Answer:
n R ln(Vf/Vi)
Explanation:
Entropy is the loss of energy available to do work. Entropy is a state function (i.e. it depends only upon the current state of the system and is independent of how that state was prepared).
Since the temperature change of the ideal is constant, hence this is an isothermal expansion of a perfect gas. The change in entropy (ΔS) for an isothermal expansion of a perfect gas is given by:
[tex]\Delta S=nR*ln(\frac{V_f}{V_i})[/tex]
Where n is the amount of gas molecules in mol and R is the gas constant in JK⁻¹mol⁻¹given by R = [tex]N_A[/tex]k, k is Boltzmann's constant in J K⁻¹ and Avogadro's constant [tex]N_A[/tex] in mol⁻¹. Vf is the final volume and Vi the initial volume.
How many flip-flop values are complemented in an 8-bit binary ripple counter to reach the next count value after: 0110111 and 01010110?
Answer:
- Four (4) flip-flop values will complemented
- one (1) flip-flop value will complemented
Explanation:
To find how many flip flop number of bits complemented, we just need to figure out what the next count in the sequence is and find how many bits have changed.
taking a look at the a) 00110111
we need to just 1 to the value,
so
00110111 + 0000001 = 00111000
So here, only the first four bits are complemented.
Therefore Four (4) flip-flop values will complemented
Next
b) 01010110
we also add 1 to the value
01010110 + 00000001 = 01010111
only the first bit is complemented.
Therefore one (1) flip-flop value will complemented
LOLOLOLOKOLLOLLOLOLOO STRIKER KID THINKS HES SO GOOD LLOLOLOLOLOLOLOLOLOLOOLOLOLOLOLOLOL
Answer:
UUUUUUMMMM do you mean in soccer ????????????????
Explanation:
Determine the size of memory needed for CD recording of a piece of music, which lasts for 26 minutes, is done with a 20-bit Analog-to-Digital Converter (ADC) in stereo (2 channels), at the rate of 44.1 kSa/s, with the compression factor 6 (allow 10% error margin).
Answer: the size of memory needed for the CD recording is 28.7 MB
Explanation:
so in the case of stereo, the bitrate is;
⇒ 26 × 60 × 44.1 × 10³ × 2
= 137592 × 10³
for 10 bit
⇒ 137592 × 10³ × 10
= 1375920 × 10³ bits
now divide by 8 (convert to bytes)
⇒ (1375920 × 10³) / 8
= 171,990,000 BYTE
divide by 1000 (convert to kilobytes)
= 171,990,000 / 1000
= 171,990 KILOBYTES
now Given that, the compression ratio is 6
so
171,990 / 6
= 28665 KB
we know that. 1 MB = 1000 KB
x MB = 28665 KB
x MB = 28665 / 1000
⇒ 28.665 MB ≈ 28.7 MB
Therefore the size of memory needed for the CD recording is 28.7 MB
In a compression test, a steel test specimen (modulus of elasticity 30 106 lb/in2 ) has a starting height 2.0 in and diameter 1.5 in. The metal yields (0.2% offset) at a load 140,000 lb. At a load of 260,000 lb, the height has been reduced to 1.6 in. Determine (a) yield strength and (b) fl ow curve parameters (strength coeffi cient and strain-hardening exponent). Assume that the cross-sectional area increases uniformly during the test.
Answer:
A) σ_y = 79096 lb/in² = 79.1 ksi
B) strain-hardening exponent = 0.102
(strength coefficient = 137838.78 lb/in²
Explanation:
A) Formula for volume is;
V = πd²h/4
We are given;
height 2.0 in and diameter 1.5 in
Thus;
V = (π × 1.5² × 2)/4
V = 3.53 in³
Area is;
A = πd²/4
A = (π × 1.5²)/4
A = 1.77 in²
Yield strength is gotten from the formula;
σ_y = Force/Area
We are given load = 140,000 lb
Thus;
σ_y = 140000/1.77
σ_y = 79096 lb/in²
B) We are given
modulus of elasticity: E = 30 × 10^(6) lb/in²
Formula for strain is;
ε = σ_y/E
ε = 79096/(30 × 10^(6))
ε = 0.00264
The metal yields (0.2% offset), thus;
strain offsets = 0.00264 + 0.002
strain offsets: ε1 = 0.00464
Thus;
(h_i - h_o)/h_o = 0.00464
(h_i/h_o) - 1 = 0.00464
(h_i/h_o) = 1.00464
h_i = h_o(1.00464)
h_o = 2 in
Thus; h_i = 2(1.00464) = 2.00928 in
Area = Volume/height = 3.53/2.00928 = 1.757 in²
True stress is;
σ = force/area = 140000/1.757
σ1 = 79681.27 lb/in²
At a load of 260,000 lb, the height has been reduced to 1.6 in. Thus;
Area = 3.53/1.6 = 2.206 in²
True stress is;
σ2 = 260000/2.206
σ2 = 117860.38 lb/in²
True strain;
ε2 = In(2/1.6)
ε2 = 0.223
From flow curve;
σ = kεⁿ
Thus;
σ1 = k(ε1)ⁿ
79681.27 = k(0.00464ⁿ) - - - (eq 1)
Also for σ2 = k(ε2)ⁿ;
117860.38 = k(0.223ⁿ) - - - - - (eq 2)
From eq 1,
k = 79681.27/0.00464ⁿ
Putting this for k in eq2 to get;
117860.38 = (0.223ⁿ) × 79681.27/0.00464ⁿ
117860.38/79681.27 = 0.223ⁿ/0.00464ⁿ
Solving for n, we have ≈ 0.102
Thus,K is;
k = 79681.27/0.00464^(0.102)
k = 137838.78 lb/in²
A person walks into a refrigerated warehouse with head uncovered. Model the head as a 25- cm diameter sphere at 35°C with a surface emissivity of 0.95. Heat is lost from the head to the surrounding air at 25°C by convection with a convection coefficient of ???????????????? ???????? ????????????????∙???????? , and by radiation to the surrounding black walls at 15°C. Determine the total rate of heat loss. StefanBoltzmann Constant, ???????? = ????????. ???????????????? × ????????????????−???????? ???????? ????????????????∙???????????????? . (10 points)
Answer:
Hello some parts of your question is missing below is the missing part
Convection coefficient = 11 w/m^2. °c
answer : 44.83 watts
Explanation:
Given data :
surface emissivity ( ε )= 0.95
head ( sphere) diameter( D ) = 0.25 m
Temperature of sphere( T ) = 35° C
Temperature of surrounding ( T∞ ) = 25°C
Temperature of surrounding surface ( Ts ) = 15°C
б = ( 5.67 * 10^-8 )
Determine the total rate of heat loss
First we calculate the surface area of the sphere
As = [tex]\pi D^{2}[/tex]
= [tex]\pi * 0.25^2[/tex] = 0.2 m^2
next we calculate heat loss due to radiation
Qrad = ε * б * As( [tex]T^{4} - T^{4} _{s}[/tex] ) ---- ( 1 )
where ;
ε = 0.95
б = ( 5.67 * 10^-8 )
As = 0.2 m^2
T = 35 + 273 = 308 k
Ts = 15 + 273 = 288 k
input values into equation 1
Qrad = 0.95 * ( 5.67 * 10^-8 ) * 0.2 ( (308)^4 - ( 288)^4 )
= 22.83 watts
Qrad ( heat loss due to radiation ) = 22.83 watts
calculate the heat loss due to convection
Qconv = h* As ( ΔT )
= 11*0.2 ( 35 -25 ) = 22 watts
Hence total rate of heat loss
= 22 + 22.83
= 44.83 watts
Support with three reasons the decision to use a plastic material for the package in the following
scenario.
Situation: A client has hired Jose, a materials engineer, to develop a package for an item he has begun
to market. The object needs to be mailed to customers within three days of being ordered.
Answer:
its durable. it's cheap. its recyclable
Explanation:
Plastic is made of lots of recycled materials that make it very useful and cheap.
The purpose of pasteurizing milk is to
A. Kill pathogens
B. Break down milk fat
C. Add vitamins and minerals
D. Prevent spoilage by sunlight
Plis can someone help me ?
Answer:
i think it c
Explanation:
Which of the following terms describes the path from an electrical source to a switch or plug?
transmitter
circuit breaker
raceway
breaker panel
Answer:
transmitter hope thus helped!
Explanation:
Raceway is the answer
"A raceway is an enclosed conduit that forms a physical pathway for electrical wiring."
An astronomer of 65 kg of mass hikes from the beach to the observatory atop the mountain in Mauna Kea, Hawaii (altitude of 4205 m). By how much (in newtons) does her weight change when she goes from sea level to the observatory?
Answer:
[tex]0.845\ \text{N}[/tex]
Explanation:
g = Acceleration due to gravity at sea level = [tex]9.81\ \text{m/s}^2[/tex]
R = Radius of Earth = 6371000 m
h = Altitude of observatory = 4205 m
Change in acceleration due to gravity due to change in altitude is given by
[tex]g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2[/tex]
Weight at sea level
[tex]W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}[/tex]
Weight at the given height
[tex]W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}[/tex]
Change in weight [tex]W_h-W=636.805-637.65=-0.845\ \text{N}[/tex]
Her weight reduces by [tex]0.845\ \text{N}[/tex].