Physics College

Acceleration
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Study the motion map shown. Some of the vectors have been circled.
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What do the circled vectors represent?
distance
speed
velocity
acceleration
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Answers

Answer 1

The circled vectors represents acceleration.

The last option is correct.

How do we explain?

We see in the  first motion diagram the length of velocity vector is increasing this shows that the velocity is increasing in the magnitude with time so this is an accelerated motion in which a uniform acceleration must be in the same direction of velocity must be there.

We also notice in the second motion diagram the length of velocity vector is decreasing with time which shows the velocity is decreasing me magnitude which shows a constant deceleration and the direction of acceleration must be opposite to that of velocity.

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AccelerationQuiz Active1 2 3 4 5 6 7 8 9 10Study The Motion Map Shown. Some Of The Vectors Have Been

Related Questions


Question 1

At one section of a long pipe the velocity of the fluid is 1.6 m/s. At another section of the pipe the diameter is three times greater.
What is the velocity of the fluid at this section?
O 0.533 m/s
○ 4.80 m/s
O Not enough information to tell
O 0.178 m/s

Question 2

Three thermometers are placed in a closed, insulated box and are allowed to reach thermal equilibrium. One is calibrated in
Fahrenheit degrees, one in Celsius degrees, and one in Kelvins. If the Celsius thermometer reads -40 °C the Fahrenheit
thermometer would read -40°F.

True
False

Answers

Answer:

Answer 1: The answer is O 0.178 m/s.

Answer 2: True:  But in this specific case where the Celsius temperature is -40, the Fahrenheit temperature will also be -40.

So, in short, the answer is:

-40 Celsius is equal to -40 Fahrenheit

A satellite weighing 5,400 kg is launched into orbit 3.6400 x 107 m above the center of the earth.

The mass of Earth is 6.0 × 1024 kg. The gravitational constant is 6.673 × 10–11 N•m2/kg2.

The gravitational force of Earth on the satellite is ___



Group of answer choices

9.1 x 10^4

1.6 x 10^3

2.1 x 10^6

Answers

Answer:

[tex]\tt F=1.63*10^3 N[/tex]

Explanation:

Gravitational force is defined as the force of attraction between two objects with mass. It is a fundamental force of nature, and it is what keeps us on the ground and what keeps the planets in orbit around the Sun.

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

For the Question:

We can use the following formula to calculate the gravitational force between the Earth and the satellite:

[tex]\boxed{\tt F =\frac{ G * M * m }{ r^2}}[/tex]

Where:

F is the gravitational force

G is the gravitational constant[tex]\tt (6.673 * 10^{-11} Nm^2/kg^2)[/tex]

M is the mass of the Earth [tex]\tt (6.0 * 10^24 kg)[/tex]

m is the mass of the satellite[tex]\tt (5,400 kg)[/tex]

r is the distance between the satellite and the center of the Earth [tex]\tt (3.6400 * 10^7 m)[/tex]

Plugging in these values, we get the following:

[tex]\tt F = \frac{6.673 * 10^{-11} * 6.0 * 10^{24}* 5,400 }{ (3.6400 * 10^7 )^2}[/tex]

[tex]\tt F=1.63*10^3 N[/tex]

Therefore, answer is [tex]\tt F=1.63*10^3 N[/tex]

What is Moral subjectivism?

Answers

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

A steam turbine receives steam with a velocity of 28 m/s, specific enthalpy 3000 kJ/kg at a rate of 3500 kg per hour. The steam leaves the turbine with a specific enthalpy of 2200 kJ/kg at 180 m/s. Calculate the turbine output, neglecting losses.

Answers

A steam turbine receives steam with a velocity of 28 m/s, specific enthalpy 3000kJ/kg at a rate of 3500 kg per hour. The steam leaves the turbine with a specific enthalpy of 2200kJ/kg at 180 m/s then turbine output is 777.76kW.

To get the turbine output, we must first compute the change in specific enthalpy (h) and mass flow rate ().

Assume that the inlet steam velocity (v1) is 28 m/s.

Specific enthalpy at the inlet (h1) = 3000 kJ/kg

()=3500kg/h mass flow rate

2200 kJ/kg outlet specific enthalpy (h2)

v2 (outlet steam velocity) = 180 m/s

To begin, convert the mass flow rate from kg/h to kg/s as follows: =

[tex]3500 kg/h (1 h/3600 s) = 0.9722 kg/s[/tex]

The change in specific enthalpy (h) can then be calculated:

3000kJ/kg-2200kJ/kg=800kJ/kgh=h1-h2

The following formula can be used to compute the turbine output (P):

[tex]P = ṁ * Δh[/tex]

Substituting  P=0.9722kg/s*800kJ/kg=777.76kJ/sork W

As a result, ignoring losses, the turbine output is roughly 777.76kW

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¿Cuál es el trabajo neto en J que se necesita para acelerar un auto de 1500 kg de 55 m/s a 65 m/s?

What is the net work in J required to accelerate a 1500 kg car from 55 m/s to 65 m/s?

Answers

The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

How do i determine the net work done?

First, we shall obtain the initial kinetic energy. Details below:

Mass (m) = 1500 Kginitial velocity (u) = 55 m/sInitial kinetic energy (KE₁) =?

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

Mass (m) = 1500 KgFinal velocity (v) = 65 m/sFinal kinetic energy (KE₂) =?

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

Initial kinetic energy (KE₁) = 41250 JFinal kinetic energy (KE₂) = 3168750 JNet work done (W) =?

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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The temperature of a aluminum bar rises by 10.0°C when it absorbs 4.73 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of aluminum from these data. Answer is in kJ/kg · °C.

Answers

Answer:

Certainly! We can use the formula:

q = mcΔT

where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.

Substituting the given values, we get:

4.73 kJ = (0.525 kg) x c x (10.0°C)

Solving for c, we get:

c = 0.901 kJ/kg · °C

Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.

Explanation:

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