1/2(77)8.2²

Workdone = 1245.09 + 2588.74

Workdone = 3833.83Joules

Hence the amount of non conservative work done on the sofa is 3833.83Joules

The non-conservation work done will be "3833.83 Joules".

Given:

Velocity, v = 8.2 m/sHeight, h = 1.65 mMass, m = 77 kg

We know,

→ [tex]Work \ done = Potential \ energy +Kinetic \ energy[/tex]

or,

                     [tex]= mgh +\frac{1}{2} mv^2[/tex]

By putting the values,

                     [tex]= 77\times 9.8\times 1.65+\frac{1}{2}\times 77\times (8.2)^2[/tex]

                     [tex]= 1245.09+2588.74[/tex]

                     [tex]= 3833.83 \ Joules[/tex]

Thus the above approach is right.

Learn more about work done here:

https://brainly.com/question/24230840

Describe which relationships in Ohm’s law are DIRECT and which are INVERSE. Use examples to support your answer. You can use calculations, drawings, or graphs to make your point more clear

Answers

Answer:

I like to memorize excerpt from articles to solve and answer questions like these. I hope this can help, it's from study.com: "The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r."

A jogger runs 6km north, 5km east, then another 4km north. Her average speed is 8 km/h. How long will it take her to complete her run?

Answers

Answer:

t = 1.875 hours

Explanation:

Speed

The speed is the rate at which an object moves. If the speed is constant, then the formula to calculate it is:

[tex]\displaystyle v=\frac{d}{t}[/tex]

Where d is the distance traveled in time t.

The jogger runs 6 Km plus 5 Km plus 4 Km north for a total of 15 Km.

It's given her average speed is 8 Km/h. We can calculate the time take to complete the run by solving the above formula for t:

[tex]\displaystyle t=\frac{d}{v}[/tex]

[tex]\displaystyle t=\frac{15\ Km}{8\ Km/h}[/tex]

t = 1.875 hours

Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is

Answers

This question is incomplete, the complete question is;

Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 970 km/hr above East Lansing. The downward component of the earth's magnetic field at this place is 0.7 × 10⁻⁴ T. (DATA: Assume that the wingspan is 60 meters.)

Answer:

the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts

Explanation:

Given that;

Speed S = 970 KM/hr

downward component of the earth's magnetic field B = 0.7 × 10⁻⁴

wingspan 1 = 60min

Velocity V = (970 × 10³) / 3600 = 269.44 m/s

So Average Induced Voltage E = VBI

we substitute

E = 269.44 × (0.7 × 10⁻⁴) × 60

E = 1.132 Volts

Therefore the average induced voltage between the tips of the wings of a Boeing 747 flying is 1.132 Volts


In ultimate the disc may be passed in any direction.
True
False

Answers

I think is True: Because...

when you throw a disc you can throw it in any direction, many people call it "Flying Saucer" I'll give you an example ... When you throw something, for example a paper, you want to throw it at your classmate. You already know what address you want to send it to, then I say it is: True ...

Sorry if it's wrong :(

A typical blood pressure is 120 mm Hg. How high would you need to hang an IV bag so that the fluid enters the blood stream at this pressure? Assume the IV fluid has a density of 1000 kg/m^3.

Answers

Answer:

1.63 m

Explanation:

The following data were obtained from the question given above:

Pressure (P) = 120 mmHg

Density (d) = 1000 Kg/m³

Height (h) =?

Next, we shall convert 120 mmHg to N/m². This can be obtained as follow:

760 mmHg = 101325 N/m²

Therefore,

120 mmHg = 120 mmHg × 101325 N/m² / 760 mmHg

120 mmHg = 15998.68 N/m²

Thus, 120 mmHg is equivalent to 15998.68 N/m².

Finally, we shall determine the height to which the IV bag should be placed so that the fluid can enter the blood stream. This is illustrated below:

Pressure (P) = 15998.68 N/m².

Density (d) = 1000 Kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

P = dgh

15998.68 = 1000 × 9.8 × h

15998.68 = 9800 × h

Divide both side by 9800

h = 15998.68 / 9800

h = 1.63 m

Therefore, the the IV bag should be placed at a height of 1.63 m

An 800 kg car is parked next to a 1000 kg car. Their centers of mass are 3.5 m apart. Find the gravitational force between them.

Answers

Answer:

4.356e-6 Newtons

Explanation:

Using the equation for the force of gravity F=[tex]\frac{Gm_1m_2}{r^2}[/tex]. The two masses are m1=800kg and m2=1000 kg. The value of G, the gravitational constant =6.67e-11. The problem states the distance between the center of masses of the two cars is 3.5 meters(r). Plugging in what we have from the problem, you will get 4.346e-6 newtons. This makes sense as gravity in itself is a weak force requiring extremely massive objects to result in a noticeable force.

Fast and safe heart rate for workouts is called muscular strength? True or false

Answers

Answer:

False

Explanation:

Answer:

false :3

hope this helps

The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 89.0 cm from a slit of width 0.710 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.

Answers

We know, for single slit :

[tex]y =\dfrac{ n\lambda L}{a}\\\\\lambda = \dfrac{ya}{nL}[/tex]       ...1)

[tex]y = 1.4\ mm = 1.4 \times 10^{-3}\ m[/tex]

n = 2

L = 89 cm = 0.89 m

[tex]a=7.1\times 10^{-4}\ m[/tex]

Putting all these in equation 1), we get :

[tex]\lambda = \dfrac{ya}{nL}\\\\\lambda = \dfrac{1.4\times 10^{-3}\times 7.1\times 10^{-4}}{2\times 0.89 }\\\\\lambda = 5.584 \times 10^{-7}\ m[/tex]

Therefore, wavelength of the incident light is [tex]5.584 \times 10^{-7}\ m[/tex] or 558.4 nm.

Hence, this is the required solution.

from a flying aeroplane abody should be dropped in advance to hit the target why​

Answers

the body should be dropped in advance as when the body is dropped it has the velocity of the plane. So, in air the body moves forward which we have to take into consideration in order to hit the target.

From a flying plane a body should dropped in advance to hit the target,Why? ... The body should be dropped in advance as when the body is dropped it has the velocity of the plane. So, in air the body moves forward which we have to take into consideration in order to hit the target.

1.) There was an earthquake in Salt Lake City, Utah, on March 18, 2020, in the morning at  9 hours, 9 minutes, and 45 seconds Mountain Standard Time (9:9:45 MST).  If the velocity of the p-wave is 7.3 km/sec and the velocity of the s-wave is 5.1 km/sec and the s-p time lag is 16 seconds, what is the distance in kilometers from Salt Lake City to the focus of the earthquake?  Explain how you calculated the answer.


Answers

Answer:

7 because salt lake and Southis weat

In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to

Answers

Answer:

Fall

Explanation:

significance of practicals in the discipline of geography​

Answers

Geographic information provides context for understanding spatial relationships and human-environment interaction. Geography is considered a science and thus also uses the scientific method for data collection, analysis, and interpretation.

Why Geography is a discipline?
Geography as a discipline is related to space and takes note of spatial characteristics and attributes. It studies the patterns of distribution, location and concentration of phenomena over space and interprets them providing explanations for these patterns.

A golf ball (m=26.7g) is struck a blow that makes an angle of 33.6 degrees with the horizontal. The drive lands 190m away on a flat fairway. The acceleration of gravity is 9.8 m/s^2 . If the golf club and ball are in contact for 7.13 ms, what is the average force of impact?

Answers

Answer:

Th average force impact is [tex]F = 168.298 \ N[/tex]

Explanation:

From the question we are told that  

   The mass of the golf ball is  [tex]m_g = 26.7 \ g = 0.0267 \ kg[/tex]

    The angle made is [tex]\theta = 33.6 ^o[/tex]

    The range of the golf ball  is [tex]R = 190 \ m[/tex]

     The duration of contact is [tex]\Delta t = 7.13 \ ms = 7.13 *10^{-3} \ s[/tex]

Generally the range of the golf ball is mathematically represented as

       [tex]R = \frac{v^2 sin2(\theta)}{g}[/tex]

Here v  is the velocity with which the golf club propelled it with, making  v the subject

       [tex]v = \sqrt{\frac{R * g}{sin 2 (\theta)} }[/tex]

=>     [tex]v = \sqrt{\frac{190 * 9.8}{sin 2 (33.6)} }[/tex]

=>     [tex]v = 44.94 \ m/s[/tex]

Generally the change in momentum of the golf ball is mathematically represented as

      [tex]\Delta p = m * (v - u )[/tex]

here u  is the initial  velocity of the ball before being stroked and the value is 0 m/s

       [tex]\Delta p = 0.0267 * ( 44.94 - 0 )[/tex]

=>    [tex]\Delta p = 1.19996 \ kg \cdot m/s[/tex]

Generally the  average force of impact is mathematically represented as      

         [tex]F = \frac{\Delta p }{\Delta t}[/tex]

=>        [tex]F = \frac{1.19996 }{7.13 *10^{-3}}[/tex]

=>        [tex]F = 168.298 \ N[/tex]

     

C4. A 50.0 kg boy runs at 10.0 m/s, jumps on a cart and rolls off at 2.50 m/s. What is the mass of the cart

Answers

Answer:

The mass of the cart is 150 kg.

Explanation:

Given that,

Mass of a boy, m₁ = 50 kg

Initial speed of boy, u₁ = 10 m/s

Initial speed of car, u₂ = 0 (at rest)

The speed of the cart with the boy on it is 2.50 m/s, V = 2.5 m/s

Let m₂ is the mass of the cart. Using the conservation of momentum as follows :

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\50(10)+m_2(0)=(50+m_2)(2.5)\\\\500=125+2.5m_2\\\\375=2.5m_2\\\\m_2=150\ kg[/tex]

So, the mass of the cart is 150 kg.

An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net work while rejecting the waste heat to a sink at 300K. Is this a reasonable claim

Answers

Answer:

the claim is not valid or reasonable.

Explanation:

In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:

η(max) = 1 - T₁/T₂

where,

η(max) = maximum efficiency = ?

T₁ = Sink Temperature = 300 K

T₂ = Source Temperature = 400 K

Therefore,

η(max) = 1 - 300 K/400 K

η(max) = 0.25 = 25%

Now, we calculate the actual frequency of the engine:

η = W/Q

where,

W = Net Work = 250 KJ

Q = Heat Received = 750 KJ

Therefore,

η = 250 KJ/750 KJ

η = 0.333 = 33.3 %

η > η(max)

The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.

Therefore, the claim is not valid or reasonable.

How many neutrons does protium have

Answers

Answer:

I believe none

Explanation:

The mass number of protium is also 1 since there are no neutrons in the nucleus of protium. The atomic mass of protium is about 1.00794 amu. The symbol for protium is 1H. The electron configuration of protium is 1s1.

You are a world-famous physicist-lawyer defending a client who has been charged with murder. It is alleged
that your client, Mr. Lawton, shot the victim, Mr. Cray. The detective who investigated the scene of the
crime, Mr. Dibny, found a second bullet, from a shot that missed Mr. Cray, that had embedded itself into a
chair. You arise to cross-examine the detective.
You: In what type of chair did you find the bullet?
Dinby: A wooden chair.
You: How massive was this chair?
Dinby: It had a mass of 20 kg.
You: How did the chair respond to being struck with a bullet?
Dinby: It slid across the floor.
You: How far?
Dinby: Three centimeters. The slide marks on the dusty floor are quite distinct.
You: What kind of floor was it?
Dinby: A wood floor.
You: What was the mass of the bullet you retrieved from the chair?
Dinby: Its mass was 10 g.
You: Have you tested the gun you found in Mr. Lawton's possession?
Dinby: I have.
You: What is the muzzle velocity of bullets fired from that gun?
Dinby: The muzzle velocity is 450 m/s.
With only slight hesitation, you turn confidently to the jury and proclaim, "My client's gun did not fire those
shots!"
(a) How are you going to convince the jury and judge?
(b) Choose one part of your solution and perform a sense-making analysis. Clearly state which sensemaking analysis you’ve chosen and why.

Answers

Answer:

It was not fired from the client's gun because the chair slid only 3 centimeters . If it had been fired from the client's gun the chair would slid 25.82 centimeters.

Explanation:

According to the law of conservation of momentum the momentum of the system before collision must be equal to the momentum of the system after the collision.

M1u1= m2u2

Let M1 = mass of the chair = 20kg

     m2= mass of the bullet= 10g= 0.001kg

      u1= velocity of the chair before collision = zero m/s

      u2 =  velocity of the bullet before collision = zero m/s

         v1= velocity of the chair after collision = ?  m/s  

        v2 =  velocity of the bullet after collision = 450 m/s

After collision their velocities change from u1 to v1 and u2 to v2 so

M1v1= m2v2

v1= m2v2/M1

v1= 0.01 *450/ 20=  0.225 m/s

Now according to the law of conservation of energy the energy of the system before collision must be equal to the energy of the system after the collision.

The energy of the chair after the bullet is hit is

KE of the chair + KE of the bullet=  1/2 (M)(v1)²+ 1/2 m(v2)²=

1/2 ( 20) (0.225 )² + 1/2 (0.01) (450)²

= 0.50625 + 1012.5=  1013.00625 Joules

Frictional force = Coefficient of kinetic force of wood on wood ( M+m) g

                           = 0.2* ( 20.01) 9.8=   39.2196 N

Work done by friction = frictional force * distance

If law of conservation of energy is applied  the KE  must be equal to the work done

KE = W

W= f*d

KE= F*d

d = KE/f= 1013.00625/ 39.2196= 25.82 cm

The chair did not move 25.82 cm .

It only moved 3 centimeter.

Hence the bullet fired was not from the client's gun.

How many stars are in the universe (approximately)? O 40 sixtillion 0 365 billion O 86.4 million O one​

Answers

Answer:

a i belive

Explanation:

the univerce is VERY large so a, if im wrong i apologise :(

What is the highest order dark fringe, , that is found in the diffraction pattern for light that has a wavelength of 575 nm and is incident on a single slit that is 1410 nm wide?

Answers

Answer:

The highest order dark fringe is 2

Explanation:

From the question we are told that

   The wavelength is  [tex]\lambda = 575 \ nm = 575 *10^{-9} \ m[/tex]

    The width is of the slit is  [tex]d = 1410 nm = 1410 *10^{-9} \ m[/tex]

Generally the highest order dark fringe  is mathematically represented as

       [tex]m = \frac{w}{\lambda }[/tex]

=>     [tex]m = \frac{ 1410 *10^{-9}}{ 575 *10^{-9} }[/tex]

=>     [tex]m =2[/tex]

A current is flowing in a wire in direction 3i + 4j where the direction of the magnetic field is 5j + 12k. The force on the wire is:_____

a. 0.71(i + j).
b. 0.78i - 0.58j + 0.24k.
c. 0.78i + 0.58j - 0.24k.
d. 0.78i + 0.58j + 0.24k.

Answers

Answer:

F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^

the correct answer is "b"

Explanation:

The magnetic force is

          F = i l x B

The bold are vectors, in this case they give us the direction of the current and the magnetic field, for which we can solve as a determinant

         

[tex]F = i \left[\begin{array}{ccc}x&y&z\\3&4&0\\0&5&12\end{array}\right][/tex]

resolver

     F = i ^ (4 12 - 0) + j ^ (0- 3 12) + k ^ (3  5 - 0)

     F = i (48 i ^ - 36 j ^ + 15 k⁾

in this case i is the value of the current flowing through the cable

     i = 16 mA = 0.016 A

     F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^

When reviewing the different answers, the correct answer is "b"

Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 Newtons on earth, which has more mass?

a. Object a
b. Object b
c. Same mass
d. Other

Answers

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10                (g = 10 m/[tex]s^{2}[/tex])

m = [tex]\frac{25}{10}[/tex]

   = 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

2. Heather and Matthew walk with an average velocity of +0.87 m/s eastward.
If it takes them 27 minutes to walk to the store, what is their
displacement? (include direction)
(5 points)

Answers

The answer is 27 minuets

1.The
across each resistor is
the same in a series circuit.
) voltage
current

Answers

Answer:

The answer is Current.

Explanation:

In a series circuit, every component will have the same current.

In parallel circuit, all voltage of component remains the same.

Answer:

In a series circuit, each resistor has the same charge flowing through it.

Explanation:

If you have resistors arranged in a chain, the current only has one path to take which results in an equal charge in each resistor.

A 5 kg ball and a 2 kg ball are placed at opposite ends of a massless beam so that the system is in equilibrium. What is the ratio of the length of the beam to the distance from the heavier ball to the pivot

Answers

Answer:

L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).

Explanation:

In order for the system to be in equilibrium, the moment created by both masses about the pivot point must be equal:

m₁x = m₂y

where,

m₁ = 5 kg

m₂ = 2 kg

x = distance of 5 kg ball from pivot

y = distance of 2 kg ball from pivot

Therefore,

(5 kg)x = (2 kg)y

y = (5kg/2kg)x

y = 2.5 x

but,

x + y = L

where,

L = length of beam

using the value of y from the previous equation:

x + 2.5 x = L

3.5 x = L

L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).

A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track.
The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?

Answers

Answer: The trolley is moving at 2.12m/s

Explanation:

Given from the question that the track and force are horizontal and inline, we have that

F= ma

where F= force= 1.50 N

m= mass = 0.2kg

therefore Acceleration , a = F/ m= 1.50/0.2 =7.5 m/s^2

To find how fast the trolley  is going ie the Velocity, v

Having that

initial velocity at rest , u = 0,

acceleration a = 7.5 and

and distance, s = 30 cm =  30/100 = 0.30 m

we use motion equation that

v² = u² + 2 a s

v² = 0² + 2 x 7.5  x 0.30

v² = 4.5

v = [tex]\sqrt{4.5}[/tex]

v = 2.12 m/s

* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.

Answers

I would say food but like they take weight too

If you are riding your bike west to your friend’s house, and you ride the 1.25 miles in 5 minutes, what is your velocity, in miles per hour?

Answers

Answer:

velocity = 15 miles / hour

Explanation:

distance = 1.25 mile

time traveled = 5 min.

find velocity in miles / hour

solution:

use the formula: velocity = distance / time

velocity =     1.25 mile     x 60 min  

                     5 min            1 hour

velocity = 15 miles / hour

Assume you are in the car and the car is moving at a certain speed to
school. Are you at rest or in motion with respect to the school? With
respect to the car?​

Answers

You are at rest with respect to the car.
You are in motion with respect to the School.

PLEASE PROVIDE AN EXPLANATION

THANK YOU!

Answers

Answer:

(a) 0.993 s

(b) 14.0 N/m

(c) -3.02 m/s

(d) -6.01 m/s²

Explanation:

(a) The block's position can be modeled as a cosine wave:

x(t) = A cos(ωt)

where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.

At t = 0.200 s, x(t) = 15.0 cm.

15.0 cm = 50.0 cm cos((0.200 s) ω)

0.3 = cos((0.2 s) ω)

1.266 rad = (0.2 s) ω

ω = 6.33 rad/s

The period is:

T = (2π rad) (1 s / 6.33 rad)

T = 0.993

(b) For a spring-mass system, ω = √(k/m).  The mass of the block is 0.350 kg, so:

ω = √(k/m)

6.33 rad/s = √(k / 0.350 kg)

6.33 rad/s = √(k / 0.350 kg)

40.1 rad/s² = k / 0.350 kg

k = 14.0 N/m

(c) Energy is conserved:

EE₀ = EE + KE

½ kx₀² = ½ kx² + ½ mv²

kx₀² = kx² + mv²

(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²

v = -3.02 m/s

Alternatively, we can take the derivative of our position equation:

v(t) = -Aω sin(ωt)

v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))

v = -3.02 m/s

(d) Sum of forces on the block:

∑F = ma

-kx = ma

a = -kx / m

a = -(14.0 N/m) (0.15 m) / (0.350 kg)

a = -6.01 m/s²

Alternatively, we can take the derivative of our velocity equation:

a(t) = -Aω² cos(ωt)

a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))

a = -6.01 m/s²

Other Questions
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