Ammonia's unusually high melting point is the result of:__________

a. dipole-dipole forces.
b. London dispersion forces.
c. hydrogen bonding.
d. covalent bonding.
e. ionic bonding.

Answer:

He won 32 games.

Explanation:

Another way of expressing 75% is 75/100.

To calculate how many games the baseball pitcher won, we multiply the total of games played (43, in this case) by the percent won:

43 * 75/100 = 32.25 ≅ 32

So the baseball pitcher won 32 games.

Answer:

D oxide

Explanation:

Hope this helped!

Answer:

Explanation:

The chemical expression for the reaction between iron and oxygen is:

4Fe(s)  +  3O₂ (g)  [tex]\to[/tex] 2Fe₂O₃ (s)

The number of moles of Fe = mass of Fe/ molecular mass of Fe

The number of moles of Fe = 56 g/ 55.845 g/mol

The number of moles of Fe = 1.002 moles of Fe

The number of moles of oxygen = mass of oxygen/ molecular mass of oxygen

The number of moles of oxygen = 156 g /32 g/mol

The number of moles of oxygen = 4.875 moles of oxygen

Assume that Fe is the limiting reactant, the number of Fe₂O₃ can be calculated as:

moles of Fe₂O₃ = 1.002 mole of Fe × 2 moles of Fe₂O₃/ 4 moles of Fe

moles of Fe₂O₃ = 0.501 mole of Fe₂O₃

Assume that O₂ is the limiting factor, the number of Fe₂O₃ is:

moles of Fe₂O₃ = 4.875 moles of O₂ × 2 moles of Fe₂O₃/ 3 moles of O₂

moles of Fe₂O₃ = 3.25 mole of Fe₂O₃

Thus, after the reaction is complete, Fe and O₂ contain different moles of Fe₂O₃. Only Fe gets consumed in the reaction and it is the limiting factor.

Answer:

oxygen, silicon, iron, calcium, sodium

Explanation:

these are all found in space rocks known as meteorites. hope this helps :)

Answer:

a. 122.6 mL / pH = 4.03

b. 193.6 mL / pH = 5.73

Explanation:

In the equivalence point we know: mmoles acid = mmoles base- And the pH in a titration between a weak base and a strong base, is acid, at the equivalence point. For the volume, we can replace the equation with the data given.

a. 0.125M . volume of acid = 65.5 mL . 0.234M

Volume of acid = (65.5 . 0.234) / 0.125 = 122.6 mL

Total volume at the equivalence point = 188.1 mL

b. 0.125M . volume of acid = 21.8 mL . 1.11 M

Volume of acid = (21.8 .  1.11) / 0.125 = 193.6 mL

Let's calculate the pH. In the equilavence point we have a neutralization reaction.

a. NH₃ + HCl → NH₄Cl

All the mmoles of protons (65.5 mL . 0.234M) react to ammonia, to obtain ammonium.

New concentration is: 15.32 mmoles / 188.1 mL = 0.0814 M

This is the [NH₄⁺] to determine the pH in the acid base equilibrium.

NH₄⁺  +  H₂O  ⇄  NH₃  +  H₃O⁺      Ka

Expression for Ka = [NH₃]  . [H₃O⁺] / [NH₄⁺]

5.6×10⁻¹⁰ = x² / (15.32 - x)

(We can avoid the quadratic equation 'cause Ka is so small)

√(5.6×10⁻¹⁰ . 15.32) = x → [H₃O⁺] = 9.26×10⁻⁵

pH = - log [H₃O⁺] → 4.03

b. CH₃NH₂ + HCl → CH₃NH₃Cl

All the mmoles of protons (21.8 mL . 1.11M) react to methylamine, to obtain methylammonium.

New concentration is: 24.2 mmoles / 193.6 mL = 0.125 M

This is the [CH₃NH₃⁺] to determine the pH in the acid base equilibrium.

CH₃NH₃⁺  +  H₂O  ⇄  CH₃NH₂  +  H₃O⁺      Ka

Expression for Ka = [CH₃NH₂]  . [H₃O⁺] / [CH₃NH₃⁺]

2.7×10⁻¹¹ = x² / (0.125 - x)

(We can avoid the quadratic equation 'cause Ka is so small)

√(2.7×10⁻¹¹ . 0.125) = x → [H₃O⁺] = 1.84×10⁻⁶

pH = - log [H₃O⁺] → 5.73

The pH of the equivalence point of 0.125M HCl with NH₃ is 4.03 and with CH₃NH₂ is 5.73.

In the acid - base titration, at the equivalence point equal moles of acid as well as of base are present.

First we calculate the volume of HCl by using the below equation as:

M₁ = molarity of NH₃ = 0.234 M

V₁ = volume of NH₃ = 65.5 mL

M₂ = molarity of HCl = 0.125 M

V₂ = volume of HCl = ?

V₂ =  (65.5 . 0.234) / 0.125 = 122.6 mL

Total volume at the equivalence point = 188.1 mL

Chemical reacion will be written as:

NH₃ + HCl → NH₄Cl

All moles of protons react with moles of ammonia, so new moles (n) will be calculated as:

n = molarity × volume

n = 65.5 mL × 0.234M = 15.32 moles

Now, concentration in terms of molarity will be 15.32 mmoles / 188.1 mL = 0.0814 M

pH in the acid-base reaction due to [NH₄⁺], as:

NH₄⁺  +  H₂O  ⇄  NH₃  +  H₃O⁺

Value of Ka for this reaction is = 5.6×10⁻¹⁰

According to the ICE table, Ka equation will be written as-

5.6×10⁻¹⁰ = x² / (15.32 - x)

x = [H₃O⁺] = 9.26 × 10⁻⁵

pH = - log [H₃O⁺] = 4.03

0.125M . volume of acid = 21.8 mL . 1.11 M

Volume of acid = (21.8 .  1.11) / 0.125 = 193.6 mL

Total volume at the equivalence point = 215.4 mL

Chemical reacion will be written as:

CH₃NH₂ + HCl → CH₃NH₃Cl

All moles of protons react with moles of ammonia, so new moles (n) will be calculated as:

n = 21.8 mL . 1.11M = 24.2 moles

Now, concentration in terms of molarity will be 24.2 moles / 215.4 mL = 0.11M

pH in the acid-base reaction due to [CH₃NH₃⁺], as:

CH₃NH₃⁺  +  H₂O  ⇄  CH₃NH₂  +  H₃O⁺

Value of Ka = 2.7×10⁻¹¹

According to the ICE table, Ka equation will be written as-

2.7×10⁻¹¹ = x² / (0.11 - x)

x = [H₃O⁺] = 5.4×10⁻⁶

pH = - log [H₃O⁺] = 5.73

Hence the value of pH will be 4.03 and 5.73 respectively.

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Answer:

[tex]r_{NOCl}=9.28x10^{-2}M[/tex]

Explanation:

Hello!

In this case, given the balanced chemical reaction:

[tex]2 NO(g) + Cl_2(g) \rightarrow 2 NOCl(g)[/tex]

Since there is 1:2 mole ratio between chlorine and NOCl, based on the rate proportions, we can write:

[tex]\frac{1}{-1}r_{Cl_2} =\frac{1}{2}r_{NOCl}[/tex]

It means that for the formation of NOCl, we obtain:

[tex]r_{NOCl}=\frac{2}{-1}r_{Cl_2} \\\\r_{NOCl}=\frac{2}{-1}(-4.64x10^{-2}M)\\\\r_{NOCl}=9.28x10^{-2}M[/tex]

Notice that chlorine is disappearing, which means its rate is negate.

Best regards!

Answer:

39.1-32.5 and you will find your answer it always like that, you subtract your starting point from your ending point

Explanation:

The volume of the piece of lead is 6.6 mL

From the question given above, the following data were obtained:

The volume of the lead can be obtained as follow:

Volume of lead = (Volume of water + Lead) – (Volume of water)

Volume of lead = 39.1 – 32.5

Volume of lead = 6.6 mL

Therefore the volume of the lead is 6.6 mL

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Answer:

B- beaker

Explanation:

..............

Answer:

geruow0irghvn3p0unhie0ghik

Explanation:

Answer:

Animals need food, water, shelter, and space to survive. Herbivores can live only where plant food is available. Carnivores can live only where they can catch their food. Omnivores can live in many places because they eat both plants and animals.

The coefficient for Br and OH has been 3 and 6 respectively. Thus option C is correct.

If the reaction takes place in a basic medium, the reaction can be given as:

[tex]\rm Br_2\;+\;OH^-\;\rightarrow\;BrO_3^-\;+\;Br\;+H_2O[/tex]

The coefficient has been placed in the chemical reaction to balance the number of atoms on the product and the reactant side.

The number of atoms of Br on the product side has been 2, and the reactant side has been 2.

The oxygen atoms have been 1 on the reactant side, and 3 on the product side.

It has been balanced as:

[tex]\rm 3\;Br_2\;+\;6\;OH^-\;\rightarrow\;BrO_3^-\;+\;5\;Br^-\;+\;3\;H_2O[/tex]

The coefficient for Br and OH has been 3 and 6 respectively. Thus option C is correct.

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Answer:

100Jkg/°C

Explanation:

Given parameters:

Mass of metal  = 2kg

Amount of heat energy  = 1600J

Initial temperature  = 5°C

Final temperature = 13°C

Unknown:

Specific heat capacity of the metal  = ?

Solution:

Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.

  H  = m x C x (T₂ - T₁ )

H is the amount of heat

m is the mass

C is the unknown specific heat capacity

T is the temperature

     Insert the parameters and solve;

  1600 = 2 x C x (13 - 5)

   1600  = 16C

        C = 100Jkg/°C

Answer:

Displacement reaction

Answer:

These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses. Mass is the word for how much substance (or matter) something has.

Answer:

C. The wavelength decreases

Explanation:

This is because frequency is how often the wave hits the top (peak) and the bottom (through). The more it hits the less wavelength it will have because it is moving faster and has more energy.

Answer:

The temperature is on the y-axis and the time is on the x-axis.

Explanation:

Which statement describes how phase changes can be diagrammed as a substance is heated? (D is the answer)

The phase is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the phase is on the x-axis.

The time is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the time is on the x-axis.

Which statement describes the appearance of a temperature-vs.-time graph? (C is the answer)

A horizontal line shows that the temperature increases at a constant rate over time.

A vertical line shows that the temperature decreases at a constant rate over time.

Horizontal lines where the temperature is constant during phase changes connect upward-sloping lines where the temperature increases.

Horizontal lines where the temperature increases are connected by upward-sloping lines where the temperature is constant for each phase.

Answer:

Observational study

Explanation:

An investigation of what happened over the years to the people who were exposed to radiation during the 1986 Chernobyl nuclear disaster would be termed an observational study because it will require observing subjects and finding out if there is a kind of correlating factor in the subjects that could indicate the level of exposure to the nuclear radiation.

There are basically two types of research studies:

1. Observational studies

2. Experimental studies

Observational studies involve just the observation of subjects and trying to find out some correlation factors. This kind of study could be prospective when it deals with what could happen in the future based on certain factors or retrospective when it considers what has already happened. An observational study can be cross-sectional, case-only, case-control, or cohort study.

Experimental studies are also referred to as randomized or controlled trial studies. Here, subjects are grouped and each group receives a different treatment in order to isolate the effect of a particular factor or variable relating to the treatment.

Answer:

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Answer:

0.0681 HCl moles

Explanation:

First we convert 22.7 mL to liters:

Then we use the definition of molarity:

So there are 0.0681 hydrochloric acid moles in 22.7 mL of a 3.0 M HCl solution.

Answer:

[tex]T'=30^{\circ} C[/tex]

Explanation:

Initial pressure, P = 125 kPa

Initial temperature, T = 25.0°C

If new pressure is increased to P' = 150.0 kPa

We need to find new temperature. According to Gay-Lussac's law,

P ∝ T

or

[tex]\dfrac{P}{T}=\dfrac{P'}{T'}\\\\T'=\dfrac{P'T}{P}\\\\T'=\dfrac{150\times 25}{125}\\\\=30^{\circ} C[/tex]

So, the new temperature will be [tex]30^{\circ} C[/tex].

Answer:

answer is c

Explanation: cause there breaking it

Answer:

2 mol H₂O

Explanation:

With the reaction,

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we calculate the moles of H₂O produced, starting from the moles of limiting reactant:

The number of moles of H₂O that could be produced in the reaction is 2.00 moles

From the question,

We are to determine the number of moles of H₂O that could be produced.

The given balanced chemical equation is

2 H₂(g) + O₂(g) → 2 H₂O(g)

This means,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

From the given information

Number of moles of H₂ present = 2.00 moles

and

Number of moles of O₂ present = 1.55 moles

Since,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

Then,

The 2.00 moles of H₂(g) will react with 1.00 mole of O₂(g) to produce 2.00 moles of H₂O

∴ 2.00 moles of H₂O will be produced during the reaction

(NOTE: Only 1.00 mole of the O₂(g) will react, meaning O₂(g) is the excess reactant)

Hence, the number of moles of H₂O that could be produced in the reaction is 2.00 moles

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Answer:

anor277

Nov 17, 2017

Well, by definition,

Molarity

≡

Moles of solute

Volume of solution

Explanation:

And thus...

moles of solute

=

molarity

×

volume

We use a molar quantity of

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

=

0.461

⋅

m

o

l

with respect to

potassium sulfate

And thus

volume

=

moles of solute

molarity

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

3.12

⋅

m

o

l

⋅

L

−

1

=

0.148

⋅

L

.

The buoyant force is one that acts against the weight of an object suspended in a fluid. The value of the buoyant force on each are:

i. Buoyant force on the cube of iron = 25.0 N

ii. Buoyant force on the cube of wood = 1.20 N

Upthrust is a force which acts against the direction of the weight of an object when suspended in a fluid. It acts majorly upwards against gravity, and it can be referred to as a buoyant force.

The amount of upthrust on object in a fluid sometimes depends on the density, volume and gravity acting on the object.

So that;

Upthrust = density x volume x gravity

Thus from the given question;

i. The buoyant force on the cube of iron can be determined by:

Upthrust = 7.86 x [tex]10^{3}[/tex] * 3.25 x [tex]10^{-4}[/tex] * 9.8

              =  25.034

Upthrust = 25.0 N

Therefore, the buoyant force on the cube of iron is 25.0 N.

ii. The buoyant force on the cube of wood can be determined by:

Upthrust = 3.73 x [tex]10^{2}[/tex] * 3.25 x [tex]10^{-4}[/tex] * 9.8

              = 1.1880

Upthrust = 1.20 N

Therefore, the buoyant force on the cube of wood is 1.20 N.

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Electrons - 7

Atomic mass - 14

For future reference, you can find the number of Electrons by subtracting the number of protons (7) from the element's mass number (14

We know, Atomic Number = Number of Electrons (In a neutral atom).

& Atomic mass = Number of protons + Number of Neutrons

The atomic number of nitrogen is 7. The number of electrons a neutral nitrogen atom has is "Seven (7)", and its atomic mass is approximately "Fourteen(14)" amu

Hope this helps!

Answer:

[tex]C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Explanation:

Hello!

In this case, by considering thermodynamics and the temperature of zinc, we can infer it is hot while water is cold, it means that the heat lost by the zinc is gained by the water and we can write:

[tex]Q_{Zn}=-Q_{water}[/tex]

In terms of mass, specific heat and temperatures we can write:

[tex]m_{Zn}C_{Zn}(T_{eq}-T_{Zn})=-m_{water}C_{water}(T_{eq}-T_{water})[/tex]

In such a way, by solving for the specific heat capacity of the zinc we write:

[tex]C_{zinc}=\frac{-m_{water}C_{water}(T_{eq}-T_{water})}{m_{Zn}(T_{eq}-T_{Zn})}[/tex]

Thus, by plugging in the given values we obtain:

[tex]C_{zinc}=\frac{-45.0g*4.184\frac{J}{g\°C}* (27.1\°C-98.8\°C)}{13.8g*(27.1\°C-98.8\°C)}\\\\C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Best regards!

Explanation:

Answer:

76.366

Explanation:

Knewton answer is 76.4

Answer:

76.4mL

Explanation:

First, calculate the final number of moles of carbon dioxide (n2) in the container.

n2 = n1+n added = 3.41×(10^-3) mol+8.41×(10^-4) mol = 4.25×(10^-3) mol

Rearrange Avogadro's law to solve for V1.

V1 =(V2×n1)/n2

Substitute in the known values for n1, V2, and n2.

V1 = (95.2mL×(3.41×10^-3 mol))/(4.25×(10^-3) mol)=76.4mL

So the initial volume is 76.4mL.

Answer:

The Mass in Grams= 0.5145

Explanation:

The atomic mass of Na=23

The atomic mass of No3= 62

we multiply 0.0035×((23×1)+(62×2)) = 0.5145 grams

Answer:

m = 0.00659 kg = 6.59 g

Explanation:

From Faraday's Law of Electrolysis, we know that:

m = ZQ

where,

m = mass of silver deposited = ?

Q = charge supplied = (1.65 A-hr)(3600 s/1 hr) = 5940 C

Z = electrochemical equivalent of silver = 1.18 x 10⁻⁶ kg/C

Therefore,

m = (1.11 x 10⁻⁶ kg/C)(5940 C)

m = 0.00659 kg = 6.59 g

The mass of silver that would be deposited by a battery is 6.65 grams

The precipitation of Ag requires the removal of one electron. The reduction process for silver electrode at the cathode is as follows:

[tex]\mathbf{Ag^+ + e^- \to Ag(s)}[/tex]

∴

In one mole of an electron, the charge carried = 96500 C

Recall that:

The atomic mass of silver (Ag) = 108 g

∴

The mass of silver that would be deposited in a 5940 C can be computed as:

[tex]\mathbf{=5940\ C \times \dfrac{108 \ g }{96500 \ C}}[/tex]

= 6.65 grams

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