An air-filled toroidal solenoid has 370 turns of wire, a mean radius of 15.0 cm , and a cross-sectional area of 4.30 cm2
a) If the current is 5.90 A, calculate the magnetic field in the solenoid
b) Calculate the self-inductance of the solenoid.
c) Calculate the energy stored in the magnetic field.
d) Calculate the energy density in the magnetic field.
e) Find the answer for part D by dividing your answer to partC by the volume of the solenoid.

Answers

Answer 1

The magnetic field in the solenoid is 2.674*10^-3T at 5.90 A of current. The solenoid has a 6.936*10^-5H self-inductance. 1.2072*10^-3J of energy is held in the magnetic field.

The magnetic field has a 2.846 J/m^3 energy density. We obtain 2.846 J/m^3 by dividing your response to part C by the solenoid's volume. An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A solenoid is a particular kind of electromagnet that produces a regulated magnetic field and is made of a helical coil of wire whose length is significantly higher than its diameter.

The magnetic field in the solenoid'

L = Mo*N*I/2*pi*r L = 4*pi*10^-7*340*5.90/28*pi*(0.15m),

where the current is 5.90 A, is equal to 2.674*10^-3T.

a solenoid's internal inductance

The magnetic field's stored energy, L, is given by L = Mo*N2*I/2*pi*r = 6.936*10^-5H.

Ul = 1/2*L*I Ul = 1/2*6.936*10-5*(5.90)2

Ul = 1/2*1.2072*10^-3J.

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Related Questions

which planet(s) will experience an increase in gravitational force and an increase in orbital speed from this added mass? explain your reasoning.

Answers

Saturn, Uranus, and Neptune

The reason is that  more mass is added interior to those planets' orbits. With a greater interior mass, Saturn, Uranus, and Neptune will experience a larger gravitational force and an increased orbital speed.

A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther   from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

As seen in the equation v = SQRT(G * Mcentral / R), the mass of the central body (earth) and the radius of the orbit affect orbital speed.

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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?

Answers

The kinetic energy of the bullet when it left the gun barrel is 1000J.

We know that ,

K.E. = F d

where, K.E. = kinetic energy

F = force

d = distance

Given, F = 1* 10^4 N

          d = 10cm = 0.1 m

Putting these values in above equation we get,

K.E. = 1000J

So the kinetic energy of the bullet when it left the gun barrel is 1000J.

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To practice Problem-Solving Strategy 24.1 Magnetic field problems.
The element niobium, which is a metal, is a superconductor at temperatures below 9 K . This means that at such low temperatures a niobium wire has no electrical resistance. The superconductivity of the wire, however, is destroyed if the magnetic field at the surface of the wire exceeds 0.10 T . What is the maximum current in a straightsuperconducting niobium wire of radius 1.5 mm ? You may assume that all the current flows in the center of the wire.
Prepare
Create a visual representation of the problem. First choose the best orientation for the wire, then draw the magnetic field created by the current. You can then determine your known variables and identify those that you must find.
Recall that you are to treat the current as if it all runs through the center of the wire, and you are interested in the value of the magnetic field at the surface of the wire. Sort the following variables as known or unknown: the magnitude of the magnetic field B, the current I, and the distance r between the current and the point at which the magnetic field has a value of B.

Answers

u0= 4pi*10^-7

  r=1.5mm= 1.5*10^-3m

  substitute these values

 The answer is 750 A                      

Long straight wire :B =µ01/2πr = Icrit==(2π)*(r=D/2)(Bcrit))/µ0                                    

A 15-kilogram cart is at rest on a horizontal surface. A 5-kilogram box is placed in the cart. Compared to the mass and inertia of the cart, the cart-box system has.

Answers

Compared to the mass and inertia of the cart, the cart-box system has more mass and more inertia.

Inertia refers to the position in which a body repels a change in its position of motion or rest. Moreover, it also includes a change in the direction of an object.A 15-kilogram cart at rest and a 5-kilogram box would make up a 20-kilogram cart and box that is at rest on a horizontal surface.The mass changed into something more, of course, as a result of combining the two object into one and by combining the two objects' mass, the inertia that it previously possessed as a cart by itself was increased when the inertia of the box was also combined to the cart.

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Answer:

More mass and more inertia

Explanation:

No explanation

what is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at 8.00 cm? take the lens-to-retina distance to be 2.00 cm.

Answers

Power of the eye is 62.5 diopter The size of the image is - 0.5 mm The size of the image be if the object were held at the normal 25.0 cm is -0.16 mm

What is the power of the eye when viewing an object?The power of the eye varies from 50.0 D (for distant entirely relaxed vision) to 54.0 D (for near fully accommodated vision), which is an increase of 8%, for an eye with this usual 2.00 cm lens-to-retina distance.In other words, multiply 50.5 diopters by 1 over 2.00 times 10 to the minus 2 meters, then take the difference and multiply the result by 1 then multiply that result by the exponent to obtain 2.00 meters. As a result, they can only see a maximum of 2 meters in front of them without glasses since they are severely nearsighted.It is 2.00 cm from the lens to the retina.

Given details :

a)  For this exercise we use the equation for thin lenses

              1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

In this case q is the distance from the lens to the retina q = 2.00 cmThe distance p is the distance from the object to the lens p = 8.00 cm

              1 / f = 1 / 8.00 + 1/2

              1 / f = 0.625 cm⁻¹

power is the inverse of the focal length in meters

             P = 1 / f [m]

             P = 0.625

             P = 62.5 diopter

b)  the size of the image

            m = - p / q

            m = - 2 / 8.00

            m = -0.25 X

if we assume that the object is right

           m = h´ / h

           h´ = m h

           h´ = -0.25 x 2

           h´ = -0.5 mm

if the height of the object h is straight the image and inverted

c) if the object were at p = 25.0 cm

          m = - 2/25

          m = -0.08

            h´ = -0.08 x 2

            h´ = -0.16 mm

the image would be much smaller

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suppose that an object is dropped, not from the earth's surface, but from a height rearth above the earth's surface. with what acceleration will it start to fall? give your answers as a fraction of gearth

Answers

The acceleration of the object when it will start falling from the height above the earth is ( 1/9 ) gₓ.

Acceleration due to gravity from the height = gₙ

Acceleration due to gravity on earth = gₓ

Distance between the core of earth and the point at a height above earth = h

Radius of the earth = rₓ

Now, for h = rₓ

= Using the gravitational formula

= gₙ = gₓ ( rₓ / (rₓ + rₓ))²

= gₙ = ( 1/4 ) gₓ

Similarly for h = 2rₓ,

= gₙ = gₓ ( rₓ / (rₓ + rₓ))²

= gₙ = ( 1/9 ) gₓ

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a machine works with an efficiency of 18%. the energy input is 500 joules/second. how much useful energy will the machine generate in 15 minutes?(1 point)

Answers

The useful energy the machine will generate in 15minutes is 81000J

What is efficiency of a machine?

The efficiency of a machine indicates how well its input energy is converted to useful output energy or work. It is a major factor in the usefulness of a machine and is the fraction or percentage of the output divided by the input.

Therefore the efficiency of a machine is given as Energy output/ energy input ×100 or power output/ power input ×100

let the power output be x

therefore 18=( x/500)×100

100x = 18×500

x= 18×500/100= 90J/s

Energy = power ×time

in 15minutes = 15×60s, the machine will generate energy of 90×15×60= 81000J

Therefore the machine will generate a useful energy of 81000J

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in the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in case 2 as in case 1. 1)how are the maximum velocities in the two cases related?

Answers

The maximum velocities in the two cases related are Vmax,2 = 2 Vmax,1

Simple harmonic motion :

In physics, simple harmonic motion is the repeated back-and-forth  motion through an equilibrium, or center, position so that the maximum displacement on one side of this position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.

Complete question:

In the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in Case 2 as in Case 1.

1)How are the maximum velocities in the two cases related?

Vmax,2 = Vmax,1

Vmax,2 = 2 Vmax,1

Vmax,2 = 4 Vmax,1

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what is the speed of visible light waves when traveling through a vacuum? about 3 cross 10^8 m/s about 350 m/s about 1 cross 10^8 m/s light waves cannot travel through a vacuum. about 2 cross 10^8 m/s

Answers

The speed of visible light waves when travelling through a vacuum is about 3 X 10⁸ m/s.

The speed of electromagnetic waves, which includes visible light, radio light and x-rays is 3 X 10⁸ m/s. This is same as that of the speed of visible light in the presence of air.

The speed of light is depicted using the letter 'c', and it a universal constant value. It is a physical constant and important in many areas of physics.

The speed of light in water is 2.25 X 10⁸ m/s and that in glass is 2 X 10⁸ m/s. The speed varies with respect to the medium.

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What is the maximum speed at which a car can safely travel around a circular track of radius 55. 0 m if the coefficient of friction between the tire and road is 0. 350?.

Answers

The maximum speed at which a car can safely travel around a circular track of radius 55. 0 m is 10.84  m/s

What does it imply to speak of centripetal forces?

Any object is drawn toward the center of a curved surface by a centripetal force. Imagine that you are a yo-yo being spun. The yo-yo is set in motion by your arm movement, and as you twirl it, the tension of the string keeps it spinning.

Given : r=30 m            

μ=0.4                  

g=9.8m/s

2The maximum speed        

v max =μgr= 0.4×9.8×30 =10.84  m/s

How would you describe centripetal force to a young person?

A force known as centripetal force keeps things moving in a circular motion. The object will keep rotating in a circle as long as the centripetal force persists and all other forces are equally balanced. One object that moves in a circle as a result of centripetal force is a yo-yo.

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a 6.0 v ideal battery is being used to charge a 5.0 x 10-6 f capacitor through a resistor r. the capacitor attains a potential difference of 3.6 v in 1.0 s after the charging begins. the value of the resistance r is

Answers

The value of the resistance R in the above case is 120000 Ohms.

In this case

Charge is given by

Q=CV

=6*5*10^-6

=30*10^-6 C

Then the current through the resistor, R is

I=Q/t

=(30*10^-6)/1

=30*10^-6 A

From Ohm's law

R=V/I

=3.6/(30*10^-6)

=120000 Ohms

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Which of the following statements are true of free-
falling objects of different mass? Include all that apply.
a. The rate of acceleration is the same despite their
different masses.
b. They experience the same force of gravity.
c. They have the same g value but a different
acceleration.
d. They have the same acceleration but a different g
value.
e. nonsense! None of these statements are true of
such objects.

Answers

Statement "a" is true.

it's the only one of the bunch.

The true statement for free-falling objects of different masses is the rate of acceleration is the same despite their different masses. The correct option is a.

What is acceleration?

Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

If things of different masses are dropped from the same height, they will still impact the ground at the same time because Earth provides everything with the exact same acceleration.

Therefore, the correct option is a, The rate of acceleration is the same despite their different masses.

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for a counter flow double pipe heat exchanger insulated from its surroundings, the mean outlet temperature of the initially cold fluid can exceed the outlet temperature of the initially hot fluid.

Answers

Yes, In case of the counter-flow warmth exchangers the hot and bloodless fluids enter the warmth exchanger from the alternative ends and the outlet temperature of the bloodless fluid may exceed the hole temperature of the new fluid.

Observe that in a counter-flow warmth exchanger the outlet temperature of the cold fluid can exceed the opening temperature of the hot fluid but this can not take place in a parallel glide device. right here, ΔTk refers to temperature difference among the recent and cold fluids at factor okay (okay = 1 or 2).

This distributes the warmth extra calmly across the warmth exchanger and permits for maximum efficiency. In principle, the bloodless fluid can exit the heat exchanger at a better temperature than the temperature of the recent fluid outlet, despite the fact that in reality that is very tough to achieve.

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in the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. suppose the background signal level is 13 mv, the signal is 91 mv with no attenuator and is 25 mv with an attenuator in place. calculate pt/pi including the background correction. round your answer to 3 digits after the decimal point.

Answers

15.38 % is pt/pi including the background correction.

What is the definition of an amplitude simple?

The greatest deviation from equilibrium of a point on either a vibrating body or wave in terms of displacement or distance traveled. It is similar to the half-length of the vibration path.

Briefing :

Background [tex]=13mv[/tex]

corrected signal [tex]= 91mv - 13 mv = 78mv[/tex]

with attenuator[tex]=25mv - 13mv = 12 mv[/tex]

[tex]\frac{P_{t} }{P_{i} } = \frac{12}{78} . 100[/tex]

[tex]= 15.38 %[/tex] %

Therefore , the pt/pi is 15.38 %

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a bicyclist is riding north on level ground and has zero net force. a single force pointing south then acts on the bicycle. which effect does the new force have on the motion of the bicycle? responses

Answers

If the single force pointing south acts on the bicycle then it will slow down or even stop, depending on the size of the force applied.

The cyclist is travelling north at a constant speed because the question says there is no net force acting on him.

The new force is against the direction of travel so will decelerate (slow down) the cyclist because,

Force, mass and acceleration are linked by the formula

= Force = mass x acceleration

= F = m X a

Moreover, it is given that the net force acting initially on the bicycle is zero.

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In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 x 107 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 x 1027 kg). Part A What is the value of g on this large, but low-density, world? Express your answer with the appropriate units. НА ? g= Value Units Submit Request Answer Provide Feedback

Answers

3.86 m/s^2  is the value of gravity  on this large, but low-density, world.

given :

Kepler-12b

diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),

mass = 0.43  Jupiter (M_Jupiter = 1.90 × 10^27 kg ).

g = GM/r^2

g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2

g = 3.859 ~ 3.86 m/s^2

Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.

On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.

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the magnitude of the magnetic field 50 cm from a long, thin, straight wire is 8.0 μt. what is the current through the long wire?

Answers

The current through the long wire is 20A.

What is a magnetic field in simple terms?

The magnetic field is the area around a magnet in which the effect of magnetism is felt. We use the magnetic field as a tool to describe how the magnetic force is distributed in the space around and within something magnetic in nature.

What causes a magnetic field?

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the nucleus, or core, of an atom.

How do you find current in a wire in a magnetic field?

The strength of a magnetic field, , some distance  away from a straight wire carrying a current, , can be found using the equation  =   2  , where  is a constant known as “the permeability of free space”

What happens when a wire with a current is placed in a magnetic field?

The wire will bend away from the poles of the magnet.

[tex]i=\frac{2\pi RB}{m_{0}}[/tex]

Given : [tex]R=0.50m, B=8*10^{-6}[/tex]

[tex]i=\frac{2\pi *0.50*8*10^{-6}}{4\pi *10^{-7}}[/tex]

[tex]i=20A[/tex]

Thus, the current flowing in the wire is 20A.

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Nuclear decay occurs according to first-order kinetics. A nuclide decays in 23. 0 minutes from 12. 9 g to 2. 04 g. What is the rate constant for the nuclide?.

Answers

The rate constant for the nuclide is 0.08.

We know that rate of first order reaction is given by: [tex]kt = 2.303 * log(R'/R)[/tex]

where k = rate of reaction

           t = time = 23 minutes

           R' = initial mass = 12.9 grams

           R = final mass = 2.04 grams

Putting these values in above equation we get k = 0.08.

i.e. the rate constant for the nuclide is 0.08.

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a 0.030-kg bullet is fired vertically at 200 m/s into a 0.15-kg baseball that is initially at rest. how high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?

Answers

If a 0.030-kg bullet is shot vertically at 200 m/s into a 0.15-kg baseball, the combined height of the bullet and baseball following the collision is at most 56.6 m, provided the bullet embeds itself in the ball.

This phase will begin immediately prior to the collision and conclude immediately following the impact (when the two objects are on the verge to move up as a single unit). Note that we are assuming the ball will initially be moving at a speed of 200 m/s when the bullet then collision with it. At this point, we define the system as the ball plus the bullet. We are ignoring any outside factors, such as air resistance or even gravitational force, that can affect this system. As a result, the final velocity of the system immediately following the impact can be determined using the conservation of momentum principle, p=0. The gravitational potential energy is being ignored because we assume that the ball and the bullet were at the same level just before (and just after) colliding.

Yf = v1^2*2*9.8

Yf = 33.3^2*2*9.8

Yf = 56.6 metres.

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explain the relationship between diffraction angle and wavelength using the two dimensional diffraction relationship n

Answers

Diffraction is described as the bending of waves around the corners of an obstruction or through an opening into the region of the barrier.

The angle of diffraction is directly proportional to the size of the wavelength.

How to. Define relationship between angle of diffraction and wavelength using 2-D diffraction?

Angular displacement ∅ = wt = 2 × 10 = 20 rad

Here w = constant

Thus, angular acceleration will be zero.

Here,

∅=wt=4×20= =80 rad

w= constant

∅=wt=3×8=24 rad

w= constant.

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after 10 seconds the car body is 1/3 foot above its equilibrium position and at the high point in its cycle. what were the initial conditions ?

Answers

force is required to stretch it a certain length than you would need to stretch a less stiff spring the same length.

How do you find the amplitude of oscillation?The angular frequency ω, period T, and frequency f of a simple harmonic oscillator are given by ω=√km, T = 2π√mk, and f = 12π√km, where m is the mass of the system and k is the force constant.if one increases the mass of a simple harmonic oscillator (and keeps everything else the same) the frequency of oscillation must decrease. This means that the oscillator will move more slowly. On the other hand if one increases the spring constant K the frequency will increase.So, recapping, the period of a mass on a spring does not depend on the amplitude. You can change the amplitude, but it will not affect how long it takes this mass to go through a whole cycle.x(t) = A cos(ωt + φ). A is the amplitude of the oscillation, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction.

0.43622 seconds

0.9158 foot

-4.43 ffot/sec

we first find the period of oscillation

= 2π√w/gk

= 2π√4000/32x2600

= 2π√0.00481

= 2π0.0694

= 0.43622

b. we find the angular velocity

2π/T

= 2π/0.43622

= 14.41 rad/sec

we find displacement

rom the calculation in the attachment

Ф = -144.1

initial condition

1*cos(-144.1 rad)

= 0.9158 foot

initial velocity of the car

= (-1)(14.41)sin(ω(0)-144.1)

= -4.44 foot/sec

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A lever requires an energy input of 10,000 J to move a 35 kg box up a distance of 18 m. What is the efficiency of this lever?

Answers

The efficiency of the lever will be 62%

What is Efficiency?

Efficiency is the ratio of the work performed by a machine to the total energy expended or heat consumed.

Efficiency refers to how close we can get to a particular outcome of the given input with as much less wastage as possible. Efficiency is the ability to minimise wasting materials, efforts, energy and time in performing something or producing the desired result.

The ratio of energy transferred to a useful form compared to the total energy supplied initially is called the efficiency of the device.

Efficiency (%) = (work output/work input) x 100%

work output = mgh

work input = 10,000J

Efficiency (%) = (35 x 18 x 9.8/10,000) x 100

Efficiency (%) = 0.62 x 100

Efficiency (%) = 62%

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using newton law of gravity calculate the lenghth of the year. consider the orbit of earth is a circule

Answers

Using Newton's Law of gravity, the length of the year is 364.24 days.

According to Newton's law, there exist a force of gravitation between the sun and the earth, The gravitational force is responsible for the revolution of earth around the sun,

So, we can write,

MW²/R = GMm/R²

Where,

M is the mass of earth,

m is the mass of the sun,

R is the distance between the sun and the earth,

G is the universal Gravitational constant.

Solving the relation,

W² = Gm/R

W = √(Gm/R)

The time period of revolution is given by,

T = 2π/W

So, we can write,

T = 2π√(R/Gm)

Bow, putting all the values,

T = 2π(147 x 10⁶/2 x 10³⁰ x 6 x 10⁻¹¹)

T = 364.24 Days.

So, the length of the year is 364.24 years.

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NASA's Skylab, the largest spacecraft ever to fall back to the Earth, reentered the Earth's atmosphere on July 11,1979, and broke into a myriad of pieces. One of the largest fragments was a 1770-kg, lead-lined film vault, which landed with an estimated speed of 120 m/s.
If its speed at an altitude of 146 km was 7950 m/s, how much nonconservative work was done on the film vault during reentry?

Answers

When the movie vault landed, it had a kinetic energy of 12744000J. The energy an object has as a result of motion is known as kinetic energy in physics.

It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. Where m is the mass and v is the velocity, the definition of kinetic energy is:

Equation 1 can be used to calculate the kinetic energy of the movie vault when it landed.

As a result, 12744000J of kinetic energy was present when the movie vault landed.

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metallic bonding occurs when a. a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction b. positive metallic ions are bonded with delocalized free electrons. c. the negative side of one molecule bonds with the positive side of a neighboring molecule d. two metallic atoms share electrons in their outer valence shells

Answers

The answer is A. Metallic bonding occurs when a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction

Metallic bonds are formed when the charge is spread over a larger distance than the size of single atoms in solids. Metallic bonding is a chemical bonding that arises from the attractive electrostatic force between conduction electrons (in the form of an electron cloud of delocalized electrons) and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions (cations). Metallic bonding is not the only type of chemical bonding a metal can exhibit, even as a pure substance.

Metallic bonding occurs when you have a metal in a solid or liquid state. The s and p valence electrons of metals are loosely held. They leave their “own” metal atoms. This forms a "sea" of electrons that surrounds the metal cations. The electrons are free to move throughout this electron sea. A strong metallic bond will be the result of more delocalized electrons, which causes the effective nuclear charge on electrons on the cation to increase, in effect making the size of the cation smaller.

Metallic bonds are strong and require a great deal of energy to break, and therefore metals have high melting and boiling points. A metallic bonding theory must explain how so much bonding can occur with such few electrons (since metals are located on the left side of the periodic table and do not have many electrons in their valence shells). The theory must also account for all of a metal's unique chemical and physical properties.

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a 100 meter long copper wire has a resistance of 100 ω. another copper wire has the same mass but is 10 meters long. find the resistance of the second wire. group of answer choices 1 ω 10 ω 100 ω 1,000 ω

Answers

The resistance of the second wire will be 10 ω.

What is resistance?
Electrical resistance, or resistance to electricity, is a force that opposes the flow of current. It acts as a gauge for the difficulty of current flow in this way. Ohms (Ω) are used to express resistance values. Electricity would then flow from high to low when two terminals have an electron differential. That flow is countered by resistance. The current decreases as resistance increases. On the other hand, the current increases as the resistance decreases. Resistance could be calculated as a number using the circuit's voltage and current.

The resistance of a wire is inversely proportional to its length, so the second wire, which is 10 meters long, will have a resistance that is 10 times less than the first wire, which is 100 meters long. The resistance of the second wire will be 100 ω ÷ 10 = 10 ω.

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you shoot a 51 g pebble straight up with a catapult whose spring constant is 320 n/m. the catapult is initially stretched by 0.20 m. how high above the starting point does the pebble fly? ignore air resistance

Answers

Applying the Conservation of Energy, the point above the starting point of the pebble will fly is 12.8 m

Given Parameters:

Mass of the pebble (m) = 51 g

Spring Constant (k) = 320 N/m

Extension (x) = 0.20 m

Law Of Conservation Of Energy:

According to the rule of conservation of energy, energy cannot be created or destroyed. Energy doesn't evaporate when it is used by people.

Within a specific frame of reference, the total energy of an isolated system either remains constant or is conserved.

According to the law of conservation of energy

Kinetic Energy is equal to potential Energy,

[tex](1/2)kx^2 = mgh\\\\h = (kx^2) / (2mg)= [(320 N/m)(0.20m)^2] / [2(0.051kg)(9.8 m/s^2)]= 12.8 m[/tex]

Thus, The point above the starting point of the pebble will fly is 12.8 m.

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suppose two cards, one twice as massive as the other, fly apart when compressed, spring that joins them is released. how fast does the heavier car roll compared with the lighter card

Answers

Answer: The heavier car rolls with half the acceleration as the lighter car.

An electron is accelerated from rest through a potential difference V. Its final speed is proportional to???

Answers

Answer:

E = V q      energy attained by charge q thru potential energy V

E = 1/2 m v^2      kinetic energy of charge q

1/2 m v^2 = V q        equating energy attained

v^2 = 2 V q / m

v = (2 V q / m)^1/2

The final  speed is proportional to the square roots of V, q, and inverse of square root of m.

Keiko is riding a skateboard 2 m/s, west. How long will it take her to reach a velocity of 8 m/s, west if her acceleration is 2 m/s2?By definition, acceleration is the measure of a velocity change in time. In a particular case when the acceleration is constant, the velocity of an object is changed uniformly (linearly) with time.
If we denote the initial velocity as V_0, the constant acceleration as a and the time since the initial moment as t, then the new speed V at time t will be
V=V_0+at.
In our problem the velocities and the acceleration are given, and we need to solve the above equation for t. It is simple:
t=(V-V_0)/a=(8-2)/2=3(s).This is the answer. Note that it is important that the initial velocity and the final velocity have the same direction (west). If they would have opposite direction, one of them should be taken with a minus sign, and the acceleration might be negative.

Answers

The time taken to reach a velocity of 8 m/s, west if her acceleration is 2 m/s is 3 seconds

Given,

Velocity of Keiko's skateboard = 2 m/s

Velocity to reach = 8 m/s

Acceleration = 2 m/s²

Velocity is known to be the total displacement that occurred in a particular given time.

It is a vector quantity that has both magnitude and direction.

By the 1st equation of motion regarding velocities,

v = u + at ...........(1)

where,

v = final velocity = 8 m/s

u = initial velocity  = 2 m/s

t = time = ?

a = acceleration = 2 m/s²

Now put all the given values in the above equation 1, we get:

8 m/s = 2m/s + (2 m/s²)t

t = 3 seconds

Therefore, using the velocities, we got the the time taken will be 3 seconds.

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