Answer:
Straight line in the direction of the tangential velocity the ball had at the moment the string broke
Explanation:
After the string breaks, the ball now disconnected from the centripetal force that was exerted via the string, continues its travel in a straight line in the direction of the tangential velocity it had at the moment the string broke.
Answer:
B
Explanation:
just took the test :)
The chilled water system for a 27-story building has a pump located at ground level. The lost head in a vertical riser from the pump to an equipment room on the twenty-seventhfloor is 40ftof water, and the pump produces 270ft of head. What is the pressure on the suction side of the pump for a pressure of 8 psig to exist in the riser on the twenty-fifth floor
This question is incomplete, the complete question is;
The chilled water system for a 27-story building has a pump located at ground level. The lost head in a vertical riser from the pump to an equipment room on the twenty-seventh floor is 40ft of water, and the pump produces 270ft of head. What is the pressure on the suction side of the pump for a pressure of 8 psig to exist in the riser on the twenty-fifth floor
Assume 12ft of elevation per floor
Answer: 48.68 psig
Explanation:
First we calculate the elevation of the building
hb = 27 story * 12ft per floor/story
hb = 324 ft
given that the head lost in the vertical riser hL = 40 ft
now the delivery head required in the riser on he 27th floor;
hd = 8 psig * (2.31 ft / 1 psig)
hd = 18.46 ft
Now calculate the suction head required by balancing the energy per unit weight of water, considering pump as the control volume
hp = (hb + hL + hd) - hs
hs = hb + hL + hd - hp
where hp is the head developed by the pump (270 ft)
hb is the elevation of the 27th floor of the building ( 324 ft)
hL is the head lost in the vertical riser ( 40 ft)
hd is the head required to exist in the riser on the 27th floor (18.46 ft)
so we substitute
hs = 324 ft + 40 ft + 18.46 ft - 270 ft
hs = 112.46
so 112.46ft * (1 psig / 2.31 ft)
= 48.68 psig
during which stage do you have sleepwalking and sleeptalking
A. stage 2
B. stage 4
C. REM
D. stage 1
What is the net Force needed to get a 16 kg box moving 4 m/s^2?
Answer:
The net force should be of a magnitude of 64 N
Explanation:
We use Newton's second Law for this:
[tex]F_{net} = m\,*\,a[/tex]
which for our case gives:
[tex]F_{net} = m\,*\,a=16\,(4)\,N= 64\,\,N[/tex]
Does the US use the metric system? Please Only Real Answers Like Yes Or No Or yes because...... no because...... Thank You
Answer:
No
Explanation: It is the only country that does not. Hope this helped :)
Which is not one of the basic nutrients of your body?
1.Vitamins
2.Minerals
3.Molecules
4.Protein
What is Bill's average running speed?
Answer:
Hello!
Sorry you haven't put up an image of your question! Without it we can't answer your question!
Explanation:
Maybe put up another one and it'll be answered!
:D
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in contact with the pavement, the lower side of the ball is temporarily flattened. Suppose the maxi-mum depth of the dent is on the order of 1 cm. Find the order of magnitude of the maximum acceleration of the ball while it is in contact with the pavement. State your assumptions, the quantities you estimate, and the values you estimate for them.
Answer:
a = 1.1 10⁵ m / s²
Explanation:
This is a momentum exercise, where we use the relationship between momentum and momentum
I = ∫ F dt = Δp
= p_f - p₀
as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction
F t = 2 (m v)
therefore the average force is
F = 2 m v / t
where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy
starting point. Done the ball is released with zero initial velocity
Em₀ = U = mgh
final point. Upon reaching the ground, just before the deformation begins
Em_f = K = ½ m v²
energy is conserved in this system
Em₀ = Em_f
m g h = ½ m v²
v = √ (2gh)
This is the velocity of the body when it reaches the ground, so the force remains
F = 2m √(2gh) /t
where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds
knowing this force let's use Newton's second law
F = m a
a = F / m
a = 2 √(2gh) / t
We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s
a = 2 √ (2 9.8 1.5) / 10⁻³
a = 1.1 10⁵ m / s²
How did oxygen get into the earths atmosphere in its early days? plz explain
Answer:
The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen. In fact, all the plants on Earth incorporate symbiotic cyanobacteria (known as chloroplasts) to do their photosynthesis for them down to this day.
Explanation:
Which value represents accuracy: the mean, median, mode, range from center, or distance between farthest beanbags?
Answer:
the mean
Explanation:
The mean (informally, the “average“) is found by adding all of the numbers together and dividing by the number of items in the set: 10 + 10 + 20 + 40 + 70 / 5 = 30. The median is found by ordering the set from lowest to highest and finding the exact middle. The median is just the middle number: 20.
A hockey puck initially travelling to the right at 34 m/s. It moves for 7 before
coming to a stop. How far did it move in 7 seconds?
You can use kinematic equations
Answer:
[tex]x=119m[/tex]
Explanation:
Hello,
In this case, since the hockey puck was moving at 34 m/s and suddenly stopped (final velocity is zero) in 7 seconds, we can first compute the acceleration via:
[tex]a=\frac{v_f-v_o}{t}=\frac{0m/s-34m/s}{7s}\\ \\a=-4.86m/s^2[/tex]
In such a way, we can compute the displacement via:
[tex]x=\frac{v_f^2-v_o^2}{2a}\\ \\x=\frac{0^2-(34m/s)^2}{2*-4.86m/s^2}\\ \\x=119m[/tex]
Best regards.
A place kicker launches a kickoff at an angle of 25° to the horizontal and at a velocity of 20 m/s. Calculate the initial velocities in the x- and y-directions.
4. What is the velocity of an object that doesn't move?
It depends on the object b. it depends on the speed c. it depends on the height
O mis
help
Answer:
Acceleration /Speed
Explanation:
An objects Velocity can be determined by acceleration,
Please pay attention in your middle school class, speed and velocity quiz.
What is the term for heat transfer because of the movement of electromagnetic waves?
r = (2+2+1) i - (t+1)] + t3 k
what is the direction of initial velocity
Answer:
In the - j direction, that is negative of the y-axis
Explanation:
As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:
r (t) = 5 i - (t + 1 ) j + t^3 k
and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:
v(t) = 0 i - 1 j +3 t^2 k
which for the initial velocity requested (that is at time zero) we have:
v(t) = 0 i - 1 j +3 (0)^2 k = = 1 j
Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.
A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A that splits at point B and attaches to the ship at points C and D. The two rope segments BC and BD angle away from the center of the ship at angles of ϕ = 26.0 ∘ and θ = 21.0 ∘, respectively. The tugboat pulls with a force of 1200 lb . What are the tensions TBC and TBD in the rope segments BC and BD?
Answer:
The tensions in [tex]T_{BC}[/tex] is approximately 4,934.2 lb and the tension in [tex]T_{BD}[/tex] is approximately 6,035.7 lb
Explanation:
The given information are;
The angle formed by the two rope segments are;
The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°
The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°
Therefore, we have;
The tension in rope segment BC = [tex]T_{BC}[/tex]
The tension in rope segment BD = [tex]T_{BD}[/tex]
The tension in rope segment AB = [tex]T_{AB}[/tex] = Pulling force of tugboat = 1200 lb
By resolution of forces acting along the line A_F gives;
[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = [tex]T_{AB}[/tex] = 1200 lb
[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb............(1)
Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;
[tex]T_{BC}[/tex] × sin(26.0°) + [tex]T_{BD}[/tex] × sin(21.0°) = 0...........................(2)
Which gives;
[tex]T_{BC}[/tex] × sin(26.0°) = - [tex]T_{BD}[/tex] × sin(21.0°)
[tex]T_{BC}[/tex] = - [tex]T_{BD}[/tex] × sin(21.0°)/(sin(26.0°)) ≈ - [tex]T_{BD}[/tex] × 0.8175
Substituting the value of, [tex]T_{BC}[/tex], in equation (1), gives;
- [tex]T_{BD}[/tex] × 0.8175 × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb
- [tex]T_{BD}[/tex] × 0.7348 + [tex]T_{BD}[/tex] ×0.9336 = 1200 lb
[tex]T_{BD}[/tex] ×0.1988 = 1200 lb
[tex]T_{BD}[/tex] ≈ 1200 lb/0.1988 = 6,035.6938 lb
[tex]T_{BD}[/tex] ≈ 6,035.6938 lb
[tex]T_{BC}[/tex] ≈ - [tex]T_{BD}[/tex] × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb
[tex]T_{BC}[/tex] ≈ -4934.1733 lb
From which we have;
The tensions in [tex]T_{BC}[/tex] ≈ -4934.2 lb and [tex]T_{BD}[/tex] ≈ 6,035.7 lb.
seagull is flying at a rate of 20 miles per hour south, it encounters wind blowing 20 miles per hour north. What is the resultants
Answer:
the winds will make the bird stop
Explanation:
is basically 20 - 20
A penny is dropped from the top of the chrysler building ( 320 m high) . How fast is it moving when it hits the ground?
A brick is lying on a table in a state of static equilibrium. If the mass of the brick is 7.52 kilograms, what is the normal force exerted by the table on the brick? A. -73.7 newtons B. 73.7 newtons C. 80.7 newtons D. 7.52 newtons E. 8.07 newtons
The answer is OPTION B : 73.7 N
Answer:
B
Explanation:
- When a mixture contains substances that are not evenly mixed, it is called?
Answer: Heterogenous mixture
Explanation:
A heterogeneous mixture in which the components of the mixture are not evenly mixed or uniform, allowing one to identify the different constituents of each components and enable the mixture to be separated physically.
Examples of heterogeneous mixtures includes
-- sand and nails
---rice and beans
--- water and oil
Another type of mixture is the homogeneous mixture in which all the components are evenly mixed causing that each components cannot be visible with the eye and therefore separated chemically.
If a 65-kilogram astronaut exerts a force with a magnitude of
50. N on a satellite that she is repairing, the magnitude of the
force that the satellite exerts on her is
50N.
The magnitude of the reaction to any force is equal to the magnitude of the first force. (See Newton #3.)
The satellite will also apply the same magnitude of force ( 50 N ) but in opposite direction.
Given data:
The mass of astronaut is, m = 65 kg.
The magnitude of force exerted on the satellite is, F = 50 N.
In this problem, we will apply the Newton's Third Law of motion, which says that, "To every action, there is an equal and opposite reaction". Which means if any object (say object 1) apply some force on another object (say object 2), then the object 2 will also apply same magnitude of force on object 1, but it will be in opposite direction.
In the given problem, the satellite will also apply the same magnitude of force on Astronaut.
Which means,
F' = - F
F' = - 50 N.
Negative sign shows that the direction of force is opposite.
Thus, we can conclude that the satellite will also apply the same magnitude of force ( 50 N ) but in opposite direction.
Learn more about the Newton's Third Law here:
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On a still water, a speedboat decreases its speed uniformly from 30 m/s to 20 m/s. How long does it take the boat to travel a distance of 200m?
a. -8 s
b. 8 s
c. -200 s
d. 200 s
Answer:
t=8
Explanation:
u have solution I give solution also
don't mark plzz follow y
Ricardo finds an online site about the gas laws. The site shows the equation below for Charles’s law. What change would correct the error on the site? “Charles’s law” should read “Gay-Lussac’s law,” which explains changes in volume and temperature. The symbol for T2 should be smaller than for T1 because if volume increases, then temperature should decrease. Each T should be replaced by a P in the equation because Charles’s law describes changes in volume and pressure. The volume should be divided by temperature on each side of the equation.
Answer:
D. The volume should be divided by temperature on each side of the equation.
Explanation:
Charles's Law is [tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }[/tex].
Answer:
The volume should be divided by temperature on each side of the equation.
Explanation:
In order to have good physical fitness, you __________. A. should be able to complete daily tasks without being physically taxed B. must be able to run a 4-minute mile C. need to work out at the gym four times a week D. don't need to worry about eating healthy foods
Answer:
A) should be able to complete daily tasks without being physically taxed
Explanation:
B) you dont need to run that fast to have good physical fitness
C) you dont need to workout four times a week
D) you should always eat healthy as diet contributes to health
In order to have good physical fitness, you should be able to complete daily tasks without being physically taxed.
What is physical fitness?Physical fitness is the ability to be fit to do work without getting tired easily.
Exercise and workouts are necessary to build and improve physical fitness.
Exercises required include jogging and running.
Therefore, in order to have good physical fitness, you should be able to complete daily tasks without being physically taxed.
Learn more about physical fitness at: https://brainly.com/question/1744272
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blutions math practice
Maddie Hicks: Attempt 1
07.5 ml
Question 4 (1 point)
You have a stock bottle of 3mM tetrodotoxin solution, but your protocol states that
you need 6ml of 1mM tetrodotoxin (MW=319.27 g/mol). How much of your 3mM
stock solution (liquid) should you use to make the 1mM solution?
Answer:
[tex]V_1=2mL[/tex]
Explanation:
Hello,
In this case, considering this as a dilution problem, the first step here is to consider that the moles of tetrodotoxin remains the same and just the volumes and concentrations are modified from the initial stock (1) and the required dilution (2):
[tex]V_1M_1=V_2M_2[/tex]
Whereas V is referred to volume and M to molar concentration, in this case in mM. In such a way, solving the V1 as the volume of the 3-mM solution we obtain:
[tex]V_1=\frac{V_2M_2}{M_1} \\\\V_1=\frac{6mL*1mM}{3mM} \\\\V_1=2mL[/tex]
It means you need 2 mL of the 3-mM solution.
Best regards.
You are trying to get to class on time using the UCF Shuttle. You are later than usual getting to the stop and see the shuttle pulling away from the stop while you are still 3.9 m behind the bus stop. In 40.9 m you will reach a barrier and you must catch the shuttle before that point. The shuttle has a constant acceleration of 4.5 m/s2. What is the minimum velocity you have to run at to catch the bus before it reaches the barrier
Answer:
20.1 m/s
Explanation:
Since You are later than usual getting to the stop and see the shuttle pulling away from the stop while you are still 3.9 m behind the bus stop. And In 40.9 m you will reach a barrier and you must catch the shuttle before that point.
Given that the shuttle has a constant acceleration of 4.5 m/s2.
The total distance to cover is:
Total distance = 40.9 + 3.9 = 44.8 m
Assuming you are starting from rest. Then initial velocity U = 0
Using the 3rd equation of motion to calculate the minimum velocity.
V^2 = U^2 + 2as
V^2 = 0 + 2 × 4.5 × 44.8
V^2 = 403.2
V = sqrt (403.2)
V = 20.1 m/s
Therefore, the minimum velocity you have to run at to catch the bus before it reaches the barrier is 20.1 m/s
A box measures 3.12 ft in length, 0.0455 yd in width and 7.87 inches in height. Since volume can be found using length x width x height, find the volume in cubic centimeters. Now find the volume in gallons.
Explanation:
This problem is on units conversion
given the dimensions
3.12 ft in length,
0.0455 yd in width and
7.87 inches in height
we have to convert to cm first
3.12 ft to cm=
1 ft-------30.48cm
3.12--------x
x=95.09cm
0.0455 yd to cm
0.0455yd ft to cm=
1 yd-------91.44cm
0.0455--------x
x=4.16cm
7.87 in to cm
1 in-------2.54cm
7.87--------x
x=19.98cm
the volume is =95.09cm*4.16cm*19.98cm
volume= 7907.45cm^3
the volume in gallon is
1 cm^3------0.000264172gal
7907.45cm^3-------x
x=7907.45*0.000264172
x=2.088gallons
True or false: points that lie on the same plane are Collinear
Torque can be best described as which of the following? Give an example of both a force and a torque and explain why in a couple of sentences.
A. Rotational force.
B. Rotational velocity.
C. Rotational energy.
D. Rotational power.
E. All of the above.
Answer: rotational force
Explanation:
Torque is the twisting force which cause rotation and the axis of rotation is the point at which the object rotates.
Torque is a rotational force as it leads to the rotation of an object about an axis. Force simply means a pull or push. When an unbalanced ball acts on a force, the ball, the ball will be moved towards the linear motion.
Then, the unbalanced force that is acting in the ball produces torque which causes the ball's rotational motion.
The Torque is best described as a rotational force.
It is the force that causes an object to rotate. Torque is measured in Newton-meters (N-m).
An example of a force is the force of gravity. When you hold a ball in your hand, the force of gravity is pulling down on the ball.
However, the ball is not rotating because the force of gravity is being counteracted by the force of your hand pushing up on the ball.
An example of a torque is when you use a wrench to loosen a bolt. When you apply force to the wrench, you are creating a torque that is trying to turn the bolt.
The more force you apply, the greater the torque.
Torque is not the same as rotational velocity. Rotational velocity is the rate at which an object is rotating. It is measured in radians per second (rad/s).
Torque is also not the same as rotational energy.
Rotational energy is the energy that an object has due to its rotation.
It is measured in joules (J).
Torque is also not the same as rotational power. Rotational power is the rate at which rotational energy is transferred. It is measured in watts (W).
Learn more about Torque with the given link,
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What is 902 in proper scientific notation?
What potential difference is required to produce a current of 0.5 A in a bulb of power 60 W
Answer:
ans is 120
Explanation:
I= 0.5 A
p= 60w
p=Iv
60/0.5
v= 120
Answer:
V=P/I
V=60/0.5
V=120
Explanaton:
the formula P=IV is converted to V=P/I to make V (voltage) the subject. then sub in the values to get your answer
note that potential difference is same as voltage