Hi there!
[tex]\large\boxed{\text{vf }\approx 29.70 m/s}[/tex]
Use the following kinematic equation to evaluate the final velocity:
vf² + vi² + 2ad, where:
vf = final velocity
vi = initial velocity
a = acceleration (due to gravity in this situation, or 9.8 m/s²)
d = distance
Plug in the given values. Note that vi = 0 m/s since the object was dropped from rest:
vf² = 0 + 2(9.8)(45)
Simplify:
vf² = 882
Take the square root of both sides:
√vf² = √882
vf ≈ 29.70
Which wavelength would scientists use to measure the molecular structure of H2O?
Answer:
To find out what water is made of, it helps to look at its chemical formula, which is H2O. This basically tells us that the water molecule is composed of two elements: hydrogen and oxygen or, more precisely, two hydrogen atoms (H2) and one oxygen atom (O).
Explanation:
Which process involves a chemical change?
Sugar dissolves in hot water.
B
Candle wax changes from a solid to a liquid.
A chair breaks.
D
Water evaporates from a heated test tube.
E
Exposed iron in a moist environment rusts.
What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨
Answer:
Information from the leading mathematicians was considered "classified".
Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
The release of particles or waves from unstable atoms is called?
A bowling ball rolled a distance of 13 meters in 5.9 seconds what is the speed of the bowling ball in m/s?
Answer:
2.2m/s
Explanation:
s = d/t
s = 13/5.9
s= 2.2m/s
btw I rounded this, not rounded it's 2.20338983
If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.
Answer:
The mass of the copper is 3.00kg
Explanation:
[O.04H]The table below shows the use of some energy production methods over time.
Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500
Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.
I think The coastal areas were highly polluted
Answer:
i think its greenhouse gases may increase
Explanation:
PLEASE HELP What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)
total solar eclipse
partial solar eclipse
total lunar eclipse
partial lunar eclipse
Decay of ______ waste present in waste water leads to unpleasant smell
Decay of Schizomycetes waste present in waste water leads to unpleasant smell.
These microorganisms, known as iron and sulfur bacteria, cause hydrogen sulfide to be found in water supplies. They include crenothrix and beggiatoa. Most often found in groundwater supplies, they produce an offensive odor of decaying matter. (I'm not sure)
A football (450 g) falls vertically from rest onto the ground from a height of 5.0 m. If the force that
compresses the ball when it hits the ground is (100 N). What is the amount of compression of the ball?
Draw explanatory diagram.
marks]
Which of the following planets were the ancient Greeks able to see and make careful observations of?
Saturn and Neptune
Neptune and Uranus
Mars and Venus
Mercury and Uranus
Answer:
Neptune and Uranus
Explanation:
Did a quiz on this not to long ago
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling with a force of 60 Newtons. The third child, Eric, is pulling with enough force to exactly balance Abe and Barry (no child is winning the tug-o-war for the toy). We can label our forces A, B, and E (from each child's name). These three forces are in equilibrium.
If Abe is pulling toward the North and Barry is pulling toward the East, we want to find the total force R due to Abe and Barry (the Resultant of their forces). Note: in THIS case the two forces and R form a right-triangle (with R as the hypotenuse) - as seen using graphical vector addition. As a convention let's have NORTH upward and EAST rightward on this page.
a. Sketch an ACCURATE free-body diagram (three arrows outward from a point showing LABELED forces A, B, and E - each arrow a reasonable length and correct direction):
b. Sketch a labeled diagram for graphical addition of A and B to get R:
c. Show the calculation of the magnitude of R from the magnitudes of A and B:
d. Give the magnitude of force E (in units of Newtons):
e. Describe the direction of force E in terms of the "cardinal" directions (north, east, south, and/or west):
Solution :
c). [tex]$\vec{F}_A = $[/tex] force applied by Abe
[tex]$\vec{F}_B = $[/tex] force applied by Barry
[tex]$\vec{F}_E = $[/tex] force applied by Eric
[tex]$\vec{F}_R = $[/tex] Resultant force
[tex]$\vec{F}_A $[/tex] in the vector form can be written as :
[tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]
[tex]$\vec{F}_B $[/tex] in the vector form can be written as :
[tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]
The resultant,
[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]
[tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]
[tex]$=60 \hat i + 60 \hat j$[/tex]
[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]
= 84.853 N
d). As the three forces are in equilibrium, therefore,
[tex]$|\vec F_E| = |\vec F_R|$[/tex]
[tex]$|\vec F_E| =84.853 \ N$[/tex]
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]
[tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]
= 45° north east
The direction of the force E is 45° west or 45° south west.
a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?
Answer:
L = 2 J.s
Explanation:
The angular momentum of an object travelling in a horizontal circle is given by the following formula:
[tex]L = mvr[/tex]
where,
L = Angular momentum = ?
m = mass = 0.8 kg
v = linear speed = rω
r = radius of circular path = length of rope = 0.5 m
ω = Angular Speed = 10 rad/s
therefore,
[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]
L = 2 J.s
why are all people not doing business?
Answer:
ion knoww im sorry
Explanation:
The lab you are working in has asked you to select a data acquisition board as part of a new instrument designed to record a voltage waveform. The waveform to be measured is a triangle shape with a duration of 100 ms and an amplitude of 50 mV. Your budget is $1500 and you must purchase a data acquisition board from National Instruments with a USB interface.
Required:
Draw a model to purchase and include an explanation of why you selected this model.
Answer:
USB-6000
Explanation:
For this strange exercise, you must take into account two fundamental aspects of the data acquisition cards;
* The resolution of the cards, which for a 12-bit card is 2.24mV =2.24 10⁻³V , for which a card of this resolution is sufficient
In your case, the amplitude is 50 mv, which is why it is much higher than the resolution of the card.
* The sampling rate or the frequency in which the card can acquire the data, the typical frequencies go from 200 Khz to the MHz, in general a card that has more than double the frequency to be measured should be selected.
In this case the frequency of your wave is
f = 1 / T
f = 1/100 10⁻³
f = 10 Hz
therefore a low frequency card is suitable.
- The third point is the requirement that it has a USB interface, most of the card do not have it
If you check the National Instruments catalog, there are low-cost cards for example: USB-6000 of 12bits and 10KS / s the latter is the samples taken per second
HELPP!!!! URGENT!!!!
What is the value of the angular deviation? step by step justify your answer.
1-The angular difference is 15 degrees.
2-The angular difference is worth 1.67 rad.
3-The angular difference is 0.60 degrees.
4-The angular difference is worth 0.60 rad.
Answer:
How Urgent are we talking?
Explanation:
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank?
Answer:
18km/h
Explanation:
vector addition
Photosynthesis is an example of an endothermic reaction. Which statement is true about photosynthesis?
A.
Energy is absorbed in the reaction.
B.
Thermal energy is given off by the reaction.
C.
It is a type of combustion reaction.
D.
Light is given off by the reaction.
Answer:
its a
Explanation:
a p e x trust me
A heat engine does 200 J of work per cycle while exhausting 400 J of waste heat. what is the engine's thermal efficiency?
The engine thermal efficiency is 50%
The engine does 200 joules of work per cycle
It exhausts 400 j
The thermal efficiency can be calculated as follows
= 200/400
= 0.5 × 100
= 50 %
Hence the engine thermal efficiency is 50%
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A person drives a car around a circular road with a constant speed of 20 m/s. The
radius of the circular road is twenty-five meters. What is the acceleration of the car?
o 20 m/s2
O 16 m/s2
O 10 m/s2
O 8 m/s2
Answer:
16 m/s^2
Explanation:
acceleration tangential = (v^2)/r
a=400/25
a=16 m/s^2
Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:
angular acceleration=acceleration tangential/r
angular acc.=16/25
angular acc.=0.64 rad/s^2
F = 480N
Mass = 15 kg
What is your acceleration?
ira a saber diosito xdddi.l.Explanation:
A Body OF Volume 36cc Floats With 3/4 of its volume submerged in water . The density Of Body is
1. 0.25g/cc 2. 0.75g/cc
3. 0.9g/cc 4. 0.1g/cc
Answer:
Density of body = 0.25g/cc
Explanation:
Given:
Volume submerged in water = 3/4
Find:
Density Of Body
Computation:
Density of body = fraction of body in liquid x density of water
Density of body = [1-3/4]1
Density of body = 0.25g/cc
The velocity of an object with mass = 2kg is given as a function of time:
V = 2ti + 4[tex]t^{2}[/tex]j
Find the force acting on the object at t = 2 seconds.
Answer:
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Explanation:
Given that object has a constant mass in time, the force acting on the object ([tex]\vec F[/tex]), in newtons, is defined by following expression:
[tex]\vec F = m\cdot \vec a[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]\vec a[/tex] - Acceleration, in meters per square second.
By definition of acceleration, we know that:
[tex]\vec a = \frac{d}{dt} \vec v[/tex] (2)
Let suppose that given vector velocity is expressed in meters per second. If we know that [tex]m = 2\,kg[/tex], [tex]\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right][/tex] and [tex]t = 2\,s[/tex], then the force acting on the object is:
[tex]\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec F = (4, 16\cdot t)\,[N][/tex]
[tex]\vec F = (4, 32)\,[N][/tex]
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Which is used for comparison to determine if another object is in motion?
O A. speedometer
O
B. magnet
O C. compass
o D. reference point
Answer:
D. Reference Point
Explanation:
An object is in motion if it changes position relative to a reference point
Which equation relates charge, time, and current?
O 1=
Δg.
1
49
O 1 = Agt
O 1= 49+1
answer fast pls
Answer:
I = Δq / t
Explanation:
The quantity of electricity i.e charge is related to current and time according to the equation equation:
Q = It
Δq = It
Where:
Q => is the quantity of electricity i.e charge
I => is the current.
t => is the time.
Thus, we can rearrange the above expression to make 'I' the subject. This is illustrated below:
Δq = It
Divide both side by t
I = Δq / t
Which are uses of convex mirrors? Check all that apply.
magnifying mirrors for putting on makeup
side-view mirrors on vehicles
hallway safety mirrors
focusing automobile headlights
lenses in sunglasses
Answer:
B. Side-view mirrors on vehicles
C. Hallway safety mirrors
E. Lenses in sunglasses
Explanation:
Trust Me, Look At Attachment.
Answer:
2, 3, and 5 on Edge, 2022.
Explanation:
I had this question on Edge.
(See the attachment below.)
The rest of the answers are:
O Slide 8 - Sample Response: The image seems to be behind the mirror, but nothing is really there.
O Slide 9 - Concave
O Slide 10 - Same size
write any three utilities of plastics
Explanation:
container, bottles, boxes, cups
8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?
Explanation:
We use Hooke's Law, which states that,
F=kx
F- is the force in newtons
k- is the spring constant
x- is the extension of the spring in meters
Solving for k we get k=F/x
k= 10N/0.50m
=100 N/m
Light passing through a double slit
with separation d = 2.42x10-5 m
creates its second maximum (m = 2)
at an angle of 2.74 deg. What is the
wavelength of the light, IN
NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)
Answer:
573
Explanation:
totally not stealing previous answer cause I know it's right
The wavelength of the light is 578.45 nm.
Light passing through a double slit with separation is given as
d = 2.42 × 10⁻⁵ m.
Line number m = 2
Angle θ = 2.74°
How wavelength is calculated and what is the wavelength of the light?The distance between two sound waves i.e., crest and trough is called the wavelength.
To find the wavelength, here we use the formula as,
sin θ = Line number × λ ÷ ( distance )
By substituting all the given values,
Sin ( 2.74° ) = 2 × λ ÷ ( 2.42 × 10⁻⁵ )
Rearranging the equation,
λ= (Sin ( 2.74° ) × ( 2.42 × 10⁻⁵ ) ) ÷ (2)
λ = 578.45 nm.
Thus, wavelength λ of the light is 578.45 nm.
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