A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v i

=18.0m/s. The cliff is h=50.0m above a body of water as shown in above figure. (a) What are the coordinates of the initial position of the stone? (b) What are the components of the initial velocity of the stone? (c) What is the appropriate analysis model for the vertical motion of the stone? (d) What is the appropriate analysis model for the horizontal motion of the stone? (e) Write symbolic equations for the x and y components of the velocity of the stone as a function of time. (f) Write symbolic equations for the position of the stone as a function of time. (g) How long after being released does the stone strike the water below the cliff? (h) With what speed and angle of impact does the stone land?

Answers

Answer 1

a) The starting speed of the stone was 18.0 m/s, and the cliff's height was 50.0 m.

The expression for the stone's initial x-coordinate

[tex]x_{i}[/tex] = 0

The stone's initial x-coordinate is shown here.

the definition of the top of the cliff's initial y-coordinate

[tex]y_{i}[/tex] = 50m

The stone's initial y-coordination is seen here.

Consequently, the stone's starting position's coordinates are (0, 50.0m)

b) The expression for the stone's starting speed in the x direction

[tex]v_{ix}[/tex] = 18.0m/s

The stone's initial horizontal velocity [tex]v_{ix}[/tex]  is seen here. The formula for the starting velocity in the y direction .

[tex]v_{iy}[/tex] = 0m/s

Here,  [tex]v_{iy}[/tex] is the stone's initial vertical velocity.

Consequently, the initial component of the stone's speed are [tex]v_{ix}[/tex] = 18.0m/s and  [tex]v_{iy}[/tex] = 0m/s.

c) A free fall motion with constant g-force governs the stone's vertical movement.

Particle motion with constant acceleration is what is happening in the y direction.

As a result, the acceleration in the y direction remains constant.

d) Because there is zero acceleration in the x-direction and no net force acting to modify the stone's inertia, the particle's velocity remains constant throughout the motion.

As a result, the motion in the y-direction is motion at a constant speed.

As a result, motion in the x-direction is caused by constant velocity motion.

e) Because the stone doesn't experience any acceleration in the x direction, its speed remains constant throughout the motion.

The stone's ultimate x-direction velocity is equal to its x-direction beginning velocity.

the relationship between the x-final direction's and beginning velocities,

[tex]v_{fx} = v_{ix}[/tex]

Here, [tex]v_{fx}[/tex] is the final horizontal velocity.

The speed in the x direction is independent of time.

The stone experiences a constant acceleration in the y direction, or g, which determines the stone's y-direction velocity.

The formula for the y-ultimate direction's velocity

[tex]v_{fy} = v_{iy} + at[/tex]

Here, [tex]v_{fy}[/tex] is the ultimate vertical velocity, and an is the vertical acceleration.

Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the above equation to find [tex]v_{fy}[/tex]

   [tex]v_{fy}[/tex] = -gt

Consequently, the velocity's x and y components are [tex]v_{fx} = v_{ix}[/tex]  and  [tex]v_{fy}[/tex] = -gt respectively.

f) The term for the stone's x-direction position

[tex]x_{f} = x_{i} + v_{ix}t + a_{x} t^{2}[/tex]                                (i)

Here, [tex]x_{f}[/tex] is the final horizontal position and [tex]a_{x}[/tex] is the acceleration in the x-direction.

The term for the stone's y-direction position

[tex]y_{f} = y_{i} + v_{iy} t + \frac{1}{2} at^{2}[/tex]                                (ii)

Here, [tex]y_{f}[/tex] is the final vertical position.

Substitute 0 for [tex]x_{i}[/tex] and 0 for [tex]a_{x}[/tex] in the equation (i)

[tex]x_{f} = 0 + v_{ix} t + 0\\ = v_{ix} t[/tex]

Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the equation (ii)

[tex]y_{f} = y_{i} + 0 - \frac{1}{2} (g)t^{2}[/tex]

    [tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex]

Consequently, the position's x and y components are [tex]v_{xi} t[/tex] and  [tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex] respectively.

g) The formula to calculate time

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

Substitute 50m for h and 9.8m/[tex]s^{2}[/tex] for g in above equation to find t.

t = [tex]\sqrt{\frac{2(50m)}{9.8m/s^{2} } }[/tex]

 = 3.19s

As a result, the stone will hit the sea below the cliff in 3.19 seconds.

h) The expression to calculate velocity.

[tex]v_{fy}[/tex]  = -gt

Substitute 3.19s for t and 9.8 m/[tex]s^{2}[/tex] Obtain for g in the previous equation [tex]v_{fy}[/tex].

[tex]v_{fy}[/tex]  = (9.8m/[tex]s^{2}[/tex]) (3.19s)

     = -31.26m/s

     ≈ - 31.3m/s

The method for estimating the speed of stone land

v = [tex]\sqrt{v^{2} _{fx} }+ \sqrt{v^{2} _{fx} }[/tex]                             (iii)

The speed of the stone when it lands in this case is v.

The formula for calculating the stone land's angle

∅ = [tex]tan^{-1}[/tex] ( [tex]\frac{v_{fy} }{v_{fx} } )[/tex]                                   (iv)

Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iii) to find v.

v = [tex]\sqrt{(18m/s)^{2} }[/tex] + [tex]\sqrt{(-31.3m/s)^{2} }[/tex]

  = 36.1m/s

As a result, the stone was moving at 36.1 m/s when it hit the ground.

Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iv) to find ∅.

∅ =  [tex]tan^{-1}[/tex] ([tex]\frac{-31.3m/s}{18m/s} )[/tex]

    = -60.09°

   ≈ -60.1°

As a result, the stone terrain has an angle that is -60.1° below the horizontal.

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calculate the orbital period of a comet with a perihelion distance of 0.5 au and aphelion in the oort cloud, at a distance of 50,000 au from the sun.

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The value of the major axis of the comet will be [tex]A=50AU[/tex]and the major axis of the comet is the sum of aphelion distance [tex]\left(a_y\right)[/tex] and perihelion distance [tex]$\left(p_y\right)$[/tex] is [tex]49 AU[/tex]

It is given that,

The value of the perihelion distance of 0.5 au and aphelion in the Oort cloud, at a distance of 50,000 au from the sun.

We need to determine the value of the orbital period of a comet

As we know,

Half of the semi-major axis is the radius of the orbit.

[tex]$$\begin{aligned}a & =\frac{50000 \mathrm{~A} \cdot \mathrm{U}}{2} \\& =25000 \mathrm{~A} . \mathrm{U}\end{aligned}$$[/tex]

From the Kepler's third law, the square of the period of a comet is directly proportional to the cube of its radius of the orbit.

So, applying the above concept.

We will get,

[tex]$$\begin{aligned}p^2 & =a^3 \\p & =[a]^{\frac{3}{2}} \\& =[25000 \mathrm{~A} U]^{\frac{3}{2}} \\& \approx 4 \times 10^6 \text { years (or) } 4.0 \text { million years }\end{aligned}$$[/tex]

(2) Using keplers third law calculate the semi major axis of the comet can be calculated as follows

[tex]$$\begin{aligned}p^2 & =a^3 \\a & =[p]^{\frac{2}{3}} \\& =[125]^{\frac{2}{3}} \\& =25 \mathrm{~A} . \mathrm{U}\end{aligned}$$[/tex]

So, the value of the major axis of the comet will be:

[tex]$$\begin{aligned}A & =2 \mathrm{a} \\& =2(25 \mathrm{~A} \cdot \mathrm{U}) \\& =50 \mathrm{~A} \cdot \mathrm{U}\end{aligned}$$[/tex]

Major axis of the comet is the sum of aphelion distance [tex]\left(a_y\right)[/tex] perihelion distance [tex]$\left(p_y\right)$[/tex].

[tex]$$\begin{aligned}A & =a_y+p_y \\p_y & =A-a_y \\& =50 \mathrm{~A} . \mathrm{U}-1.0 \mathrm{~A} . \mathrm{U} \\& =49 \mathrm{A.U}\end{aligned}$$[/tex]

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a 140 nf capacitor is used in a standard 120 volt ac circuit with a frequency of 60 hz, what is the capacitive resistance?

Answers

The capacitive resistance [tex]x_c[/tex] = 18956 ohms

as per given in the question,

a capacitor having a capacitance (c) is 140nf

the standard voltage of the ac circuit (v) is 120 volts

the frequency of the circuit (f) is 60 hertz

we need to find the capacitive resistance of the given circuit

The opposition offered by a capacitor to the flow of ac current in the ac circuit is known as capacitive resistance.

the formula to find capacitive resistance of the circuit is

[tex]x_c = \frac{1}{2\pi fc}[/tex]                                                        ----(1)

where

[tex]x_c[/tex] is the capacitive resistance

[tex]\pi[/tex] is a constant value 3.14

[tex]f[/tex] is the frequency

[tex]c[/tex] is the capacitance of the capacitor

[tex]c =140nf[/tex]  

[tex]f=60hz[/tex]

[tex]v=120\ volt[/tex]

substitute all the values in equation (1) we get

[tex]x_c = \frac{1}{2(3.14)(60)(140\times10^{-9}) }[/tex]

=> [tex]x_c = \frac{1}{6.28(60)(140\times10^{-9}) }[/tex]

=> [tex]x_c = \frac{1}{376.8(140\times10^{-9}) }[/tex]

=>[tex]x_c = 1.8956\times10^{4}[/tex]

=>[tex]x_c[/tex] = 18956 ohms

the capacitive resistance is 18956 ohms

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The capacitive resistance of the capacitor is 18947 ohms.

The capacitive resistance of a capacitor is given by the formula:

Xc = 1 / (2πfc)

where:

Xc is the capacitive resistance in ohms

π is a constant with the value of 3.14

f is the frequency in hertz

c is the capacitance in farads

In this case, the capacitance is 140 nf, which is equal to 140 * 10^-9 farads. The frequency is 60 hz.

Plugging these values into the formula, we get:

Xc = 1 / (2π * 60 * 140 * 10^-9)

= 18947 ohms

A 140 nf capacitor is used in a standard 120-volt ac circuit with a frequency of 60 hz. The capacitive resistance of the capacitor is given by the formula Xc = 1 / (2πfc). Plugging in the values for capacitance, frequency, and pi, we get Xc = 18947 ohms. Therefore, the capacitive resistance of the capacitor is 18947 ohms.

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what is the magnetic field in the middle of the capacitor plates at a distance d from the center, as a function of time t ? give your answer in terms of d , r , i0 , t , r , c , and any necessary constants.

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That completely depends on the voltage wave-form that's being impressed across the capacitor

What is magnetic field and capacitor ?

The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field. Moving electric charges and magnetic dipoles combine to form a magnetic field, which acts as a force field on other adjacent moving charges and magnetic dipoles.

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You measure 48 turtles' weights, and find they have a mean weight of 34 ounces. Assume the population standard deviation is 4.4 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight.

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While measuring the weight of 48 turtles' weights with a mean weight of 34 ounces and a population standard deviation of 4.4 ounces, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight is +- 0.634

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The closest z value from the z table corresponding to critical value =3.181 is [tex]z=0.99926[/tex]

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I understand that the question you are looking for is:

The nuclear force is:

a) short range and charge independent electromagnetic in nature.

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c)short range and charge independent.

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what is the lift (in newtons) due to bernoulli's principle on a wing of area 89 m2 if the air passes over the top and bottom surfaces at speeds of 260 m/s and 180 m/s , respectively?

Answers

The lift in newtons due to Bernoulli's principle on a wing of area 89 m² is 22,704 N.

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According to this question, the following information are given:

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Density of air = 1.29kgm³

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Speed at the bottom surface (V1) = 180m/sec

According to Bernoulli's principle, force is given by the following expression: F = A × d × V2 - V1/2

Where;

F = force

A = area

d = density

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F = 1.29 × 17,600

F = 22,704 N

Therefore, the lift in newtons due to Bernoulli's principle on a wing of area 76 m² is 22,704 N.

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Purchasing uses information from the  sales order plan to place purchase orders for raw materials with qualified suppliers.

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A bowler rolls a 5 kg ball down a frictionless bowling alley. The ball accelerates at an average rate of 2 m/s. How much force did the bowler apply to the ball

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A force of 10N was applied to the ball by the bowler.

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From the question;

m = 5kg

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F = ma

F = 5 x 2

F = 10N

Hence, the bowler applied a force of 10N to the ball.

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in our milky way galaxy, the orion spur is the select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer. a closest arm to the central bulge. b closest arm to our sun. c farthest arm from the central bulge.

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According to the given information in our milky way galaxy, the orion spur is closest arm to our sun.

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A vast disc of stars has an element of stars in the centre. Even though there are many spiral galaxies that share this characteristic, researchers have spent decades trying to figure out how and when the Way Way for sure central bulge may have developed. A spiral galaxy is the Spiral Galaxy. We think it has four large arms, several lesser arm segments, and a central bulge.

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A spiral known universe structure is intricate; it consists of a revolving disc with a spiral architecture that originates at a dense central bulge. Halos, which are roughly spherical regions along each plane of the discs, encircle spiral galaxies and are sparsely inhabited.

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An old version of stellar evolution, popular at the beginning of the twentieth century, maintained that stars begin their lives as large, cool spheres of gas, like the giant stars on the H-R diagram. They then contract and heat up under the pull of their own gravity to become hot, bright blue O stars. For the remainder of their lives they lose energy, becoming dimmer and redder with age. As they slowly move down the main sequence, they eventually end up as cool, dim red M stars. Explain how observations of stellar clusters, plotted on the H-R diagram, contradict this idea.

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Every star goes through distinct evolutionary stages that are determined by  its internal structure and method of energy production depending on its initial mass. The temperature and luminosity of the star change with each of these stages, and as the star develops, it can be seen moving to various locations on the HR diagram.

One of the most crucial tools for studying stellar evolution is the HR diagram, also known as the Hertzsprung-Russell diagram. It was independently created by Ejnar Hertzsprung and Henry Norris Russell in the early 1900's and plots either the colour of stars against their absolute magnitude or the temperature of stars against their luminosity.

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a square coil, enclosing an area with sides 7.9 cm long, is wrapped with 2,786 turns of wire. a uniform magnetic field perpendicular to its plane is turned on and increases to 0.11 t during an interval of 0.5 s. what average voltage is induced in the coil? express the answer with two decimal places.

Answers

The average voltage induced in the coil is 97.00 V.

What is voltage?
The difference throughout electric potential between two points is known as voltage, also referred to as electric pressure, electric tension, as well as (electric) potential difference. It translates into the amount of work required to move a charge from one point between two points in a static electric field. Volt is the name of the voltage-derived unit in the International System of Units. 166 Joules per coulomb, or 1 volt equals 1 joule (of work) per 1 coulomb, is how work per unit of charge is expressed in SI units (of charge). Power and current were used in the previous SI definition for the volt, the quantum Hall as well as Josephson effect was introduced in 1990, and as of 2019 fundamental physical values obtained have been used in the definition of any and all SI units as well as derived units.

The average voltage induced in the coil can be calculated using Faraday's Law:
V = (B*A*N*Δt)/t
V = (0.11 T *(7.9 cm)^2 * 2,786 turns * 0.5 s)/0.5 s
V = 97.0 V
Therefore, the average voltage induced in the coil is 97.00 V.

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write the rate law that you determined from the experimental data. include the numerical value for k, and the appropriate orders for each reactant.

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[tex]v_{0}[/tex]= k [A]^x [B]^y is the general rate law or rate law equation for any chemicals reaction where A and B means concentration of the species.

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Rate law or rate law equation is the equation linking the initial and final or forward reaction rate in any chemical reaction taking place. the general rate law equation is  [tex]v_{0}[/tex]= k [A]^x [B]^y.

Description of   [tex]v_{0}[/tex]= k [A]^x [B]^y.

 [tex]v_{0}[/tex]= k [A]^x [B]^y. here in the given equation A and B represents the concentration of the species reacting in the given chemical equation.

the data id find or calculated experimentally.

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suppose an experiment determines that the amount of work required for a force field f to move a particle from the point s1, 2d to the point s5, 23d along a curve c1 is 1.2 j and the work done by f in moving the particle along another curve c2 between the same two points is 1.4 j. what can you say about f? why?.

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The force of moving a particle is 0.00262 N.

The electric field exerts force on a charged particle when it shifts from one position to another while moving through the same electric field. We can define a potential energy for the force produced by an electric field because it is conservative work. This enables us to analyze physical processes involving charged particles and electric fields using the concepts of work, energy, and the conservation of energy.

displacement is (1,2) to (5,23)

Work is 1.2 J

[tex]Work =Force * Displacement\\\\Force= Work/Displacement[/tex]

F=1.2/[(X-x)²+(Y-y)²]

F=1.2/457

F=0.00262 N

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the swirling gas that collects around a compact object, as its binary companion transfers material to it, is called

Answers

The swirling gas that collects around a compact object, as its binary companion transfers material to it, is called NOT an event horizon.

NOT an event horizon is its binary counterpart, which transports matter to it.

What is an object in a sentence?

To refer to the item or person that is the target of an action, we typically use the word "object." Alternatively, the recipient. In a sentence, a verb's action is transferred to a noun or pronoun as a direct object. It typically responds to the what- or whom-questions regarding the verb.

What is a picture or an object?

Icons, cursors, buttons, sprites, and other complicated artworks can be made from a collection of simple visual pieces called image objects. Without having to sketch a single pixel, Image Objects let you express creativity.

The object we are talking about here is the death of the star.

Starlight is impacted by atmospheric winds, as well as regions with varying temperatures and densities, when it enters our atmosphere. The night sky appears to sparkle because of the impact of the Earth's atmosphere.

When starlight reaches the atmosphere, it is affected by winds in the atmosphere and areas with different temperatures and densities. This causes the star's light to sparkle when seen from Earth.

But when they run out of fuel, they die and supernova happens.

Therefore here, the object, we are talking in context with star and the swirling gas that collects around a compact object, as its binary companion transfers material to it, is called NOT an event horizon.

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what was the key discovery that led to the identification and definition of the intense radio emitters known as quasars?

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Strong emission lines in their visible spectra were found to be hydrogen lines with very high redshifts.

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A nearly disastrous attempt to observe a far-off radio source results in the discovery of the first quasar, also known as a quasi-stellar astronomical phenomenon.

Quasars produce as much energy from a volume as small as our solar system as more than 100 regular galaxies.

According to NASA, "quasars are some of the most brilliant and energetic objects in the entire universe, with the ability to emit hundreds or even thousands of times the energy output of our galaxy.

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a steel ball is dropped onto a very hard floor. over and over again, the ball rebounds to its origional height (assume that no energy is lost during the collision with the floor). is the motion of the ball simple harmonic motion?

Answers

Yes, the motion of ball is following simple harmonic oscillation.

An equilibrium position exists for harmonic motion. No force is present there. The force acting on the mass attempts to bring the mass back to equilibrium if it is deflected from its equilibrium position. Given that the displacement from equilibrium is measured by x and the force is linear, F = -k * x. K is equal to newtons/meter for springs because k = force/distance. Because of linearity, force and displacement are inversely proportional. Small force, small displacement. Strong force, strong displacement. The period of the simple harmonic oscillator is independent of amplitude because of this proportionality.

No matter where the ball is, there is a constant downward force applied by the bouncing object. Only at the bottom of the bounce is there a significant upward force. Nearly all of the damping is at the bounce point. The amplitude has a strong bearing on the period.

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A 80 g , 35-cm-long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 11 g ball of clay traveling horizontally at 2.3 m/s hits and sticks to the very bottom tip of the rod. To what maximum angle, measured from vertical, does the rod (with the attached ball of clay) rotate?

Answers

The maximum angle measured from vertical is [tex]\theta=57^{o}}[/tex]

Calculation:-

Substituting values:

[tex]\small (1-\cos\theta)=\frac{\left (\frac{1}{3}(0.08\;kg)+(0.011\;kg) \right )\left (0.67168\;m/s \right )^{2}}{(0.011\;kg\times 9.8\;m/s^{2\times } 0.35\;m)}\small (1-\cos\theta)=0.4503\small \cos\theta=1-0.4503\small \cos\theta=0.5496\small \therefore \theta=\cos^{-1}\left (0.5496 \right )\small \boldsymbol{\therefore \theta=56.66^{o}}ROUNDING TO 2 SIGNIFICANT FIGURES:\small \boldsymbol{\therefore \theta=57^{o}}[/tex]

The maximum angle at which a given quantity of bulk goods can be conveyed in a given time even if the conveyor is tilted. Bulk material throughput generally decreases as the maximum angle is approached. The sum of the three angles of a triangle is 180 degrees.

Maximum Permissible Slope means the steepest slope of excavation that can be tolerated to prevent collapse under the most favorable field conditions, expressed as the ratio of horizontal distance to the vertical slope. The maximum elevation angle at solar noon is a function of latitude and declination.

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what is the pressure of the system when all the stopcocks are opened, assuming that the temperature remains constant? (we can neglect the volume of the capillary tubing connecting the bulbs.)\

Answers

Through a stopcock, this bulb was connected to a 0.5 liter evacuated bulb. When the stopcock was opened, the pressure at each location increased to 530 mm, but the temperature stayed the same.

The relationship between temperature and pressure for a given volume of gas is direct. Pressure increases in systems as temperature increases and vice versa. The Gay-Lussac's law specifies the relationship between a gas's pressure and temperature. the relationship between a gas's temperature and the force it applies to its container. Gay-Lussac's Law or Amontons' Law of Pressure-Temperature are two names for this. A gas will press more forcefully against its container as its temperature rises. By heating a gas, you can hasten the motion of its molecules. The pressure will rise and there will be more impacts on the container's walls.

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three particles are fixed in place. the mass of b is greater than the mass of c. can a fourth particle (particle d) be pplaces somewhere so that the net gravitational force on particle a from particles b, c, and d is zero?

Answers

Its position of this particle D must be near the positive y-axis in the second meiotic division of the aforementioned equations.

What is gravitational force and example?

This attraction that earth has on an object is referred to as gravitational force. Examples of motion brought on by gravitational force also include upwards motion of a ball being thrown, the downward motion of water moving through a stream, and the pull of gravity on river flow.

Briefing:

When two bodies are separated by a distance R and have masses M and m, the gravitational attraction between them is:

F= GMm/R²

The gravitational force is a result of the interaction between the gravitational forces exerted by particle B and particle C on particle A.

We can claim that because particle B has a larger mass than particle A does, the gravitational force was closer to and roughly equal to the mass of the bodies.

The net gravitational force on particle A would be zero if particle D force is exerted that is equal to it and opposite to the normal Force that results.

As a result, particle D need to be positioned close to the positive y-axis in the second quadrant.

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A car, mass 1225 kg, traveling at 105 km/h, slows to a stop in 53 m. What is the size of the force that acted on the car

Answers

The force acting on the car is 9700N.

First, the speed has to be converted to m/s units (SI)

105 km/h x 1000m/3600s ≅ 29 m/s

Then, using kinematics, we must determine the acceleration to determine the force. Kinematics is the area of mechanics that studies pure motion without taking into account the masses or forces at play, likewise known as applied kinematics. The concept of mechanical devices that change one type of motion into another.

[tex]V_{final^{2} } = V_{intial^{2} } + 2ax[/tex]

[tex]29^{2} = 0^{2} + 2 * a * 53[/tex]

a ≅ [tex]7.9\frac{m}{s^{2} }[/tex]

Using equation,

F = ma

F = 1225 x 7.9

9677 N ≅ 9700 N

Therefore, The force acting on the car is 9700N.

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For a hydrogen atom, calculate the wavelength of light (in m) that would be emitted for the orbital transition of n(initial) = 3 to n(final) = 1. Submit an answer to four significant figures. The Rydberg constant is 1.09678 x 10⁷ m⁻¹.

Answers

The wavelength of the light emitted for the orbital transition from n = 3 to n = 1 is 0.975m.

For hydrogen, the wavelength of the light emitted for the orbital transition of n = 3 to n = 1 is given by,

1/λ = R(1/n²-1/n'²)

Where,

R is the Rydberg's constant,

n is the initial orbital,

n' is the final orbital,

Putting values,

1/λ = 1.097(1/1-1/9)

1/λ= 1.097 x 8/9

λ = 0.975 m.

Hence, the wavelength of the light emitted is 0.975m.

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if you pull them back together the same distance and release them to start them swinging, what will you notice about the oscillations of the two children?

Answers

The motion of the lighter child would look faster than that of the heavier child, but both have the same period of oscillation.

Oscillation is a type of simple harmonic motion which involves the to and fro movement of an object. The oscillation takes place at a required time called the period of oscillation.

Since the swings are similar, the period of oscillation of the two children are the same and they would complete one oscillation in the same time. Though the oscillation of the lighter child seems faster than that of the heavy child, their masses does not affect the period of oscillation.

When a heavy object oscillates, its mass increases the drag or damping force, but not the period of oscillation. Thus, it oscillate slowly.

Therefore, we can notice about the oscillation that the motion of the child having light weight will be faster than the motion of child having heavy weight.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS :

At a playground, two young children are on identical swings. One child appears to be about twice as heavy as the other. Part A If you pull them back together the same distance and release them to start them swinging, what will you notice about the oscillations of the two children]

the focal length of david's lens is 50 cm . if rebecca stands in front of david at a distance of do and david perceives the position of rebecca at di , what does do equal if the magnification is -0.40?

Answers

The distance of do is 83.34 cm for the magnification -0.40.

Magnification is the process of increasing apparent size.

It is usually done to see the object in an enlarged view by increasing its resolutions so that a more clear view of the object can be visualized.Microscopes like light, electron and compound microscopes are used to see a high resolution image of the object.Magnification can be calculated by the formula M = -(l/f₀)(25/f₁)

M = magnification = - 0.40

l = distance between the eyepiece and the objective lens

f₀ = focal length of the objective

f₁ = focal length of the eyepiece

the focal length of David's lens is: f = 50 cm.

Distance 'u' between the object is to be calculated

According to the formula;

u =f( 1/m -1)

⇒ u = 50(-1/0.40-1) = 83.34 cm.

Hence, distance do is 83.34 cm.

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Which of the following best reduces atmospheric distortion?
adaptive optics

Answers

The best reduces atmospheric distortion is through adaptive optics.

Optical aberrations can be fixed using a technology called adaptive optics (AO). The work that led to the Nobel Prize-winning discovery of a supermassive compact object at the center of our galaxy was made possible by a method that was initially devised to account for the blurring effect of atmospheric turbulence on images in ground-based observatories. We can research the functioning of the visual system and evaluate ocular health in the microscopic domain when AO is employed to compensate for the eye's defective optics.

By detecting retinal changes at the cellular level, AO allows us to adjust for the eye's imperfect optics. AO has expanded the capabilities of imaging in thick tissue specimens, such as when examining neuronal processes in the brain, by correcting for sample-induced blur in microscopy.

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a small artery has a length of 1.6 ✕ 10−3 m and a radius of 2.4 ✕ 10−5 m. if the pressure drop across the artery is 1.8 kpa, what is the flow rate (in mm3/s) through the artery? (assume that the temperature is 37°c.)

Answers

The flow rate through the artery is 7.03*10-11 m3/s (measured in mm3/s). What is the flow rate through the artery in mm3/s if the pressure drop across the artery is 1.8 kpa?

How can I calculate flow rate?

To determine the flow rate represented as Q, which is equal to Q = V/t, we must define both the volume V and the instant in time that it is passing past represented by t. In addition, the relationship between flow rate and velocity is shown by the equation Q = Av, where A is the flow's cross-sectional area and v is its average velocity.

What three different flow rates are there?

Vacuum technology primarily deals with three forms of flow: viscous or continuous flow, molecular flow, and at the interface between these two.

Briefing:

Given,

Pressure Δp = 1.8 kPa

Viscosity μ = 2.03*10-3Pa

Subsituting the values in equation,

Δp = 8μLQ / π

Q = Δp × π / 8μL

Q=7.03*10-11 m3/s

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in this class we will mostly analyze systems where each microstate equally probable. does a coin flip system have equally probably microstates? explain why or why not. come up with examples of systems where the contrary is true.

Answers

Yes, a coin flip system has equally probable microstates because the probabilities of heads and tails are both 50%.

What is microstate?
A microstate is a particular microscopic configuration of the a thermodynamic system which the system may occupy with a specific probability throughout its thermal fluctuations, according to statistical mechanics. The macroscopic characteristics of a system, including its temperature, pressure, volume, and density, are referred to as its macrostate. A specific set of values for the energy, the number of particles, as well as the volume of the an isolated thermodynamic system is thought to specify a specific macrostate of it, according to statistical mechanics treatments. Microstates are depicted in this description as various ways the system might be able to reach a specific macrostate.

Examples of systems where the microstates are not equally probable include rolling a dice, where each side has a different probability of being rolled, and the stock market, where the outcomes are not predetermined and are affected by many variables.

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Why do astronomers suspect that a supernova explosion occurred near the nebula that gave birth to the solar system?.

Answers

Answer:

Meteorites Contain Magnesium-26

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determine force p on the cable if the spring is compressed 0.025 m when the mechanism is in the position shown. the spring has a stiffness of k

Answers

Force P on the cable if the spring is compressed 0.025 m when the mechanism is in the position shown is 0.198 kN.

The force applied by a spring on objects joined to its finishes is corresponding to the spring's adjustment of a length away from its balance length and is constantly coordinated toward its harmonious position. F = - kx. The proportional constant k is known as the spring steady. It is a proportion of the spring's solidness. Assuming x is positive (uprooting to the right), the subsequent power is negative (toward the left), as well as the other way around. As such, the spring force generally acts to reestablish mass back toward its harmony position. Hence the force P on the cable is 0.198 kN if the spring is compressed 0.025 m when the mechanism is in the position shown.

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