Answer:
Energy stored in the rod, W = 4.55 × 10⁻⁴ J
Explanation:
From the question, the following values are given:
Mass of the brass rod, m = 10kg
Length of rod, l = 1 m
Radius of brass rod, r =1 cm
Change in length of rod, e = ?
Energy stored, W = ?
Young's modulus of brass, Y = 3.5 × 10¹⁰ N/m²
Using the formula for energy stored in an elastic material;
W = 1/2 F × e
Force due to the load, F = mg = 10 × 10 = 100N
To determine the change in length, e, we use the formula for Young's modulus of elasticity;
Y = (F/A)/(e/l) = F × l / A × e
e = (F × l) / (Y × A)
where A = πr²
e = 100 × 1 / (3.5 × 10¹⁰ × π × (0.01)²
e = 9.09 × 10⁻⁶ m
Therefore, energy stored in the rod, W = 1/2 × 100 × 9.09 × 10⁻⁶
Energy stored in the rod, W = 4.55 × 10⁻⁴ J
The cause of weather systems on earth is ___________?
A. Conduction
B. Convection
C. Radiation
Answer:
Convection and Radiation
Explanation:
Because the sun heats up the earth which cause the warm temperature and you probably know convection heat up the coefficient and radiation transfer heat electromagnetic or heat LOL
The cause of weather systems on earth is CONVECTION.
Convection can be defined as the transfer of heat from one site to another caused by the movement of fluid.This transfer of heat can be calculated as
Q=h A\Delta Twhere Q is equal to the rate of transference of heat; h is equal to convection heat-transfer coefficient; A to the surface area that is exposed and Delta T is equal to the temperature difference.Heat energy is always transferred from hot sites to cooler sites.This transfer of heat (convection) only occurs in liquids and gases.In conclusion, the cause of weather systems on earth is CONVECTION.
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She walks 50 yards north 20 yards east 50 yards south what is total displacement
Answer:
|---20----|
| |
| 50 |50
|---D--->|
Start End
Total displacement(D) 20 yards (East).
Explanation:
Janice jumps directly up into the air. Which direction is she accelerating as she moves upward?
A Up
B.
Down
C.
Not accelerating
Answer:
b down
Explanation:
because as she is jumping she is bending her nees so the acceleration is down words
Answer:
b down
Explanation:
an oscillator with a mass of 310 g and a period of 0.180 s has amplited that decreases by 20 % during each complete oscillation what is the damping constant
Answer:
1.241/s
Explanation:
From this question, we have the following information:
Mass of oscillator = 310
The time Period, t = 0.180
Decrease = 20 %
Amplitude of oscillation has the formula
A = Aoe^yt
1-20% = 80%
= 0.80
Y x 0.18 = -ln(0.8)
= 0.18Y = 0.2234
Y = 0.2233/0.18
Y = 1.241/s
The damping constant y is Therefore equal to 1.241s
A train takes 2.5 hours to travel 120 kilometers. What is the train's average speed?
A: 0.02 hr/km
B: 48 km/hr
C: 48 hr/km
D: 0.02 km/hr
PLS HELPPP
Answer:
48
Explanation:
The formula is d, time t, and speed or rate of travel r is:
d = rt.
We know that d = 120 km and t = 2 hours and 30 minutes = 2.5 hrs.
So you now plug in for d and t to find r, we get:
120 km = r(2.5 hrs)
divide both sides by 2.5 and we get
120 km/2.5 hrs = [r(2.5 hrs)]/2.5 hrs
120 km/2.5 hrs = r(2.5 hrs/2.5 hrs)
48 km/hr = r(1)
r = 48 km/hr
Speed = (distance covered) / (time to cover the distance)
Speed = (120 km) / (2.5 hr)
Speed = (120/2.5) (km/hr)
Speed = 48 km/hr (B)
A kid on a trampoline has 1,000 J of potential energy when they are at the top of a jump. How much kinetic energy will the kid have when they come halfway down?
a. 100 J
b. 250 J
c. 500 J
d. 1,000 J
The kinetic energy which will the kid have when they come halfway down is 500 Joules. Thus, the correct option is C.
What is Kinetic energy?Kinetic energy is the energy of motion of an object, it is observable as the movement of an object or the subatomic particles. Every moving object have certain amount of kinetic energy.
Potential energy of the kids at the top of the trampoline is,
P.E = 1000 J
At the top of the trampoline, the kids have only the potential energy.
On the half way down, the kids will have both the kinetic energy and potential energy.
At the bottom of the trampoline, the kids will have only kinetic energy.
Based on the statements given above, the kinetic energy of the kids will be half way down and it is calculate as:
P.E + K.E = 1000 J
Base on the law of conservation of energy, P.E = K.E
2 K.E. = 1000 J
K.E. = ¹/₂ x 1000 J
K.E. = 500 Joules
Therefore, the correct option is C.
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What is an indicator that the universe is exapanding?
Answer:
*Doppler effect by the displacement or towards the red
*The microwave temperature of the universe
Explanation:
The expansion of the universe can be visualized in various facts
* the stars and galaxies are moving away from us, this is observed in the Doppler effect by the displacement or towards the red of the hydrogen lines.
* The microwave temperature of the universe that comes from everywhere, this temperature is the rest of the temperature of an initial great explosion (big ban), for which the expanding universe must cool down.
Need help with this pleases
A 166-g hockey puck is gliding across the ice at 24.5 m/s. A player whacks it with her stick, sending it moving at 39.1 m/s at 45.0∘ to its initial direction of motion.
What is the angle between the initial velocity of the puck and the force exerted on the puck?
If stick and puck are in contact for 136 ms, what is the magnitude of the average force that was exerted on the puck?
Answer:
θ = 83.5º, F = 33.97 N
Explanation:
For this exercise we use Newton's second law that the resultant of the external forces is in the direction of the acceleration, therefore we look for the force for each axis
the initial velocity is on the x axis v₀ₓ = 24.5 m / s
let's break down the final velocity
sin 45 = v_y / v
cos 45 = vₓ / v
v_y = v sin 45
vₓ = v cos 45
v_y = 39.1 sin 45 = 27.65 m / s
vₓ = 39, 1cos 45 = 27.65 m / s
now let's use the ratio of momentum and amount of movement, for each exercise
∫ F dt = Δp
X axis
Fₓ t = [tex]p_{fx} - p_{ox}[/tex]
Fₓ = [tex]m \frac{v_{fx} - v_{ox} }{t}[/tex]
Fₓ = 166 10⁻³ (27.65 - 24.5) / 136 10⁻³
Fₓ = 3.84 N
Y axis
F_y t = [tex]p_{fy} - p_{oy}[/tex]
the initial velocity in the y axis is zero
F_y = m [tex]\frac{v_{fy} }{t}[/tex]
Fy = 166 10⁻³ 27.65 / 136 10⁻³
Fy = 33.75 N
Let's use the Pythagorean theorem to find the magnitude of the force
F = [tex]\sqrt{F_x^2 + F_y^2}[/tex]
F = [tex]\sqrt{3.84^2 +33.75^2}[/tex]
F = 33.97 N
the direction is found using trigonometry
tan θ = F_y / Fₓ
θ = tan⁻¹ F_y / Fₓ
θ = tan⁻¹ 33.75 / 3.84
θ = 83.5º
1. The more velocity an object has the harder it is to slow
it down, speed it up, or turn it.
Answer:
The more velocity an object has the harder it is to slow it down
Explanation:
slow it down
Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1 m. Conductor B is a hollow tube of inside diameter 1 m and outside diameter 2 m. The ratio of their resistance, RA/RBRA/RB, is:
Answer:
Ra / Rb = 3
Explanation:
The resistance is defined by the expression
r = ρ L / A
where A is the area of the wire and L is the length
let's find the area of each wire
a) solid wire (A) of d₁ = 1 m
r = d₁ / 2 = 0.5 m
A = π r²
A = π 0.5²
R_a = [tex]\frac{\rho \ L}{\pi \ 0.5^2}[/tex]
R_a = 4 \frac{\rho \ L}{\pi }
b) hollow tube (B) of d₁ = 1 m and d₂ = 2m
the radios are
r₁ = 0.5 m
r₂ = 1 m
the area is
A = π r₂² - π r₁²
A = π (r₂² - r₁²)
A = π (1² - 0.5²)
A = π 0.75
resistance is
R_b = [tex]\frac{ \rho \ L }{\pi \ 0.75}[/tex]
R_b = 1.33 \frac{ \rho \ L }{\pi }
therefore the relationship between these two resistances is
Ra / Rb = 4 / 1.33
Ra / Rb = 3
Force is a vector because it has both ___
and ____
A. distance and direction
B. size and distance
C. size and direction
Answer:
C. Size and Direction
What are the characteristics of Earth’s lithosphere and how does the lithosphere play a role in plate tectonics?
A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant speed of 6 m/s. a) Calculate the magnitude of the normal force acting on the car when it is on the top of the circle and when it is on the bottom of the circle, respectively. b) What is the minimum speed the car needs to go around the circle without falling off
Answer:
a)[tex]|N|=9.83\: N[/tex] at the top
[tex]|N|=33.37\: N[/tex] at the botton
b) The minimum velocity will be [tex]v=4.43\: m/s[/tex].
Step-by-step explanation:
a) Using the second Newton's law, at the top of the circle we have.
[tex]\Sigma F=ma_{c}[/tex]
The forces at the top are the weight and the normal force.
[tex]W-N=m\frac{v^{2}}{R}[/tex]
[tex]mg-N=m\frac{v^{2}}{R}[/tex]
[tex]N=mg-(m\frac{v^{2}}{R})[/tex]
[tex]N=1.2*9.81-(1.2\frac{6^{2}}{2})[/tex]
[tex]N=-9.83\: N[/tex]
[tex]|N|=9.83\: N[/tex]
At the botton of the circle we have:
[tex]N-W=m\frac{v^{2}}{R}[/tex]
[tex]N-mg=m\frac{v^{2}}{R}[/tex]
[tex]N=1.2*9.81+(1.2\frac{6^{2}}{2})[/tex]
[tex]|N|=33.37\: N[/tex]
b) If we do the normal force equal to zero we can find the minimum velocity, which means:
[tex]W-0=m\frac{v^{2}}{R}[/tex]
[tex]mg=m\frac{v^{2}}{R}[/tex]
[tex]v=\sqrt{Rg}[/tex]
[tex]v=\sqrt{2*9.81}[/tex]
Therefore, the minimum velocity will be [tex]v=4.43\: m/s[/tex].
I hope it helps you!
What are some of the physical properties of minerals
Answer:
hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.
Explanation:
doesn't really need one.
A 30.8 kg box rests on an incline of 13 degrees. What is the normal force, in Newtons, exerted by the incline?
so 30.8/13= is 2.369
so round your ans to I dp which is
2.4d/kg
What is the length of the x-component of the vector shown below?
c. 6.6
What is x component?The x-component of a vector can be either sinθ or cosθ, depending on which angle you are given.
Cosθ always goes with the side of a right triangle that is adjacent to (touches) the given angle.
The projection of a vector quantity on the x axis of a coordinate system.
If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is
x-component = 8· cosine(34°)
x-component = 8 · (0.829)
x-component = 6.6
Therefore,
6.6 is the length of the x-component of the vector.
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a stone is thrown vertically upward with a velocity of 29.4m/s from the top of tower 34.3m high.calculate the total time taken by the stone to reach the foot of the tower.
Answer:
7 s
Explanation:
We'll begin by calculating the maximum height reached by the stone from the point of projection. This can be obtained as follow:
Initial velocity (u) = 29.4 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =?
v² = u² – 2gh (since the stone is going against gravity)
0² = 29.4² – (2 × 9.8 × h)
0 = 864.36 – 19.6h
Collect like terms
0 – 864.36 = –19.6h
–864.36 = –19.6h
Divide both side by –19.6
h = –864.36 / –19.6
h = 44.1 m
Next, we shall determine the time taken to reach the maximum height from the point of projection. This can be obtained as follow:
Initial velocity (u) = 29.4 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Time (t₁) take to reach the maximum height =?
v = u – gt (since the stone is going against gravity)
0 = 29.4 – (9.8 × t₁)
0 = 29.4 – 9.8t₁
Collect like terms
0 – 29.4 = – 9.8t₁
–29.4 = –9.8t₁
Divide both side by –9.8
t₁ = –29.4 / –9.8
t₁ = 3 s
Next, we shall determine the time taken for the stone to reach the ground from the maximum height reached by the stone. This can be obtained as follow:
Maximum height (H) from the ground = 34.3 + 44.1 = 78.4 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t₂) taken for the stone to reach the ground from the maximum height reached by the stone =?
H = ½gt₂²
78.4 = ½ × 9.8 × t₂²
78.4 = 4.9 × t₂²
Divide both side by 4.9
t₂² = 78.4 / 4.9
t₂² = 16
Take the square root of both side
t₂ = √16
t₂ = 4 s
Finally, we shall determine the total time taken for the stone to reach the ground. This can be obtained as follow:
Time (t₁) take to reach the maximum height = 3 s
Time (t₂) taken to reach the ground from the maximum height reached by the stone = 4s
Total time (T) taken to reach the ground =?
T = t₁ + t₂
T = 3 + 4
T = 7 s
Thus, it took the stone 7 s to reach the ground.
What is Gravitational force?
Answer:
the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface
Explanation:
Answer:
Gravitational force is the force of attraction in which body having certain mass in the universe attracts every other body which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Assume the ground is uniformly level. If the horizontal component a projectile's velocity is doubled, but the vertical component is unchanged, what is the effect on the time of flight
Answer:
Explanation:
Time of flight = 2 x u sinα / g where u sinα is vertical component of projectile's velocity u .
So Time of flight = 2 x vertical component / g
vertical component = constant
g is also constant so
Time of flight will also be constant .
It will remain unchanged .
The manufacturer of a 9[V] flashlight battery says that the battery will deliver 20[mA] for 80 continuous hours. However, during that time the voltage will drop from 9[V] to 6[V]. Assume the voltage change with time is linear in time; in other words, the plot of voltage versus time is a straight line. Assume that the current is constant during these 80 hours.
Your question should includes how much energy does the battery deliver in 80 hours interval.
Answer:
The battery delivers 17,280 J
Explanation:
Starting voltage v1 = 9V
Final voltage v2 = 6V = voltage drop after 80hrs
v = v1 - v2 = 9 - 6 = 3V
Electrical current (i) = 20[mA] = 20*10^-3 A
Discharging time = 80 Hrs = 80*(60*60) sec = 288,000 sec
Work done = energy (W) = p.t
Where p = v*i
W = v*i*t
W = 3*(20*10^-3)*288,000
W = 17,280 J
The battery delivers 17,280 J
6.8. A marble with a mass m of 3.00 g is released from rest in a bottle of syrup. Its terminal speed vt is 1.79 cm/s. (a) Presuming the resistive force R = −bv, what is the value of b (N s/m)? (b) What is the strength of the resistive force (N) when the marble reaches terminal speed? (c) How long in milliseconds does it take for it to reach a speed of 0.600vt?
Answer:
a. 1.642 Ns/m b. 0.0294 N c. 5 × 10⁵ ms
Explanation:
a. Presuming the resistive force R = −bv, what is the value of b (N s/m)?
Using the equation of motion on the object,
W + R = ma where W = weight of the mass = mg where m =mass of marble = 3.00 g = 0.003 kg and g = acceleration due to gravity = 9.8 m/s² , R = resistive force = -bv where v = velocity and a = acceleration of marble.
So,
mg - bv = ma
At terminal speed, a = 0,
So, mg - bvt =m(0)
mg - bvt = 0
mg = bvt
b = mg/vt since terminal speed vt = 1.79 cm/s = 0.0179 m/s
So, b = 0.003 kg × 9.8 m/s²/0.0179 m/s
b = 0.0294 kgm/s² ÷ 0.0179 m/s
b = 1.642 Ns/m
b. What is the strength of the resistive force (N) when the marble reaches terminal speed?
Since the resistive force R = -bv, at terminal speed, vt
R = -bvt
R = -1.642 Ns/m × 0.0179 m/s
R = -0.0294 N
So, its strength is 0.0294 N
(c) How long in milliseconds does it take for it to reach a speed of 0.600vt?
Using mg - bv = ma where a = dv/dt,
mg - bv = mdv/dt
g - bv/m = dv/dt
separating the variables, we have
dv/(g - bv/m) = dt
Integrating, we have
∫dv/(g - bv/m) = ∫dt
(-b/m)/(-b/m) × ∫dv/ (g - bv/m) = ∫dt
1/(-b/m) ∫(-b/m)dv/(g - bv/m) = ∫dt
1/(-b/m) ㏑(g - bv/m) = t + C
㏑(g - bv/m) = -m/bt - mC/b
㏑(g - bv/m) = -m/bt + C' (C' = -mC/b)
taking antilogarithm of both sides, we have
g - bv/m = exp(-m/bt + C')
g - bv/m = exp(-m/bt)expC'
g - bv/m = Aexp(-m/bt) (A = expC')
bv/m = g - Aexp(-m/bt)
v = mg/b - (Am/b)exp(-m/bt)
when t = 0, v = 0 (since the marble starts from rest)
0 = mg/b - (Am/b)exp(-m/b(0))
0 = mg/b - (Am/b)exp(0))
-mgb = -Am/b
A = g
v = mg/b - (mg/b)exp(-m/bt)
when v = 0.600vt = 0.600 × 0.0179 m/s = 0.01074 m/s
mg/b = 0.003 kg × 9.8 m/s²/1.642 Ns/m = 0.0179 m/s and m/b = 0.003 kg/1.642 Ns/m = 0.00183/s
So,v = mg/b - (mg/b)exp(-m/bt)
0.01074 m/s = 0.0179 m/s - (0.0179 m/s)exp[(-0.00183/s)t]
0.01074 m/s - 0.0179 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]
-0.00716 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]
exp[(-0.00183/s)t] = -0.00716 m/s/-0.0179 m/s
exp[(-0.00183/s)t] = 0.4
taking natural logarithm of both sides, we have
(-0.00183/s)t = ㏑(0.4)
(-0.00183/s)t = -0.9163
t = -0.9163/-0.00183
t = 500 s
t = 500 × 1000 ms
t = 5 × 100000
t = 5 × 10⁵ ms
an atom possesses 18 protons and 20 electrons what is the net charge on the atom
Answer:
It's a neutral atom.
Explanation:
Atomic No. = Mass No. − No. of neutrons
Atomic No. = No. of protons = 18
Mass No. = Atomic No. + No. of Neutrons= 18 + 20 = 38
Hope this helps
What is the potential energy at point e when the total mechanical energy is 4900 for the 100 kg moving at 2 m/ s
Answer:
B. 4700 J
Explanation:
Given the following data;
Mechanical energy = 4900J
Mass = 100kg
Velocity = 2m/s
To find the potential energy;
Mechanical energy = kinetic energy + potential energy
First of all, we would determine the kinetic energy of the object;
K.E = ½mv²
K.E = ½*100*2²
K.E = 50*4
K.E = 200 J
Substituting into the equation, we have;
4900 = 200 + P.E
P.E = 4900 - 200
P.E = 4700 Joules
A jet aircraft with a mass of 4,250 kg has an engine that exerts a force (thrust) equal to 60,100 N.
(a) What is the jet's acceleration when it takes off? (Give the magnitude.)
m/s2
(b)What is the jet's speed after it accelerates for 9 s? (Assume it starts from rest.)
m/s
(c) How far does the jet travel during the 9 s?
m
Answer:
A. 14.14 m/s²
B. 127.26 m/s
C. 572.67 m
Explanation:
From the question given above, the following data were obtained:
Mass (m) of jet = 4250 kg
Force (F) = 60100 N
A. Determination of the acceleration of the jet.
Mass (m) of jet = 4250 kg
Force (F) = 60100 N
Acceleration (a) =?
F = ma
60100 = 4250 × a
Divide both side by 4250
a = 60100 / 4250
a = 14.14 m/s²
B. Determination of the speed of the jet after 9 s.
Initial velocity (u) = 0 m/s
Acceleration (a) = 14.14 m/s²
Time (t) = 9 s
Final velocity (v) =?
v = u + at
v = 0 + (14.14 × 9)
v = 0 + 127.26
v = 127.26 m/s
C. Determination of the distance travelled during the time.
Initial velocity (u) = 0 m/s
Acceleration (a) = 14.14 m/s²
Time (t) = 9 s
Distance travelled (s) =?
s = ut + ½at²
s = (0 × 9) + (½ × 14.14 × 9²)
s = 0 + (7.07 × 81)
s = 0 + 572.67
s = 572.67 m.
2. The kinetic energy of an object is 30. Find Its kinetic energy If Its mass Is
doubled and Its speed Is multiplied by four.
Answer:
To determine the kinetic energy in this case, what you would do is to multiply the original kinetic energy value by the proportional amounts of the mass change and the speed change.
Basically if m = 1 and speed = 1 squared where KE = 30
Then m = 2 and speed = 4 squared is when KE is 16 x 2 x 30 which would be 32 x 30 = 960 Joules.
What are the functions of the codons
why do bees sting i think they do because when the get disturbed they use thier stinger to sting people
The diagram shows a proposed design for a ship that could be used for long-distance space travel. Explain why the ship must rotate so that passengers feel effects similar to gravity.
Answer:
I don't know this for sure, but I think its because they need to be able to sit in their seats without flying in the air.
Explanation:
Because of the centrifugal force he ship must rotate so that passengers feel effects similar to gravity.
What is Centrifugal force ?''Centrifugal force is force acting on a body performing circular motion, which is along radius of the circle and directed outwards from the center of circle". Since Centrifugal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.
centripetal force is given by,
F= mv²÷r
Where m is mass of the body v is velocity of the body r is radius of circle at which body is moving.
When space ship rotate to the certain angular velocity, centrifugal force will act on each object in the space ship. that force will force the object radially outwards as result all will stuck on the floor and all will experience the feel of gravity.
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How do motion and Newton's laws apply to your everyday life? (all of the laws)
Answer:
This may help
Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation: