Answer:
1 there,here, somewhere,nowhere,everywhere
2.now,yesterday,then,
John and Caroline go out for a walk one day. This graph represents the distance they traveled over time.
During what part of thelr walk are they not moving?
A) From 0 to 0.75 hours
B)From 1.25 to 2.0 hours
From 0.75 to 1.25 hours
C) from 1.25 to 2.0 hours
D) they are moving the entire time
Answer:
From 0.75 to 1.25 hours
Explanation:
Given
See attachment for graph
Required
Point where they didn't move
This means that we identify the point where the distance didn't change.
Given that the distance is plotted on the y-axis, we simply check for the end points of any horizontal line on the graph
The horizontal line on the graph represents 30km and the time interval is: 0.75 to 1.25 hours.
Hence, (c) is correct
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its element was drawing power for 6.3 X 10^2 min in a period of one month. Calculate the electrical energy in kWh used by the pan during the month
Answer:
378 KWh
Explanation:
We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:
10³ W = 1 KW
Therefore,
1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W
1.2×10³ W = 1.2 KW
Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:
60 mins = 1 h
Therefore,
6.3×10² mins = 6.3×10² mins × 1 h / 60 mins
6.3×10² mins = 10.5 h
Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:
Power (P) = 1.2 KW
Time (t) for 1 month (30 days) = 10.5 h × 30
= 315 h
Energy (E) =?
E = Pt
E = 1.2 × 315
E = 378 KWh
Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.
How much heat is absorbed by 60g of copper when it is heated from 20°C to 80°C
Answer:
I HOPE THIS IS CORRECT
Explanation:
It is heated from 20°C to 80°C. We need to find the heat absorbed. It can be given by the formula as follows : So, 1386 J of heat is absorbed.
What do different forms of energy have in common?
A. They can push or pull on objects.
B. They give objects mass.
C. They can cause changes in matter.
d
D. They can cause objects to move.
Helllp meeee
The work function of titanium metal is 6.93 x 10-19 J. Calculate the kinetic energy of the ejected electrons if light of frequency 2.50 X 1015 s-1 is used to irradiate the metal.
Answer:
g m t o k liye cbbhhhf to be be free and ear is not a short time to be a short of a week and I am a short kat key and ear to be free and ear is not a short time and ear buds and duster for a short of a week of the action is not by the action is not a short time to make sure to be free and duster and not by the way to
Explanation:
ahhhhhhh to be be free and ear is nothing to be be free and ear is not a short time to be be free and ear is not by the class is not a a short time to be be free and
What is the current running through a parallel circuit containing a 10 V battery and three resistors, each 3 ohms
Answer:
the current through the circuit is 10 A.
Explanation:
Given;
voltage of the battery, V = 10 V
number of the parallel resistors, = 3
resistance of each resistor, r = 3 ohms
The equivalent resistance is calculated as;
[tex]\frac{1}{R_t} = \frac{1}{r_1}+ \frac{1}{r_2} + \frac{1}{r_3} \\\\\frac{1}{R_t} = \frac{1}{3}+ \frac{1}{3} + \frac{1}{3}\\\\\frac{1}{R_t} =\frac{3}{3} \\\\\frac{1}{R_t} = 1\\\\R_t = 1 \ ohms[/tex]
The current through the circuit is calculated as;
V = IRt
I = V/Rt
I = 10/1
I = 10 A
Therefore, the current through the circuit is 10 A.
2. Why is it necessary for rotation to occur within a
generator?
Answer:
ON
Explanation:
Locate your computer's Power button.
Press and hold that button until your computer shuts down.
Wait until you hear the computer's fans shut off, and your screen goes completely black.
Wait a few seconds before pressing and holding the power button to initiate your computer's normal startup.
46) The rapid change of an electric field induces
A) a stronger electric field.
B) a magnetic field.
C) both of these
D) none of the above
Answer:
The answer is Option no. C because rapid changes can cause both magnetic field and stronger electric field
Appliances A, B, and C consume 250, 480 and 1450 watts of power, respectively. The system voltage is 120V, and the circuit breaker is rated at 15 amps. Which combinations of the three appliances can be on at the same time, and which combinations will trip the circuit breaker
Answer:
Appliance A and B can work together without tripping
Explanation:
We will calculate the amount of current consumed by each appliances.
Appliance A
P = VI
I = P/V
I = 250/120 = 2.08 A
Appliance B
I = 480 /120 = 4 A
Appliance C
I = 1450/120
I = 12.08 A
Hence, appliance C will trip the circuit as it consumes a lot of electricity.
In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves with a constant acceleration. The following data are collected for the cart.
t(s) x(m)
0 0
1 4
2 16
3 36
4 64
The acceleration of the cart is most nearly:_____
Given :
Initial velocity , u = 0 m/s² .
To Find :
The acceleration of the cart.
Solution :
Since, acceleration is constant.
Using equation of motion :
[tex]x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}[/tex]
Putting, t = 1 s and x = 4 m in above equation, we get :
[tex]4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2[/tex]
Therefore, the acceleration of the cart is 8 m/s².
14. Name the 3 primary causes for the expected mass migration due to Climate
Change
Answer:
Climate change means a change in the state of the climate system that is sustained over a long period of time. These types of changes can occur due to natural or human causes.
Climate change and its effects on the planet can generate massive migrations, given the affectation of nature in certain parts of the planet.
Thus, an example would be the migration of populations from island countries, such as Fiji, Tonga or Samoa, to continental territories, due to the rise in sea level caused by the melting of the poles due to global warming.
Another example may be the desertification of certain regions, which would encourage migration by the inhabitants of these places to other territories.
Finally, climate change and its negative effects not only generate massive migrations caused by natural effects, but also by the economic effects of said changes, that is, by increases in poverty and inequality in the face of the scarcity of certain natural resources.
You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity
of 0.50 m/s. What is the work done by gravity on the book?
1) +10 J
2) -10
3) +5.0
4) -5.0
The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).
The force exerted on the book by gravity has magnitude
F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N
You raise the book 1.0 m in the opposite direction, so the work done is
W = (10 N) (-1.0 m) = -10 J
The work done by gravity on the book is -10 Joules. The correct option is 2.
What is gravity?The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.
Given are the three positions. The Earth has the acceleration due to gravity, g = 9.81 m/s²,
The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).
The force exerted on the book by gravity has magnitude
F = mg = 10 N x( -9.80 m/s² )= -9.8 N
F ≈ -10 N
The book is raised by 1.0 m in the opposite direction, so the work done is
W =- 10 N x 1.0 m = -10 J
Thus, the correct option is 2.
Learn more about gravity.
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A 1350 kg automobile has a kinetic energy 3.24 x 106 J. What is the velocity of the car?
Answer:
219 m/s
Explanation:
Kinetic energy is calculated using the formula:
KE = 1/2mv²Given:
m = 1350 kg KE = 3.24 · 10⁶ JWe can solve for the unknown variable v.
Substitute these known values into the formula.
3.24 · 10⁶ = 1/2(1350)v² 3.24 · 10⁶ = 675v² (3.24 · 10⁶) / 675 = v² v² = 48,000v = 219.09 m/sThe velocity of the car is around 219 m/s.
A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A. What is the power dissipated by the resistor?
A. 50 W
B. 200 W
C. 100 W
D. 25 W
Explanation:
A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. ... A power line with a resistance of 2 ohms has a current of 80 A in it
1/8 Watt 50 kΩ resistor has 70 V applied.
A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A then the power dissipated by the resistor is 200 Watt. Therefore the correct option is B.
What is power?The rate of doing work is known as power. The Si unit of power is the watt.
Power =work/time
The mathematical expression for the power is as follows
P = VI
where P is the power
V is the voltage
I is current passing through the circuit
The expression of power can be represented in many different forms by using the ohms law
As we know from Ohm's law that V= IR
Power = VI
by substituting V=IR in place of the voltage in power formula
P = I²R
As given in the problem a 50 Ω resistor in a circuit has a current flowing through it of 2.0 A so by substituting the values of the current and the resistance in the formula of power
P = 2²×50
= 200 Watt
Therefore the correct answer is B.
Learn more about power from here
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What is the magnitude of the current in the R= 6 Ω resistor?
kirchhoff
Answer:
Here's an explanation but not the answer
Explanation:
When a resistor is traversed in the same direction as the current, the ... Traversing the internal resistance r1 from c to d gives −I2r1. ... I1 = I2 + I3 = (6−2I1) + (22.5− 3I1) = 28.5 − 5I1.
State the relation between acceleration and momentum
Answer:
Acceleration is the rate of change in velocity. Momentum is the mass times the velocity. So if you multiply the mass times the acceleration, you get the of change of momentum.
A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N?
Answer:
ans: 1750 kg
Explanation:
F = ma
so ,
m = F/a
= 3500 / 2
= 1750 kg
37 microgram to Gigagram
3.7e-1437 Gigagram
BRAINILIEST PLEASE
It is 2058 and you are taking your grandchildren to Mars. At an elevation of 34.7 km above the surface of Mars, your spacecraft is dropping vertically at a speed of 293 m/s. The spacecraft is to make a soft landing -- that is, at the instant it reaches the surface of Mars, its velocity is zero. Assume the spacecraft undergoes constant acceleration from the elevation of 34.7 km until it reaches the surface of Mars. What is the magnitude of the acceleration
Answer: [tex]1.23\ m/s^2[/tex]
Explanation:
Given
At an elevation of [tex]y=34.7\ km[/tex], spacecraft is dropping vertically at a speed of [tex]u=293\ m/s[/tex]
Final velocity of the spacecraft is [tex]v=0[/tex]
using equation of motion i.e. [tex]v^2-u^2=2as[/tex]
Insert the values
[tex]\Rightarrow 0-(293)^2=2\times a\times (34.7\times 10^3)\\\\\Rightarrow a=-\dfrac{293^2}{2\times 34.7\times 10^3}\\\\\Rightarrow a=-1.23\ m/s^2[/tex]
Therefore, magnitude of acceleration is [tex]1.23\ m/s^2[/tex].
A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.
Answer:
a) P = 70054.3 W, b) P = 18820 W, c) P = 14116.7 W
Explanation:
Power is defined as work per unit of time
P = W / t = F x / t
P = F v
a) in this case the velocity is constant, let's use the equilibrium relation to find the force.
Let's set a reference system with the x axis parallel to the plane
F - Wₓ = 0
F = Wₓ
with trigonometry let's decompose the weight
sin θ = Wₓ / W
Wₓ = W sin θ
F = W sin 15
F = 2800 sin 15
F = 724.7 lb
we look for the speed, as it rises with constant speed we can use the relations of uniform motion
v = x / t
v = 1160/12
v = 96.67 ft / s
we calculate the power
P = 724.7 96.67
P = 70054.3 W
b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy
W = ΔK
W = ½ m v_f² - ½ m v₀²
let's reduce to the SI system
v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s
v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s
mass : m = w / g
W = ½ 2800/32 (73.33² - 14.67²)
W = 225841 J
we calculate the average power
P = W / t
P = 225841/12
P = 18820 W
c) we repeat the previous procedure
v₀ = 45 mph = 66 ft / s
v_f = 15 mph = 22 ft / s
W = ½ 2800/32 (22² - 66²)
W = -169400 J
P = W / t
P = 169400/12
P = 14116.7 W
motto that will help in reaching a goal in life that related the projectile motion
Explanation:
hmm! very good questions I hope u understand
In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb
Answer:
Hola eres nuevo yo nací en el 2021 del 4 de junioIn which direction of the wave motion do longitude waves transfer energy ?
Answer:
Hello There!!
Explanation:
The answer is O parallel.
hope this helps,have a great day!!
~Pinky~
a stone is thrown vertically upward with an initial velocity of 14m/sc negleting in air resistance find (a)Maximum height reached and (b)Time taken before it reached the ground
Answer:
1/2 m v^2 = m g H conservation of energy
H = (v^2 / (2 * g))^1/2 = (14^2 / 19.6)^1/2 = 10 m
H = 1/2 g t^2 time to fall 10 m
t = (2 * H / g)^1/2 = (20 / 9.8)^1/2 = 1.43 sec
Total time in air = 2 * 1.43 = 2.86
You can also use 2 a S = V0^2 since final velocity = 1.43 * 9.8 m/s = 14 m / s
and 2 a S = 2 * 9.8 * 10 = 196 m^2 / s^2 which is V0 squared
A horizontal force of 40N is needed to pull a 60kg box across the horizontal floor at which coefficient of friction between floor and box? Determine it to three significant figures even through that's quite unrealistic. How much work is done in overcoming friction between the object and floor if the box slides 8m along horizontally on the floor?
Answer:
Coefficient of friction is [tex]0.068[/tex].
Work done is [tex]320~J[/tex].
Explanation:
Given:
Mass of the box ([tex]m[/tex]): [tex]60[/tex] kg
Force needed ([tex]F[/tex]): [tex]40[/tex] N
The formula to calculate the coefficient of friction between the floor and the box is given by
[tex]F=\mu mg...................(1)[/tex]
Here, [tex]\mu[/tex] is the coefficient of friction and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]40[/tex] N for [tex]F[/tex], [tex]60[/tex] kg for [tex]m[/tex] and [tex]9.80[/tex] m/s² for [tex]g[/tex] into equation (1) and solve to calculate the value of the coefficient of friction.
[tex]40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068[/tex]
The formula to calculate the work done in overcoming the friction is given by
[tex]W=Fd..........................(2)[/tex]
Here, [tex]W[/tex] is the work done and [tex]d[/tex] is the distance travelled.
Substitute [tex]40[/tex] N for [tex]F[/tex] and [tex]8 m[/tex] for [tex]d[/tex] into equation (2) to calculate the work done.
[tex]W=40~N\times8~m\\~~~~= 320~J[/tex]
A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support system for the machine (i.e., choose c, k) so that only 10% of the force applied to the machine is transmitted to the base supporting the machine.
Answer:
registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk
The centripetal acceleration of an object moving in a circle of radius 20 cm is 8 m/sec ^2. The possible tangential velocity of the object will be
Answer:
v = 1.26 m/s
Explanation:
Given that,
The radius of the circle, r = 20 cm = 0.2 m
The centripetal acceleration of the object, a = 8 m/s²
We need to find the tangential velocity of the object. We know that the formula for the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar}\\\\v=\sqrt{8\times 0.2}\\\\v=1.26\ m/s[/tex]
So, the tangential velocity of the object will be 1.26 m/s.
An 800-kHz radio signal is detected at a point 4.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.63 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the magnetic field amplitude of the signal at that point
Answer:
[tex]B_2=2.1nT[/tex]
Explanation:
From the question we are told that:
Frequency [tex]F=800kHz[/tex]
Distance [tex]d=4.5km[/tex]
Electric field amplitude [tex]B_2=0.63V/m[/tex]
Generally the equation for momentum is mathematically given by
[tex]B=\frac{E}{C}[/tex]
Therefore
[tex]B_2=\frac{0.63}{3*10^8}[/tex]
[tex]B_2=0.21*10^{-8}[/tex]
[tex]B_2=2.1nT[/tex]
A particle with charge q1 = +4.0 µC is located at x = 0, and a second particle with charge q2 = −2.1 µC is located at x = 15 cm. Determine the location of a third particle with charge q3 = +4.6 µC such that the net electric field at x = 25 cm is zero.
Answer:
x₃ = 0.0725 m
Explanation:
The force between the particles is electrical
F = [tex]k \frac{q_1q_2}{r_{12}^2}[/tex]
F = q₀ E_total
don q₀ is a positive test charge at the point of interest, therefore we can calculate the electric field at the point of interest x₀ = 0.25 cm
F = 0 → E_total = 0
E_total = E₁ + E₂ + E₃
E_total = [tex]k \frac{q_1}{r_{1o}^2} + k \frac{q_2}{r_{2o}^2} + k \frac{q_3}{r_{3o}^2}[/tex]
E_total = k ( [tex]\frac{q_1}{r_{1o}^2} + \frac{q_2}{r_{2o}^2} + \frac{q_3}{r_{3o}^2}[/tex] )
let's look for the distances
r₁₀ = (x₀ - 0)
r₁₀ = 0.25 m
r₂₀ = √(x₀ - x₂) ²
r₂₀ = √ (0.25 - 0.15) ²
r₂₀ = 0.10 m
r₃₀ = √ (0.25 - x₃) ²
we substitute
0 = 9 10⁹ (4 / 0.25² - 2.1 / 0.1² + 4.6 / (0.25-x₃)² )
4.6 / (0.25-x3)² = -4 / 0.25² + 2.1 / 0.1²
4.6 / (0.25-x3) ² = -146
(0.25 - x3) ² = - 4.6 / 146 = - 0.0315068
0.25 - x3 = 0.1775
x₃ = 0.25 - 0.1775
x₃ = 0.0725 m
Ples helppp meeeeee this is timedd
Answer:
50 km/h
Explanation:
From the graph, we can deduce the following parameters;
Distance = 20, 40, 60, 80, 100 km
Time = 0.5, 1.0, 1.5, 2.0 hours
To find the average velocity of the car over the first 2.00 hours.
First of all, we would determine the total distance and time.
Total distance = 20 + 40 + 60 + 80 + 100 = 300 km
Total time = 0.5 + 1.0 + 1.5 + 2.0 = 5
Average velocity = distance/time
Average velocity = 100/2
Average velocity = 50 km/h