An atom has 13 protons in its nucleus and 11 electrons revovling the nucleus. The charge on this atom:

a.
The atom has no charge .

b.
+2

c.
-2

d.
+1

Answers

Answer 1
The atoms has no charge so A would be the answer.

Related Questions

A 100 kilogram person acquires a velocity of 15 meters per second down a ski slope. What is the skier's kinetic energy? A) 11,250 B)22,5000 C)115 Joules D)3,500Joules​

Answers

Answer:

B.22,5000

Explanation:

SANA MAKATULONG

What causes electricity?
A the nucleus of an atom
B moving neutrons
C Moving protons
D moving electrons

Answers

Answer is D! It is the moving electrons

1. An object with a mass of 5 kg is pushed by a force of 10 N. What is the object's acceleration?

Answers

i believe the answer is 2ms^-2

Answer:2m/s^2

Explanation:

a=f/m

HELP WILL GIVE BRAINLIEST IF CORRECT

Answers

it’s B i literally jus learned this

Answer:closed

Explanation:

Closed is basic the mas but not all of the energy

Wind is formed when hot air rises and cool air sinks. This process is called __________

conduction
insulation
radiation
convection
plsssssssss answer this correct i put in 12 points and i will give you brainliest if you answer correct

Answers

Answer:

conduction is the correct answer

6. A garden hose attached to a nozzle is used to fill a 15-gal bucket. The inner diameter of the hose is 1.5 cm, and it reduces to 0.8 cm at the nozzle exit. If it takes 50 s to fill the bucket with water (density = 1 kg/L), determine (a) the volume and mass flow rates of water through the hose, and (b) the average velocity of water at the nozzle exit.

Answers

Answer: 1.135 L/s; 1.35 kg/s, 22.57 m/s

Explanation:

Given

Volume of bucket [tex]V=15\ gal\approx 56.78\ L[/tex]

time to fill it [tex]t=50\ s[/tex]

Volume flow rate

[tex]\dot{V}=\dfrac{56.78}{50}=1.135\ L/s\approx 1.135\times 10^{-3}\ m^3/s[/tex]

The inner diameter of the hose [tex]D=1.5\ cm[/tex]

diameter of the nozzle exit [tex]d=0.8\ cm[/tex]

we can volume flow rate as

[tex]\Rightarrow \dot{V}=Av\quad \quad \text{v=average velocity through nozzle exit}\\\\\Rightarrow 1.135\times 10^{-3}=\frac{\pi }{4}d^2\times v\\\\\Rightarrow 1.135\times 10^{-3}=\frac{\pi }{4}(0.8\times 10^{-2})^2\times v\\\\\Rightarrow v=\dfrac{4\times 1.135\times 10^{-3}}{\pi \times 64\times 10^{-6}}=22.57\ m/s[/tex]

Mass flow rate

[tex]\Rightarrow \dot{m}=\rho \times \dot{V}\\\Rightarrow \dot{m}=1\ kg/L\times 1.135\ L/s=1.35\ kg/s[/tex]

1. A basket coffee filter (see below) is very light and has a large drag coefficient. It is possible to stack several filters together so they have the same drag coefficient as a single filter. Suppose you tried dropping one filter from a ladder, then tried dropping two stacked filters from the same height, then 3 and so on. For each try you measure the time taken for the filters to fall to the floor. How would you expect the time for the filters to fall to compare to the number of filters

Answers

Answer:

he times are getting closer as we use each filter, in the expression n would be the number of filters  

t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]

Explanation:

For this exercise let's use the kinematics relations

          y = y₀ + v₀ t - ½ g t²

When the first filter reaches the ground, its height is y = 0, as they release its initial velocity is zero

for the 1st filter

          0 = y₀ - ½ g t²

          t² = 2y₀ / g

          t = [tex]\sqrt{ \frac{2y_o}{g} }[/tex]

when we release the second filter upon arrival it has a height y = h where h is the height of each filter

         h = y₀ - ½ g t²

         t = [tex]\sqrt{ \frac{2(y_o- h)}{g} }[/tex]

when we release the third filter it reaches y = 2h

         2h = y₀ - ½ g t²

          t = [tex]\sqrt{ \frac{2(y_o -2h)}{g} }[/tex]

we can write the terms of this succession

          (n-1) = y₀ - [tex]\frac{1}{2}[/tex] g t²

           t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]

therefore we see that the times are getting closer as we use each filter, in the expression n would be the number of filters

           

A 45.0 kilogram boy is riding a 15.0-kilogram bicycle with a speed of 8.00 meters per second. What is the combined kinetic energy of the boy and the bicycle? A)480.J B)240.0J C)1920J D)1440J​

Answers

Answer:

1920Joules

Explanation:

The formula for calculating the kinetic energy of a body is expressed as;

KE = 1/2 mv²

m isthe mass

V is the speed

For the two masses, the combined KE is expressed as;

KE  = 1/2(m1+m2)v²

KE = 1/2(45+15)(8)²

KE  = 1/2 * 60 * 64

KE  = 30 * 64

KE  = 1920J

Hence the combined kinetic energy of the boy and the bicycle is 1920Joules

The combined kinetic energy of the boy and the bicycle is of 1920 J.

Given data:

The mass of boy is, m = 45.0 kg.

The mass of bicycle is, M = 15.0 kg.

The speed of bicycle is, v = 8.00 m/s.

The kinetic energy of an object is defined as the energy possessed by an object by virtue of motion of object. The combined kinetic energy of the boy-bicycle system is given as,

[tex]KE = \dfrac{1}{2}(m+M)v^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2}(45+15) \times 8^{2}\\\\KE = 1920 \;\rm J[/tex]

Thus, we can conclude that the combined kinetic energy of the boy and the bicycle is of 1920 J.

Learn more about the concept of kinetic energy here:

https://brainly.com/question/12669551

can someone please help me I am so behind I neee to catch up but I need it to be correct both of them

Answers

Answer:

1.B, 2.A

Explanation:

What happens to solar radiation when it is absorbed

Answers

Answer:

Absorbed sunlight is balanced by heat radiated from Earth's surface and atmosphere. ... The atmosphere radiates heat equivalent to 59 percent of incoming sunlight; the surface radiates only 12 percent. In other words, most solar heating happens at the surface, while most radiative cooling happens in the atmosphere

Which of these would have the highest temperature?
ice
· Water
water vapor

Answers

Answer:

water vapor

Explanation:

did assignment on edge

which data set has the largest range?
A. 5,6,75
B. 102,105,103,110
C. 14,19,18,35,32,38,40
D. 1,9,2,5,4,19,2,4,3

Answers

Answer: A is correct because

A.70 as a range

B. 8 as an range

C.26 as an range

D.18 as an range

A Sonometer wire of length
l vibrates at a
frequency of
350 Hz. when the length of the
wire is increased by 15cm, the
Wire Vibrates at 280 H₂ under
constant tension. Determine l

Answers

Answer:

-75 cm

Explanation:

At l ; F = 350 Hz

At l + 15 cm ; F = 280 Hz

I = 350

I + 15 = 280

280I = 350(I + 15)

280I = 350I + 5250

280I - 350I = 5250

-70I = 5250

I = - 75cm

The length is - 75 cm

HELP DUE 3 MINUTESSSSD

Answers

Answer:

Break down small pebbles and sediments, like sand

Break down large rocks like mountains

Explanation:

6. As distance increases, gravitational force *
(10 Points)
increases
decreases

Answers

It decreasessssssssss

The velocity of an object is +47 m/s at 3.0 seconds and is +65 m/s at 12.0 seconds. Calculate the acceleration of the object

Answers

Answer:

[tex]\boxed{\text{\sf \Large 2.0 m/s^2 $}}[/tex]

Explanation:

Use acceleration formula

[tex]\displaystyle \text{$ \sf acceleration=\frac{change \ in\ velocity}{change \ in \ time} $}[/tex]

[tex]\displaystyle a=\frac{65-47}{12.0-3.0} =2.0[/tex]

An object swings in a horizontal circle, supported by a 1.8-m string. It swings at a speed of 3 m/s. What is the mass of the object given that the tension in the string is 90 N?

Answers

Answer:

Mass = 18 kg

Explanation:

Formula for force in centripetal motion is;

F = mv²/r

We have;

Mass; m.

Speed; v = 3 m/s

radius; r = 1.8 m

Force; F = 90 N

Thus;

Making m the subject;

m = Fr/v²

m = 90 × 1.8/3²

m = 18 kg

Someone help me I will mark brainless it’s 2 questions .

Answers

Answer:

1.C,2.A

Explanation:

The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000 MN/m2. What is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this steel without breaking the wire?

Answers

Answer:

The correct answer is "21195 N".

Explanation:

The given values are:

Tensile strength,

= 3000 MN/m²

Diameter,

= 3.0 mm

i.e.,

= 3×10⁻³ m

Now,

The maximum load will be:

=  [tex]Tensile \ strength\times Area[/tex]

On substituting the values, we get

=  [tex](3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)[/tex]

=  [tex](3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)[/tex]

=  [tex]21195 \ N[/tex]

5) In the last part of step 7 of the procedure, you measured the resistance of the flashlight when it had no current passing through it. The resistance of the flashlight is different, however, when current is passing through it. Explain how your measurement of the resistance of the variable resistor obtained in part 7 is a valid approximation of the resistance of the flashlight when it had current passing through it. Is the resistance higher when the flashlight is on or off

Answers

Answer:

Following are the responses to this question:

Explanation:

The small current passes thru the capacitor of the strain gauge and the current is generated throughout the resistor. For the very first time,  in contrast to what we calculate, its resistance of the multimeter is quite high and therefore the small stream flowing through the bulb would have very little impact on the measure. Thus, as the current flows through the flashbulb, this same calculation is of excellent price, its material is heated and resistance varies with increase. Therefore, when the bulb will be on, sensitivity is greater.

When an
object is placed 15 cm from "
a concave mirror, a real image magnified
3 times is formed - Find
a) the focal length of the mirror
b) where the object must be placed to
give a virtual image 3 times the height
of the object

Answers

Answer:

Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,

1/f= 1/v + 1/u

-1/15 = 1/3u + 1/u

4/3u = -1/15

u= -20 cm

v =3u= 3×(-20)= -60 cm

So object is 20 cm and image is 60 cm in front of the mirror.

Explanation:

If the net force acting on an object is 0 N, you can be sure that the forces acting on the object are
A. balanced B.Unbalanced C. acting at the same direction

Answers

I think the answer would be A.

After all, it is 0 which is technically a dead center number meaning that the net should be balanced and still.

Hope this helps and have a nice day.

-R3TR0 Z3R0

a force of 17 acts on a block of mass 4kg the forces of friction opposing the motion is 5n . the acceleration of the block is​

Answers

Fk = μK N

N = m a

N = 4 × a

N = 4a

Fk = μK N

17 = 5 × 4a

17 = 20 a

a = ¹⁷/₂₀ = 0.85 m/s²

The force applied on the block of  mass 4 kg is 17 N and a frictional force of 5 N is opposing this force. Hence, the net force is 8N and the acceleration is 2 m/s².

What is net force?

Force is a vector quantity thus, characterized by a magnitude and direction.   If two same or different forces are acting on a body from the same direction, the net force will be the sum of the magnitude of the two forces.

If two forces are acting from opposite directions, they will cancel each other and the net force is the substracted value of their magnitudes.

Given that, mass of the block = 4 kg

force applied on the block = 17 N

frictional force  = 5 N

Net force =  17 - 5 = 8 N.

Force = mass × acceleration. (by Newton's second law of motion)

acceleration = force/ mass

                     = 8 N / 4 Kg = 2 m/s²

Therefore, the acceleration of the block is 2 m/s².

To find more on net force, refer here:

https://brainly.com/question/18031889

#SPJ2

can someone help me with this

Answers

Answer:

8/3 m/s² or 2.67m/s²

Explanation:

According to the second Law of Newton, the acceleration of an object is directly related to the net force and inversely related to its mass. This can be translated in a mathematical equation:

a= F/m

a=4000N/1500kg

a=8/3m/s²

or in decimal form

2.67m/s²

Mitch holds a pumpkin at waist level. How can he add potential energy to the pumpkin?

Answers

Answer:

raise it as high as he can

Explanation:

There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of this cliff. What is the velocity of the boulder just before it strikes the ground?

Answers

Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

[tex]2gh = V_{f}^2 - V_{i}^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

[tex](2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\[/tex]

Vf = 69.61 m/s

If the object on the Moon were raised to a height of 30.0 m, what would be the potential energy? PE=mgh (g on the Moon is 1.62m/s)

Answers

PE= mgh
m=mass =?
g=1.62
h= height = 30

PE= m(1.62)(30)
PE = 48.6m Joules

( if you left out the mass by mistake just multiply it by 48.6)

In the legend of William Tell, Tell is forced to shoot an apple from his son's head for failing to show respect to a high official. In our case, let's say Tell stands 8.7 meters from his son while shooting. The speed of the 144-g arrow just before it strikes the apple is 20.4 m/s, and at the time of impact it is traveling horizontally. If the arrow sticks in the apple and the arrow/apple combination strikes the ground 8 m behind the son's feet, how massive was the apple

Answers

Answer:

M = 0.31 kg

Explanation:

This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved

let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple

initial instant. Just before the crash

          p₀ = m v₁ + M 0

instant fianl. Right after the crash

          p_f = (m + M) v

          p₀ = p_f

          m v₁ = (m + M) v

          v =[tex]\frac{m}{m+M} \ v_1[/tex]                          (1)

now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set

          x = v t

          y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when it reaches the ground, its height is y = 0 and as it comes out horizontally, [tex]v_{oy} = 0[/tex]

          0 = h - ½ g t²

          t² = 2h / g

     

For the solution of the exercise, the height of the child must be known, suppose that h = 1 m

            t = [tex]\sqrt{ \frac{ 2 \ 1}{9.8} }[/tex]

            t = 0.452 s

let's find the initial velocity

             v = v / t

             v = 8 / 0.452

             v = 17.7 m / s

From equation 1

              v = m / (m + M) v₁

              m + M = [tex]m \ \frac{v_1}{v}[/tex]

              M = m + m \  \frac{v_1}{v}

we calculate

              M = 0.144 + 0.144  [tex]\frac{20.4}{17.7}[/tex]

              M = 0.31 kg

What do Ice core samples with lower ratios of O-18 to O-16 isotopes tell scientist about past climates

Answers

Answer:

Ocean-floor sediments can also be used to determine past climate. ... Ice cores contain more 16O than ocean water, so ice cores have a lower 18O/ 16O ratio than ocean water or ocean-floor sediments. Water containing the lighter isotope 16O evaporates more readily than 18O in the warmer subtropical regions

Explanation:

Are we within earths Roche limit

Answers

Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest

Explanation:

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