An artist mixes yellow and blue paint to make the perfect shade of green. She uses 2 ounces of blue paint for every 7 ounces of yellow.If the mixing container only holds 40 ounces of paint, what is the most green paint the artist can make, and what recipe should she use? 20 points please help me

Answer:

5.38516480713

Step-by-step explanation:

a^2+b^2=c^2

5^2+2^2=c^2

25+4=c^2

c^2=square root of 29

c=5.38516480713

Answer:

is that paper or did you write on the screen?

Answer:

2 and 2/5

Step-by-step explanation:

Trust me on this, also can I have brainlest please? Hope you do well!

2 and two fifths i took the test 6 years ago

Answer:

The company is expected the company will receive

Answer:

[tex]t=\dfrac{9\pm 3}{6}[/tex]

[tex]1\ \text{hour}[/tex]

[tex]2\ \text{hour}[/tex]

Step-by-step explanation:

s = Speed of Emile = 6 miles/hour

d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]

Time taken to find the minimum and maximum time Emile ran for is

[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]

The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]

The time taken is

[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]

The minimum number of hours Emile runs is 1 hour.

[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]

The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].

Answer:

|6x – 9| = 3

1 Hour

2 Hours

Step-by-step explanation:

The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.

Answer:

Her brother is 10 years old

Step-by-step explanation:

14 ÷ 2 = 7

7 + 3 = 10

The answer is 10

Answer:

6543

Step-by-step explanation:

Not much to explain lol

Here,

Odd numbers are 3 and 5.

The largest odd number =6543

Answer:

a) $141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

b) $244.4

Step-by-step explanation:

The phone company Splint has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 330 minutes, the monthly cost will be $141.5. If the customer uses 890 minutes, the monthly cost will be $337.5.

Required:

a. Find an equation in the form y= mx +b, where x is the number of monthly minutes used and y is the total monthly of the Splint plan.

If a customer uses 330 minutes, the monthly cost will be $141.5.

y = mx + b

$141.5 = 330m + b

If the customer uses 890 minutes, the monthly cost will be $337.5.

$337.5 = 890m + b

Combining the equations

$141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

b. Use your equation to find the total monthly cost if 624 minutes are used

Combining the equations

$141.5 = 330m + b...... Equation 1

$337.5 = 890m + b..... Equation 2

We Subtract Equation 2 from 1

-196 = -560m

m = -196/-560

m = 0.35

$337.5 = 890m + b..... Equation 2

$337.5 = 890 × 0.35 + b

$337.5 - 311.5 = b

b = 26

When x = 624

y = 624× m + b

m = 0.35 , b = 26

y = 624 × 0.35 + 26

y = 218.4 + 26

y = $ 244.4

Answer:

5/9 x 3/10 = 15/90 as simplified as 1/6 in fraction form.

5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.

We have,

To multiply fractions, we multiply the numerators together and the denominators together.

The resulting fraction is then simplified to its simplest form.

Let's multiply 5/9 by 3/10:

(5/9) x (3/10) = (5 x 3) / (9 x 10) = 15/90

To simplify the fraction 15/90, we can divide both the numerator and denominator by their greatest common divisor, which is 15:

15/90 = (15 ÷ 15) / (90 ÷ 15) = 1/6

Therefore,

5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.

Learn more about fractions here:

https://brainly.com/question/24370499

#SPJ6

Answer:

No it's not unusual

Step-by-step explanation:

That's an unusual definition for unusual if you don't mind me saying so.

There are 4 sixes in a standard deck of cards without the jokers. There are 52 cards in that deck

4/52 = 0.077

This is greater than 0.05 so it is not unusual.

Let's add the 2 jokers and see what happens.

4/54 = 0.074

That's still not going to get the situation defined as unusual.

Answer:

Ax=6

Y=12

Therefore a=6, x=1, y=12

Answer:

{([tex]\frac{6}{a}[/tex],12)}

Step-by-step explanation:

[tex]\left \{ {{ax+y=18} \atop {4ax-y=12}} \right.[/tex]

[tex]5ax = 30[/tex]

[tex]x = \frac{6}{a}[/tex]

[tex]a(\frac{6}{a}) + y = 18[/tex]

6 + y =18→y=12

[tex]4a(\frac{6}{a}) - 12 = 12[/tex]

6 - 12 = 12 → 12 = 12 true  x=[tex]\frac{6}{a}[/tex]  y=12

Answer:

I mean it would just be q(x) = 0

Step-by-step explanation:

Answer: q=0

Step-by-step explanation: Let's solve for q.

qx=2−2

Step 1: Divide both sides by x.

qx

x

=

0

x

q=0

Answer:

q=0

Answer:

2

4/.5 = 2

Therefore, your answer is 2, or A. Hope this helped!

Answer:

the answer is B) 8

Step-by-step explanation:

hope this helped sorry if it didn't and if it's wrong sorry for that also.

Answer:

Not a function

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

1+1=2

Answer:

$12.55

Step-by-step explanation:

25-6.75=18.25

18.25-3.70=14.55

14.55-2=12.55

Miguel has $12.55 left

Answer:

[tex] - \bigg(3a - \frac{5}{2} b) \bigg)^{2} [/tex]

Step-by-step explanation:

[tex]15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2} [/tex]

Answer:

20.77

Step-by-step explanation:

Answer:

20.77

Step-by-step explanation:

Simplify  16.9+ 1.7  to  18.6

18.6 +0.17+2.0

Simplify  18.6+0.17 to  18.77

18.77+2.0

Simplify.

ANddddd the answer is

20.77

x = 10.4 (1dp)

Step-by-step explanation:

Using Pythagoras' theorem, a^2 = b^2 + c^2 where a is the hypotinues; b and c is the two sides

a^2 = b^2 + c^2

12^2 = 6^2 + x^2

144 = 36 + x^2

x^2 = 144 - 36

x^2 = 108

x = _/108

x = 10.4 (1dp)

Answer:

0.75

Step-by-step explanation:

To find the slope of the graph, you have to find the rise and the run by any two points on the graph. (I'm going to calculate using the two blue dots as shown in the picture)

[tex]\frac{rise}{run}[/tex] = [tex]\frac{(-2)-(-5)}{4-0}[/tex]

           = [tex]\frac{-2+5}{4}[/tex]

           = [tex]\frac{3}{4}[/tex]

           = 0.75

Step-by-step explanation:

Step one:

We are told that the store offers off 10% of sales, this means that the store is offsetting the price down by 10% hence a price reduction.

Moreso, a coupon is a voucher entitling the holder to a discount off a particular product. the coupon is 40%, hence this is equal to a discount, that is price reduction by 40%.

Step two:

Say the price of an item is $100, a coupon if 40% will entitle the holder to only pay $60, that is

=40/100*100

=0.4*100

=$40 off

= 100-40

=$60

The total percent of reduction 10+40= 50%

This is equal to a discount on the sales price

Answer:

Step-by-step explanation:

surface area = 2πrh + 2πr²

where r = 7 m radius

           h = 2 m

plugin values into the formula

surface area = 2πrh + 2πr²

                     = 2π (7) 2  +  2π (7)²

                     = 87.965  +  307.867

                     = 395.841 m²

Answer:

395.841 m²

Step-by-step explanation:

surface area = 2πrh + 2πr² and r = 7 m radius

h = 2 m

Plugin

 2π (7) 2  +  2π (7)²

multiply into itself than add

87.965  +  307.867

add

395.841 m²

Therefore your answer would be 395.841 m²

Answer:

75 semanas

Step-by-step explanation:

15,000 = 200s

15,000/200 = s

75 = s

Answer:

$11.83

Step-by-step explanation:

1 gallon = 3.785 litres

0.5(1/2gallon) = x liters

x = 0.5 × 3.785 liters

x = 1.89271 liters

0.8 liter = 100 pesos

1.89271 liters = x pesos

x = 1.89271 × 100/0.8

x = 236.58875 pesos

Converting to dollars

1 mexican peso = $0.050

236.58875 pesos = x

x = 236.58875 × $0.050

x = $11.8294375

Approximately = $11.83

A half gallon jug of the same wine cost in dollars $11.83

Answer:

The equations have one solution at (5, -5).

Step-by-step explanation:

We are given a system of equations:

[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]

This system of equations can be solved in three different ways:

Graphing the Equations

We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].

Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.

[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]

Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].

Equation 2 also needs y to be isolated.

[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]

Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].

Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.

The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]

Now, we can place these values in our table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.

For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]

And now, we place these values into the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.

Equation 1                  Equation 2

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]                 [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

Therefore, using this data, we have one solution at (5, -5).