A wire with a linear mass density of 1.17 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic friction between the wire and the surface is 0.250. If the wire carries a current of 1.24 A westward and moves horizontally to the south, determine the magnitude and direction of the smallest magnetic field that can accomplish this.

Answer:

(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz

(b) 250 m/s

(c) 1250 N

(d) Positive x-direction

(e) 6.00 m/s

(f) 0.0365 m

Explanation:

(a) The standard form of the wave is:

y = A cos ((2πf) t ± (2π/λ) x)

where A is the amplitude, f is the frequency, and λ is the wavelength.

If the x term has a positive coefficient, the wave moves to the left.

If the x term has a negative coefficient, the wave moves to the right.

Therefore:

A = 0.0800 m

2π/λ = 0.300 m⁻¹

λ = 20.9 m

2πf = 75.0 rad/s

f = 11.9 Hz

(b) Velocity is wavelength times frequency.

v = λf

v = (20.9 m) (11.9 Hz)

v = 250 m/s

(c) The tension is:

T = v²ρ

where ρ is the mass per unit length.

T = (250 m/s)² (0.0200 kg/m)

T = 1250 N

(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).

(e) The maximum transverse speed is Aω.

(0.0800 m) (75.0 rad/s)

6.00 m/s

(f) Plug in the values and find y.

y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))

y = 0.0365 m

Answer:

you need to multiply the momentum and the mass

Answer:

The diameter is [tex]d = 8.18*10^{-19} \ m[/tex]

Explanation:

From the question we are told that

   The value of one atomic mass unit is [tex]u = 1.66 *10^{-27} \ kg[/tex]

    The density of the proton is  [tex]\rho = 5.8 *10^{27} \ kg/m^3[/tex]

Generally the volume of the proton (sphere)is mathematically represented as

     [tex]V = \frac{4}{3} * \pi * r^3[/tex]

Generally this volume can also be evaluated as

      [tex]V = \frac{u}{\rho}[/tex]

=>   [tex]V = \frac{1.66 *10^{-27}}{5.8*10^{27}}[/tex]  

=>   [tex]V = 2.862 *10^{-55} \ m^3[/tex]

So

[tex]2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3[/tex]

=>   [tex]r^3 = 6.832 *10^{-56}[/tex]

=>  [tex]r = 4.088 *10^{-19} \ m[/tex]

Now the diameter is mathematically represented as

    [tex]d = 2 * r[/tex]

=> [tex]d = 2 * 4.088 *10^{-19}[/tex]

=> [tex]d = 8.18*10^{-19} \ m[/tex]

Answer:

A. 29.7 m/s

B. 6.06 s

Explanation:

From the question given above, the following data were obtained:

Maximum height (h) = 45 m

A. Determination of the initial velocity (u)

Maximum height (h) = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 m/s (at maximum height)

Initial velocity (u) =.?

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – (2 × 9.8 × 45)

0 = u² – 882

Collect like terms

0 + 882 = u²

882 = u²

Take the square root of both side

u = √882

u = 29.7 m/s

Therefore, the ball must be thrown with a speed of 29.7 m/s.

B. Determination of the time spent by the ball in the air.

We'll begin by calculating the time take to reach the maximum height. This can be obtained as follow:

Maximum height (h) = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) to reach the maximum height =?

h = ½gt²

45 = ½ × 9. 8 × t²

45 = 4.9 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the time spent by the ball in the air. This can be obtained as follow:

Time (t) to reach the maximum height = 3.03 s

Time (T) spent by the ball in the air =?

T = 2t

T = 2 × 3.03

T = 6.06 s

Therefore, the ball spent 6.06 s in the air.

Answer:

Leave onions in cold water for about 15 minutes! Takes out the chemical reaction in the onion's defense system.

Explanation:

This is what people NEED to know for cooking... Lol :)

Answer:

128

Explanation:

Answer:

54 degrees

Explanation:

Answer:

Explanation:

According to law of conservation of momentum

m1u1+ m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are their initial velocities

v is their common velocity

Given

m1 = 3kg

m2 = M

u1 = 8m/s

u2 = 0m/s (object at rest)

v = 6.0m/s

Substitute and get M

3(8) + M(0) = (3+M)6

24 = 18+6M

24-18 = 6M

6 = 6M

M = 1kg

Hence the mass M is 1kg

Answer:

E=mc2

Explanation:

It explains that in their interiors, atoms fuse together, creating energy.

To solve this we must be knowing each and every concept related to energy and its different types. Therefore, the famous equation that describes the energy of stars is E=mc².

In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms.

There is also heat and work—energy inside the process of being transferred by one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy. The famous equation that describes the energy of stars is E=mc²

Therefore, the famous equation that describes the energy of stars is E=mc².

To know more about energy, here:

https://brainly.com/question/29763772

#SPJ2

Answer:

I can't see the post :/

Explanation:

Answer:

ok

Explanation:

ok how many points is this?????

Answer:

gas

Explanation:

it is gas because the particles are floating up none of the above would be floating up.

Answer:

Solid

Explanation:

A: Solid- Solids have the particles tightly packed. They have a definite shape and volume

B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume

C: Gas- Gas has particles freely all around. Indefinite shape and volume

D: Plasma- Plasma is different and should be explained with an example; think of lighting....

Since the image shows tightly packed particles, it is clear the answer is a solid.

Answer:

angular speed = 67.91 rad/s

Explanation:

Given that,

The diameter of a tire, d = 72 cm

The radius of a tire, r = 36 cm = 0.36 m

Linear speed of an automobile, v = 88 km/h = 24.45 m/s

We need to find the angular speed of the tires about their axles. The relation between angular speed and angular speed is given by :

[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{24.45 }{0.36}\\\\\omega=67.91\ rad/s[/tex]

So, the angular speed of the tire is 67.91 rad/s.

Answer:

brain

Explanation:

brain and blood

I feel like I'm in a city

Answer:

0.03 cm

Explanation: If the scale is 500:1, you have to divide 500 by 15 to get 0.03. You do not multiply 500 times 15 because the cells are smaller than the scale representation so you divide.

Answer:

357 J

Explanation:

The elastic potential energy of arrow in the stretched bow is 357 J.

The kinetic energy of the arrow after it has been shot is given by half of the product of the arrow's mass and velocity of the arrow.

Here there are no other forms of energy at play here. Only potential and kinetic energy.

As we know that in any system the energy is conserved accordingly the elastic potential energy of the arrow will be equal to the kinetic energy of the bow after it is released i.e., 357 J.

Answer:

B

Explanation:

it could be because they have a difference in genes

Answer: I don't  do   adopt me   but I do have a Ro.blox username its  Nvm i cant but my user name

Explanation:

Answer:

adopt me sucks but my best pet was an albino monkey I think or a king monkey

Explanation:

Answer:

–1652 N. The negative sign indicate that the force is in opposite direction to car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 1400 kg

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Force (F) applied on the car =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Acceleration (a) =?

a = (v – u) /t

a = (12 – 25) /11

a = –13/11

a = –1.18 m/s²

Finally, we shall determine the force on the car as follow:

Acceleration (a) = –1.18 m/s²

Mass (m) of car = 1400 kg

Force (F) applied on the car =?

F = ma

F = 1400 × –1.18

F = –1652 N

Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{20}{30} = \frac{2}{3} \\ = 0.6666666...[/tex]

We have the final answer as

Hope this helps you

Answer:

WHATATATATTAT

Explanation:

Answer:

janakajnakanabjjiaj yav good day for you to everyone else to do with my family is it just doesn't want me and I am

Answer:

Answer is: c. It must lose two electrons and become an ion.

Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

Explanation:

Answer:

the third option

Explanation:

Steps 1 and 2)

The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.

The goal is to solve for the unknown time t.

-----------------------

Step 3)

Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P

-----------------------

Step 4)

t = W/P

t = 9514/347

t = 27.4178674351586

t = 27.4 seconds

-----------------------

Step 5)

The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.

-----------------------

Note: we don't use the mass at all

Answer:

The value is  [tex]I = 0.0932 ML ^2[/tex]  

Explanation:

From the question we are told that

  The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]

   The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]

Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is  [tex]0.4 M[/tex]

Generally the length of the rod from the its beginning to the axis of rotation consider is

      [tex]k = 1 - 0.4 L = 0.6L[/tex]

Generally the mass of the portion  of the rod from the its beginning to the axis of rotation consider is

    [tex]m = 1- 0.4 M = 0.6 M[/tex]

Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is

     [tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]

    [tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]

Generally the rotational inertia about the axis of rotation consider for the second  portion of the rod is

     [tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]

=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]

=>  [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]

Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is

  [tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]

=>   [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]

=>   [tex]I = 0.0932 ML ^2[/tex]  

Answer:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

Explanation:

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Answer:

A. Oceanic crust is continually recycled through convection in the earth's mantle

Explanation:

The oceanic plate is constantly being recycled through the forces of convection within the earth's mantle.

New oceanic plate are formed mid-oceanic ridge for example. As the magma cools and solidifies, they are moved away continually.

This is not the case for the continental curst.

Answer:

A. speed = 7.14 Km/s

B. distance = 1820.7 Km

Explanation:

Given that: a = 14.0 m/[tex]s^{2}[/tex], t = 8.50 minutes.

But,

t = 8.50 = 8.50 x 60

  = 510 seconds

A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

u = 0

So that,

v = 14 x 510

 = 7140 m/s

The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.

B. the distance traveled can be determined by applying second equation of motion.

s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.

u = 0

s = [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

  = [tex]\frac{1}{2}[/tex] x 14 x [tex](510)^{2}[/tex]

 = 7 x 260100

 = 1820700 m

The distance that the shuttle has traveled during the given time is  1820.7 Km.