A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?

Answers

Answer 1

Answer:

67.6m/s

Explanation:

Given parameters:

Initial velocity  = 8.2m/s

Acceleration  = 9.0m/s²

Time  = 6.6s

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use the expression below:

     Acceleration  = [tex]\frac{v - u }{t}[/tex]

v is the final velocity

u is the initial velocity

 t is the time taken

    9  = [tex]\frac{v - 8.2}{6.6}[/tex]  

    v - 8.2  = 59.4

    v  = 59.4 + 8.2 = 67.6m/s


Related Questions

A 2 kg marble moving at 4 mi./s collides into a 1 kg marble at rest. After collision, the 2 kg marble speed decreased to 2 mi./s. Calculate the velocity and speed of the 1 kg marble immediately after colliding.

Please show work and please help me as fast as possible because this is time

Please help as soon as possible please

Please I’m begging

Answers

Answer:

[tex]2\sqrt{6}[/tex]  [tex]\frac{mi}{s}[/tex]

Explanation:

Assuming there is no waste of energy:

[tex]K_{1} = K_{2}\\\frac{1}{2}m_{1}v_{1_{1}}^{2} + \frac{1}{2}m_{2}v_{2_{1}}^2 = \frac{1}{2}m_{1}v_{1_{2}}^{2} + \frac{1}{2}m_{2}v_{2_{2}}^2\\\\=> m_{1}v_{1_{1}}^{2} + m_{2}v_{2_{1}}^2 = m_{1}v_{1_{2}}^{2} + m_{2}v_{2_{2}}^2\\\\m_{1} = 2 kg, m_{2} = 1 kg, v_{1_{1}} = 4 \frac{mi}{s} , v_{2_{1}} = 0\\=> 32 = 8 + v_{2_{2}}^{2} => v_{2_{2}} = 2\sqrt{6} \frac{mi}{s}[/tex]

Please help me
27. A 20 kg object is at rest. A 6 N force pulls to the right on
the object for 10 seconds.
A) Find the impulse on the object.
B) Find the final momentum of the object.
C) What is its final velocity?

Answers

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

Learn more about impulse and momentum: https://brainly.com/question/904448

Radar tells an air traffic controller that a jet is slowing as it nears the
airport. Which might represent the jet's velocity?

A. 700 h/km

B. 700 km

C. 700 km/hr

D. 700 km/h west

Answers

Choice-D is the only velocity on the list.

(It has a speed and a direction.)

The jet's velocity might be represented by  700 km/h west. Hence, option (D) is correct.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

In this question, 700 h/km, 700 km have different unit that of velocity. So, option (A) and option (B) is not correct. . 700 km/hr has same unit that of velocity.  But it does not has direction. So, option (C) is also incorrect.  700 km/h west has the same unit of velocity with define direction. So, option (D) is correct.

Hence option (D) is correct answer.

Learn more about velocity here:

https://brainly.com/question/18084516

#SPJ6

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