A triangle has one angle that measures 81° and one that measures 37° what is the measure of a third angle

Answer: Im answering this for points

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Explanation:

based on the law of conservation of energy its it atoms hold by strong chemical bonds

Answer:

2.44 g S

Explanation:

One mole of Na2SO4 contains 1 mol of S.

Step 1: Find out the moles of Na2SO4:

10.8 g Na2SO4/MM Na2SO4

Step2: Find out the moles of S:

moles S = moles Na2SO4

Step 3: Find out the mass of S.

mass S = moles S x MM S

Dimensional analysis:

? g S = 10.8 g Na2SO4 x (1mol Na2SO4/MM Na2SO4) x (1mol S/1mol Na2SO4) x (MM S/ 1 mol S) = (10.8/142.04)x32.1 = 2.44 g S

Answer:

3. 116.5 V

4. 119.6 V

Explanation:

3. Determination of the voltage.

Resistance (R) = 25 Ω

Current (I) = 4.66 A

Voltage (V) =?

V = IR

V = 4.66 × 25

V = 116.5 V

Thus, the voltage is 116.5 V

4. Determination of the voltage.

Current (I) = 9.80 A

Resistance (R) = 12.2 Ω

Voltage (V) =?

V = IR

V = 9.80 × 12.2

V = 119.6 V

Thus, the voltage is 119.6 V

Answer:

Chalk is does not dissolve in water

Explanation:

i had the same question as you

Answer:

its C

Explanation:

The skeletal structure shows the outline of the compound with lines and bonds. Both the structures are unrelated. Thus, option C is correct.

Isomers are structures with identical molecular structures but differ in the skeletal or molecular representation. They also have varied properties as compared to the parent structure.

Identical compounds are structures that have the same atoms and are arranged with the same spatial design and orientation. The number of atoms and the spatial arrangement of the two compounds is different.

Therefore, the two compounds are unrelated.

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Answer:

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Answer:

Chlorine bleach is strongly basic. We actually make it by dissolving chlorine gas in a concentrated solution of sodium hydroxide, which forms sodium hypochlorite and sodium chloride, in the following equilibrium.

Explanation:

BTS ARMY

We inherit genes from our biological parents in specific ways. One way is called autosomal dominant inheritance.

What is autosomal dominant inheritance?

Autosomal dominant inheritance means that the gene in question is located on one of the autosomes. These are numbered pairs of chromosomes, 1 through 22. (These chromosomes do not determine an offspring's gender.) Dominant means that only one gene from one parent is necessary to pass down a trait or a disorder. When a parent has a dominant trait or disorder, there is a 50 percent chance that any child he or she has will also inherit the trait or disorder:

Genetic illustration demonstrating autosomal dominant inheritance

Click Image to Enlarge

What is Marfan syndrome?

Marfan syndrome occurs in one of 5,000 live births. It is a connective tissue disorder associated with autosomal dominant inheritance. Connective tissue is abundant in the body and is important as a supporting structure. It is especially important for the musculoskeletal system. It also provides support for other body systems as well, including the eyes and the heart. The gene for Marfan syndrome is called fibrillin-1. This gene is localized to chromosome #15 on the long arm (q) at 15q21.1.  

Common findings in individuals with Marfan syndrome include those related to connective tissue disorders. These include abnormal enlargement of the aortic root of the heart, dislocated lenses of the eyes, and a tall, lanky body with increased joint mobility, scoliosis, long flat feet, and long fingers. Findings may vary among individuals diagnosed with this condition, even within a family.

If an individual carries an abnormal gene for Marfan syndrome, that individual has a 50 percent risk of passing down the disorder to each future offspring. If a person does not carry the gene abnormality, then the risk for occurrence of the disorder in future offspring is the same as for the general population.

Explanation:

Answer:

Explanation:

Molarity of NaOAc needed

Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.

pH = pKa + log [NaOAc]/[HOAc]

5.00 = 4.75 + log[NaOAc]/[1.00M]

5.00 - 4.75 = log [NaOAc] - log[1.00M]

log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78

Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.

Determine Volume of Base Needed

(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base

Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.

Checking Results:

5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00    QED.

The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.

We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:

[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex]   (1)  

Where:

[CH₃COOH] = 1.00 M                      

[CH₃COONa] =?

pH = 5.00

pKa = 4.75

From equation (1), we have:

[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]

Now, the volume of the acetate solution is:

[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]  

Since the total volume is the same, we have:

[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]  

[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]  

Solving for Vb

[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]

Therefore, we need to add 17.8 mL of sodium acetate solution.

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Answer:C

Explanation:

Answer:

D

Explanation:

because both H's should be positive and O is supposed to be negative.

Answer:

the theoretical 100% yield of the product in milligrams is 302920 mg

Explanation:  

Given the data in the question;  

245 mg of an oil

Using the moles of our protected aldehyde calculated earlier (2.96)

the molecular weight of the product (102 g/mol) = 102000 mg/mol

so, the mass of aldehyde produced (100% yield) will be;

⇒ number of moles × molar mass

⇒ 2.96 mol × 102000 mg/mol

⇒ 302920 mol.mg / mol

⇒ 302920 mg

Therefore, the theoretical 100% yield of the product in milligrams is 302920 mg

Answer: The coefficients are 2, 2 and 1.

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants.

The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the given reaction is:

2H2o➡️2h2+o2

oops...  sorry...  I need to delete this response.  I was trying to answer a different question,

Answer:

molar mass of H2CO3 = 72.0228

Answer:

62.02 g/mol

Explanation:

Took the test and got it right. if you have enough faith in brainly youll choose the right answer

the answer is A I took the test

Answer:

D . Na

Explanation:

Answer:

ΔH = -44.029 KJ/mol

Explanation:

We are told that 60.0 g of NaOH is dissolved in one litre of water.

From conversion, 1 litre = 1000 g

From tables, specific heat capacity of water; c = 4.18 J/g/°C

We are given ΔT = 15.8 °C

Formula for the heat absorbed by the solution is given as;

Q = mcΔT

Where;

Q = Heat gained by the water

m = Mass of the water

c = Specific heat of water

ΔT = change in temperature

Thus;

Q = 1000 × 4.18 × 15.8

Q = 66044 J

The solution absorbed 66044 J and therefore it means that the dissolution of the salt gave off 66044 J.

Thus;

Enthalpy is; ΔH = -66044 J

Now, Mass of NaOH is 60 g.

We know that molar Mass of NaOH is 39.997 g/mol. Thus;

Converting to moles, we have;

n = 60/39.997

n = 1.5 mol

Now, enthalpy when 1.5 moles of NaOH are dissolved in water will be;

ΔH = -66044 J/1.5 moles

ΔH = -44029.33 J/mol

ΔH = -44.029 KJ/mol

Answer:

D group

................

Answer:

-0.0132 atm

Explanation:

Step 1: Calculate the atmospheric pressure change if altitude increases 100. m

Atmospheric pressure decreases by 1.00 mmHg as altitude increases 10.0 m. The decrease in pressure when the altitude increases 100. m is:

100. m × (-1.00 mmHg/10.0 m) = -10.0 mmHg

Step 2: Convert "-10.0 mmHg" to atm

We will use the conversion factor 1 atm = 760 mmHg.

-10.0 mmHg × 1 atm/760 mmHg = -0.0132 atm

Answer:

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Answer:

Explanation:

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Answer:

6.46×10²² formula units

Explanation:

From the question given above, the following data were obtained:

Mass of MgCl₂ = 10.2 g

Number of formula units =?

From Avogadro's hypothesis,

1 mole of MgCl₂ = 6.02×10²³ formula units

But,

1 mole of MgCl₂ = 24 + (35.5×2) = 24 + 71 = 95 g

Thus, we can say:

95 g of MgCl₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units in 10.2 g MgCl₂. This can be obtained as follow:

95 g of MgCl₂ = 6.02×10²³ formula units

Therefore,

10.2 g of MgCl₂ = (10.2 × 6.02×10²³) / 95

10.2 g of MgCl₂ = 6.46×10²² formula units

Thus, 10.2 g of MgCl₂ contains 6.46×10²² formula units