Answer:
a) [tex] \Delta U = 7.5 kJ [/tex]
b) [tex]T_{f} = 900 K [/tex]
Explanation:
a) To find the change in its internal energy (U) we need to use the following equation:
[tex] \Delta U = W + Q [/tex]
Where:
W: is the work done on the system
Q: is the energy transferred into the system by heat = 12.5 kJ
Since we have an isobaric expansion, the work is:
[tex] W = - P\Delta V = - P(V_{f} - V_{i}) [/tex]
Where:
[tex]V_{f}[/tex]: is the final volume = 3.00 m³
[tex]V_{i}[/tex]: is the initial volume = 1.00 m³
P: is the pressure = 2.50 kPa
[tex] W = -P(V_{f} - V_{i}) = -2.5 \cdot 10^{3} Pa(3.00 m^{3} - 1.00 m^{3}) = -5.00 \cdot 10^{3} J [/tex]
Now, we can find the change in its internal energy:
[tex] \Delta U = W + Q = -5.00 \cdot 10^{3} J + 12.5 \cdot 10^{3} J = 7.5 \cdot 10^{3} J [/tex]
b) The final temperature can be found as follows:
[tex] \frac{V_{i}}{V_{f}} = \frac{T_{i}}{T_{f}} [/tex]
[tex] T_{f} = \frac{T_{i}*V_{f}}{V_{i}} = \frac{300 K*3.00 m^{3}}{1.00 m^{3}} = 900 K [/tex]
Hence, the final temperature is 900 K.
I hope it helps you!
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?
0.66 N
9.2 N
13 N
180 N
Answer is 9.2 N
Answer: Magnitude of the force exerted on the egg by the ground is 9.2N
Explanation:
Given the following :
Mass of egg (m) = 150g = 0.15kg
Height(h) from which egg is dropped = 3m
velocity of egg before hitting the ground (u) = 4.4m/s
Final velocity of egg (V) = 0
Time taken (t) = 0.072s
Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:
Momentum = mass × velocity
From Newton's second law:
Force = mass × change in Velocity with time ;
That is
F = m * ΔV / t
Inputting our values
F = 0.15 * (4.4 - 0) / 0.072
F = 0.15 × (4.4 / 0.072)
F = 0.15 × 61.11
F = 9.16N
F = 9.2N
Answer:
9.2 N
Explanation:
Just took practice quiz
Is it necessary to convert time in its S.I unit while solving acceleration and velocity numericals
Answer:
yes
Explanation:
In any calculation, we make sure we use all quantity in it simplest s.i unit
for better understandingfor a clearer work analysisHope this will help
write examples of adaptation in mangrove .?
what are the adaptation of rainforest.?
Answer:
example of adaptation in mangrove
Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.
adaptation of rainforest
Many animals have adapted to the unique conditions of the tropical rainforests.
hope this can help you
WILL GIVE BRANLIET PLS HELP!!!!! AT LEAST TAKE A LOOK!!!!! I REALLY COULD USE THE HELP!!! SHARE YO SMARTNESSS!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.
Answer:
λ = 6,108 10⁻⁷ m = 610.8 nm
λ = 5.513 10⁻⁷ m = 551.3 nm
Explanation:
Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression
d sin θ = m λ
where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference
In this exercise they give us several conditions
The first
the angle is 1.12º to the maximum m = 8
the distance between the slits d = 0.000250 m
of the initial equation
λ = d sin θ / m
λ = 0.000250 sin 1.12 / 8
λ = 6,108 10⁻⁷ m = 610.8 nm
The second
the distance from the slits to the screen is L = 302.0 cm = 3.020 m
the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5
in this case we use that the angle in the experiment is small
tan θ = y / L
tan θ = sin θ / cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
λ = d y / L m
we calculate
λ = 0.000250 0.0333 / (3,020 5)
λ = 5.513 10⁻⁷ m = 551.3 nm
A train moves at a constant velocity of 50 km/hHow far will it move in 0.5 h?
A. 10 km
B. 45 km
C.25 km
D. 20 km
Answer:
C
Explanation:
[tex]\dfrac{50km}{h}\cdot 0.5h= \\\\\\50km\cdot 0.5=25km[/tex]
Therefore, the correct answer is choice C. Hope this helps!
The correct answer is C.
It is C because .5 h is equal to 30 minutes. So half of 50 km is 25 km(Divided by 2)
What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?
Which type of wave tables faster through solids than it does through gases
A- electromagnet waves
B- reverse waves
C- longitudinal waves
D- periodic waves
Answer:peroidic waves
Explanation:
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
why do we generally hear a thunder when there is a Bolt of lightning
Please answer me fast
Answer:
Explanation:
When a lightning bolt travels from the cloud to the ground it actually opens up a little hole in the air, called a channel. Once then light is gone the air collapses back in and creates a sound wave that we hear as thunder. The reason we see lightning before we hear thunder is because light travels faster than sound!
Answer:
light travels faster than sound
Explanation:
A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity
Answer:
[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 10 seconds
To Find:
Final velocity (v)
Explanation:
[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]
What is the formula for calculating the efficiency of a heat engine? Answers:
an object experiences buoyant force of 15.9 n when immersed in a fluid of density 917 kg/m^3. what is the volume of the object?
Answer:
0.00176
Explanation:
Credit to the person above.
A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)
Options:
a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.
b) An arrow of magnitude 6.50 N points down the slope of the hill.
c) An arrow of magnitude 78.5 N points down the slope of the hill.
d) An arrow of magnitude 852.6 N points straight down.
Answer:
d) An arrow of magnitude 852.6 N points straight down.
Explanation:
The total mass of the two riders, m = 87.0 kg
The free body diagrams of the situation described are drawn and contained in the files attached to this solution.
Note that the weight of the toboggan will act directly downwards.
Therefore, the weight of the toboggan, W = mg
W = 87 * 9.8
W = 852.6 N
Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.
A football player kicks a ball at a 30o angle from the ground with an initial velocity of 15 m/s. What is the final velocity of the ball when it hits the ground?
Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
[tex]T=\dfrac{2u\sin\theta}{g}[/tex]
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
[tex]T=\dfrac{2\times15\sin30}{9.8}[/tex]
[tex]T=1.5\ sec[/tex]
We need to calculate the final velocity of the ball
Using equation of motion
[tex]v=u+gt[/tex]
[tex]v=15+9.8\times1.5[/tex]
[tex]v=29.7\ m/s[/tex]
Hence, The final velocity of the ball is 29.7 m/s.
Which object has the most gravitational potential energy?
O A. A 5 kg book at a height of 2 m
B. An 5 kg book at a height of 3 m
C. An 8 kg book at a height of 3 m
O D. A 8 kg book at a height of 2 m
SUBARU
Answer:
D
Explanation:
its the heaviest so i would assume its D
The vibrations of a string fixed at both ends are represented by y=16sin(πx/15 )cos(96πt). Where x and y are in cm and t in seconds. Then the phase difference between the points at x=13cm and x=16 in radian
Answer:
Explanation:
y = 16 sinπx/15 cos(96πt)
When t = 0
y = 16 sinπx/15
here πx/15 is phase of the point at x
if x = 13
Phase = 13π/15
if x = 16
Phase = 16π/15
Phase difference
= 16π/15 - 13π/15
= 3π/15
= π/5 radian .
what are laws of newton
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction
Explanation:
Answer:
Newton's Law of Motion
1- Every object persists in its state of rest or uniform motion - in a straight line unless it is compelled to change that state by forces impressed on it.
2- Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration.
3- For every action, there is an equal and opposite reaction.
Dominic made the table below to organize his notes about mixtures.
Properties of Mixtures
has no set composition
must have more than one state of matter
must have more than one substance
What mistake did Dominic make?
The title should read "Properties of Solutions" because some mixtures do not have all of the properties listed.
There is a definite recipe to make each mixture, so the composition of a mixture is set.
Although it is possible to have more than one state, it is also possible to have only one state.
A single substance can be used to make a mixture if the substance is composed of more than one element.
Answer:
Althought it us possible to have more then one state, it's also possible to have only one state of matter
Explanation:
You can make solutions of only one state if matter, for example , it two liquids can be mixed to form a solution they are called miscible.
Answer:
The correct answer is C.) Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
I just did the test on edge and got it right
help fast I want the correct answer please does spectral diffusion cause light to scatter
Answer: No
Explanation:
Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.
Scattering of light occurs when light passes through a rough path or a diffused surface.
But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.
Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.
Fluctuation in frequency does not mean diffraction of light or particles
Therefore, spectral diffusion does not cause light to scatter.
Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.
Answer:
6.67×10⁻⁸ cm³/g/s²
Explanation:
6.67×10⁻¹¹ Nm²/kg²
= 6.67×10⁻¹¹ (kg m/s²) m²/kg²
= 6.67×10⁻¹¹ m³/kg/s²
= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)
= 6.67×10⁻⁸ cm³/g/s²
During the warm-up and your scheduled physical activity, what was the weather like? Did the
temperature or conditions affect how much water you drank? How?
Answer: I did these exercises outdoors. The weather was hot and humid, so I drank about two cups of water during the workout. I also drank a cup of water about an hour before I started. Yes, the weather most definitely affected how much I drank.
Explanation: Edmentum
A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Answer:
0.109 m/s
Explanation:
The calculation of the volume flow rate of the water is shown below:-
Av = Velocity ([tex]\pi[/tex])(Radius)^2
= 0.87([tex]\pi[/tex])(0.2)^2
= 0.135258 m^3 / sec
= 0.109371429 m/s
or
= 0.109
So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come
what is acceleration???
Answer:
The rate at which velocity changes.
Explanation:
Acceleration is when motion changes, it is the rate at which velocity changes.
Answer:
Acceleration is defined as change in velocity per unit time.The increase in velocity per unit time is called acceleration.
Hope this is helpful for you.
1-D Kinematics
A car starts at a position of -153 m
and undergoes a displacement of
512 m. What is its final position?
(Unit = m)
Answer:
hope it helps you...........
A 0.675 kg mass is attached to a
spring of spring constant 42.4 N/m,
pulled, and released. What is the
frequency of the resulting
oscillation?
(Unit = Hz)
Answer:
1.26
Explanation:
f=1/(2pi) square root k/m
f=1/(2pi) square root 42.4/.675
f=1.26 I just did this question and found this right
If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.
Answer:
a. It would shrink
b. It would expand
Explanation:
a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out
b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out
a force of 50 n acts on abody of mass 5 kg .calculate the acceleration produced
Answer:
a = 10 m/s²
Explanation:
Given:
Force = F = 50 N
Mass = m = 5 kg
Required:
Acceleration = a = ?
Formula:
F = ma
Solution:
Rearranging the formula for a
=> a = F/m
=> a = 50/5
=> a = 10 m/s²
What are some of the major differences between the ancient Olympics and modern-day Olympics? List and describe at least two differences.
Answer:
-Women are now allowed to participate in the Olympics unlike before when it was only men allowed.
-Modern Olympic Games include many more events. There are more than 20 different sports and almost 300 events in the modern games, while the first Olympics only had running.
-The Olympics are held every two years. While the ancient Olympics were originally held every four years.
-Athletes from countries around the world participate in the modern Olympics unlike in the ancient Olympics where only athletes from ancient Greece competed.
Explanation:
Edmentum Plato answer (i already reworded most of it so you don't have to) <33
how does gravitational pull affect planets with the same mass but different distance from the sun?
Answer:
it just pulls them at the same time
Explanation: