Answer:
B is the answer
Cost of each egg= 1.80/12=$0.15
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
12 egg=$1.80 ,1 egg= $1.80÷12 =$0.15
the ratio of the angle measures of a pentagon is 4:5:3:8:7. what is the measure of the smallest angle. help pleasee
Answer:
geometry
The ratio of the angle measures of a pentagon is 4:5:3:8:7. What is the measure of the smallest
The sum of the interior angles of a pentagon is 180(5-2) = 540º
so
4x + 5x + 3x + 8x + 7x = 540
solve for x and sub into 3x
A radio that costs $29.49 was marked up by 35%
Answer:
the new price of the radio is $39.81
Step-by-step explanation:
multiply the cost by the mark up to find how much the price was raised by
29.49•0.35= 10.32
then add the mark up to the original price
10.32+29.49= $39.81
and I rounded to the hundreds place because it's money
hope this helps babe <3
Answer:
I think it is $21.84
Step-by-step explanation:
Write the equation of the line in fully simplified slope intercept form
Answer: right of the picture
Step-by-step explanation:
Caleb is comparing the growth of plants using two different fertilizers
Part A use the measures of center from the box plots to make an inference about the data. Use the drop down menus to explain your answer
Part B use the box plots to make an inference using the variability of the data. Drag words to complete the statement. Words may be used once, more than once, or not at all.
Answer: Medians, Less
Part A
Use the measures of center from the box plots to make an inference about the data. Use the drop-down menus to explain your answer.
Based on the medians, the plants in Group A grew
less on average, as compared to the plants in Group B.
Part B Answer: Greater, Less
The range and IQR are greater
in Group B as compared to Group A, so there is less variability in the growth of plants in Group B.
Answer:
Answer: Medians, Less
Part A
Use the measures of center from the box plots to make an inference about the data. Use the drop-down menus to explain your answer.
Based on the medians, the plants in Group A grew
less on average, as compared to the plants in Group B.
Part B Answer: Greater, Less
The range and IQR are greater
in Group B as compared to Group A, so there is less variability in the growth of plants in Group B.
Step-by-step explanation:
10. Which of the following could be the lengths of the three sides of a triangle?
A 1 cm, 2 cm, 3 cm
B. 3 in., 3 in., 7 in.
C. 4ft, 8 ft, 12 ft
D. 5 cm, 7 cm, 9 cm
Answer: D
Step-by-step explanation:
the sum of any two sides of a triangle must be greater than the third side.
5 + 7 = 12
12 > 9
Mark is six years older than his brother Sam. The sum of their ages is 30. Let a be Sam's age. Set
up an equation using the information given.
Answer:
(m+6)+m=30
Step-by-step explanation:
what is 46 converted from ft and in
Answer:
552 inches
Step-by-step explanation:
2/7 of 49
fractions
Answer:
14
Step-by-step explanation
what is the area of the shaded region ?
Answer: The area is 8 it litterally tells you there
Step-by-step explanation:
Help I’m doing 8th grade work
Answer:
I think B by I'm not sure
Step-by-step explanation:
I'm not good with this subject
write the fraction whole
diameter is 7 and numerator is 4
Answer:
[tex]\dfrac{4}{7}[/tex]
Step-by-step explanation:
A fraction can be written as :
[tex]F=\dfrac{x}{y}[/tex]
Where
x is numerator and y is denominator
We need to write a fraction for denominator 7 and numerator 4.
Substitute the values,
[tex]F=\dfrac{4}{7}[/tex]
Hence, the fraction is equal to [tex]\dfrac{4}{7}[/tex].
There are two aircraft carriers, A and B, and carrier A is longer in length than the carrier B. The total length of these two carriers is 2178 feet, while the difference of their lengths is only 14 feet.
1. Find the length of each carrier.
2. Of a football field has a length of 100 yards, determine the length of carrier A in teams of the number of football fields.
helpppppp ill give brainliest answer if you know
Answer: 280
Step-by-step explanation: all you have to do is multiply one of the numbers by another one and than multiply that number by the final number
The student body President of a high school claims to know the names of at least 1000 of the 1800 students at the school. To test this claim, the Student Government Advisor randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students. What would be the 99% confidence interval for p in this case?
Answer:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.
This means that:
[tex]n = 100, \pi = \frac{46}{100} = 0.46[/tex]
99% confidence level
So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 - 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.3317[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 + 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.5883[/tex]
The 99% confidence interval for p in this case is (0.3317, 0.5883).
1. Two walls of a room or being painted each measure 16 6/2' how many square feet will be painted
2. A rectangular canvas covers 225 inches on a wall if the canvas has a height of 18 inches then what is the base
Answer:
3.167 ft²
12.5 inches
Step-by-step explanation:
1.)
Measure of each wall : 16 6/2 '
Number of walls = 2
Total area to be painted :
16 6/2' * 2 = (16 + 3) * 2 = 19 * 2 = 38 inches
1 feet = 12 inches
x = 38 inches
12x = 38
x = 38 / 12 = 3.167 ft²
2.)
Area of rectangular canvas = 225
Height = 18
Base, b =?
Area of rectangle = height * base
225 = 18 * b
225 / 18 = 18b / 18
12.5 = b
Base = 12.5 inches
A middle school took all of its 6th grade students on a field trip to see a ballet at a theater that has 3840 seats. The students left 2496 seats vacant. What percentage of the seats in the theater were filled by the 6th graders on the trip?
Answer:
35%
Step-by-step explanation:
Answer:
35%
Step-by-step explanation:
First, we must calculate how many seats are taken by 6th graders. We do this by subtracting the total seats by vacant seats. 3840-2496=1,334. Then, we must find the percent of students that were 6th grade who filled the seats. We do this by dividing all the chairs taken by the 6th graders and divide it by the total chairs which gets you .35. And with percentages, you move the decimal place two times to the right which gets you 35%.
What is the area of the object above?
A.
158 sq cm
B.
94 sq cm
C.
142 sq cm
D.
102 sq cm
Answer:
102cm2
Step-by-step explanation:
Split the shape into two rectangles:
A. 4 x 8 = 32cm2
B. 7 x 10 = 70cm2
70 + 32 = 102cm2
6 ft = ____ yd
6 ft = 6 x 1 ft
= 6 x ____ yd
= ____ yd
Answer:
6 ft = 2 yd
6 ft = 6 x 1 ft
= 6 x 2 yd
= 12 yd
Determine whether the given answer is a Solution or Not a Solution
x<6 x=3
x≥10 x=10
x>−3 x=−6
x≤15 x=20
x<9 x=9
x≥8 x=12
Answer:
1- yes
2- yes
3- no
4- no
5- no
6- yes
Step-by-step explanation:
A grain of sand with a diameter of
0.06 millimeter has a mass of approximately
3.0 x 10-13 gram. How is the mass of a grain
of sand expressed using standard notation?
Answer:
Mathematics
College
A grain of sand with a diameter of what
Step-by-step explanation:
tmi,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
A birthday cake is cut into 8 slices. The arc length of one piece is 8.0 inches. What is the diameter of the cake? Round to the nearest tenth.
Answer:
D =20 inches
Step-by-step explanation:
Given that,
A birthday cake is cut into 8 slices. The arc length of one piece is 8.0 inches.
We need to find the diameter of the cake.
The circumference of a circle is given by :
[tex]C=2\pi r[/tex]
ATQ,
[tex]\dfrac{1}{8}\times 2\pi r=8\\\\2r=\dfrac{64}{\pi}\\\\2r=20\ in[/tex]
Diameter, D = 2r
So, the diameter of the cake is equal to 20 inches.
If the perimeter of A is 36ft and the perimeter of B is 48 ft, what is the perimeter of square C?
Answer:
64
Step-by-step explanation
48/36=4/3
36x4/3=48 so...
48x4/3=64
Answer:
64
Step-by-step explanation:
Which is the graph of y=-x-3?
Either graph A or C, i'm leaning more towards A
A
Step-by-step explanation:
because slope is 3/4 and y-intecept is (0,-3)
1. Xian gets 95% of the Math test correctly which is 38. How many items does the test have?
Answer:
If the
an hold 16 ounces, how many ounces
________________________________
38 ÷ 95 × 100= 40There Is 40 Questions In Total________________________________
Answer:
40
[tex]38 \div 95 \times 100\%[/tex]
NEED HELP FOR THIS QUESTION
I want to buy some Botswana pulas and the exchange rate is 8.25 BWP = £1 if I buy them abroad using a credit card or 8.5 BWP = £1 for a cash transaction at a Bureau de Change. The credit card company will charge me 2.3% commission on a credit card transaction whereas a Bureau de Change charges 2% commission plus a fee of £3.
Write down an expression for the cost (including commission) of buying a particular number of Botswana pulas
(a) by credit card and
(b) from a Bureau de Change.
c. Evaluate each of these expressions for 700 BWP, 800 BWP, and 1000 BWP respectively.
d. Hazard a guess as to the number of pulas you would have to buy for the cost to be the same whether you use a credit card or cash.
Answer:
(a) A = 0.00278787878787878x
(b) B = 0.00235294117647058x + 3
(c) The answers are as follows:
For buying by credit card
For 700 BWP: Cost = A = £1.95
For 800 BWP: Cost = A = £2.23
For 800 BWP: Cost = A = £2.79
For buying from a Bureau de Change
The equation (4) is used as follows:
For 700 BWP: Cost = B = £4.65
For 800 BWP: Cost = B = $4.88
For 1000 BWP: Cost = B = £5.35
(d) You would have to buy 6,897.54 pulas for the cost to be the same whether you use a credit card or cash.
Step-by-step explanation:
(a) by credit card
For the exchange rate, we have:
8.25 BWP = £1 ⇒ 8.25 / 8.25 BWP = £1 / 8.25 = 1.00 BWP = £0.121212121212121
The expression can therefore be written as follows:
A = £0.121212121212121 * r * x ................. (1)
Where;
A = cost (including commission) of buying a particular number of Botswana pulas by credit card
r = commission on a credit card transaction = 2.3%, or 0.023
x = the number of pulas bought
Substituting for r into equation (1), we have:
A = £0.121212121212121 * 0.023 * x
A = 0.00278787878787878x ................. (2)
Equation (2) is the expression.
(b) from a Bureau de Change
For the exchange rate, we have
8.5 BWP = £1 ⇒ 8.5 / 8.5 BWP = £1 / 8.5 = 1.00 BWP = 0.117647058823529
B = (£0.117647058823529 * r * x) + F ................. (3)
Where;
B = cost (including commission) of buying a particular number of Botswana pulas by from a Bureau de Change.
r = commission charged by Bureau de Change. = 2%, or 0.02
x = the number of pulas bought
F = fee = £3
Substituting for r and F into equation (3), we have:
B = (£0.117647058823529 * 0.02 * x) + £3
B = 0.00235294117647058x + 3 ................. (4)
Equation (4) is the expression.
c. Evaluate each of these expressions for 700 BWP, 800 BWP, and 1000 BWP respectively.
For buying by credit card
The equation (2) is used as follows:
For 700 BWP: A = £0.00278787878787878 * 700 = £1.95
For 800 BWP: A = £0.00278787878787878 * 800 = £2.23
For 800 BWP: A = £0.00278787878787878 * 1000 = £2.79
For buying from a Bureau de Change
The equation (4) is used as follows:
For 700 BWP: B = (£0.00235294117647058 * 700) + £3 = £1.65 + £3 = £4.65
For 800 BWP: B = (£0.00235294117647058 * 800) + £3 = £1.88 + £3 = $4.88
For 1000 BWP: B = (£0.00235294117647058 * 1000) + £3 = £2.35 + £3 = £5.35
d. Hazard a guess as to the number of pulas you would have to buy for the cost to be the same whether you use a credit card or cash.
This can be calculated by equating equations (2) and (4) and then solve for x as follows:
0.00278787878787878x = 0.00235294117647058x + 3
0.00278787878787878x - 0.00235294117647058x = 3
x(0.00278787878787878 - 0.00235294117647058) = 3
x0.0004349376114082 = 3
x = 3 / 0.0004349376114082
x = 6,897.54 pulas
Therefore, you would have to buy 6,897.54 pulas for the cost to be the same whether you use a credit card or cash.
What are the solutions to this equation?
7x7 - 28 = 0
OA.
-2 and 1
2
OB.
I = -4 and 1
4
O C.
1
|--V7 and r
V7
D.
=
E –V2 and I
V2
2
Step-by-step explanation:
7x^2-28=0
x^2-4=0
x^2=4
x=-2
x=2
another expression 3/4÷6
Answer:
1/16 + 1/16
..............................
Answer:
3/4 x 1/6
Step-by-step explanation:
both would end up as 1/8
hope this helps :)
pls answer no scams ty
Answer:
x<3
Step-by-step explanation:
-9.5x-1.5>-30
move the constant to the right
-9.5x>-28.5
divide both sides to get x<3
Answer:
3.3
Step-by-step explanation:
TO ANYONE WHO WILL HELP ME..
I need someone to explain this math problem with me to contact me
gracie.hill.24 at student.nashvillesd.com
Answer:
there isn't a math question
Step-by-step explanation:
In a time of t seconds, a particle moves a distance of s meters from its starting point, where s = 6t^2 + 4.
(a) Find the average velocity between t = 1 and t = 1 + k if (i) h = 0.1 (ii) h = 0.01 (iii) h = 0.001 Enter the exact answers.
(i) When h = 0.1, the average velocity between t = 1 and t = 1 + h is m/sec.
(ii) When h = 0.01, the average velocity between t = 1 and t = 1 + h is m/sec.
(iii) When h = 0.001, the average velocity between t = 1 and t = 1 + h is m/sec.
(b) Use your answers to part (a) to estimate the instantaneous velocity of the particle at time t = 1. Round your estimate to the nearest integer. The instantaneous velocity appears to be m/sec.
Answer:
(a)
i) [tex]V=12.6m/s[/tex]
ii) [tex]V=12.06m/s[/tex]
iii) [tex]V=12.006m/s[/tex]
(b)
[tex]V = 10m/s[/tex]
Step-by-step explanation:
Given
[tex]s = 6t^2 + 4[/tex]
Solving (a): Average velocity between t = 1 and t = 1 + h
When t = 1
[tex]t_1 = 1[/tex]
[tex]s_1 = 6t^2 + 4 = 6 * 1^2 + 4 = 6 + 4 =10[/tex]
i) h = 0.1
When t = 1 + h
[tex]t_2 = 1 + 0.1 = 1.1[/tex]
[tex]s_2= 6t^2 + 4 = 6 * (1.1)^2 + 4 = 11.26[/tex]
Average velocity is then calculated as:
[tex]V = \frac{s_2 - s_1}{t_2 - t_1}[/tex]
[tex]V = \frac{11.26 - 10}{1.1- 1} = \frac{1.26}{0.1} = 12.6[/tex]
[tex]V=12.6m/s[/tex]
ii) h = 0.01
When t = 1 + h
[tex]t_2 = 1 + 0.01 = 1.01[/tex]
[tex]s_2= 6t^2 + 4 = 6 * (1.01)^2 + 4 = 10.1206[/tex]
Average velocity is then calculated as:
[tex]V = \frac{s_2 - s_1}{t_2 - t_1}[/tex]
[tex]V = \frac{10.1206 - 10}{1.01- 1} = \frac{0.1206}{0.01} = 12.06[/tex]
[tex]V=12.06m/s[/tex]
ii) h = 0.001
When t = 1 + h
[tex]t_2 = 1 + 0.001 = 1.001[/tex]
[tex]s_2= 6t^2 + 4 = 6 * (1.001)^2 + 4 = 10.012006[/tex]
Average velocity is then calculated as:
[tex]V = \frac{s_2 - s_1}{t_2 - t_1}[/tex]
[tex]V = \frac{10.012006 - 10}{1.001- 1} = \frac{0.012006 }{0.001} = 12.006[/tex]
[tex]V=12.006m/s[/tex]
Solving (b): Instantaneous velocity at t = 1
When t = 1
[tex]t = 1[/tex]
[tex]s = 6t^2 + 4 = 6 * 1^2 + 4 = 6 + 4 =10[/tex]
Velocity is:
[tex]V = \frac{s}{t}[/tex]
[tex]V = \frac{10}{1}[/tex]
[tex]V = 10m/s[/tex]