Ai Mi went to the store to buy some chicken. The price per pound of the chicken is $3.50 per pound and she has a coupon for $2.50 off the final amount. With the coupon, how much would Ai Mi have to pay to buy 3 pounds of chicken? Also, write an expression for the cost to buy pp pounds of chicken, assuming at least one pound is purchased.

Answers

Answer 1

Answer:

$8 for 3 pounds

cost for p pounds: 3.50p - 2.50

Step-by-step explanation:

Cost of 3 pounds:

Original cost = Cost per pound x 3

= 3.50 x 3

= 10.50

Coupon = 2.50

Final cost = Original cost - Coupon

= 10.50 - 2.50

= $8

Cost of p pounds:

Original cost = Cost per pound x p

= 3.50 x p

= 3.50p

Coupon = 2.50

Final Cost = Original Cost - Coupon

= 3.50p - 2.50

Answer 2

Ai Mi has to pay $8 to buy 3 pounds of chicken.  An expression for the cost to buy p pounds of chicken would be; 3.50p - 2.50

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

The Cost of 3 pounds:

Thus Original cost = Cost per pound x 3

= 3.50 x 3

= 10.50

Also, we know that the Coupon cost is 2.50

The Final cost = Original cost - Coupon

= 10.50 - 2.50

= $8

Now Let the Cost of pounds is p

The Original cost = Cost per pound x p

= 3.50 x p

= 3.50p

Also the cost of the Coupon = 2.50

The Final Cost = Original Cost - Coupon

= 3.50p - 2.50

Hence, Ai Mi has to pay $8 to buy 3 pounds of chicken.  An expression for the cost to buy p pounds of chicken would be; 3.50p - 2.50

To learn more about the unitary method, please visit the link given below;

https://brainly.com/question/23423168

#SPJ2


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Answers

Answer: The age of the fossilized leaf is 13829 years.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

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b) for finding the age

[tex]t=\frac{2.303}{0.00012}\log\frac{100}{18}[/tex]  

[tex]t=13829years[/tex]

The age of the fossilized leaf is 13829 years.

The fossilized leaf is 13855 years old.

Half life is given by:

[tex]N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\Where\ N(t)\ is \ the \ value\ of\ the\ substance\ after\ t\ years,N_o\ is\ the\\original\ value\ and\ t_\frac{1}{2} \ is\ the\ half\ life[/tex]

Given that half life = 5600 years, N(t) = 18% of normal amount = 0.18N₀. Hence:

[tex]0.18N_o=N_o(\frac{1}{2} )^\frac{t}{5600} \\\\0.18=(\frac{1}{2} )^\frac{t}{5600}\\\\ln(0.18)=\frac{t}{5600}ln(0.5)\\\\t=13855\ years[/tex]

The fossilized leaf is 13855 years old.

Find out more at: https://brainly.com/question/4483570

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