After a long day of driving you take a late-night swim in a motel swimming pool. When you go to your room, you realize that you have lost your room key in the pool. You borrow a powerful flashlight and walk around the pool, shining the light into it. The light shines on the key, which is lying on the bottom of the pool, when the flashlight is held 1.2 m above the water surface and is directed at the surface a horizontal distance of 1.5 m from the edge (Fig. P33.44). If the water here is 4.0 m deep, how far is the key from the edge of the pool

Answer:

The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Explanation:

Given the data in the question;

from the Newton's second law of motion;

F = ma

where m is the mass, a is acceleration and F is the force exerted on the pipe due to the airflow in it

now in terns of mass flow;

F = [tex]m^{"}[/tex]V

where [tex]m^{"}[/tex] is the mass flow rate, V is the velocity(

so

[tex]m^{"}[/tex] = pAV

[tex]m^{"}[/tex] = p × ([tex]\frac{\pi }{4}[/tex] d² ) × V

where d is the diameter of the pipe( 0.5 m)

p is the density( 1.23 kg/m³ )

velocity v is 100 m/s

so we substitute

[tex]m^{"}[/tex] = 1.23 × ([tex]\frac{\pi }{4}[/tex] (0.5)² ) × 100

[tex]m^{"}[/tex] = 30.75 × [tex]\frac{\pi }{4}[/tex]

[tex]m^{"}[/tex] = 24.15 kg/s

Now lets write the equation for the force exerted on the pipe by the airflow

F = [tex]m^{"}[/tex]( V₁ - V₂)

where V₁ is velocity at inlet ( 100 m/s )

V₂ is velocity at exit ( - 100 m/s )

so we substitute

F = 24.15 ( 100 - (-100))

F = 24.15 × 200

F = 4830 N

The pipe is symmetric about horizontal axis so the force should also b acting only in the horizontal direction since any force component in the vertical direction is nullified due to this symmetry

Therefore, The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Answer:

300

Explanation Hope I'm not wrong.

Answer:

yes it is a great question. Thank you .

Answer:

L = 30.85 m

Explanation:

First, we calculate the resistance of the wire by using Ohm's Law:

V = IR

where,

V = Potential Difference = 1.5 V

I = Current = 0.42 A

R = Resistance of Wire = ?

Therefore,

[tex]R = \frac{1.5\ V}{0.42\ A}\\\\R = 3.57\ Ohms[/tex]

Now, the cross-sectional area of wire will be:

[tex]Area = A = \frac{\pi d^{2}}{4}\\\\A = \frac{\pi (0.00054\ m)^{2}}{4}\\\\A = 2.29\ x\ 10^{-7}\ m^{2}[/tex]

Now, the resistance of the wire is given as:

[tex]R = \frac{\rho L}{A}\\\\L = \frac{RA}{\rho}[/tex]

where,

L = Length of Wire = ?

ρ = resistivity of aluminum = 2.65×10⁻⁸ Ohm.m

Therefore,

[tex]L = \frac{(3.57\ Ohms)(2.29\ x\ 10^{-7}\ m^{2})}{2.65\ x\ 10^{-8}\ Ohm.m}[/tex]

L = 30.85 m

Answer:

Yes.

Explanation:

Answer:

I do believe it is. (more characters for character limit)

Answer:

T₁ = 15.66 N

Explanation:

From the given information:

Using the free body system in the chain.

T - mg = ma

47 - 3.12 × 9.8 = 3.12a

47 - 30.576  = 3.12a

16.424 = 3.12a

a = 16.424/3.12

a = 5.26 m/s²

Now, by the free body diagram of the lowest link; the tension (T₁ ) in the chain is:

T₁ - (3.12/3)  × 9.8 = (3.12/3) × 5.26

T₁ - 1.04 × 9.8 = 1.04  × 5.26

T₁ - 10.192 = 5.4704

T₁ = 5.4704 + 10.192

T₁ = 15.6624

T₁ = 15.66 N

Explanation:

Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.

Answer:

if you are very excited to know why ball doesn't go up

Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

Answer:

momentum = mass × velocity = 6× 20 =120 kg.ms-1

Explanation:

not sure if this is right

Answer:

The net force will be:

[tex] F_{net} = 142.53\: N[/tex]

Explanation:

The net force is given by:

[tex] F_{net} = W_{b}+F[/tex]

[tex] F_{net} = m_{b}g+15[/tex]

[tex] F_{net} = 142.53\: N[/tex]

I hope it helps you!

Answer:

True.

Explanation:

The density of an object is given by its mass divided by its volume. It can be given as follows :

[tex]d=\dfrac{m}{V}[/tex]

It can be seen that the density of an object is directly proportional to its mass. It means if the mass of an object increase, its density will also increase. Hence, the given statement is true.

spray him in the eyes and you have until he washes it put

Answer:

house away far from

Explanation:

I dont know tbh

Answer:

1)  LIQUID, 2) LIQUID, 3) GASEOU, 4)  GASEOUS,    v = 0.76 m³ / kg

Explanation:

In this exercise it is asked to determine the state of the water, that is, if it is solid, liquid or gas. For this we must use a phase diagram of water which is a graph of Pressure versus Temperature. Let's describe the water diagram

* Below 0ºC and normal pressure the water is in a solid state

* Below this temperature and at low pressure it becomes a gaseous state

* Above 0.01ºC and normal pressure is in liquid state

* Above 0.01ºC and low pressure is in a gaseous state

there are two important points

* The triple point at t + 0.01ºC and P = 0.006 atm where the three states coexist

* The critical point T = 374ºC and P = 218 atm where water decomposes into hydrogen and oxygen

Specific volume is related to density

        v = 1 / ρ

        ρ = 1 / v

the density of water is approximately 1000 kg / m³ in the liquid state at t = 4ºC and decreases with increasing pressure 960 kg / m³ at T = 100ºC (but without changing to the gaseous state

With the above considerations we can answer the questions

1) P = 300 kPa = 3 105 Pa

   v = 0.5 m³ / kg

atmospheric pressure is Patm = 1.01 105 Pa

     P = 3 105 Pa (1 atm / 1.01 105 Pa) = 3 atm

From the phase diagram described, the water can be in two liquid or gaseous states, depending on the temperature, as indicated by the speed of the same state, the water must be LIQUID

the parameter v that you indicate is the

with the other parameter we can calculate the density

     rho = 1 / 0.5

     rho = 2.0 kg / m³

in a thermodynamic system the three basic properties are: pressure, volume and temperature,

we can calculate the body temperature

The body must be at a temperature between 0 <T <100ºC

2) P = 28 Mpa = 28 106 Pa

   P = 28 106 Mpa (1 atm / 1.01 105 Pa) = 280 atm

   T = 200ºC

When examining the diagram it can be seen that the water is in the range of the LIQUID state

3) P = 1MPa

   P = 1 106 Pa (1atm / 1.01 105Pa) = 10 atm

   T = 405ºC

In this case, the only accessible state is the GASEOUS

4) T = 100ºC

     x = 60%

Examining the phase diagram at this temperature depending on the pressure the possible states are Vapor and liquid, for pressures below 1 atm the state is GASEOUS

for the gaseous state we can use the ideal gas equation

            PV = nR T

let us perform the calculation for a mole of gas n = 1, the ideal gas constant is R = 8,206 10-2 atm / mol K

          V = nRT / p

           V = 1 8,206 10-2 100/1

           V = 8,206 m³

          v = V / m

The mass of the water is 18 Kg / mol, which indicates that 60% is in the gaseous state, so the mass in this state is

         m = 0.60 18

         m = 10.8 kg

          v = 8.206 / 10.8

          v = 0.76 m³ / kg

Explanation:

It depends upon the magnitude of the charge, the velocity of the particle and its strength .

Answer:

B) μ = 0.23

Explanation:

The coefficient of friction is equal to μ = F / N where μ (mu) is the coefficient of friction, F is the friction force, and N is the normal force (the force of an object being applied onto the earth by gravity).

F, the friction force, is given as 67 N

Since the weight of the crate is 289 N, that means the normal force is 289 N.

This means that the coefficient of friction is  μ = F / N = 67 N / 289 N = 0.23183391 = 0.23

Therefore, B is the correct answer

Answer:

umm it says he but I'm a she :p

Answer:

a. 104.5 C b. 7.94 × 10⁶ A/m² c. 5.83 × 10⁻⁴ m/s

Explanation:

a. How much electric charge passes through the starter motor?

Using Q = It where Q = electric charge passing through the starter motor, I = current = 110 A and t = time = 0.95 s

So, Q = It = 110 A × 0.95 s = 104.5 C

b. What is the current density in the wire?

The current density, J = I/A where I = current = 110 A and A = cross-sectional area = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, J = I/A

= I/πd²/4

= 4I/πd²

= 4 × 110 A/π(4.20 × 10⁻³ m)²

= 440 A/55.42 × 10⁻⁶ m²

= 7.94 × 10⁶ A/m²

c. How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)

To find how far the electron travels, we need to find the electron drift velocity from

J = nev where J = current density = 7.94 × 10⁶ A/m², n = electron density = 8.50 × 10²⁸ m⁻³, e = electron charge = 1.602 × 10⁻¹⁹ C, v = drift velocity of electrons and A = cross-sectional area of wire = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, v = J/ne

Substituting the values of the variables into the equation, we have

v = 7.94 × 10⁶ A/m² ÷ (8.50 × 10²⁸ m⁻³ × 1.602 × 10⁻¹⁹ C)

v = 7.94 × 10⁶ A/m² ÷ (13.617 × 10⁹ Cm⁻³)

v = 0.583 × 10⁻³ m/s

v = 5.83 × 10⁻⁴ m/s

Answer:

for the first paragraph introduce the definition. for the second paragraph write about the first law, for the third paragraph write about the 2nd for the fourth paragraph write about the 3rd law. for the last paragraph do a brief summary of what you wrote and a conclusion about the laws.

i hope this helps a bit

Answer:

You can start off with the first law of motion (newtons first law), talk about what it is or what it does, give examples.

Answer:

chinese

Explanation:

Answer:

B chinese

hope this helps you

Answer:

–I6 N

Explanation:

From the question given above, the following data were obtained:

Spring constant (K) = 80 N/m

Initial position = 0.6 m

Final position = 0.4 m

Force (F) =?

Next, we shall determine the compression of the spring. This can be obtained as follow:

Initial position = 0.6 m

Final position = 0.4 m

Compression (x) =?

Compression = Final position – Initial position

Compression (x) = 0.4 – 0.6

Compression (x) = – 0.2 m

Finally, we shall determine the force. This can be obtained as follow:

Spring constant (K) = 80 N/m

Compression (x) = – 0.2 m

Force (F) =?

F = Kx

F = 80 × –0.2

F = –I6 N

Answer:

Explanation:

emf   due to movement of a rod of length L in a perpendicular to magnetic field B with velocity v is given as

emf = BLv

Putting in the given values ,

E = 2.45 x 12.5 x 10⁻² x 2.4

= .735 V

This emf produces current in resistance . Power consumed by resistance

V² / R where R is resistance , V is emf induced .

Power = .735² / 1.2

= .45 W .

Answer:

the mouse

Explanation:

the mouse has a momentum of 33 m kg/s

while the elephant has a momentum of 27 m kg/s

i found this out using p=mv

Answer:

I don't understand the question

Explanation:

sorry I cant help because I am just a first former

Answer:

Explanation:

From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.

So, in light of that, to determine the electric charges values & signs on each of them, we have:

on a = +3 C

on b = -7 C

on c = -7 C

on d = +3 C

on e = -7 C