Answer:
The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
Explanation:
Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?
Answer:
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field, E can be calculated by putting the values in the formula above:
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?
Answer:
Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2
E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2
= 0.0054 ÷ 0.000000152881
=35321.58999 N/C
6. A garden hose attached to a nozzle is used to fill a 15-gal bucket. The inner diameter of the hose is 1.5 cm, and it reduces to 0.8 cm at the nozzle exit. If it takes 50 s to fill the bucket with water (density = 1 kg/L), determine (a) the volume and mass flow rates of water through the hose, and (b) the average velocity of water at the nozzle exit.
Answer: 1.135 L/s; 1.35 kg/s, 22.57 m/s
Explanation:
Given
Volume of bucket [tex]V=15\ gal\approx 56.78\ L[/tex]
time to fill it [tex]t=50\ s[/tex]
Volume flow rate
[tex]\dot{V}=\dfrac{56.78}{50}=1.135\ L/s\approx 1.135\times 10^{-3}\ m^3/s[/tex]
The inner diameter of the hose [tex]D=1.5\ cm[/tex]
diameter of the nozzle exit [tex]d=0.8\ cm[/tex]
we can volume flow rate as
[tex]\Rightarrow \dot{V}=Av\quad \quad \text{v=average velocity through nozzle exit}\\\\\Rightarrow 1.135\times 10^{-3}=\frac{\pi }{4}d^2\times v\\\\\Rightarrow 1.135\times 10^{-3}=\frac{\pi }{4}(0.8\times 10^{-2})^2\times v\\\\\Rightarrow v=\dfrac{4\times 1.135\times 10^{-3}}{\pi \times 64\times 10^{-6}}=22.57\ m/s[/tex]
Mass flow rate
[tex]\Rightarrow \dot{m}=\rho \times \dot{V}\\\Rightarrow \dot{m}=1\ kg/L\times 1.135\ L/s=1.35\ kg/s[/tex]
When an
object is placed 15 cm from "
a concave mirror, a real image magnified
3 times is formed - Find
a) the focal length of the mirror
b) where the object must be placed to
give a virtual image 3 times the height
of the object
Answer:
Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,
1/f= 1/v + 1/u
-1/15 = 1/3u + 1/u
4/3u = -1/15
u= -20 cm
v =3u= 3×(-20)= -60 cm
So object is 20 cm and image is 60 cm in front of the mirror.
Explanation:
If the net force acting on an object is 0 N, you can be sure that the forces acting on the object are
A. balanced B.Unbalanced C. acting at the same direction
I think the answer would be A.
After all, it is 0 which is technically a dead center number meaning that the net should be balanced and still.
Hope this helps and have a nice day.
-R3TR0 Z3R0
Electromagnetic radiation is made up of wave components of electric and magnetic fields moving together. What form of energy is most closely associated with electromagnetic waves?
A.
light energy
B.
chemical energy
C.
electrical energy
D.
mechanical energy
Answer:
A) Because light is due to the electromagnetic fields (fields moving at the speed of light)
Note: Electrical energy is also used to describe the energy usage
in RLC circuits
A frictionless pendulum is made with a bob of mass 12.6 kg. The bob is held at height = 0.650 meter above the bottom of its trajectory, and then pushed
forward with an initial speed of 4.22 m/s. What amount of mechanical energy does the bob have when it reaches the bottom?
For the circuit in the previous part, the current flowing in the wire between the positive terminal of the battery and the resistor is ___________ the current flowing between the resistor and the negative terminal of the battery. For the circuit in the previous part, the current flowing in the wire between the positive terminal of the battery and the resistor is ___________ the current flowing between the resistor and the negative terminal of the battery. less than equal to greater than
Answer:
Explanation:
because it is godhood
The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000 MN/m2. What is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this steel without breaking the wire?
Answer:
The correct answer is "21195 N".
Explanation:
The given values are:
Tensile strength,
= 3000 MN/m²
Diameter,
= 3.0 mm
i.e.,
= 3×10⁻³ m
Now,
The maximum load will be:
= [tex]Tensile \ strength\times Area[/tex]
On substituting the values, we get
= [tex](3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)[/tex]
= [tex](3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)[/tex]
= [tex]21195 \ N[/tex]
A Sonometer wire of length
l vibrates at a
frequency of
350 Hz. when the length of the
wire is increased by 15cm, the
Wire Vibrates at 280 H₂ under
constant tension. Determine l
Answer:
-75 cm
Explanation:
At l ; F = 350 Hz
At l + 15 cm ; F = 280 Hz
I = 350
I + 15 = 280
280I = 350(I + 15)
280I = 350I + 5250
280I - 350I = 5250
-70I = 5250
I = - 75cm
The length is - 75 cm
An object swings in a horizontal circle, supported by a 1.8-m string. It swings at a speed of 3 m/s. What is the mass of the object given that the tension in the string is 90 N?
Answer:
Mass = 18 kg
Explanation:
Formula for force in centripetal motion is;
F = mv²/r
We have;
Mass; m.
Speed; v = 3 m/s
radius; r = 1.8 m
Force; F = 90 N
Thus;
Making m the subject;
m = Fr/v²
m = 90 × 1.8/3²
m = 18 kg
In the legend of William Tell, Tell is forced to shoot an apple from his son's head for failing to show respect to a high official. In our case, let's say Tell stands 8.7 meters from his son while shooting. The speed of the 144-g arrow just before it strikes the apple is 20.4 m/s, and at the time of impact it is traveling horizontally. If the arrow sticks in the apple and the arrow/apple combination strikes the ground 8 m behind the son's feet, how massive was the apple
Answer:
M = 0.31 kg
Explanation:
This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved
let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple
initial instant. Just before the crash
p₀ = m v₁ + M 0
instant fianl. Right after the crash
p_f = (m + M) v
p₀ = p_f
m v₁ = (m + M) v
v =[tex]\frac{m}{m+M} \ v_1[/tex] (1)
now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set
x = v t
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
when it reaches the ground, its height is y = 0 and as it comes out horizontally, [tex]v_{oy} = 0[/tex]
0 = h - ½ g t²
t² = 2h / g
For the solution of the exercise, the height of the child must be known, suppose that h = 1 m
t = [tex]\sqrt{ \frac{ 2 \ 1}{9.8} }[/tex]
t = 0.452 s
let's find the initial velocity
v = v / t
v = 8 / 0.452
v = 17.7 m / s
From equation 1
v = m / (m + M) v₁
m + M = [tex]m \ \frac{v_1}{v}[/tex]
M = m + m \ \frac{v_1}{v}
we calculate
M = 0.144 + 0.144 [tex]\frac{20.4}{17.7}[/tex]
M = 0.31 kg
What happens to solar radiation when it is absorbed
Answer:
Absorbed sunlight is balanced by heat radiated from Earth's surface and atmosphere. ... The atmosphere radiates heat equivalent to 59 percent of incoming sunlight; the surface radiates only 12 percent. In other words, most solar heating happens at the surface, while most radiative cooling happens in the atmosphere
1. An object with a mass of 5 kg is pushed by a force of 10 N. What is the object's acceleration?
Answer:2m/s^2
Explanation:
a=f/m
What Kind of clothing would you most likely wear at 15 latitude?
A. Fleece or jacket and long pants
B. cotton shirts, light jacket, long pants
C. parka, gloves,insulated pants, heavy boots
D. shorts , sandals and T-shirts
Answer:
I'd say A, but I'm not 100% what kind of latitude you're referring to
Answer:
D. shorts, sandals and T-shirts
Explanation:
The 15th parallel north is a circle of latitude that is 15 degrees north of the Earth's equatorial plane. It crosses Africa, Asia, the Indian Ocean, the Pacific Ocean, Central America, the Caribbean and Atlantic Ocean. All these areas are all warm and weather for wearing shorts, sandals and T-shirts!
(Hope this helped! If so please mark this answer as brainliest!)
Which of these would have the highest temperature?
ice
· Water
water vapor
Answer:
water vapor
Explanation:
did assignment on edge
HELP DUE 3 MINUTESSSSD
Answer:
Break down small pebbles and sediments, like sand
Break down large rocks like mountains
Explanation:
Which type of biological molecule would control cell activities?
A) Amino Acids.
C) Nucleic Acids.
B) Lipids.
D) Carbohydrates.
Answer:
C. Nucleic Acids.
Explanation:
Nucleic acids are thus uniquely capable of directing their own self-replication, allowing them to function as the fundamental informational molecules of the cell. The information carried by DNA and RNA directs the synthesis of specific proteins, which control most cellular activities.
Did some simple research, if that's fine and I hope this is correct as it says on the sites. Have a good one :)
Are we within earths Roche limit
Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest
Explanation:
Mitch holds a pumpkin at waist level. How can he add potential energy to the pumpkin?
Answer:
raise it as high as he can
Explanation:
If the object on the Moon were raised to a height of 30.0 m, what would be the potential energy? PE=mgh (g on the Moon is 1.62m/s)
A 45.0 kilogram boy is riding a 15.0-kilogram bicycle with a speed of 8.00 meters per second. What is the combined kinetic energy of the boy and the bicycle? A)480.J B)240.0J C)1920J D)1440J
Answer:
1920Joules
Explanation:
The formula for calculating the kinetic energy of a body is expressed as;
KE = 1/2 mv²
m isthe mass
V is the speed
For the two masses, the combined KE is expressed as;
KE = 1/2(m1+m2)v²
KE = 1/2(45+15)(8)²
KE = 1/2 * 60 * 64
KE = 30 * 64
KE = 1920J
Hence the combined kinetic energy of the boy and the bicycle is 1920Joules
The combined kinetic energy of the boy and the bicycle is of 1920 J.
Given data:
The mass of boy is, m = 45.0 kg.
The mass of bicycle is, M = 15.0 kg.
The speed of bicycle is, v = 8.00 m/s.
The kinetic energy of an object is defined as the energy possessed by an object by virtue of motion of object. The combined kinetic energy of the boy-bicycle system is given as,
[tex]KE = \dfrac{1}{2}(m+M)v^{2}[/tex]
Solve by substituting the values as,
[tex]KE = \dfrac{1}{2}(45+15) \times 8^{2}\\\\KE = 1920 \;\rm J[/tex]
Thus, we can conclude that the combined kinetic energy of the boy and the bicycle is of 1920 J.
Learn more about the concept of kinetic energy here:
https://brainly.com/question/12669551
5) In the last part of step 7 of the procedure, you measured the resistance of the flashlight when it had no current passing through it. The resistance of the flashlight is different, however, when current is passing through it. Explain how your measurement of the resistance of the variable resistor obtained in part 7 is a valid approximation of the resistance of the flashlight when it had current passing through it. Is the resistance higher when the flashlight is on or off
Answer:
Following are the responses to this question:
Explanation:
The small current passes thru the capacitor of the strain gauge and the current is generated throughout the resistor. For the very first time, in contrast to what we calculate, its resistance of the multimeter is quite high and therefore the small stream flowing through the bulb would have very little impact on the measure. Thus, as the current flows through the flashbulb, this same calculation is of excellent price, its material is heated and resistance varies with increase. Therefore, when the bulb will be on, sensitivity is greater.
What do Ice core samples with lower ratios of O-18 to O-16 isotopes tell scientist about past climates
Answer:
Ocean-floor sediments can also be used to determine past climate. ... Ice cores contain more 16O than ocean water, so ice cores have a lower 18O/ 16O ratio than ocean water or ocean-floor sediments. Water containing the lighter isotope 16O evaporates more readily than 18O in the warmer subtropical regions
Explanation:
a force of 17 acts on a block of mass 4kg the forces of friction opposing the motion is 5n . the acceleration of the block is
The force applied on the block of mass 4 kg is 17 N and a frictional force of 5 N is opposing this force. Hence, the net force is 8N and the acceleration is 2 m/s².
What is net force?Force is a vector quantity thus, characterized by a magnitude and direction. If two same or different forces are acting on a body from the same direction, the net force will be the sum of the magnitude of the two forces.
If two forces are acting from opposite directions, they will cancel each other and the net force is the substracted value of their magnitudes.
Given that, mass of the block = 4 kg
force applied on the block = 17 N
frictional force = 5 N
Net force = 17 - 5 = 8 N.
Force = mass × acceleration. (by Newton's second law of motion)
acceleration = force/ mass
= 8 N / 4 Kg = 2 m/s²
Therefore, the acceleration of the block is 2 m/s².
To find more on net force, refer here:
https://brainly.com/question/18031889
#SPJ2
1. A basket coffee filter (see below) is very light and has a large drag coefficient. It is possible to stack several filters together so they have the same drag coefficient as a single filter. Suppose you tried dropping one filter from a ladder, then tried dropping two stacked filters from the same height, then 3 and so on. For each try you measure the time taken for the filters to fall to the floor. How would you expect the time for the filters to fall to compare to the number of filters
Answer:
he times are getting closer as we use each filter, in the expression n would be the number of filters
t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]
Explanation:
For this exercise let's use the kinematics relations
y = y₀ + v₀ t - ½ g t²
When the first filter reaches the ground, its height is y = 0, as they release its initial velocity is zero
for the 1st filter
0 = y₀ - ½ g t²
t² = 2y₀ / g
t = [tex]\sqrt{ \frac{2y_o}{g} }[/tex]
when we release the second filter upon arrival it has a height y = h where h is the height of each filter
h = y₀ - ½ g t²
t = [tex]\sqrt{ \frac{2(y_o- h)}{g} }[/tex]
when we release the third filter it reaches y = 2h
2h = y₀ - ½ g t²
t = [tex]\sqrt{ \frac{2(y_o -2h)}{g} }[/tex]
we can write the terms of this succession
(n-1) = y₀ - [tex]\frac{1}{2}[/tex] g t²
t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]
therefore we see that the times are getting closer as we use each filter, in the expression n would be the number of filters
6. As distance increases, gravitational force *
(10 Points)
increases
decreases
can someone help me with this
Answer:
8/3 m/s² or 2.67m/s²
Explanation:
According to the second Law of Newton, the acceleration of an object is directly related to the net force and inversely related to its mass. This can be translated in a mathematical equation:
a= F/m
a=4000N/1500kg
a=8/3m/s²
or in decimal form
2.67m/s²
can someone please help me I am so behind I neee to catch up but I need it to be correct both of them
Answer:
1.B, 2.A
Explanation:
g A rigid air cylinder with a volume of 100 cm3 is punctured with a hole having a crosssectional area of 0.3 mm2 . The original pressure and temperature of the air inside the cylinder are 800 kPa and 35 C. As the air leaves the hole in the cylinder, it reaches a pressure of 100 kPa and a temperature of 5 C. The velocity of the air as it escapes through the hole is 100 m/s. Calculate the original mass of air inside the tank and the mass in the tank 5 seconds after it is punctured, assuming the exit conditions of the air remain independent of time g
Solution :
The volume of the rigid cylinder = [tex]$100 \ cm^3 = 100 \times 10^{-6} \ m^3$[/tex]
Initial pressure inside the cylinder, [tex]$P_i = 800 \ kPa$[/tex]
Initial temperature inside the cylinder, [tex]$T_i = 35^\circ C= 308 \ K$[/tex]
Final temperature inside the cylinder, [tex]$T_f = 5^\circ C= 278 \ K$[/tex]
Final pressure inside the cylinder, [tex]$P_f = 100 \ kPa$[/tex]
Area of the hole, A = [tex]$0.3 \ mm^2 = 3 \times 10^{-7} \ m^2$[/tex]
Velocity of the air through the hole, V = 100 m/s
The final pressure and the temperature inside the cylinder will be the condition same as the ambient conditions.
At initial state, from the equation of state,
PV = mRT, where R = 287 J/kg-K for air
[tex]$800 \times 10^3 \times100 \times10^{-6} = m_1 \times 287 \times 308$[/tex]
∴ [tex]$m_1=9.1 \times 10^{-4} \ kg$[/tex]
Since the exit condition does not change with time, we have ,
At ambient condition, [tex]$P_f = 100 \kPa$[/tex] and [tex]$T_f= 278 \ K$[/tex].
Therefore, we can find the density of the air
[tex]$P=\rho R T$[/tex]
[tex]$\rho = \frac{P}{RT}$[/tex]
[tex]$=\frac{100 \times 10^3}{287 \times 278}$[/tex]
[tex]$= 1.25 \ kg/m^3$[/tex]
Mass flow rate of air from the cylinder = [tex]$\dot m$[/tex]
[tex]$\dot m$[/tex] can be written as [tex]$\dot m$[/tex] [tex]$=\rho_{f} \times A \times v$[/tex]
[tex]$\dot m$[/tex] = [tex]$1.25 \times 3 \times 10^{-7} \times 100$[/tex]
[tex]$\dot m$[/tex] = [tex]$3.75 \times 10^{-5}$[/tex] kg/s
Mass escaped from the cylinder in 5 seconds
[tex]$m=3.75 \times 10^{-5} \times 5$[/tex]
[tex]$= 1.875 \times 10^{-4} \ kg$[/tex]
Mass of air remaining in the cylinder after 5 seconds :
[tex]$m_2 = m_1 - m$[/tex]
[tex]$m_2 = 9.1 \times 10^{-4} - 1.875 \times 10^{-4}$[/tex]
[tex]$m_2 = 7.225 \times 10^{-4} \ kg$[/tex]
= 0.7225 grams
A student picks up two spheres that are the same size. One is made of steel and the other is made of aluminum. The student notices that the steel sphere feels much heavier than the aluminum sphere. He then holds one sphere in each hand at eye level and lets go of them at the same time. They fall to the floor. Which ball, if any, will hit the ground first and for what reason
Answer:
They will fall at the same time. This is because gravity accelerates all objects at the same speed, Earth's gravity being approximately 9.8m/s²
They'll both fall at the same time. This is because gravity accelerates everything at the same rate, with Earth's gravity being approximately 9.8 m/s2.
What is gravity with some instances?The energy that holds the gases inside the sun together. the force that causes a ball to fall after being thrown into the air the force that causes a car to coast downhill even when the gas pedal is not depressed the force that causes a glass to shatterGravity, also known as gravitation, affects all material objects in the universe. Gravity attracts any two objects or particles with nonzero mass toward one another. Gravity affects everything from subatomic particles to galaxy clusters. Gravity is the attraction force between two objects. It's what causes things to fall and keeps us from floating away into space. Gravity is a fundamental natural force.To learn more about gravity, refer to:
https://brainly.com/question/16275567
#SPJ2
What is heredity and how does it influence physical fitness?