A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v i

=18.0m/s. The cliff is h=50.0m above a body of water as shown in above figure. (a) What are the coordinates of the initial position of the stone? (b) What are the components of the initial velocity of the stone? (c) What is the appropriate analysis model for the vertical motion of the stone? (d) What is the appropriate analysis model for the horizontal motion of the stone? (e) Write symbolic equations for the x and y components of the velocity of the stone as a function of time. (f) Write symbolic equations for the position of the stone as a function of time. (g) How long after being released does the stone strike the water below the cliff? (h) With what speed and angle of impact does the stone land?

Answers

Answer 1

a) The starting speed of the stone was 18.0 m/s, and the cliff's height was 50.0 m.

The expression for the stone's initial x-coordinate

[tex]x_{i}[/tex] = 0

The stone's initial x-coordinate is shown here.

the definition of the top of the cliff's initial y-coordinate

[tex]y_{i}[/tex] = 50m

The stone's initial y-coordination is seen here.

Consequently, the stone's starting position's coordinates are (0, 50.0m)

b) The expression for the stone's starting speed in the x direction

[tex]v_{ix}[/tex] = 18.0m/s

The stone's initial horizontal velocity [tex]v_{ix}[/tex]  is seen here. The formula for the starting velocity in the y direction .

[tex]v_{iy}[/tex] = 0m/s

Here,  [tex]v_{iy}[/tex] is the stone's initial vertical velocity.

Consequently, the initial component of the stone's speed are [tex]v_{ix}[/tex] = 18.0m/s and  [tex]v_{iy}[/tex] = 0m/s.

c) A free fall motion with constant g-force governs the stone's vertical movement.

Particle motion with constant acceleration is what is happening in the y direction.

As a result, the acceleration in the y direction remains constant.

d) Because there is zero acceleration in the x-direction and no net force acting to modify the stone's inertia, the particle's velocity remains constant throughout the motion.

As a result, the motion in the y-direction is motion at a constant speed.

As a result, motion in the x-direction is caused by constant velocity motion.

e) Because the stone doesn't experience any acceleration in the x direction, its speed remains constant throughout the motion.

The stone's ultimate x-direction velocity is equal to its x-direction beginning velocity.

the relationship between the x-final direction's and beginning velocities,

[tex]v_{fx} = v_{ix}[/tex]

Here, [tex]v_{fx}[/tex] is the final horizontal velocity.

The speed in the x direction is independent of time.

The stone experiences a constant acceleration in the y direction, or g, which determines the stone's y-direction velocity.

The formula for the y-ultimate direction's velocity

[tex]v_{fy} = v_{iy} + at[/tex]

Here, [tex]v_{fy}[/tex] is the ultimate vertical velocity, and an is the vertical acceleration.

Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the above equation to find [tex]v_{fy}[/tex]

   [tex]v_{fy}[/tex] = -gt

Consequently, the velocity's x and y components are [tex]v_{fx} = v_{ix}[/tex]  and  [tex]v_{fy}[/tex] = -gt respectively.

f) The term for the stone's x-direction position

[tex]x_{f} = x_{i} + v_{ix}t + a_{x} t^{2}[/tex]                                (i)

Here, [tex]x_{f}[/tex] is the final horizontal position and [tex]a_{x}[/tex] is the acceleration in the x-direction.

The term for the stone's y-direction position

[tex]y_{f} = y_{i} + v_{iy} t + \frac{1}{2} at^{2}[/tex]                                (ii)

Here, [tex]y_{f}[/tex] is the final vertical position.

Substitute 0 for [tex]x_{i}[/tex] and 0 for [tex]a_{x}[/tex] in the equation (i)

[tex]x_{f} = 0 + v_{ix} t + 0\\ = v_{ix} t[/tex]

Substitute 0 for [tex]v_{iy}[/tex] and -g for a in the equation (ii)

[tex]y_{f} = y_{i} + 0 - \frac{1}{2} (g)t^{2}[/tex]

    [tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex]

Consequently, the position's x and y components are [tex]v_{xi} t[/tex] and  [tex]= y_{i} - \frac{1}{2} (g)t^{2}[/tex] respectively.

g) The formula to calculate time

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

Substitute 50m for h and 9.8m/[tex]s^{2}[/tex] for g in above equation to find t.

t = [tex]\sqrt{\frac{2(50m)}{9.8m/s^{2} } }[/tex]

 = 3.19s

As a result, the stone will hit the sea below the cliff in 3.19 seconds.

h) The expression to calculate velocity.

[tex]v_{fy}[/tex]  = -gt

Substitute 3.19s for t and 9.8 m/[tex]s^{2}[/tex] Obtain for g in the previous equation [tex]v_{fy}[/tex].

[tex]v_{fy}[/tex]  = (9.8m/[tex]s^{2}[/tex]) (3.19s)

     = -31.26m/s

     ≈ - 31.3m/s

The method for estimating the speed of stone land

v = [tex]\sqrt{v^{2} _{fx} }+ \sqrt{v^{2} _{fx} }[/tex]                             (iii)

The speed of the stone when it lands in this case is v.

The formula for calculating the stone land's angle

∅ = [tex]tan^{-1}[/tex] ( [tex]\frac{v_{fy} }{v_{fx} } )[/tex]                                   (iv)

Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iii) to find v.

v = [tex]\sqrt{(18m/s)^{2} }[/tex] + [tex]\sqrt{(-31.3m/s)^{2} }[/tex]

  = 36.1m/s

As a result, the stone was moving at 36.1 m/s when it hit the ground.

Substitute 18m/s for [tex]v_{fx}[/tex] and -31.3m/s for [tex]v_{fy}[/tex] in equation (iv) to find ∅.

∅ =  [tex]tan^{-1}[/tex] ([tex]\frac{-31.3m/s}{18m/s} )[/tex]

    = -60.09°

   ≈ -60.1°

As a result, the stone terrain has an angle that is -60.1° below the horizontal.

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The distance of do is 83.34 cm for the magnification -0.40.

Magnification is the process of increasing apparent size.

It is usually done to see the object in an enlarged view by increasing its resolutions so that a more clear view of the object can be visualized.Microscopes like light, electron and compound microscopes are used to see a high resolution image of the object.Magnification can be calculated by the formula M = -(l/f₀)(25/f₁)

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A 80 g , 35-cm-long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 11 g ball of clay traveling horizontally at 2.3 m/s hits and sticks to the very bottom tip of the rod. To what maximum angle, measured from vertical, does the rod (with the attached ball of clay) rotate?

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[tex]\small (1-\cos\theta)=\frac{\left (\frac{1}{3}(0.08\;kg)+(0.011\;kg) \right )\left (0.67168\;m/s \right )^{2}}{(0.011\;kg\times 9.8\;m/s^{2\times } 0.35\;m)}\small (1-\cos\theta)=0.4503\small \cos\theta=1-0.4503\small \cos\theta=0.5496\small \therefore \theta=\cos^{-1}\left (0.5496 \right )\small \boldsymbol{\therefore \theta=56.66^{o}}ROUNDING TO 2 SIGNIFICANT FIGURES:\small \boldsymbol{\therefore \theta=57^{o}}[/tex]

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Answers

The value of the major axis of the comet will be [tex]A=50AU[/tex]and the major axis of the comet is the sum of aphelion distance [tex]\left(a_y\right)[/tex] and perihelion distance [tex]$\left(p_y\right)$[/tex] is [tex]49 AU[/tex]

It is given that,

The value of the perihelion distance of 0.5 au and aphelion in the Oort cloud, at a distance of 50,000 au from the sun.

We need to determine the value of the orbital period of a comet

As we know,

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[tex]$$\begin{aligned}a & =\frac{50000 \mathrm{~A} \cdot \mathrm{U}}{2} \\& =25000 \mathrm{~A} . \mathrm{U}\end{aligned}$$[/tex]

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We will get,

[tex]$$\begin{aligned}p^2 & =a^3 \\p & =[a]^{\frac{3}{2}} \\& =[25000 \mathrm{~A} U]^{\frac{3}{2}} \\& \approx 4 \times 10^6 \text { years (or) } 4.0 \text { million years }\end{aligned}$$[/tex]

(2) Using keplers third law calculate the semi major axis of the comet can be calculated as follows

[tex]$$\begin{aligned}p^2 & =a^3 \\a & =[p]^{\frac{2}{3}} \\& =[125]^{\frac{2}{3}} \\& =25 \mathrm{~A} . \mathrm{U}\end{aligned}$$[/tex]

So, the value of the major axis of the comet will be:

[tex]$$\begin{aligned}A & =2 \mathrm{a} \\& =2(25 \mathrm{~A} \cdot \mathrm{U}) \\& =50 \mathrm{~A} \cdot \mathrm{U}\end{aligned}$$[/tex]

Major axis of the comet is the sum of aphelion distance [tex]\left(a_y\right)[/tex] perihelion distance [tex]$\left(p_y\right)$[/tex].

[tex]$$\begin{aligned}A & =a_y+p_y \\p_y & =A-a_y \\& =50 \mathrm{~A} . \mathrm{U}-1.0 \mathrm{~A} . \mathrm{U} \\& =49 \mathrm{A.U}\end{aligned}$$[/tex]

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That completely depends on the voltage wave-form that's being impressed across the capacitor

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a 140 nf capacitor is used in a standard 120 volt ac circuit with a frequency of 60 hz, what is the capacitive resistance?

Answers

The capacitive resistance [tex]x_c[/tex] = 18956 ohms

as per given in the question,

a capacitor having a capacitance (c) is 140nf

the standard voltage of the ac circuit (v) is 120 volts

the frequency of the circuit (f) is 60 hertz

we need to find the capacitive resistance of the given circuit

The opposition offered by a capacitor to the flow of ac current in the ac circuit is known as capacitive resistance.

the formula to find capacitive resistance of the circuit is

[tex]x_c = \frac{1}{2\pi fc}[/tex]                                                        ----(1)

where

[tex]x_c[/tex] is the capacitive resistance

[tex]\pi[/tex] is a constant value 3.14

[tex]f[/tex] is the frequency

[tex]c[/tex] is the capacitance of the capacitor

[tex]c =140nf[/tex]  

[tex]f=60hz[/tex]

[tex]v=120\ volt[/tex]

substitute all the values in equation (1) we get

[tex]x_c = \frac{1}{2(3.14)(60)(140\times10^{-9}) }[/tex]

=> [tex]x_c = \frac{1}{6.28(60)(140\times10^{-9}) }[/tex]

=> [tex]x_c = \frac{1}{376.8(140\times10^{-9}) }[/tex]

=>[tex]x_c = 1.8956\times10^{4}[/tex]

=>[tex]x_c[/tex] = 18956 ohms

the capacitive resistance is 18956 ohms

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The capacitive resistance of the capacitor is 18947 ohms.

The capacitive resistance of a capacitor is given by the formula:

Xc = 1 / (2πfc)

where:

Xc is the capacitive resistance in ohms

π is a constant with the value of 3.14

f is the frequency in hertz

c is the capacitance in farads

In this case, the capacitance is 140 nf, which is equal to 140 * 10^-9 farads. The frequency is 60 hz.

Plugging these values into the formula, we get:

Xc = 1 / (2π * 60 * 140 * 10^-9)

= 18947 ohms

A 140 nf capacitor is used in a standard 120-volt ac circuit with a frequency of 60 hz. The capacitive resistance of the capacitor is given by the formula Xc = 1 / (2πfc). Plugging in the values for capacitance, frequency, and pi, we get Xc = 18947 ohms. Therefore, the capacitive resistance of the capacitor is 18947 ohms.

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Force P on the cable if the spring is compressed 0.025 m when the mechanism is in the position shown is 0.198 kN.

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Through a stopcock, this bulb was connected to a 0.5 liter evacuated bulb. When the stopcock was opened, the pressure at each location increased to 530 mm, but the temperature stayed the same.

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When a home computer scanner employs electromagnetic waves, two things happen:

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A type of radiation that moves in waves at the speed of light is called electromagnetic energy. Light, electromagnetic radiation, electromagnetic waves, radiant energy, or the movement of radiation are some other names for it. Electromagnetic field radiation can be used to transfer heat.

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A bowler rolls a 5 kg ball down a frictionless bowling alley. The ball accelerates at an average rate of 2 m/s. How much force did the bowler apply to the ball

Answers

A force of 10N was applied to the ball by the bowler.

What is a force?

A force is any interaction that, when unopposed, will change the motion of an object. It can be a push or a pull. What are the Effects of Force?

Typically, motion can either be described as:

Change in speedChange in direction

Effects of a forceForce can make a body that is at rest to move.It can stop a moving body or slow it down.It can accelerate the speed of a moving body.It can also change the direction of a moving body along with its shape and size.

It is determined by the formula; F = ma

Where m = mass

a = acceleration

From the question;

m = 5kg

a = 2m/s2

F = ma

F = 5 x 2

F = 10N

Hence, the bowler applied a force of 10N to the ball.

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what is the lift (in newtons) due to bernoulli's principle on a wing of area 89 m2 if the air passes over the top and bottom surfaces at speeds of 260 m/s and 180 m/s , respectively?

Answers

The lift in newtons due to Bernoulli's principle on a wing of area 89 m² is 22,704 N.

How to calculate lift force?

According to this question, the following information are given:

Area of the wing = 89m²

Density of air = 1.29kgm³

Speed at the top surface (V2) = 260m/sec

Speed at the bottom surface (V1) = 180m/sec

According to Bernoulli's principle, force is given by the following expression: F = A × d × V2 - V1/2

Where;

F = force

A = area

d = density

F = 89 × 1.29 × (260² - 180²)/2

F = 1.29 × 17,600

F = 22,704 N

Therefore, the lift in newtons due to Bernoulli's principle on a wing of area 76 m² is 22,704 N.

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You measure 48 turtles' weights, and find they have a mean weight of 34 ounces. Assume the population standard deviation is 4.4 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight.

Answers

While measuring the weight of 48 turtles' weights with a mean weight of 34 ounces and a population standard deviation of 4.4 ounces, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight is +- 0.634

Given:

The sample size or the number of total turtles, [tex]n=48[/tex]

The mean of the weights of the sample of 48 turtles, [tex]x=34[/tex]

The population standard deviation is the diffference between each value of the sample and the sample mean.

Population standard deviation[tex]=4.4[/tex]

Confidence interval= 90% [tex]=0.90[/tex]

Significance level[tex]= 1- confidence[/tex][tex]=1-0.90=0.10[/tex]

The critical value of a statistical distribution is the value of the test statistic which defines the upper and lower bounds of a confidence interval, or which defines the threshold of statistical significance in a statistical test.

The critical value, [tex]z=\frac{n-x}{deviation} =\frac{48-34}{4.4} =3.181[/tex]

A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values. Z-score is measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

The closest z value from the z table corresponding to critical value =3.181 is [tex]z=0.99926[/tex]

The margin of error, [tex]E=z*\frac{deviation }{\sqrt{sample size} } =0.99926*\frac{4.4}{\sqrt{48} } =0.634[/tex]

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the nuclear force is group of answer choices long range and charge independent electromagnetic in nature. short range and charge dependent. short range and charge independent. long range and charge dependent

Answers

The term "short range forces" refers to nuclear forces. Due to the fact that nuclear forces only work over relatively short distances, such as 1 fermi or 10-15 m.

This means that option a) is the appropriate response.

What is the nature of nuclear force?

The nuclear force is electromagnetic in nature, with a vast range and no charge. charge dependent and limited range. limited range and independent of charging. extended and charge-dependent

A force known as the nuclear force interacts with the protons and neutrons of atoms. The force that holds protons and neutrons in a nucleus together is known as the nuclear force. Protons and protons, neutrons and neutrons, or neutrons and neutrons can all be affected by this force.

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I understand that the question you are looking for is:

The nuclear force is:

a) short range and charge independent electromagnetic in nature.

b) long range and charge dependent.

c)short range and charge independent.

d)long range and charge dependent

in this class we will mostly analyze systems where each microstate equally probable. does a coin flip system have equally probably microstates? explain why or why not. come up with examples of systems where the contrary is true.

Answers

Yes, a coin flip system has equally probable microstates because the probabilities of heads and tails are both 50%.

What is microstate?
A microstate is a particular microscopic configuration of the a thermodynamic system which the system may occupy with a specific probability throughout its thermal fluctuations, according to statistical mechanics. The macroscopic characteristics of a system, including its temperature, pressure, volume, and density, are referred to as its macrostate. A specific set of values for the energy, the number of particles, as well as the volume of the an isolated thermodynamic system is thought to specify a specific macrostate of it, according to statistical mechanics treatments. Microstates are depicted in this description as various ways the system might be able to reach a specific macrostate.

Examples of systems where the microstates are not equally probable include rolling a dice, where each side has a different probability of being rolled, and the stock market, where the outcomes are not predetermined and are affected by many variables.

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a steel ball is dropped onto a very hard floor. over and over again, the ball rebounds to its origional height (assume that no energy is lost during the collision with the floor). is the motion of the ball simple harmonic motion?

Answers

Yes, the motion of ball is following simple harmonic oscillation.

An equilibrium position exists for harmonic motion. No force is present there. The force acting on the mass attempts to bring the mass back to equilibrium if it is deflected from its equilibrium position. Given that the displacement from equilibrium is measured by x and the force is linear, F = -k * x. K is equal to newtons/meter for springs because k = force/distance. Because of linearity, force and displacement are inversely proportional. Small force, small displacement. Strong force, strong displacement. The period of the simple harmonic oscillator is independent of amplitude because of this proportionality.

No matter where the ball is, there is a constant downward force applied by the bouncing object. Only at the bottom of the bounce is there a significant upward force. Nearly all of the damping is at the bounce point. The amplitude has a strong bearing on the period.

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if you pull them back together the same distance and release them to start them swinging, what will you notice about the oscillations of the two children?

Answers

The motion of the lighter child would look faster than that of the heavier child, but both have the same period of oscillation.

Oscillation is a type of simple harmonic motion which involves the to and fro movement of an object. The oscillation takes place at a required time called the period of oscillation.

Since the swings are similar, the period of oscillation of the two children are the same and they would complete one oscillation in the same time. Though the oscillation of the lighter child seems faster than that of the heavy child, their masses does not affect the period of oscillation.

When a heavy object oscillates, its mass increases the drag or damping force, but not the period of oscillation. Thus, it oscillate slowly.

Therefore, we can notice about the oscillation that the motion of the child having light weight will be faster than the motion of child having heavy weight.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS :

At a playground, two young children are on identical swings. One child appears to be about twice as heavy as the other. Part A If you pull them back together the same distance and release them to start them swinging, what will you notice about the oscillations of the two children]

suppose an experiment determines that the amount of work required for a force field f to move a particle from the point s1, 2d to the point s5, 23d along a curve c1 is 1.2 j and the work done by f in moving the particle along another curve c2 between the same two points is 1.4 j. what can you say about f? why?.

Answers

The force of moving a particle is 0.00262 N.

The electric field exerts force on a charged particle when it shifts from one position to another while moving through the same electric field. We can define a potential energy for the force produced by an electric field because it is conservative work. This enables us to analyze physical processes involving charged particles and electric fields using the concepts of work, energy, and the conservation of energy.

displacement is (1,2) to (5,23)

Work is 1.2 J

[tex]Work =Force * Displacement\\\\Force= Work/Displacement[/tex]

F=1.2/[(X-x)²+(Y-y)²]

F=1.2/457

F=0.00262 N

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For a hydrogen atom, calculate the wavelength of light (in m) that would be emitted for the orbital transition of n(initial) = 3 to n(final) = 1. Submit an answer to four significant figures. The Rydberg constant is 1.09678 x 10⁷ m⁻¹.

Answers

The wavelength of the light emitted for the orbital transition from n = 3 to n = 1 is 0.975m.

For hydrogen, the wavelength of the light emitted for the orbital transition of n = 3 to n = 1 is given by,

1/λ = R(1/n²-1/n'²)

Where,

R is the Rydberg's constant,

n is the initial orbital,

n' is the final orbital,

Putting values,

1/λ = 1.097(1/1-1/9)

1/λ= 1.097 x 8/9

λ = 0.975 m.

Hence, the wavelength of the light emitted is 0.975m.

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a square coil, enclosing an area with sides 7.9 cm long, is wrapped with 2,786 turns of wire. a uniform magnetic field perpendicular to its plane is turned on and increases to 0.11 t during an interval of 0.5 s. what average voltage is induced in the coil? express the answer with two decimal places.

Answers

The average voltage induced in the coil is 97.00 V.

What is voltage?
The difference throughout electric potential between two points is known as voltage, also referred to as electric pressure, electric tension, as well as (electric) potential difference. It translates into the amount of work required to move a charge from one point between two points in a static electric field. Volt is the name of the voltage-derived unit in the International System of Units. 166 Joules per coulomb, or 1 volt equals 1 joule (of work) per 1 coulomb, is how work per unit of charge is expressed in SI units (of charge). Power and current were used in the previous SI definition for the volt, the quantum Hall as well as Josephson effect was introduced in 1990, and as of 2019 fundamental physical values obtained have been used in the definition of any and all SI units as well as derived units.

The average voltage induced in the coil can be calculated using Faraday's Law:
V = (B*A*N*Δt)/t
V = (0.11 T *(7.9 cm)^2 * 2,786 turns * 0.5 s)/0.5 s
V = 97.0 V
Therefore, the average voltage induced in the coil is 97.00 V.

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A car, mass 1225 kg, traveling at 105 km/h, slows to a stop in 53 m. What is the size of the force that acted on the car

Answers

The force acting on the car is 9700N.

First, the speed has to be converted to m/s units (SI)

105 km/h x 1000m/3600s ≅ 29 m/s

Then, using kinematics, we must determine the acceleration to determine the force. Kinematics is the area of mechanics that studies pure motion without taking into account the masses or forces at play, likewise known as applied kinematics. The concept of mechanical devices that change one type of motion into another.

[tex]V_{final^{2} } = V_{intial^{2} } + 2ax[/tex]

[tex]29^{2} = 0^{2} + 2 * a * 53[/tex]

a ≅ [tex]7.9\frac{m}{s^{2} }[/tex]

Using equation,

F = ma

F = 1225 x 7.9

9677 N ≅ 9700 N

Therefore, The force acting on the car is 9700N.

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when the frequency of an ac circuit is decreased, the current in the circuit increases. which combination of elements is most likely to comprise the circuit?

Answers

The correct answer is resistor, inductor and capacitor.

Impedance of an LCR circuit is given by

Z = √[R² + (X₁ - X(C))²]

Z = √[R² + {2πνL - (1/2πνC)²]

The variation of Z with ν is shown in the figure.

As ν increases , Z decreases and hence current increases.

At ν = ν(r), Z is minimum,  current is maximum

Beyond

ν = ν(r)

Z increases and current decreases.

Therefore, the combination of circuit elements is most likely to comprise

the circuit are R, L and C .

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