a spring scale shows a net force of 0.8 n acting on a 1.5-kg mass. what happens to the acceleration of the object if the net force is decreased to 0.2 n?(1 point)

Aristarchus argued that Earth rotates on its axis.

Who was Aristarchus of Samos?

Ancient Greek astronomer and mathematician Aristarchus of Samos proposed the first known heliocentric model, according to which the Sun is at the center of the known universe and the Earth revolves once a day around the Sun.

Aristarchus believed the stars to be very distant suns, and as a result, he believed there was no detectable parallax—the movement of the stars with respect to one another as the Earth revolves around the Sun. Aristarchus determined that planets circled around the Sun after discovering that the Sun was much larger than the Earth and the other planets.

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Answer: it explodes

Explanation:

The separation between the plates is [tex]8.51*10^{-8}[/tex].

Information: The distance between the square plates is 8.6 cm, and the rate at which the electric field changes is 1.3 x 106 V/m.s.

using formula: d=eA(E/t), d=8.85*10¬¹²*(0.086)²*1.30*10⁶

d=8.51*10⁻⁸m.

A flow of electrical charge carriers, often electrons or atoms deficient in electrons, is referred to as current. The capital letter I is a typical sign for current. The ampere, represented by the letter A, is the common unit.

It is current if it is true at the moment, right now, and in the present. The term current's origins all relate to its "present" sense. Things that are current are now occurring; they are a part of the present. Since past events are history and no longer news, news reporting focuses on "present affairs."

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Answer:

Below

Explanation:

Acceleration =  Δ v / Δ t   =  -13.6 m/s   /  2.5 s =  - 5.4 m/s^2

   ( the negative sign shows this to be a deceleration)

The relationship between the force and length is given by  F = -kx.

What is hooke's law?

The force a spring applies to items fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium.

The equilibrium point of the spring's free end is at x = 0, and if the x-axis of a coordinate system is selected to be parallel to the spring, then

F = -kx.

The term "spring constant" refers to the proportional constant k.

So,

K will be large if the spring is stiff or powerful, and it will be little if the spring is weak.

According to hooke's law

ΔF / Δx = k

Slope of the graph gives "spring constant"

So,

If we consider strong spring, then curve will have high slope.

and if we consider weak spring, then the curve will have low slope.

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There are no blue spheroidal stars.

Population I stars are disc stars. They are therefore relatively young stars with circular orbits in the galactic plane. They are typically rich in metal. As a result of the disk's abundance of gas and dust, vigorous star formation occurs there. The spiral arms of the galaxy are where stars develop.

There is always some matter around the star when it originates, and this material collects into a disc around the rotating star's equator. This substance can also condense into solid or gaseous structures in the form of a disc.

The researchers discovered that the thick disc of the galaxy's stars were, in fact, billions of years older than the stars observed elsewhere.

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Number of molecules in the vessel are n = 3.15 x [tex]10^{11}[/tex]  molecules

A physical formula that states that the ratio of an ideal gas's measurable qualities is P (pressure) V (volume) = n (number of moles) R (the gas constant) T. (temperature in Kelvin). It is developed from a synthesis of the Boyle, Charles, and Avogadro gas laws. referred to as the universal gas law.

According to the given information

P = 1.00 x 10-9 Pa

V = 1.30 [tex]m^{3}[/tex]

Temperature T =  26° C = 299.15 K

Known

Gas constant R = 8.314 J/ moles K

Avogadro's constant N = 6.022 x [tex]10^{23}[/tex]

Solution :

PV = n RT

1.00 x [tex]10^{-9}[/tex] x 1.30 = n x 8.314 x 299.15

n = 5.23 x [tex]10^{-13}[/tex]  moles

n  = 5.23 x [tex]10^{-13}[/tex] x 6.022 x [tex]10^{23}[/tex]

n = 3.15 x [tex]10^{11}[/tex]  molecules

Number of molecules in the vessel are n = 3.15 x [tex]10^{11}[/tex]  molecules

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It is not possible for me to accurately estimate the hydraulic conductivity of an unconfined aquifer without additional information.

The hydraulic conductivity of an aquifer is a measure of its ability to transmit water, and it depends on various factors such as the porosity and permeability of the aquifer materials, the depth and thickness of the aquifer, the extent of the aquifer's saturation with water, and the hydraulic gradient within the aquifer.

The radius of influence around a pumping well is not necessarily related to the hydraulic conductivity of an aquifer.

In order to estimate the hydraulic conductivity of an unconfined aquifer, a hydrologist would need to conduct detailed field measurements and possibly use modeling techniques to take into account the various factors that affect the aquifer's ability to transmit water.

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The volume and temperature graph is straight line passing through origin .

The origin corresponds to V = 0 and T = 0, the volume of gas is directly proportional to absolute temperature at constant pressure. so the volume and temperature graph is straight line passing through origin.

The cube (x3) of a unit of length represents a unit of volume in its most basic form. The cubic metre is the comparable unit of volume, for instance, if the metre (m) is chosen as the length unit (m3). [12] So, L3 is the unit dimension for volume, a SI-derived unit. [13] Metric prefixes that are strictly powers of ten are used with the metric units of volume. When prefixes are applied to volume units, which are stated as units of length cubed, the cube operators are applied to the unit of length containing the prefix. Converting from cubic centimeter to cubic meter is demonstrated by the following formula: 2.3 cm3 = 2.3 (cm)3 = 2.3 (0.01 m)3 = 0.0000023 m3 (five zeros).

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An object is 50 cm from a concave mirror with radius of curvature of magnitude 60 cm. The transverse magnification produced by the mirror is 75 cm.

To find the transverse magnification, the given data is,

object distance=p=50cm

Radius of curvature=R=60cm

Magnification refers to the image's size in relation to the item that produced it.

The ratio of image length to object length, measured in planes perpendicular to the optical axis, is referred to as linear magnification.

For imaging, optical microscopes combine ocular and objective lenses. The sum of the magnifying powers of the individual lenses produces the observation magnifying power.

then f=R/2

f=60/2

f=30cm

Using mirror formula,

1/f=1/p+1/q

1/30=1/50+1/q

1/30–1/50=1/q

(5–3)/150=1/q

2/150=1/q

2q=150

q=75

The transverse magnification produced by the mirror is 75 cm.

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The age comparison given between my age and the age of an individual n my group is a relative age.

The relative age of an individual is the age of that individual when compared to the age of other people.

The Absolute age of an individual is the exact age of an individual given in years.

Considering the statement above:

You are the same age as someone in your group

The age given here is a comparison of the ages of two individuals without giving the exact age in years. Hence, the age given is a relative age.

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The correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.

(A) The total resistance reduces in comparison to the resistance of each individual lamp when the lamps are connected in parallel. Compared to the bulb with greater resistance, the lamp with less resistance will draw more current and become brighter.

(b) Compared to the resistance of each individual lamp, the total resistance rises when the lamps are connected in series. In comparison to the bulb with less resistance, the lamp with greater resistance will draw more current and become brighter.

Hence, the correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.

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#Complete question is:

Two lamps have different resistances. (a) If the lamps are connected in parallel, which one is brighter, the lamp with greater resistance or the lamp with less resistance? (b) If the lamps are connected in series, which one is brighter? Note that the brighter lamp dissipates more power.

A. (a) lamp with greater resistance; (b) lamp with less resistance

B. (a) lamp with greater resistance; (b) lamp with greater resistance

C. (a) lamp with less resistance; (b) lamp with less resistance

D. a. lamp with less resistance; b. lamp with greater resistance

To convert gravitational force into newtons sm3/(kgs2), we need to know the units again for gravitational constant g.

The force that attracts two masses to one another in physics is known as gravity. If you can believe it, every every particle of matter in the cosmos pulls on every other particle. When referring to the attraction between anything with energy or mass, the terms attraction and gravity are sometimes used synonymously.

Because it continually attempts to bring masses together and drive them apart, the gravitational force is referred to as attractive. Given that the strength of the gravitational attraction is clearly inversely correlated with the masses of the two interdependent parts, it stands to reason that larger, more galaxies will attract one another would fiercely.

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The ratio of energy needed to escape from the surface of the moon to the energy needed to escape from the earth is 0.045

The ratio of energy needed to escape from the surface of Jupiter to energy needed to escape from the earth is  28.5

Calculation:-

Mass of earth = 5.95 *10²⁴ kg

Mass of moon = 7.36*10²² kg

Mass of Jupiter = 1.89 * 10²⁷kg

The radius of the earth = 6.37 * 10⁶ m

The radius of the moon = 1.74 *10⁶ m

The radius of Jupiter = 6.99 *10⁷

The amount of energy needed to escape from the surface is the same as its gravitational potential energy at the original position.

The formula is as follows:

K = GMm/R

where, M, and m are masses, R is the radius, G is the gravitational constant and K is energy.

DetermiNE the ratio of energy needed to escape from the surface of the moon to energy needed to escape from the earth.

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A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place.

Explain about toggle clamp.

A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator. Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.

Toggle clamps with standard or light action are often constructed from components of pressed steel that have been zinc-plated.

Depending on the setting in which you work, Stainless Steel is another alternative for Toggle Clamp production. Stainless steel toggle clamps are frequently used in regulated areas where hygiene is crucial, such as the food industry and the pharmaceutical business.

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The time period of oscillation is 1.670s

What is time period?

A period of time committed for a specific activity that regularly takes up a portion of a calendar year.

Time period of rod is calculated by

T = 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]

Here,

D = x = [tex]\frac{L}{2} -0.084[/tex]

= 0.332m

The moment of inertia = [tex]I[/tex] = [tex]I_cm + MD^2 \\[/tex]

                                         [tex]= \frac{1}{12} MD^2 + Mx^2[/tex]

Time period = 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]

= 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]

where [tex]I =[/tex]   [tex]\frac{1}{12} MD^2 + Mx^2[/tex]

= 2π  [tex]\sqrt{\frac{ \frac{1}{12} 0.832^2 + 0.084^2}{9.8 * 0.084}[/tex]

= 2π [tex]\sqrt{ \frac{0.0576 + 0.00059}{0.8232}[/tex]

= 2π * 0.265

= 1.670s

The time period of oscillation is 1.670s

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After release, the magnitude of the net torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

The term fulcrum refers to the point or support on which a lever rotates, or to the center of a key activity.

Given, distance between fulcrum and mark , d = 0.4 m

mass hung with fulcrum , m = 1 kg.

Value of another mass , m = 0.5 kg.

distance kept , d' = 1.0 m.

torque= F d- F1 (d1- d)

Torque = m g - m g(d1 - d)

= 1 * 9.8 * 4 - 0.5 * 9.8(1 - 0.4)

Torque = 1N

Thus,  the magnitude of the torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

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Answer: Plasma is made up of groups of positively and negatively charged particles but particles of a gas are mostly uncharged.

Explanation:

Because unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely.

Voltage is proportional to inductance just as, for resistors, it is proportional to resistance. Now, the (independent) voltages for parallel elements are equal (V₁ = V₂) and the currents (which are generally functions of time) add i(t) = i₁(t) + i₂(t)

This leads to the equation,

i = i₁ + i₂ + i₃ = V [(1/R₁) + (1/R₂) + (1/R₃)] for resistors.

We note that this condition on the currents implies

d₁(t)/dt + d₂(t)/dt = d(it)/dt

Thus, although the inductance equation, ε = -L(di/dt) involves the rate of change of current, as opposed to current itself, the conditions that led to the parallel resistor formula also apply to inductors.

Therefore, 1/L(eq) = 1/L₁ + 1/L₂

Therefore to ensure the independence of the voltage values, it is important that the inductors not be too close together. The requirement is that the field of one inductor not to have significant influence (or "coupling") in the next.

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Answer:

180 km

Explanation:

velocity (v) = distance (s)  / time (t)

From there we get that the distance is: s=v*t

s = 15 km/s * 12 s

s =180 km

The lens should be kept at a distance of 3.67 cm from the film in the camera to be photographed and convex lens should be used.

Focal length = f = 35.0 mm = 3.5 cm

Distance at which flower is kept = p = 75 cm

The type of lens that should be used = convex

Distance at which camera should be kept = q =

= Using the lens formula

= 1/p + 1/q = 1/f

= 1/75 + 1/q = 1/3.5

= 1/q = 1/3.5 - 1/75

= q = 3.67 cm

So, the film should be kept 3.67 cm behind the convex lens.

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A 1,000-mw (el) energy plant running at 35% thermal performance 100% of the time (base load). The quantity of CO₂ emitted through the plant is 7773579.832 metric tones consistent with year.

What is thermal efficiency?

The thermal efficiency of a heat engine is the percentage of heat energy that is transformed into work. Thermal efficiency is defined as. The efficiency of even the best heat engines is low; usually below 50% and often far below. So the energy lost to the environment by heat engines is a major waste of energy resources.

The amount of CO₂ emitted by the plant is 7773579.832 metric tonnes per year.

Power of the plant = Capacity of the plant = 1000 MW

Working efficiency = 35%

Time = 100%

Heating value of coal = 30 mj/Kg

One year KWh of the plant =

= 1000 X 1000 X 365 X 24

= 31536 X 10¹² metric tonnes per year

Amount of coal =

= (31536 X 10¹² ) / (30 X 10⁶ X 0.35)

= 3003428571 Kg

Thus, the amount of CO₂ emitted by the plant =

= (3003428571 X 44) / 17

= 7773579832 Kg/ year

= 7773579.832 metric tonnes per year

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The variable which represents the height of an object's bounce is Option A. Response variable

In a study or experiment, the query is focused on the response variable. A variable that explains changes in another variable is an explanatory variable. Anything could have an impact on the response variable.

The variable whose fluctuation depends on other variables is known as a response variable (or dependent variable).

The independent variable, often known as the explanatory variable, and the response variable are frequently connected. In an experiment, the response variable is the thing that changes, frequently as a result of variations in the explanatory factors.

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The force of friction is 0.8 N.

Friction is the force that prevents motion when the surface of one object comes into contact with the surface of another.

μ  is the coefficient of friction between the surfaces which are in the contact.

Fn is the normal force acting on the object due to its mass.

Mass of the object = m = 8.0 kg

coefficient of kinetic friction between an object and the surface upon which it is sliding  = 0.10

Frictional force = F = 8.0 * 0.10

F = 0.8 N

The force of friction is 0.8 N.

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According to the given statement 6.0 m/s² accelerate this object toward the north at.

Velocity: the rate at which direction and velocity of a moving item vary over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle increases even while the speed remains constant because the vector will always be changing.

The force is directly related to the rate of change in momentum, according to Newton's second law of motion.

F is the energy, m is the mass, and an is the acceleration, so F = ma.

F = 4 × 3

 = 12 Newtons

The same force acts on a 2.0 kg object

F = ma

a = F/ m

 = 12 /2

 = 6.0 m/s²

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After 102.7 oscillations, the amplitude decreases to one-fourth of the initial value.

Amplitude is the separation between the wave's resting position and its maximum displacement. Frequency is the number of waves that cross a particular point in a second. Period is the length of time it takes for a wave cycle to complete.

λ = 1/51⋅0.20slog(1/2)

λ = −0.68⁻¹s

Using the previous finding, we can calculate the amplitude as a function of time to determine how long it will take before it reaches one-fourth of its initial value.

1/4=Aeλt

Solving for the time,

t = 1/λlog(1/4)

t = 20.4s

Comparing this result with the period,

t = 102.7T.

The amplitude is the largest displacement or distance that a point on a vibrating body or wave can move away from its equilibrium location. It is equal to dividing by two the length of the vibration path. The distance between a wave's resting position and its greatest displacement is known as amplitude. The frequency is the number of waves that pass through a specific location in a second. Period: the time required to complete a wave cycle to complete.

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(a) The work function is 7.5(10)¹⁴ Hz.

(b) The kinetic energy of photoelectron is - 1.898 eV

The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.  

If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.  

This is what Einstein proposed:  

Light behaves like a stream of particles called photons with an energy  

E = h.ν ----- eq1

So, the energy E  of the incident photon must be equal to the sum of the Work function  Φ of the metal and the kinetic energy K of the photoelectron:  

E = Φ + K ----- eq2

Where Φ is the minimum amount of energy required to induce the photoemission of electrons from the surface of a metal, and its value depends on the surface.  

In case, Φ = 5eV

So, applying equation (1) in this problem:  

E = hν

Where:

h = 4.136(10)⁻¹⁵ eV is Planck constant

ν is the frequency

Now the frequency has an inverse relation with the wavelength

λ = 400(10)⁻⁹ m

ν = c/λ

Being c = 3(10)⁸ m/s is the speed of light in vacuum.

ν = 7.5(10)¹⁴ Hz.

Substituting,

E = 4.136(10)⁻¹⁵ {7.5(10)⁻¹⁰}

E = 3.1 eV

Now,

3.1 eV = 5 ev + K

K = - 1.898 eV

Since a negative kinetic energy is not physically possible, the only explanation is: the conditions for a photoelectric effect were not met, hence the photoelectric effect cannot occur.

Therefore, the main condition for the occurrence of the photoelectric effect is that the energy incident photon  must be greater than the work function and E > Φ

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The value of acceleration due to gravity  in at a location where the length of such a pendulum is 0.960 m for period 2.00 s is 9.48 m/s².

The period of oscillation of a pendulum is the time taken for the pendulum to complete one cycle.

Mathematically, the period of oscillation is given as;

T = 2π √ (L / g)

where;

At a constant period, the final equation becomes;

L₁ / g₁ = L₂ / g₂

g₂ = (g₁L₂) / (L₁)

g₂ = (g₁ x 0.96 ) / (0.993)

g₂ = 0.967 g₁

g₂ = 0.967 x 9.8 m/s²

g₂ = 9.48 m/s²

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The mass of the star would be 9.97 x 10³⁵ Kg.

We have a star was observed to have a planet orbiting it at a distance of 1.12 × 10⁸ km. The orbital period of the planet is 329 days.

Let the mass of star be [M] and that of planet be [m]. Since, the planet revolves around the star, we can write -

F{Centripetal} = F{Gravitation}

mv²/r = GMm/r²

v² = GM/r

(rω)² = GM/r

r²ω² = GM/r

ω² = GM/r³

(2π/T)² = GM/r³

M = (2π/T)² (r³)/G

M = 46.8 x (r³)/G

M = {46.8 x (1.12)³ x (10⁸)³}/{(6.6) x 10 ⁻¹¹}

M = (65.7/6.6) x (10²⁴/ 10 ⁻¹¹)

M = 9.97 x 10³⁵ Kg

Therefore, the mass of the star would be 9.97 x 10³⁵ Kg.

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The frequency of the rotation having a radius of 1.1 m is 3.53 rpm

The rotational acceleration = 1.4 g

The radius of the rotation = 1.1 m

The frequency of the rotation can be found using the formula,

         ω = √(α/r)

where ω is the frequency of the rotation

           α is the acceleration of the rotation

           r is the radius of the rotation

Let us substitute the known values in the above equation, we get

       ω = √ (1.4 x 9.8 / 1.1 )

           = √ (13.72 / 1.1)

           = √12.47

       ω = 3.53

Therefore the frequency of the rotation is 3.53 rpm

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