Answer and Explanation:
Magnesium = Mg (metal) ⇒ oxidation number = +2 (it loses 2 electrons)
Oxygen = O (non-metal) ⇒ oxidation number in oxides = -2 (it gains 2 electrons)
a) We first write the chemical elements with their oxidation numbers in superscripts:
Mg⁺² O⁻²
Then, the oxidation numbers are written crossed as subscripts:
Mg₂O₂
Finally, we divide by a common denominator (2):
MgO
b) Between a metal (Mg) and a non-metal (O), the formed bond is an ionic bond. The metallic element (Mg) loses 2 electrons that are accepted by the non-metallic element (O).
c) Mg : loses 2 electrons ⇒ +2
O: gains 2 electrons ⇒ -2
The total electrical charge is: +2 + (-2) = 0
Solution A is yellow when alizarin yellow is added and blue when thymol
blue is added. Which of the following correctly identifies Solution A?
A. 3.2 x 10-4 mol/L HCI
B. 3.2 x 10-4 mol/L NaOH
C. 6.3 x 10-5 mol/L HCI
D. 6.3 x 105 mol/L NaOH
Answer:
D. 6.3 x 10-5 mol/L NaOH
Explanation:
Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9
That means the pH of the solution is between 9 - 10.1
Any acid as HCl could have a pH of these.
The solution of 3.2x10⁻⁴M NaOH has a pH of:
pOH = -log[OH-] = 3.49
pH = 14-pOH = 10.51. The pH of the solution is not 10.5
Now, the solution of 6.3x10⁻⁵M NaOH has a pH:
pOH = -log[OH-] = 4.2
pH = 14-pOH = 9.8
The pH of the solution could be 9.8. Right option is:
D. 6.3 x 10-5 mol/L NaOHWhat is the volume in milliliters of 7.92 g of acetone?
Answer:
The volume of acetone is 9.24 mL
Explanation:
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the metal (M). Please provide your answer in 2 decimal places.
a. How many moles of oxygen atoms are found in 4.00 g of O2?
b. How many atoms of hydrogen are found in 0.400 mol of H2S?
c. How many hydrogen atomsare present in 0.235 g of NH3?
Answer:
See solution.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:
[tex]\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%[/tex]
Thus, we solve for the molar mass of the metal to obtain:
[tex]59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol[/tex]
For the subsequent problems, we proceed as follows:
a.
[tex]4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2[/tex]
b.
[tex]0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH[/tex]
c.
[tex]0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH[/tex]
Regards!
Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.
Answer:
glucose<NaCl<CaCl2
Explanation:
Hello there!
In this case, since the general equation for the calculation of the freezing point depression is:
[tex]\Delta T=-i*m*Kf[/tex]
Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:
glucose<NaCl<CaCl2
Regards!
first law of the thermodynamic indicates.?
Answer:
The first law of thermodynamics states that energy can neither be created nor destroyed, only altered in form. For any system, energy transfer is associated with mass crossing the control boundary, external work, or heat transfer across the boundary. These produce a change of stored energy within the control volume.
Explanation:
What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.
Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.
a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.
The question is incomplete, the complete question is:
Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.
a. [tex]p_A[/tex] will be greater than
b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]
c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]
d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.
Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Explanation:
Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.
We are given:
Vapor pressure of A < Vapor pressure of B
This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.
Thus, [tex]p_A<p_B[/tex]
Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Ayuda plissss es para hoy
alimientos procesados:
cereales, queso ,verduras enlatadas, un pan bocadillos salados, como patatas fritas, panecillos de salchicha, tartas y empanadas productos cárnicos, como tocino, salchicha, jamón, salami y paté comidas para microondas o comidas preparadas pasteles y galletas bebidas, como leche o refrescos
alimientos naturales
1. Pescado · 2. Brócoli o cualquiera de las verduras crucíferas · 3. Remolacha · 4. Espinacas y otras verduras de hoja verde · 5. Col rizada · 6. Mantequilla de maní · 7. Almendras.pechugas de pollo, Cordero, Salmón, Camarón,Aceite de coco,Nueces y semillas
Answer:
what
Explanation:
Enter the molecular formula for butane, C4H10
Answer:
C4H10
Explanation:
you already written it :)
Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M
Answer:0.46
Explanation:
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?
1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin
Answer: 30.66945 kelvin
Explanation:
Based on a specific example of titration method. How do titration methods play a role in agriculture industry?
Answer:
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Answer:
How is titration used in the industry?
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
1. Write the structural formulas and give IUPAC names for all isorneric alcohols of molecular formula
С4Н9OH
Explanation:
Butanol (С4Н9OH)
Structural formula is :-
CH3-CH2-CH2-CH2-OH
Which of these statements are true? Select all that apply.
The AH+ for Br2() is 0 kJ/mol.
The AH; for Hel) is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AHp for Cl2(g) is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Answer:
The AH+ for Br2() is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Explanation:
The statements 1,3,4 and 5 are true.
What is meant by enthalpy ?Enthalpy is defined as a thermodynamic quantity, which can be considered equal to the total heat of the system.
Here,
1) The enthalpy of formation of Br₂ (cr, l) is 0 kJ/mol.
So, the statement is true.
2) The enthalpy of formation of He(l) is not zero.
So, the statement is false.
3) The enthalpy of formation of Hg(l) is 0 kJ/mol.
So, the statement is true.
4) The enthalpy of formation of Cl₂(g) is 0 kJ/mol.
So, the statement is true.
5) The enthalpy of formation of N₂ is 0 kJ/mol.
So, the statement is true.
Hence,
The statements 1,3,4 and 5 are true.
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g Calculate the moles of methanol in a first distillate that has a total volume of 0.5 mL and contains 23.4% methanol. The density of methanol is 0.791 g/mL, and the molar weight of methanol is 32.04 g/mol. 2.9 x10-3 mol Methanol 9.3 x10-3 mol Methanol 1.17 x 10-2 mol Methanol None of the above
Answer:
2.9 × 10⁻³ mol
Explanation:
Step 1: Calculate the volume of methanol
0.5 mL of distillate contains 23.4% methanol.
0.5 mL × 23.4% = 0.117 mL
Step 2: Calculate the mass corresponding to 0.117 mL of methanol
The density of methanol is 0.791 g/mL.
0.117 mL × 0.791 g/mL = 0.0925 g
Step 3: Calculate the moles corresponding to 0.0925 g of methanol
The molar weight of methanol is 32.04 g/mol.
0.0925 g × 1 mol/32.04 g ≈ 2.9 × 10⁻³ mol
What is the molar mass of a substance
A) the mass in grams of one mole of a substance
B) the number of particles in one gram of a substance
C) the number of moles in one gram of a substance
D) the mass in grams of one particle of a substance
thank you :)
Answer:
A) the mass in grams of one mole of a substance.
Explanation:
The molar mass of a substance is the mass in grams of 1 mole of the substance. As shown in this video, we can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.
Question List (4 items) (Drag and drop into the appropriate area) Find the volume of HCl that will neutralize the base. Find the mass (in grams) of Ca(OH)2. Calculate the number of moles of Ca(OH)2. Calculate the number of moles of H required to neutralize the base.
The question is incomplete, the complete question is:
The solubility of slaked lime, [tex]Ca(OH)_2[/tex], in water is 0.185 g/100 ml. You will need to calculate the volume of [tex]2.50\times 10^{-3}[/tex]M HCl needed to neutralize 14.5 mL of a saturated
Answer: The volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of
Explanation:
Given values:
Solubility of [tex]Ca(OH)_2[/tex] = 0.185 g/100 mL
Volume of [tex]Ca(OH)_2[/tex] = 14.5 mL
Using unitary method:
In 100 mL, the mass of [tex]Ca(OH)_2[/tex] present is 0.185 g
So, in 14.5mL. the mass of [tex]Ca(OH)_2[/tex] present will be =[tex]\frac{0.185}{100}\times 14.5=0.0268g[/tex]
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of [tex]Ca(OH)_2[/tex] = 0.0268 g
Molar mass of [tex]Ca(OH)_2[/tex] = 74 g/mol
Plugging values in equation 1:
[tex]\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol[/tex]
Moles of [tex]OH^-[/tex] present = [tex](2\times 0.000362)=0.000724mol[/tex]
The chemical equation for the neutralization of calcium hydroxide and HCl follows:
[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]
By the stoichiometry of the reaction:
Moles of [tex]OH^-[/tex] = Moles of [tex]H^+[/tex] = 0.000724 mol
The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(2)
Moles of HCl = 0.000724 mol
Molarity of HCl = [tex]2.50\times 10^{-3}[/tex]
Putting values in equation 2, we get:
[tex]2.50\times 10^{-3}mol=\frac{0.000724\times 1000}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.000725\times 1000}{2.50\times 10^{-3}}=290mL[/tex]
Hence, the volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
Explain the science of water pressure
"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "
Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you. Which causes greater force.
Draw the R enantiomer of CFClBrI as a 3-D (wedge and dotted line) structure and as a Fischer projection (putting the I at the top and the F to the right). Be able to draw Fischer projections for other simple compounds with a single chiral carbon.
The 3D structure of R- CFClBrI is drawn using wedges and dotted line with I in the top and F right to I and Fischer projection is drawn using lines for bonds where C is placed at center and I in the top with F right to it.
What is an enantiomer?An enantiomer is a spatial isomer of a compound having different spatial configuration but the same formula. Enantiomers are non-superimposable mirror images of each other.
In R- enantiomer, the elements are arranges in a way that on numbering in clockwise direction, the priority of group decreases from 1 to 2 to 3 and follows. The highest priority group is numbered first.
If the count 1..2..3 goes in anti-clockwise direction, then the enantiomer is termed as S. In 3D projection, wedges and dotted lines are used for representing bonds.
In Fischer projection, lines are used for bonds as shown in the uploaded image. Where the chiral carbon is shown in center and other groups are allotted as per the R or S configuration.
Therefore, the 3D image and Fischer projection of CFClBrI is drawn as in the image uploaded.
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Calculate the lattice energy of CuBr(s) using a Born–Haber cycle.
Data:
Enthalpy of sublimation of Cu(s) = 337.7 kJ/mol
1st ionization energy of Cu(g) = 745 kJ/mol
Enthalpy of vaporization of Br2(l) = 29.96 kJ/mol
Find the pH of 0.05M Pyridine C 6 H 5 N solution. Know the base dissociation constant K C6H5N = 1.7.10 -9 .
Answer: 10
Explanation:
Which sequence contains elements listed from most reactive
to least reactive?
Answer:
Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.
Hope this answer is right!
A diamond can make permanent marks on glass. It can also cut glass. Most other materſals cannot do this.Which property of a diamond allows it to make cuts or marks on glass? a. Hardness b. Heaviness c. Roughness d. transparency
11. Which of these conditions would decrease the rate of photosynthesis in a plant?
A. above average precipitation
B. Changing the daylight hours from 14 hrs to 10 hrs
C. Changing the CO2 concentration from 380 ppm to 410 ppm
D. All of these choices
Answer:
B. Changing the daylight hours from 14 hrs to 10 hrs
Explanation:
what is the formula for trioxocarbonate (IV)
Answer:
[tex]CO_3^{2-}[/tex]
Explanation:
Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.
All sodium, potassium, and ammonium of trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.
Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.
The formula for Trioxocarbonate (iv) is: [tex]CO_3^{2-}[/tex]
So, we can have Sodium trioxocarbonate as [tex]Na_2CO_3[/tex] and sodium hydrogen trioxocarbonate (iv) [tex]NaHCO_3[/tex]
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
PLEASE HELP ME SOLVE THIS.Thank you so much!
Answer: The coefficients for the given reaction species are 1, 6, 2, 3.
Explanation:
The given reaction equation is as follows.
[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]
Now, the two half-reactions can be written as follows.
Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]
This will be balanced as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)
Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]
This will be balanced as follows.
[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)
Adding both equation (1) and (2) we will get the resulting equation as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]
Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.