A train is travelling at a uniform speed of 140 km/h. How long will it take to cover a
distance of 560 km?
(

Answers

Answer 1
Hope this helps!!!!!!!!!!!!
A Train Is Travelling At A Uniform Speed Of 140 Km/h. How Long Will It Take To Cover Adistance Of 560

Related Questions

Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods are held 8.0 cm apart by insulating blocks mounted every 1.5 m. If each block can tolerate a maximum tension force of 200 N, what is the maximum allowable current

Answers

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

An object of mass 45 kg is observed to accelerate at the rate of 6 m/s2. Calculate the force required to produce this acceleration​

Answers

135 is the best way to get to the acceleration

Which of the following should be practiced among all co-workers in the workplace?
A. bullying

B. discrimination
C. stereotyping

D. tolerance

Answers

I believe it is D. Tolerance.

HELPPPPPPPPPPPPPPPPPPPQuestion 17 of 25
Which property describes the distance from one compression to the next?
A. Frequency
B. Speed
C. Wavelength
O D. Period
SUBMIT

Answers

Answer: wavelength

Explanation:

Answer:

The answer would be "Wavelength" or C

Explanation:

I just did the exam

If a Sam goes above and beyond what is expected in her job duties, what might Sam's supervisor note on Sam's next evaluation?
O A. Sam has good attendance.
O B. Sam shows initiative.
O C. Sam stays focused on assigned tasks.
OD. Sam works well with others.

Answers

Answer:

2

Exadadadwwwwwwwplanation:

Electroconvulsive therapy would be done under the
supervision of a counseling psychologist, where high level
of electric shock would be admistered.
Select one:

True
False​

Answers

Answer:

the answer of this question is true

Which is the best way to become familiar with your company's policies and procedures?
O
A. ask the person who hired you
O
B. look in the employee handbook
C. tell your supervisor you need help
D. visit the company's website

Answers

The best way to become familiar with your company’s policies and procedures is C. Tell your supervisor you need help.

Please help if you can!

Answers

Answer:

C, Red has the longest one

c red

red has longest wavelength

amnh dot org

Which of the following is a category of mechanical wave?
O A. Transverse
B. Frictional
C. Parallel
D. Perpendicular

Answers

Answer:

a

because the mechanical wave is when it goes over and over again

Answer:

The answer is a like i said 3hrs ago i dont know if this guy copied me tbh

Explanation:

A man applies a force of 315 N to push the block of 225 kg onto 10 m ramp. Calculate the efficiency of the person if the mass gains a height of 1.2 m.​

Answers

Answer:

η = 0.84 = 84%

Explanation:

The efficiency of the man can be given by the following formula:

η = output/input

where,

η = efficiency of man = ?

output = potential energy gain of the block = mgh

input = work done by man = Fd

Therefore,

[tex]\eta = \frac{mgh}{Fd}[/tex]

where,

m = mass of block = 225 kg

g = acceleration due to gravity = 9.81 m/s²

h = height gained by block = 1.2 m

F = force exerted by man = 315 N

d = distance covered by man = 10 m

Therefore,

[tex]\eta = \frac{(225\ kg)(9.81\ m/s^2)(1.2\ m)}{(315\ N)(10\ m)}[/tex]

η = 0.84 = 84%

Write about
a time you had to ride a bicycle on a difficult
surface. What did you have to do to adjust your
riding?

Answers

I don’t understand the question

Which planet has the greatest gravity (of the choices shown)
Saturn
Venus
Uranus
Earth

Answers

Answer:

Earth

Explanation:

Answer:

Saturn/has best gravity out of the 4 planets.

Design a battery to be constructed of D-cells, rated at 3Amp-hours and voltage 1.5V, that will provide a maximum operating current of 5.0A with an emf of 4.5V. One restriction is that no cell be required to supply in excess of 1.0A. What can you expect the lifetime of your battery to be while delivering maximum current

Answers

Answer:

9 hours

Explanation:

For each battery:

Current = 1 A

Voltage = 1.5 V

current and EMF required = 5.0 A and 4.5 V

Since each battery has a current of 1 A, we'll need to link five of them in parallel with our load to get a current of 5 A. so that the total current equals 5 amps . Now that each battery has a 1.5 V voltage drop and we require an emf of 4.5 V, we would use three batteries in series rather than a single battery.  So, there is a need to must substitute every single battery with three batteries in series for all five single batteries linked in parallel.

So, the total no. of batteries is

= 5 × 3 = 15 batteries.

On each battery, the charge is = 3 amp hours

The total charge = 15 × 3 = 45 amp hours.

Since the charge transferred within 1 hour = 5 amp

Then, the required lifetime of the battery is:

= 45 amp-hours/ 5 amp

= 9 hours

True or false. When a girl walks the action of pushing and the equal amd opposite reaction is being projected forward

Answers

This is true I think

It applies to Newton's Laws

it's true because it's a part of newtons law

PLS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

A) pass the ball to a teammate

B) Smash the shuttlecock downward in your opponents court

C)Do a fake hit . . .

D) Do a fake hit . . .

(Best guess)

A 10kg block is Pulled along a horizontal
Surface by a force
of 50N at an angles
of 37° with the horizontal If the
coefficient of sliding friction b/n the
block and the surface is o.2
(g=10m/s^2 Sin 37=O.6 and cos 37 = 0.8)
A, what frictional forces acting on the block?
B,what is the acceleration of the block?​

Answers

Answer:

hope u can understand the method

An 800 kg charging bull rams through a wooden fence. It was travelling at
5 m/s, now it's travelling at 3 m/s. How much impulse did the bull
experience by smashing the fence?

Answers

Answer:

J = 1600 kg-m/s

Explanation:

Given that,

The mass of charging bull rams, m = 800 kg

Initial speed, u = 5 m/s

Final speed, v = 3 m/s

We need to find the impulse the bull  experience by smashing the fence. Let it is J. We know that, impulse is equal to the change in momentum such that,

J = m(v-u)

Put all the values,

J = 800(3-5)

= 800(-2)

= -1600 kg-m/s

Hence, the magnitude of impulse is equal to 1600 kg-m/s.

when two capacitor 3muF and 6muF are connected in a parallel and combination is charged to a potential of 120 volt the potential difference across the 3muF capacitor is​

Answers

Answer:

V₁ = V = 120 V

Explanation:

Such a combination of capacitors in which;

1- Potential difference across each capacitor is the same

2- Total charge is distributed amongst the capacitors

; is called Parallel Combination.

Therefore, in this case, the potential difference across each capacitor will also be the same. Because the capacitors are connected in parallel here. So the voltage across 3 μF capacitor will be the same as the voltage across the 6 μF capacitor and they both will be equal to the total potential difference.

V₁ = V = 120 V

In designing subway trains and stations, engineers want to optimize the time and energy use between stations. A train can comfortably accelerate at 5 ft/s2 without causing its passengers to fall over. When coasting, the train will slow down at an acceleration of -2 ft/s2. The train begins at rest and must come to a complete stop at the destination. If two train stations are 2 miles apart, determine the fastest time that the train can arrive at the second station given the provided accelerations. Also, determine the maximum velocity obtained. Draw the a-t, v-t, and s-tgraphs for the train. (122 s, 174 ft/s)

Answers

Answer:

Explanation:

Let the time required for acceleration a₁ and deceleration a₂ be t₁ and t₂ .

Since final velocity during acceleration and initial velocity during deceleration are same

a₁ t₁ = a₂ t₂

5t₁ = 2 t₂ ------------------------------------------ ( 1 )

Distance travelled during acceleration = 1/2 a₁t₁²

= 1/2 x 5 x t₁² = 2.5 t₁²

Distance travelled during deceleration = 1/2 a₂t₂²

= 1/2 x 2 x t₂² = t₂²

Total distance travelled = 2 miles = 2 x 1760 x 3 ft = 10560

2.5 t₁² + t₂² = 10560

2.5 ( 2t₂ / 5  )² + t₂² = 10560

.4 t₂² + t₂² = 10560

1.4 t₂² = 10560

t₂ = 86.85 s

t₁ = 2t₂ / 5 = 34.75 s

t₁ + t₂ = 121.6 = 122 s

Total time taken = 122 s .

maximum velocity = a₁t₁

= 5 x 34.75 = 173.75 = 174 m/s .

While traveling along a highway a driver slows from 34 m/s to 17 m/s in 6 seconds. What is the automobiles acceleration?​

Answers

Answer:

-2.83 m/s²

Explanation:

Initial velocity (u) = 34 m/sFinal velocity (v) = 17 m/sTime taken (t) = 6 seconds

❖ Acceleration is defined as the rate of change in velocity with time.

→ a = (v - u)/t

v denotes final velocitya denotes accelerationu denotes initial velocityt denotes time

→ a = (17 - 34)/6 m/s²

→ a = -17/6 m/s²

→ Acceleration = -2.83 m/s²

(Minus sign implies that the velocity is decreasing.)

The period of a sound wave coming from an instrument is 2 seconds. What 1 point
is the frequency of the sound? (f = 1/T) *
5 Hz
50 Hz
ОО
0.5 Hz

Answers

Answer:

b

Explanation:

The Equipartition Theorem follows from the fundamental postulate of statistical mechanics--that every energetically accessible quantum state of a system has equal probability of being populated, which in turn leads to the Boltzmann distribution for a system in thermal equilibrium.

a. True
b. False

Answers

Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

g ou drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 kg and is 4.2 m in length. At the other end of the bar sits another 3.6-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. Assume that the bar is horizontal when the dropped ball hits it. How high (in meters) will the other ball go after the collision

Answers

Answer:

0.4112 m

Explanation:

The mass of the 1st ball = 3.6 kg

The height of the 1st ball =3.5 m

The mass of the 2nd ball = 3.6 kg

Mass of the bar M = 9.9 kg

Length of the bar L = 4.2 m

The velocity of the ball when it dropped from the height is calculated by using the formula:

[tex]\dfrac{1}{2}mv_1^2 = mgh_1 \\ \\ v = \sqrt{2gh_1} \\ \\ v =\sqrt{2\times9.8 \times 3.5} \\ \\ v = 8.283 \ m/s\\\\[/tex]

Provided that the bar is pivoted at the center and the ball is placed at the two ends, the moment of inertia for the bar is:

[tex]I = \dfrac{1}{12}ML^2 + m_1 (\dfrac{L}{2})^2 + m_2(\dfrac{L}{2})^2 \\ \\ =\dfrac{1}{12}(9.9kg)(4.2m)^2 + [3.6 kg+3.6kg](\dfrac{4.2}{2 \ m})^2 \\ \\ = 46.305 \ kg.m^2[/tex]

The angular momentum of the system due to the ball can be determined by using the formula:

L = mvr

L = (3.6 kg) (8.283 m/s) (2.1 m)

L = 62.61948 kg. m²

Now, Using the law of conservation:

[tex]L_i = L_f \\ \\ 62.61948 \ kg.m^2/s = I \omega \\ \\[/tex]

[tex]\omega = \dfrac{62.6198 \ kg.m^2/s}{46.305 \ kg.m^2}[/tex]

[tex]\omega =1.352 \ rad/s[/tex]

The linear angular velocity is deduced to be:

[tex]v = r \omega \\ \\ v = (2.1 \ m) ( 1.352 \ rad/s) = 2.839 \ m/s[/tex]

the height raised by the second ball is:

[tex]h_2 = \dfrac{v^2}{2g} \\ \\ h_2 = \dfrac{(2.839)^2}{2(9.8 \ m/s^2)} \\ \\ h_2 =0.4112 \ m[/tex]

g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 kg and is 4.2 m in length. At the other end of the bar sits another 3.6-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. Assume that the bar is horizontal when the dropped ball hits it. How high (in meters) will the other ball go after the collision

Answers

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

[tex](2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s[/tex]

Now, we will apply the law of conservation of momentum:

[tex]m_1v_1 = m_2v_2[/tex]

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

[tex](3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s[/tex]

Now, we again use the third equation of motion for the upward motion of the ball:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

[tex](2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\[/tex]

h = 3.5 m

Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22.9 Newtons at an angle of 35 degrees above the horizontal to drag his backpack a horizontal distance of 129 meters to the right. Determine the work (in Joules) done upon the backpack.​

Answers

Answer:

2420 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

Distance (d) = 129 m

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 22.9 × 129 × Cos 35

Wd = 22.9 × 129 × 0.8192

Wd ≈ 2420 J

Thus, the workdone is 2420 J.

You are playing in a volley ball game Your team has 12 and the other team has 18. 
How many points does your team needs to win?
How many points does the other team needs to win?

Answers

Answer:

you need 7 points and the other team just needs to stop you from scoring

Explanation:

You will need 7 to beat them

The length of the slope of a mountain is 2780 m, and it makes
its base?
angle of 14.1° with the horizontal. What is the height of the mountain, relative to
Additional Materials
Reading

Answers

Answer:

677 m

Explanation:

Using the definition of the sine of an angle, we can write

sin 14.1 = (height of mountain) / (slope length of mountain)

sin 14.1 = H / (2780 m) ---> H = (2780 m) x sin 14.1

= 677 m

The height of the mountain is 677.21 m

The given parameters;

length of the slope, L = 2780 m

angle of inclination, Ф = 14.1°

let the height of the mountain, = h

A simple sketch of the problem is given below;

                    ↓P

                    ↓

                    ↓ h

                    ↓                                            14.1°

                    ↓------------------------------------------------Q

                     

A straight line  joining PQ  is  the hypotenuse of the right triangle.

The height of the right triangle is calculated as follows;

[tex]sin(14.1) = \frac{h}{PQ} \\\\\h = PQ \times sin(14.1)\\\\h = 2780 \times sin(14.1)\\\\h = 677.21 \ m[/tex]

Thus, the height of the mountain is 677.21 m

Learn more here: https://brainly.com/question/4326804

A 25.0 kg mass is traveling to the right with a speed of 2.80 m/s on a smooth horizontal surface when it collides with and sticks to a second 25.0 kg mass that is initially at rest but is attached to one end of a light, horizontal spring with force constant 170.0 N/m. The other end of the spring is fixed to a wall to the right of the second mass.
1) Find the frequency of the subsequent oscillations.2) Find the amplitude of the subsequent oscillations.3) Find the period of the subsequent oscillations.4) How long does it take the system to return the first time to the position it had immediately after the collision?

Answers

Answer:

Explanation:

1 ) angular frequency ω = √ ( k / m )

=√ ( 170 / 50 )

= 1.844 rad /s

2πn = 1.844 where n is frequency of oscillation

n = 1.844 / (2 x 3.14 )

= .294 per sec

= .294 x 60 = 18 approx. per minute .

Velocity just after collision of composite mass ( using law of conservation of momentum )

= 25 x 2.8 / 50

v = 1.4 m/s

If new amplitude be A

1/2 k A² = 1/2 m v²

m = 25 + 25 = 50 kg

170 x A² = 50 x 1.4²

A = 0.76 m

3 ) period of oscillation = 1 /n

= 1 / .294

= 3.4 s

4 ) It will take complete one period of oscillation ie 3.4 s to come to its original position.

What does it mean when work is positive?

Answers

Answer:

When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.

Explanation:

Hope this helps you

From search:
When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work


So yeah basically what the person above me said

what is the definition of a moment of force?​

Answers

Answer:

The Moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

Answer:

Torque

Explanation:

I serached it up sjdjbdjd

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