Answer:
B. UDP 67
C. UDP 68
Explanation:
In this scenario, after a new firewall is installed, users report that they do not have connectivity to the Internet. The output of the ipconfig command shows an IP address of 169.254.0.101. The ports that would need to be opened on the firewall to allow the users to obtain an IP address are both the UDP 67 and UDP 68. UDP is an acronym for user datagram protocol in computer networking and it is part of the transmission control protocol/internet protocol (TCP/IP) suite.
Generally, the standard Internet communications protocols which allow digital computers to transfer (prepare and forward) data over long distances is the TCP/IP suite.
Also, the UDP 67 and 68 ports is responsible for the connectionless framework which is typically being used by the dynamic host configuration protocol (DHCP) that is used to assign IP addresses to various computer users and manage their leases.
UDP 67 is the destination port for a DHCP server while the UDP 68 is the port number for the computer user (client).
Hence, for the users to have access to the internet or internet connectivity both UDP 67 and 68 must be opened on the firewall.
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we could do division quickly. Would it be reasonable to compute an RSA signature on a long message by first finding what the message equals (taking the message as a big integer), mod n, and signing that?
Answer:
Following are the algorithm to this question:
Explanation:
In the RSA algorithm can be defined as follows:
In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.
Computing N = PQ.
In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,
[tex]\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)[/tex] where [tex]\lambda[/tex] is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from [tex]1<E < \lambda (N)[/tex]and [tex]gcd(E, \lambda (N) ) = 1;[/tex] that is [tex]E \ \ and \ \ \lambda (N)[/tex]. D was its complex number equivalent to E (modulo [tex]\lambda (N)[/tex] ); that is d was its design multiplicative equivalent of E-1.
It's more evident as a fix for d provided of DE ≡ 1 (modulo [tex]\lambda (N)[/tex] ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.
In some situations it's was shown that far lower E values (such as 3) are less stable.
E is eligible as a supporter of the public key.
D is retained as the personal supporter of its key.
Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and [tex]\lambda (N)[/tex] will also be confined as they can be used in measuring D. The Euler totient operates [tex]\varphi (N) = (P-1)(Q - 1)[/tex] however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).
It applies because [tex]\varphi (N)[/tex], which can always be split into [tex]\lambda (N)[/tex], and thus any D satisfying DE ≡ 1, it can also satisfy (mod [tex]\lambda (N)[/tex]). It works because [tex]\varphi (N)[/tex], will always be divided by [tex]\varphi (N)[/tex],. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D > [tex]\lambda (N)[/tex] ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D< [tex]\lambda (N)[/tex]. if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo [tex]\lambda (N)[/tex].
As there are common threads (P− 1) and (Q – 1) which are present throughout the [tex]N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))[/tex], it's also possible, if there are any, for all the common factors [tex](P -1) \ \ \ and \ \ (Q - 1)[/tex]to become very small, if necessary.
Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module [tex]\varphi (N)[/tex]) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.
what are the different versions of Ms word?
Answer:
ms paint will not attend as the ICRC is the time to move becuse to get free skin on your skin that you have a doubt about the quality and
1011111 ÷ 11 in numerical
Answer:
91919.18182
Explanation:
Answer:
91,919 .1HOPE IT HELPS .
Can someone compress this ipv6 address? 558c:0000:0000:d367:7c8e:1216:0000:66be
558c::d367:7c8e:1216:0:66be
________type of website is an interactive website kept constantly updated and relevant to the needs of its customers using a database.
Answer:
Data-driven Website
Explanation:
A Data-driven website is a type of website that is continually updated by its administrators so as to meet users' needs. It is opposed to a static website whose information remains the same and is never changed once uploaded.
The data-driven website is used in a platform where information has to be continually updated. An example is an online platform where people place orders for goods and services. There are usually changing prices and new goods continually uploaded. So, to keep the consumers updated, the administrators of such platforms would use a data-driven platform.
As an ICT student teacher using convincing and cogent reasons explain why you think operating system is pivotal in teaching and learning
Answer:
An operating system (OS) is a software which is responsible for the management of computer hardware, software, and also provides common services for computer programs.
Operating System is pivotal in teaching and learning because:
1. It enables computer programs to run smoothly on various computer devices.
2. The Operating System gives teachers the opportunity to install learning apps on their devices for ease of teaching.
3. It enables students to download and install learning applications, download and upload assignments, etc.
4. The Operating System makes video conferencing for online tuition easy and smooth.
5. It makes computer users to interact with other applications and softwares within a device.
Operating systems are found on many computer devices e.g: mobile phones, video games, PCs, supercomputers, etc.
mplement the function fileSum. fileSum is passed in a name of a file. This function should open the file, sum all of the integers within this file, close the file, and then return the sum.If the file does not exist, this function should output an error message and then call the exit function to exit the program with an error value of 1.Please Use This Code Template To Answer the Question#include #include #include //needed for exit functionusing namespace std;// Place fileSum prototype (declaration) hereint main() {string filename;cout << "Enter the name of the input file: ";cin >> filename;cout << "Sum: " << fileSum(filename) << endl;return 0;}// Place fileSum implementation here
Answer:
Which sentence best matches the context of the word reticent as it is used in the following example?
We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.
Explanation:
Which sentence best matches the context of the word reticent as it is used in the following example?
We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.
Write a script named dif.py. This script should prompt the user for the names of two text files and compare the contents of the two files to see if they are the same. If they are, the script should simply output "Yes". If they are not, the script should output "No", followed by the first lines of each file that differ from each other. The input loop should read and compare lines from each file, including whitespace and punctuation. The loop should break as soon as a pair of different lines is found.
Answer:
Following are the code to this question:
f1=input('Input first file name: ')#defining f1 variable that input file 1
f2=input('Input second file name: ')#defining f2 variable that input file 2
file1=open(f1,'r')#defining file1 variable that opens first files by using open method
file2=open(f2,'r')#defining file1 variable that opens second files by using open method
d1=file1.readlines()#defining d1 variable that use readlines method to read first file data
d2=file2.readlines()#defining d2 variable that use readlines method to read second file data
if d1==d2:#defining if block that check file data
print('Yes')#when value is matched it will print message yes
exit# use exit keyword for exit from if block
for j in range(0,min(len(d1),len(d2))):#defining for loop that stores the length of the file
if (d1[j]!=d2[j]):#defining if block that check value is not matched
print('No')#print the message "NO"
print("mismatch values: ",d1[j]," ",d2[j])#print file values
Output:
please find the attached file.
Explanation:
code description:
In the above code, the "f1 and f2" variable is used for input value from the user end, in which it stores the file names. In the next step, the "file1 and file2" variable is declared that uses the open method to open the file. In the next line, the"d1 and d2" variable is declared for reads file by using the "readlines" method. Then, if block is used that uses the "d1 and d2" variable to match the file value if it matches it will print "yes", otherwise a for loop is declared, that prints files mismatch values.Answer:
first = input("enter first file name: ")
second = input("enter second file name: ")
file_one = open(first, 'r')
file_two = open(second, 'r')
if file_one.read() == file_two.read():
print("Both files are the same")
else:
print("Different files")
file_one.close()
file_two.close()
Consider the following Stack operations:
push(d), push(h), pop(), push(f), push(s), pop(), pop(), push(m).
Assume the stack is initially empty, what is the sequence of popped values, and what is the final state of the stack? (Identify which end is the top of the stack.)
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
Write a Python program stored in a file q1.py to play Rock-Paper-Scissors. In this game, two players count aloud to three, swinging their hand in a fist each time. When both players say three, the players throw one of three gestures: Rock beats scissors Scissors beats paper Paper beats rock Your task is to have a user play Rock-Paper-Scissors against a computer opponent that randomly picks a throw. You will ask the user how many points are required to win the game. The Rock-Paper-Scissors game is composed of rounds, where the winner of a round scores a single point. The user and computer play the game until the desired number of points to win the game is reached. Note: Within a round, if there is a tie (i.e., the user picks the same throw as the computer), prompt the user to throw again and generate a new throw for the computer. The computer and user continue throwing until there is a winner for the round.
Answer:
The program is as follows:
import random
print("Rock\nPaper\nScissors")
points = int(input("Points to win the game: "))
player_point = 0; computer_point = 0
while player_point != points and computer_point != points:
computer = random.choice(['Rock', 'Paper', 'Scissors'])
player = input('Choose: ')
if player == computer:
print('A tie - Both players chose '+player)
elif (player.lower() == "Rock".lower() and computer.lower() == "Scissors".lower()) or (player.lower() == "Paper".lower() and computer.lower() == "Rock".lower()) or (player == "Scissors" and computer.lower() == "Paper".lower()):
print('Player won! '+player +' beats '+computer)
player_point+=1
else:
print('Computer won! '+computer+' beats '+player)
computer_point+=1
print("Player:",player_point)
print("Computer:",computer_point)
Explanation:
This imports the random module
import random
This prints the three possible selections
print("Rock\nPaper\nScissors")
This gets input for the number of points to win
points = int(input("Points to win the game: "))
This initializes the player and the computer point to 0
player_point = 0; computer_point = 0
The following loop is repeated until the player or the computer gets to the winning point
while player_point != points and computer_point != points:
The computer makes selection
computer = random.choice(['Rock', 'Paper', 'Scissors'])
The player enters his selection
player = input('Choose: ')
If both selections are the same, then there is a tie
if player == computer:
print('A tie - Both players chose '+player)
If otherwise, further comparison is made
elif (player.lower() == "Rock".lower() and computer.lower() == "Scissors".lower()) or (player.lower() == "Paper".lower() and computer.lower() == "Rock".lower()) or (player == "Scissors" and computer.lower() == "Paper".lower()):
If the player wins, then the player's point is incremented by 1
print('Player won! '+player +' beats '+computer)
player_point+=1
If the computer wins, then the computer's point is incremented by 1
else:
print('Computer won! '+computer+' beats '+player)
computer_point+=1
At the end of the game, the player's and the computer's points are printed
print("Player:",player_point)
print("Computer:",computer_point)
Design a class named Rectangle to represent a rectangle. The class contains:
Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height.
A no-arg constructor that creates a default rectangle.
A constructor that creates a rectangle with the specified width and height.
A method named getArea() that returns the area of this rectangle.
A method named getPerimeter() that returns the perimeter.
Draw the UML diagram for the class then implement the class. Write a test program that create two Rectangle objects - one with width 4 and height 40, and the other with width 3.5 and height 35.9.
Display the width, heigth, area, and perimeter of each rectangle in this order.
Answer:
function Rectangle(width=1, height= 1 ) {
this.width= width;
this.height= height;
this.getArea= ( ) = > {return width * height};
this.getPerimeter= ( ) = >{ return 2( height + width)};
}
var rectangleOne= new Rectangle(4, 40)
var rectangleTwo= new Rectangle(3.5, 35.9)
console.log(rectangleOne.width, rectangleOne.height, rectangleOne.getArea( ), rectangleOne.getPerimeter( ) )
console.log(rectangleTwo.width, rectangleTwo.height, rectangleTwo.getArea( ), rectangleTwo.getPerimeter( ) )
Explanation:
This is a Javascript class definition with a constructor specifying arguments with default values of one for both width and height, and the getArea and getPerimeter methods.
When you start your computer then which component works first?
UAAR is planning to build in house software similar to Zoom Application. University Authorities contact with you in order to provide best solution with in limited time and limited resources in term of cost.
Describe the roles, Artifacts and activities, keeping in view Scrum process model.
Compare and contract your answer with scrum over XP for development of above mention system. Justify your answer with the help of strong reasons, why you choose scrum model over XP model. How scrum is more productive for project management. Furthermore, highlight the shortcoming of XP model.
Answer:
Following are the answer to this question:
Explanation:
If working to develop Zoom-like house software, its best solution is now in a limited period of time even with effectively reduced assets;
Evaluate all roles in preparation
Create a "Pool Draw"
Choose a singular set of resources.
Utilize Time Recording.
Concentrate on assignments and project objectives.
An object, in which by-product of the development in the software. It's created for the development of even a software program. It could include database schemas, illustrations, configuration screenplays-the list just goes on.
All development activities of Scrum are composed with one or several groups from a lineout, each containing four ruck roles:
Holder of the drug
ScrumMaster and Master
Equipment for development.
Owner of the drug
It is the motivating core of the product marketing idea, that Keeps transparent the vision about what the team member is trying to seek so that to accomplish as well as interacts to all of the other members, the project manager is responsible for the success of the way to solve being formed or retained.
ScrumMaster It operates as a mentor and providing guidance throughout the development phase, it takes a leadership position in the abolishment with impediments that also impact employee productivity and therefore have no ability to control the team, but the roles of both the project team or program manager are not quite the same thing. It works as a leader instead of the management team.
Equipe for development
The Scrum characterizes the design team as a diverse, multi-functional community of individuals who design, construct as well as evaluate the application of those who want.
In this usually 5 to 9 individuals; one's representatives should be able to make quality responsive applications collaboratively.
It is a framework that operates along with teams. It is often seen as agile project management as well as explains a set of conferences, techniques, and roles that also assist individuals to organize as well as complete their employees together. The multidisciplinary team from Scrum means that a person should take a feature from idea to completion.Scrum and XP differences:
Its team members in Scrum usually operate in the various weeks with one month-long incarnation. The XP teams generally work in incarnations which are either one two weeklong. Scrum doesn't write a prescription the certain project management; XP seems to do. Scrum may not make access to other their sprints. XP teams are far more receptive to intervention inside of their repetitions.The invention of the integrated circuit was the first major advance in computing. The integrated circuit made it possible for all of a computer's electrical components to reside on one silicon chip.
This invention became known as the __________.
personal computer
microprocessor
client-server configuration
mainframe computer
Answer:
micro processor
Explanation:
Enum fruit_tag {
BLUEBERRY,
BANANA,
PINEAPPLE,
WATERMELON
};
typedef enum fruit_tag fruit_t;
void printFruit(fruit_t myFruit) {
switch(myFruit) {
case BLUEBERRY:
printf("a blueberry");
break;
case BANANA:
printf("a banana");
break;
case PINEAPPLE:
printf("a pineapple");
break;
case WATERMELON:
printf("a watermelon");
break;
}
}
void compareFruit(fruit_t fruit1, fruit_t fruit2) {
if (fruit1 > fruit2) {
printFruit(fruit1);
printf(" is larger than ");
printFruit(fruit2);
}
else {
printFruit(fruit1);
printf(" is smaller than ");
printFruit(fruit2);
}
}
int main(void) {
fruit_t myFruit = PINEAPPLE;
fruit_t otherFruit = BLUEBERRY;
compareFruit(myFruit, otherFruit);
return 0;
What is the output?
Answer:
The output is "a pineapple is larger than a blueberry ".
Explanation:
In the given C language code Enum, typedef, and two methods "printfruit and compareFruit" is declared, that can be defined as follows:
In the enum "fruit_tag" there are multiple fruit name is declared that use as the datatypes. In the next line, the typedef is defined, that enum to define another datatype that is "fruit_t". In the next step, the printFruit method is defined that accepts "myFruit" variable in its parameter and use the switch case to to check value. In the "compareFruit" method, it accepts two parameters and uses the if-else block to check its parameters value and print its value. In the main method, two variable "myFruit and otherFruit" variable is declared that stores the values and pass into the "compareFruit" method and call the method.Raj was concentrating so much while working on his project plan that he was late for a meeting. When he went back to his office, he noticed his system was restarted and his project file was not updated. What advice would you provide Raj in this situation?
Answer:
Explanation:
Depending on the software that Raj was using to create his project he should first see if the software itself saved the project. Usually many software such as those included in the Microsoft Office Suite save the file automatically every 5 minutes or so in case of a power outage or abrupt closure of the file. If this is not the case he should try and do a system restore with the unlikely hope that it restores an older version of his project.
In a situation like this, it would be advisable for Raj to contact IT personnels and seek if the files could be retrieved.
Raj being late for a meeting due to what he was doing meant that the project he was working on is very important. Therefore, to avoid losing thses files, he could contact the IT personnels and request if there is a way to retrieve the project file.These way, the files could be retrieved and avoid losing his work.
Learn more : https://brainly.com/question/15315011
what privacy risks do new technologies present,
and how do we decide if they're worth it?
Answer:
Los riesgos de las nuevas tecnologías se multiplican a medida que nos hacemos dependientes de ellas. También lo hacen a medida que sustituyen a otras formas de contacto social más cercanas
Los riesgos de las nuevas tecnologías son grandes desconocidos. El mal uso de las redes sociales y de Internet en los ordenadores y en el teléfono móvil, entre otros factores, supone un peligro real para todos los estratos de población, pero en especial para los más jóvenes. Pensemos, ¿realmente somos conscientes de los riesgos que suponen las nuevas tecnologías? ¿Sabemos cómo utilizarlas para no ponernos en riesgo?
Cabe destacar que las denominadas nuevas tecnologías de la información y de la comunicación (TICs) son un distintivo de la época actual y se han convertido en herramientas esenciales en las diferentes áreas de la vida. Esto es, para el área académica, laboral, social, de ocio…
En la mayoría de los ámbitos están presentes las TICS, pues incluyen las diferentes herramientas con las que nos manejamos hoy en día: servicios de contacto electrónico (e-mails, servicios de mensajería instantánea, chats), los teléfonos móviles, tablets y ordenadores, las plataformas online de difusión de contenidos, las redes sociales, entre otros..
Explanation:
The Cartesian product of two lists of numbers A and B is defined to be the set of all points (a,b) where a belongs in A and b belongs in B. It is usually denoted as A x B, and is called the Cartesian product since it originated in Descartes' formulation of analytic geometry.
a. True
b. False
The properties and origin of the Cartesian product as stated in the paragraph
is true, and the correct option is option;
a. True
The reason why the above option is correct is stated as follows;
In set theory, the Cartesian product of two number sets such as set A and set
B which can be denoted as lists of numbers is represented as A×B and is the
set of all ordered pair or points (a, b), with a being located in A and b located
in the set B, which can be expressed as follows;
[tex]\left[\begin{array}{c}A&x&y\\z\end{array}\right] \left[\begin{array}{ccc}B(1&2&3)\\\mathbf{(x, 1)&\mathbf{(x, 2)}&\mathbf{(x, 3)}\\\mathbf{(y, 1)}&\mathbf{(y, 2)}&\mathbf{(y, 3)}\\\mathbf{(z, 1)}&\mathbf{(z, 2)}&\mathbf{(z, 3)}\end{array}\right]}[/tex]
The name Cartesian product is derived from the name of the philosopher,
scientist and mathematician Rene Descartes due to the concept being
originated from his analytical geometry formulations
Therefore, the statement is true
Learn more about cartesian product here:
https://brainly.com/question/13266753
which approach does procedural programming follow? bottom up, top down, random, or object oriented
Answer:
Top to down approach
Explanation:
Consider two different implementations of the same instruction set architecture (ISA). The instructions can be divided into four classes according to their CPI (class A, B, C, and D). P1 with a clock rate of 2.5 GHz have CPIs of 1, 2, 3, and 3 for each class, respectively. P2 with a clock rate of 3 GHz and CPIs of 2, 2, 2, and 2 for each class, respectively. Given a program with a dynamic instruction count of 1,000,000 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C, and 20% class D.which implementation is faster?
a. What is the global CPI for each implementation?
b. Find the clock cycles required in both cases.
Answer: Find answers in the attachments
Explanation:
Explain how/where could you change the NIC Card configuration from dynamic DHCP setting to an IP address of 10.254.1.42 with a subnet mask of 255.255.0.0 and a gateway of 10.254.0.1. (hint: we spoke about 2 different methods)
Answer:
Using the terminal in linux OS to configure a static ip address, gateway and subnet mask.
Explanation:
-Enter the terminal in the linux environment and use the ifconfig eth0 or -a to bring up the main network interface and other network interfaces.
- for static network configuration, use;
- ifconfig eth0 10.254.1.42
- ifconfig eth0 netmask 255.255.0.0
- ifconfig eth0 broadcast 10.254.255.255
- and add a default gateway with;
- route add default gw 10.254.0.1 eth0.
- Now verify the settings with the ifconfig eth0 command.
Assign decoded_tweet with user_tweet, replacing any occurrence of 'TTYL' with 'talk to you later'.Sample output with input: 'Gotta go. I will TTYL.'Gotta go. I will talk to you later.code given:user_tweet = input()decoded_tweet = ''' Your solution goes here '''print(decoded_tweet)
Answer:
Here is the Python program:
user_tweet = input()
decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')
print(decoded_tweet)
Explanation:
The program works as follows:
Suppose the input is: 'Gotta go. I will TTYL'
This is stored in user_tweet. So
user_tweet = 'Gotta go. I will TTYL'
The statement: user_tweet.replace('TTYL', 'talk to you later') uses replace() method which is used to replace a specified string i.e. TTYL with another specified string i.e. talk to you later in the string stored in user_tweet.
The first argument of this method replace() is the string or phrase that is to be replaced and the second argument is the string or phrase that is to replace that specified string in first argument.
So this new string is assigned to decoded_tweet, after replacing 'TTYL' with 'talk to you later' in user_tweet.
So the print statement print(decoded_tweet) displays that new string.
Hence the output is:
Gotta go. I will talk to you later.
What is true about the pivot in Quicksort? Group of answer choices After partitioning, the pivot will always be in the center of the list. After partitioning, the pivot will never move again. Before partitioning, it is always the smallest element in the list. A random choice of pivot is always the optimal choice, regardless of input.
Answer:
The pivot is selected randomly in quick sort.
During the name resolution process, which technique is used to avoid congestion when querying a server
Answer:
"NOT lookup " is the correct approach.
Explanation:
This methodology significantly reduces the quantity of congestion of DNS messages on a certain file. The application establishes that whenever a question reaches if it is processed. Unless the file is loaded, then perhaps the response is returned with the cached cache.Typically the name resolution occurs in something like a DNS File. The conversion usually occurs throughout this cycle from Username to IP, including IP via Username.Write the following numbers in binary. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 46. 55. 61.
viết chương trình hoàn chỉnh các yêu cầu sau:
a. Định nghĩa hàm có tên là PSTG(), có hai tham số kiểu nguyên x và y hàm trả về giá trị phân số x/y ở dạng tối giản.
b. Gọi hàm đã định nghĩa ở trên trong hàm main () để in lên mà hình một phân số x/y ở dạng tối giản, với x và y được nhập từ bàn phím.
Explanation:
the perimeter of an aluminium sheet is 120 CM if its length is reduced by 10% and its breadth is increased by 20% the perimeter does not change find the measure of the length and the breadth of the sheet
All of the following are extra precautions you can take to secure a wireless network EXCEPT ________. change your network name (SSID) enable SSID broadcast turn on security protocols create a passphrase
Answer:
Enable SSID broadcast
Explanation:
All of the following are extra precautions you can take to secure a wireless network except enable SSID broadcast. The correct option is B.
What is SSID broadcast?When people in the area try to join their wireless devices, the name of your network is listed in the list of available networks thanks to broadcasting the SSID.
You can stop SSID broadcasting if you don't want arbitrary wireless devices attempting to connect to your network.
Home networks don't need to have a visible SSID unless they have many access points that devices can switch between.
If your network just has a single router, disabling this function means giving up the ease of adding new home network customers in exchange for certain security gains.
Apart from enabling SSID broadcast, there are other security measures you may take to protect a wireless network.
Thus, the correct option is B.
For more details regarding SSID broadcast, visit:
https://brainly.com/question/13191413
#SPJ6
What command would you use to place the cursor in row 10 and column 15 on the screen or in a terminal window
Answer:
tput cup 10 15
Explanation:
tput is a command for command line environments in Linux distributions. tput can be used to manipulate color, text color, move the cursor and generally make the command line environment alot more readable and appealing to humans. The tput cup 10 15 is used to move the cursor 10 rows down and 15 characters right in the terminal
Create a class named CarRental that contains fields that hold a renter's name, zip code, size of the car rented, daily rental fee, length of rental in days, and total rental fee. The class contains a constructor that requires all the rental data except the daily rate and total fee, which are calculated bades on the sice of the car; economy at $29.99 per day, midsize at 38.99$ per day, or full size at 43.50 per day. The class also includes a display() method that displays all the rental data. Create a subclass named LuxuryCarRental. This class sets the rental fee at $79.99 per day and prompts the user to respond to the option of including a chauffer at $200 more per day. Override the parent class display() method to include chauffer fee information. Write an application named UseCarRental that prompts the user for the data needed for a rental and creates an object of the correct type. Display the total rental fee. Save the files as CarRental.java, LuxaryCarRental.java, and UseCarRental.java.
Here is my code:
package CarRental;
public class CarRental
{
String name;
int zipcode;
String size;
double dFee;
int days;
double total;
public String getName()
{
return name;
}
public int getZipcode()
{
return zipcode;
}
public String getSize()
{
return size;
}
public int getDays()
{
return days;
}
public CarRental(String size)
{
if(size.charAt(0)=='m')
dFee = 38.99;
else
if(size.charAt(0)=='f')
dFee = 43.50;
else
dFee = 29.99;
}
public void calculateTotal(int days)
{
total = dFee*days;
}
public void print()
{
System.out.println("Your rental total cost is: $" + total);
}
}
package CarRental;
import java.util.*;
public class LuxaryCarRental extends CarRental
{
public LuxaryCarRental(String size, int days)
{
super(size);
}
public void CalculateTotalN()
{
super.calculateTotal(days);
dFee = 79.99;
int chauffer;
Scanner keyboard = new Scanner(System.in);
System.out.println("Do you want to add a chauffer for $200? Enter 0 for"
+ " yes and 1 for no");
chauffer = keyboard.nextInt();
if(chauffer!=1)
total = dFee;
else
total = dFee + 100;
}
}
package CarRental;
import java.util.*;
public class UseCarRental
{
public static void main(String args[])
{
String name, size;
int zipcode, days;
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter total days you plan on renting: ");
days = keyboard.nextInt();
System.out.println("Enter your name: ");
name = keyboard.next();
System.out.println("Enter your billing zipcode: ");
zipcode = keyboard.nextInt();
System.out.println("Enter the size of the car: ");
size = keyboard.next();
CarRental economy = new CarRental(size);
economy.calculateTotal(days);
economy.print();
LuxaryCarRental fullsize = new LuxaryCarRental(size, days);
fullsize.CalculateTotalN();
fullsize.print();
}
Answer:
Here is the corrected code: The screenshot of the program along with its output is attached. The comments are written with each line of the program for better understanding of the code.
CarRental.java
public class CarRental { //class name
//below are the data members name, zipcode, size, dFee, days and total
String name;
int zipcode;
String size;
double dFee;
int days;
double total;
public String getName() { //accessor method to get the name
return name; }
public int getZipcode() { //accessor method to get the zipcode
return zipcode; }
public String getSize() { //accessor method to get the size
return size; }
public int getDays() { //accessor method to get the days
return days; }
public CarRental(String size) { //constructor of CarRental class
if(size.charAt(0)=='e') // checks if the first element (at 0th index) of size data member is e
dFee = 29.99; // sets the dFee to 29.99
else if(size.charAt(0)=='m') // checks if the first element (at 0th index) of size data member is m
dFee = 38.99; // sets the dFee to 38.99
else // checks if the first element (at 0th index) of size data member is f
dFee =43.50; // sets the dFee to 43.50
}
public void calculateTotal(int days) { //method calculateTotal of CarRental
total = dFee*days; } //computes the rental fee
public void print() { //method to display the total rental fee
System.out.println("Your rental total cost is: $" + total); } }
Explanation:
LuxuryCarRental.java
import java.util.*;
public class LuxuryCarRental extends CarRental { //class LuxuryCarRental that is derived from class CarRental
public LuxuryCarRental(String size, int days) { // constructor of LuxuryCarRental
super(size);} //used when a LuxuryCarRental class and CarRental class has same data members i.e. size
public void calculateTotal() { //overridden method
super.calculateTotal(days); // used because CarRental and LuxuryCarRental class have same named method i.e. calculateTotal
dFee = 79.99; //sets the rental fee at $79.99 per day
total = dFee; } //sets total to rental fee value
public void print(){ //overridden method
int chauffeur; // to decide to include chauffeur
Scanner keyboard = new Scanner(System.in); //used to take input from user
System.out.println("Do you want to add a chauffeur for $200? Enter 0 for"
+ " yes and 1 for no"); // prompts the user to respond to the option of including a chauffeur at $200 more per day
chauffeur = keyboard.nextInt(); //reads the input option of chauffeur from user
if(chauffeur==1) //if user enters 1 which means user does not want to add a chauffeur
total = dFee; //then set the value of dFee i.e. $79.99 to total
else //if user enters 0 which means user wants to add a chauffeur
total = dFee + 200; //adds 200 to dFee value and assign the resultant value to total variable
System.out.println("Your rental total cost is: $" + total); } } //display the total rental fee
UseCarRental.java
import java.util.*;
public class UseCarRental{ //class name
public static void main(String[] args){ //start of main() function body
String name, size; // declare variables
int zipcode, days; //declare variables
Scanner keyboard = new Scanner(System.in); // to take input from user
System.out.println("Enter total days you plan on renting: "); //prompts user to enter total days of rent
days = keyboard.nextInt(); // reads value of days from user
System.out.println("Enter your name: "); //prompts user to enter name
name = keyboard.next(); //reads input name from user
System.out.println("Enter your billing zipcode: "); // prompts user to enter zipcode
zipcode = keyboard.nextInt(); //reads input zipcode from user
System.out.println("Enter the size of the car: "); // prompts user to enter the value of size
size = keyboard.next(); //reads input size from user
CarRental economy = new CarRental(size); //creates an object i.e. economy of class CarRental
economy.calculateTotal(days); //calls calculateTotal method of CarRental using instance economy
economy.print(); //calls print() method of CarRental using instance economy
LuxuryCarRental fullsize = new LuxuryCarRental(size, days); //creates an object i.e. fullsize of class LuxuryCarRental
fullsize.calculateTotal(); //calls calculateTotal method of LuxuryCarRental using instance fullsize
fullsize.print(); }} //calls print() method of LuxuryCarRental using instance fullsize
Tại một xí nghiệp có ba máy làm việc độc lập. Trong một ca, xác suất cần sửa
chữa của từng máy lần lượt là 0,1; 0,15; 0,2. Tính xác suất để trong một ca:
a) Không có máy nào cần sửa chữa.
b) Có nhiều nhất hai máy cần sửa chữa.
bạn tìm ra cách giải chưa chỉ mình với
thanks b