A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress is 4 kg. How heavy a person (in N) could the air mattress hold if it is placed in freshwater

Answers

Answer 1

Answer:

[tex]2625.156\ \text{N}[/tex]

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

[tex]m_m[/tex] = Mass of mattress = 4 kg

[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Volume of mattress

[tex]V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3[/tex]

Weight of water displaced is equal to the buoyant force

Mass of water

[tex]m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}[/tex]

Mass of person would be

[tex]m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}[/tex]

Weight of the person would be

[tex]w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}[/tex]

The air mattress could hold a person that weighs up to [tex]2625.156\ \text{N}[/tex].


Related Questions

Which device increases or decreases voltage as electricity is transmitted from power plants to homes and businesses?

generator
power line
transformer
turbine

Answers

Answer:Transformer

Explanation:All the other devices generate their own electricity apart from power line and Transformer, power line just carries electricity. A transformer can be used to step up or step down voltages from a source.

Answer:

transformer!! :)

Explanation:

Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the same weight, has been pushed by dock workers and hits car B with a velocity of 3.25 m/s. Knowing that the coefficient of restitution is 0.8 between B and C and 0.5 between A and B, determine the velocity of each car after all collisions have taken place.

Answers

Answer:

V(c)' = 0.325 m/s

V(a)' = 2.19375 m/s

V(b)'' = 0.73125

Explanation:

See attachment for explanation.

A car wheel turns through 12pi in 10.7s calculate the angular speed of the wheel

Answers

Answer:

The answer should be D..

Explanation:

A5 N object at a height has gravitational potential energy of 30 J. What is the height of the object?​

Answers

30=5×h then divide both sides by 5 you will get h=6m

If a 5 N object at a height has a gravitational potential energy of 30 J , then the height of the object would be  6 meters.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a 5 N object at a height has gravitational potential energy of 30 J, then we have to find the height of the object.

Similarly, the total gravitational  potential energy of the object,

PE = m × g × h

30  = 5 × h

h  = 30 / 5

h  = 6 meters

Thus, if a 5 N object at a height has a gravitational potential energy of 30 J, then the height of the object would be  6 meters.

To learn more about mechanical energy from here, refer to the link given below  ;

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PLEASE HELP ASAP!!!
An object has a kinetic energy of 50 J and a velocity of 5 m/s, what is the mass of the
object?

A. 4 kg

B. 55 kg

С. 10 kg

D. 1 kg

Answers

Answer:

0.5mv^2=50, v=5, 25/2×m=50, m=50×2/25, So, the answer is 4

Electromagnetic waves used in cell phones are called

a. radio waves
b.microwaves
c. Gamma rays
d. Ultraviolet rays

Answers

Answer:

A.Radio waves

Explanation:

An Atwood's machine consists of two masses, m1 and m2, connected by a string that passes over a pulley. If the pulley is a disk of radius R and mass M , find the acceleration of the masses. Express your answer in terms of the variables m1, m2, R, M, and appropriate constants.

Answers

Answer:

Explanation:

Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.

Let tension in string be T₁ and T₂  . Let common acceleration of system be a

For motion of m₁

T₁-m₁g = m₁a ----- (1)

For motion of m₂

m₂g- T₂ = m₂a ------- (2)

For motion of pulley

(T₂-T₁ )R represents net torque

(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc

(T₂-T₁ )R = 1/2 M R² x a / R

(T₂-T₁ ) = M a /2

Adding (1) and (2)

(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )

(m₂-m₁)g = (m₂+m₁)a + Ma/2

(m₂-m₁)g = (m₂+m₁+ 0.5M)a

a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)

The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

Given to us

Masses = m₁, m₂

The radius of the pulley = R

Mass of the pulley = M

Assumption

Let the mass m₁ > m₂. therefore, the mass m₁ is going down due to its weight while m₂ is going up.Assuming the tension in the string be T₁ and T₂, respectively.Also, the common acceleration in the system is a.

Tensions in strings

We know the acceleration due to gravity is denoted by g,

Tension in string 1, T₁

[tex]T_1 = m_1(a+g)[/tex]......... equation 1

Tension in string 2, T₂

[tex]T_2 = m_2(a-g)[/tex]......... equation 2

Inertia and acceleration of the pulley

The inertia of the pulley,  [tex]I = \dfrac{1}{2}MR^2[/tex]

Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]

Torque in the pulley

[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]

Substitute the values we get,

[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]

[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]

[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]

[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]

[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]

Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

Learn more about Tension in strings:

https://brainly.com/question/4087961

Tom has a mass of 50,000 g and runs up a flight of stairs 4 m high in 12.5 seconds.
Calculate Tom’s power. (g = 10 m/s2)

Answers

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

m = 50000 g   kg / 1000 grmsm = 50000 / 1000 = 50 kgh = 4 mtime = 12.5 secondsg = 10 m/s^2

Formula

P = W * d/tW = m*g *d / t

Solution

P = 50kg * 10 m/s^2 * 4 m / 12.5 P = 160 watts.

How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
50 J,
12.5 J,
25 J,
49 J​

Answers

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

[tex]W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J[/tex]

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

You push
on box A with a horizontal
100-N force (Fig. Q4.31). Box A
weighs 150 N, and box B
weighs 50 N. Is the force that
box A exerts on box B equal to 100 N, greater than 100 N, or less than 100 N? Explain.

Answers

45 because you see it in a hot min.

A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebble of mass m2 from a height of 4h, and it hits the floor with the same kinetic energy KE. How do the masses of the pebbles compare

Answers

Answer:

Hello,

QUESTION)

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

Plants are known as producers because they can make their own food. Which of the following provides a list of basic needs a plant must have for photosynthesis to happen?

A.
water and oxygen in the air

B.
soil, energy from the sun, and oxygen in the air

C.
energy from the sun, carbon dioxide in the air, water

D.
soil, carbon dioxide in the air, energy from the sun

HELP PLEASE

Answers

Answer:

C .energy from the sun, carbon dioxide in the air, water

hope my answer helps

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On a spaceship designed to support a multiyear voyage to the outer planets of the solar system, plants will be grown to provide oxygen and to recycle carbon dioxide. Because the spaceship will be so far from the sun, an artificial light source will be needed to support photosynthesis. Which wavelengths of light should be used to maximize plant growth?

Answers

Answer:

A mixture of blue & red light.

Explanation:

During photosynthesis, the oxygen delivered emanates from water particles and if a weighty isotope of oxygen atom was noticed in delivered sub-atomic oxygen, the water atoms were marked with the hefty isotope.

In order to maximize the growth rate of the plant, the required wavelength of light to be used is a mixture of blue & red light. This is on the grounds that as the absorption optima of plant's photoreceptors are at wavelength frequency of red and blue light, subsequently the combination of red and blue light would be ideal for plant growth and development.

The productivity of red (650–665 nm) LEDs on plant development is straightforward on the grounds that these wavelength frequencies entirely fit with the retention pinnacle of chlorophylls and phytochrome, while the enhanced blue light presented the possibility that development under regular light could be mirrored utilizing blue and red LEDs with negligible use of energy.

We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that: (A) No magnetic field exists in that region of space. (B) The particle must be moving parallel to the magnetic field. (C) Either no magnetic field exists or the particle is moving parallel to B. (D) Either no magnetic field exists or the particle is moving vertical (perpendicular) to B.

Answers

Answer:

(C) Either no magnetic field exists or the particle is moving parallel to B.

Explanation:

The moving charged particle tends to show no magnetic forces. Due to its moving in the same direction and will be parallel to the field. As when the magnetic fed and charged particle velocity is parallel then there will be no force. As the magnetic field are made by the generation of the current with the field line concentric to the current-carrying wire.

Two copper rods are rubbed together will they become charged

Answers

Answer:

Explanation:When insulating materials rub against each other, they may become electrically charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged.

In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00  102 m distance in 9.5 s. Assuming that he ran with a constant speed equal to his average speed, and his kinetic energy was 3.40  103 J, what was Burrell’s mass?

Answers

Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg

If a force is applied, but the object does
not move, what can we say about the
amount of work that is done?
A. Some work is done.
B. No work is done.
C. The work equals the force.
D. A large amount of work is done.

Answers

Answer:

doesn't move, no work is done; if a force is applied and the object moves a distance d in a direction other than the direction of the force, less work is done than if the object moves a distance d in the direction of the applied.

Answer:

B. No work is done.

Explanation:

Work is only done when the object moves in the direction of the force.

You've always wondered about the acceleration of the elevators in the 101 story high Empire State Building. One day, while visiting New York, you take your bathroom scale into the elevator and stand on it. The scale reads 177 lb as the door closes. As the elevator moves upward the scale reading varies between a minimum value of 138 lb and a maximum value of 227 lb as the elevator travels 101 floors.
a. What is the magnitude of the acceleration as the elevator starts upward?
b. What is the magnitude of the acceleration as the elevator brakes to a stop?

Answers

Answer:

a) 2.8 m/s2

b) 2.2 m/s2

Explanation:

The lecture on the bathroom scale is equal to the normal force that the scale exerts on you, and is directed upward.There is another force acting on you, which is gravity.This force (which we call weight) is the product of the mass times the acceleration due to gravity, g, and is directed downward, opposite to the normal force.When the elevator  is at rest, no acceleration takes place, so according Newton's 2nd Law, no net force must be exerted on you.In this condition, the normal force Fn₀ must be equal to the weight:[tex]F_{no} = m * g = 177 lb (1)[/tex]Since the normal force takes any value needed to satisfy Newton's 2nd law, the two extreme lectures can be expressed as follows, in terms of  the two forces acting on you while the elevator is moving upward:

       [tex]F_{n1} = m * (g +a_{1}) = 227 lb (2)[/tex]

      [tex]F_{n2} = m * (g +a_{2}) = 138 lb (3)[/tex]

Replacing m by 177lb/g (a given), and rearranging, we can solve (1) for a₁, as follows:

       [tex]a_{1} = (\frac{227lb}{177lb} *g) - g = 0.28*g = 0.28*9.8m/s2 = 2.8 m/s2 (4)[/tex]

As it can be seen, the normal force takes a larger value in order to be compliant with the upward acceleration that opposes to gravity.In the same way, we can find the magnitude of the downward acceleration when the elevator brakes to a stop, from (3):

       [tex]a_{2} = (\frac{138lb}{177lb} *g) - g = -0.22*g =- 0.22*9.8m/s2 = -2.2 m/s2 (5)[/tex]

In this case, the normal force takes a lower value than at rest, due to the acceleration has the same direction as gravity.

Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track

Answers

Answer: B

Explanation: an object keeps moving unless it’s acted or interrupted by another force
Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track.
Answer is B

50 points help please

Answers

Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

An airplane of mass 13300 kg is flying in a straight line at a constant altitude and with a speed of 560.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.

Answers

Answer:

The magnitude of the lift generated by the wings of the airplane is 130,340 N.

Explanation:

Given;

mass of the airplane, m = 13,300 kg

speed of the airplane, v = 560 km/h = 155.56 m/s

The magnitude of the lift generated by the wings of the airplane is calculated as;

[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]

Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.

A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the water rises part-way along the straight sides, and then 5.00 cm3 of oil is poured into one end. As a result, the top surface of the oil ends up 0.550 cm higher than the water surface on the other side of the U. What is the density of the oil

Answers

Answer:

0.89 g/cm^3 = 890 kg/m^3

Explanation:

Cross sectional area of U-tube ( A ) = 1.00 cm^2

volume of oil ( V )  = 5.00 cm^3

change between top surface = 0.550 cm

height of oil = 5 cm  ( volume / area )

height of water = 5 - 0.550 = 4.45 cm

pressure at the oil-water junction = Pressure on the second side of the U-tube at same level

Po * g * Hoil = Pw * g * Hwater

Po * 5 = 1 * 4.45

∴ Density of oil ( Po ) = 4.45 / 5  g/cm^3 = 0.89 g/cm^3

BRAINLEST FOR CORRECT ANSWER PLEASE

Which has more momentum: a 3 kg sledgehammer swung at 1.5 m/s OR a 4 kg sledgehammer swung at 0.9 m/s? SHOW YOUR WORK

Answers

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

A beam of protons is directed in a straight line along the z direction through a region of space in which there are crossed electric and magnetic fields The electric field is 550 V m in the y direction and the protons move at a constant speed of 105 m s 1 What must be the magnitude of the magnetic field such that the beam of protons continues along its straight line trajectory Express your answer using two significant figures

Answers

Answer:

B = 5.23 T

Explanation:

Given that,

Electric field, E = 550 V/m

The speed of the proton, v = 105 m/s

We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.

To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.

[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]

So, the magnitude of the magnetic field is equal to 5.23 T.

What is the amount of thermal energy needed to make 5 kg of ice at - 10 °C to
steam at 100 °C? (Heat of fusion of Ice is 3.34 x 10 j/kg, specific heat capacity of
ice is 2.09 x 10 3 J/kg °C, Specific heat capacity of water is 4.186 x 10 ? J/kg° C,
Heat of vaporization of water 2.26 x 10 J/kg)

Answers

Answer:

The amount of thermal energy needed is 15167500 joules.

Explanation:

By First Law of Thermodynamics, we see that amount of thermal energy ([tex]Q[/tex]), in joules, is equal to the change in internal energy. From statement we understand that change in internal energy consisting in two latent components ([tex]U_{l,ice}[/tex], [tex]U_{l,steam}[/tex]), in joules, and two sensible component ([tex]U_{s,w}[/tex]), in joules, that is:

[tex]Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam}[/tex] (1)

By definitions of Sensible and Latent Heat, we expanded the formula:

[tex]Q = m\cdot (h_{f,w}+h_{v,w}+c_{ice}\cdot \Delta T_{ice}+c_{w}\cdot \Delta T_{w})[/tex] (2)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]h_{f,w}[/tex] - Latent heat of fussion of water, in joules per kilogram.

[tex]h_{v,w}[/tex] - Latent heat of vaporization of water, in joules per kilogram.

[tex]c_{ice}[/tex] - Specific heat of ice, in joules per kilogram per degree Celsius.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram per degree Celsius.

[tex]\Delta T_{ice}[/tex] - Change in temperature of ice, measured in degrees Celsius.

[tex]\Delta T_{w}[/tex] - Change in temperature of water, measured in degrees Celsius.

If we know that [tex]m = 5\,kg[/tex], [tex]h_{f,w} = 3.34\times 10^{5}\,\frac{J}{kg}[/tex], [tex]h_{v,w} = 2.26\times 10^{6}\,\frac{J}{kg}[/tex], [tex]c_{ice} = 2.090\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]c_{w} = 4.186\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]\Delta T_{ice} = 10\,^{\circ}C[/tex] and [tex]\Delta T_{w} = 100\,^{\circ}C[/tex], then the amount of thermal energy is:

[tex]Q = 15167500\,J[/tex]

The amount of thermal energy needed is 15167500 joules.

1. Budding is a way that some very tiny organisms can reproduce.

True
False
____________________________________

Male-female reproduction needs two parent cells to begin.

True
False

Answers

Answer:1.. true 2 false

Explanation:

Which of the following parallel plate diagrams would have the greatest electric fields between them?

Answers

The greatest electric field between them is Option B.

An electric field is the physical subject that surrounds electrically charged particles and exerts a force on all other charged debris inside the area, either attracting or repelling them. It also refers back to the bodily field of a machine of charged particles.

Reasoning:-

Electric field = Kq/r²

Since the distance is inversely proportional to the square root of the distance between them. therefore decreasing the distance electric field will be the greatest. Hence Option B.

The electrical field is defined mathematically as a vector discipline that can be related to each point in space, the force in step with unit charge exerted on a fine take a look at the price at rest at that factor. the electric field is generated by the electrical rate or through time-varying magnetic fields. electric fields provide us with the pushing force we need to set off the contemporary float.

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At the end of the previous experiment, aclumsy scientist drops the coil, while still in the magnetic field, and still oriented with its plane perpendicular to the magnetic field, denting it and changing its shape to a semi-circle. The new shape has the same perimeter, but a different area, and it takes 0.036s to deform. What isthe average induced EMF during this mishap

Answers

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

can someone pls tell me what a force diagram is​

Answers

A diagram showing the forces acting on the object. The object is represented by a dot with forces are drawn as arrows pointing away from the dot. Sometimes called force diagrams.

Constructive interference occurs when the crest of 2 waves meet. This can occur when 2 troughs meet as well. When this occurs, water waves look


A- the same (no change)


B- larger


C- invisible


D- smaller

Answers

Answer:

B; Larger

Explanation:

I took the K-12 quiz, and that was the correct answer. Hope this helped!

Other Questions
What is an equation of the line that passes through the point (4,-1) and has a slope of -2? 6. What is the first step when looking at a data set?Un a) Find the meanb) Sort the data into categoriesFind the ranged) Put the data in ascending order Your roommate told you she doesnt need renters insurance because her parents homeowners policy covers her stuff. Is she correct? Explain your answer. Round to nearest degree.811 write an equation for the table below representing the relationship between the number of games and the total cost Why did the aztec initially accept the spanish? Which of the following will equal to a product of 8/10? PLEASE I NEED HELP ASAPFind the standard deviation of the given data rounded to the nearest hundredth. 5.6, 5.2, 4.6, 4.9, 5.7, 6.4 24 Explain how to use informal assessment to effectively prepare for an examination The excerpt below was from a notice posted by J.J. Cook of the Confederate Army.Notice! Headquarters. Galveston, October 4th, 1862. 10 o'clock P.M. The Commander of the Federal Naval Fleet having granted four days' time to remove the women and children from the City. Notice is hereby given to the citizens, that they may avail themselves of the opportunity of leaving.The notice above represents precautions taken by the Confederate army before the battle. Based on the information from the notice, which of the following statements best reflects the priorities of Texas military leaders before a battle?A. They were concerned with finding as many deserters as possibleB. They were concerned with evacuating the elderlyC. They were concerned with enlisting as many people as possible to fightD. They were concerned with evacuating women and children Factor completely 12n^3 + 15n^2 + 4n + 5 please help me solve this problem!! Lincoln joined a volunteer company in the Black Hawk War in 1832. He served only three months in the war, and he never saw battle. Even so, Lincoln considered this event to be one of the greatest successes of his life. The men in his company elected him captain, and Lincoln was very proud of, yet humbled by, their confidence in him. How does this source add to the reader's understanding of Lincoln? It shows that he was frightened by battles and war. It shows that he took his leadership roles seriously. It shows that he had only a few successes in his life. It shows that he had too much confidence in himself. If i add water to orange juice is that a physical change or chemical change? Review the event fromThe Strangers That Came to Town. The Duvitch family moves to their new house on Syringa Street.Which plot element is best represented by this event?A. complicating incidentB. expositionC. climaxD. rising action write any three methods of controlling flood landslide and soil erosion 6 of 725 = 700 rubles, how many are in 1,260 rubles? science, who ever answers this will get a brainlest At a constant temperature the pressure on a 10.0L sample of gas is charged from 1140 torr to 1.00 atm. What is the new volume of gas sample? in which layer of the atmosphere do the radio wave signals bounces off? Explain the importance of this characteristic to use