A spaceship captain lands on an unknown planet. Before venturing forth, he needs to find out the acceleration due to gravity on that planet. All he has available to him is some thin light string, a stopwatch, and a small 2.75-kg metal ball (it was a rough landing). So he lets the ball swing from a 1.5-m length of the string, starting at rest, and measures that it takes 1.9 s for it to swing from the place where he released it to the place where it first stops as it reverses direction. What is the acceleration due to gravity on this planet

Answer:

[tex]2\times 10^{8}\ \text{m/s}[/tex]

Explanation:

[tex]n[/tex] = Refractive index of glass = 1.5

[tex]c[/tex] = Speed of light in vacuum = [tex]3\times 10^8\ \text{m/s}[/tex]

Refractive index is given by

[tex]n=\dfrac{c}{v}\\\Rightarrow v=\dfrac{c}{n}\\\Rightarrow v=\dfrac{3\times 10^8}{1.5}\\\Rightarrow v=2\times 10^{8}\ \text{m/s}[/tex]

The speed of light in the glass is [tex]2\times 10^{8}\ \text{m/s}[/tex].

Answer:

The coin will reach a vertical height of 0.027 meters before it stops rolling.

Explanation:

Let suppose that coin-ground system is a conservative system and begins at a height of zero. Since the coin is experimenting a general plane motion, which is a combination of translation and rotation. By Principle of Energy Conservation we have the following model:

[tex]K_{T}+K_{R} = U_{g}[/tex] (1)

Where:

[tex]K_{T}[/tex] - Translational kinetic energy at the bottom of the incline, in joules.

[tex]K_{R}[/tex] - Rotational kinetic energy at the bottom of the incline, in joules.

[tex]U_{g}[/tex] - Gravitational potential energy at the top of the incline, in joules.

By definitions of Kinetic and Gravitational Potential Energy we expand (1):

[tex]\frac{1}{2}\cdot I \cdot \omega ^{2} + \frac{1}{2}\cdot m\cdot R^{2}\cdot \omega^{2} = m\cdot g\cdot h[/tex] (2)

Where:

[tex]I[/tex] - Momentum of inertia of the coin, in kilogram-square meters.

[tex]\omega[/tex] - Angular speed, in radians per second.

[tex]R[/tex] - Radius of the coin, in meters.

[tex]m[/tex] - Mass, in kilograms.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h[/tex] - Height reached by the coin, in meters.

The momentum of inertia of the coin is calculated by:

[tex]I = \frac{1}{2}\cdot m\cdot r^{2}[/tex] (3)

Then, we expand and simplify (2):

[tex]\frac{3}{4}\cdot R^{2}\cdot \omega^{2} = g\cdot h[/tex]

[tex]h = \frac{3\cdot R^{2}\cdot \omega^{2}}{4\cdot g}[/tex]

If we know that [tex]R = 0.0108\,m[/tex], [tex]\omega = 55.2\,\frac{rad}{s}[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the height reached by the coin is:

[tex]h = 0.027\,m[/tex]

The coin will reach a vertical height of 0.027 meters before it stops rolling.

Answer:

velocity = displacement / time taken

velocity = 100/5

velocity = 20m/s

Answer:

An atomic nucleus contains most of the atom’s mass

Explanation:

The first and second answer choices are incorrect because the nucleus has a charge -- but it is positive due to the presence of protons.

The third answer choice is incorrect because the nucleus is extremely dense and packed with all of the protons and neutrons of the atom.

The fourth answer choice is correct because protons and neutrons contain the mass of the atom.

Answer:

An atomic nucleus contains most of the atom’s mass

Explanation:

Hope this helps

Answer:

the answer is a C a newton

Answer:

Explanation:

Let the equilibrium position of third charge be x distance from q₁.

Force on third charge due to q₁

= 9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x²

Force on third charge due to q₂

= 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

Both the force will act in opposite direction and for balancing , they should be equal.

9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x² = 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

5  / x² = 2 / ( .4 - x )²

Taking square root on both sides

2.236 / x = 1.414 / .4 - x

2.236 ( .4 - x ) = 1.414 x

.8944 - 2.236 x = 1.414 x

.8944 = 3.65 x

x = .245 m

24.5 cm

So the third charge should be at a distance of 24.5 cm from q₁ .

Oxygen has an atomic number 8, because it has 8 protons and 8 electrons.

The first shell of an atom can hold up to 2 electrons but oxygen has 8 electrons, in that eight electrons 2 are in the first shell, so it has 6 more electrons left. The second shell can hold up to 8 electrons, oxygen has only 6 more electrons after the first shell is full, so it will have 6 electrons in the second shell

From this we know that oxygen has 2 shells so it is in period 2, and by counting from left to right, the sixth box in period 2 lies on group 16

Therefore Oxygen lies on group 16 and period 2

Happy to help :)

If you need my help for any other question, feel free to ask

Explanation:

the pressure is given by P=hpg

where h is height,p is density, g is 10m/s²

thus P= 0.05m•13.6x10³•10

P=6.8x10³ Hgmm

Answer:

Tension.

tension is the name of force that opposes or goes opposite of gravity

Hope this helps!

Answer: Friction

Explanation: Friction opposes gravity and any motion in two surfaces.

Hope This Helped, Have A Great Day!

Answer:

F = 63.25 N

Explanation:

a = 2.5 m / s ²

m = 25.3 kg

F =?  

We calculate the force.

F = ma

F = (25.3 kg) (2.5m / s²)

F = 63.25 N

Solution.

F = 63.25 N

Answer: DISSOCIATIVE IDENTITY DISORDER

Explanation:

Well its a snack

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Answer:

The time it will take for the car to reach a velocity of 28 m/s is 7 seconds

Explanation:

The parameters of the car are;

The acceleration of the car, a = 4 m/s²

The final velocity of the car, v = 28 m/s

The initial velocity of the car, u = 0 m/s (The car starts from rest)

The kinematic equation that can be used for finding (the time) how long it will take for the car to reach a velocity of 28 m/s is given as follows;

v = u + a·t

Where;

v = The final velocity of the car, v = 28 m/s

u = The initial velocity of the car = 0 m/s

a = The acceleration of the car = 4 m/s²

t = =The time it will take for the car to reach a velocity of 28 m/s

Therefore, we get;

t = (v - u)/a

t = (28 m/s - 0 m/s)/(4 m/s²) = 7 s

The time it will take for the car to reach a velocity of 28 m/s, t = 7 seconds.

Answer:1.) 2 seconds

2.) 4.5 hertz

3.) it will become one third is original value

4.)5.9 seconds

5.)0.87 meters

Explanation:

1. The time period of wave is 0.125 second

2. The frequency of a wave in the second rope is 1.5 hertz.

3. The frequency will become one third of its original value.

4. the time taken by sound of a clap of thunder to travel 2 kilometers is 5.9 seconds.

5. The wavelength of note is 0.87 meter

1. Time period [tex]=\frac{1}{frequency} =\frac{1}{8} =0.125second[/tex]

2. Since both rope are identical. Therefore, both rope have same frequency.

Thus,  The frequency of a wave in the second rope is 1.5 hertz.

3. In relation between wavelength and frequency, wavelength is inversely proportional to frequency.

If the wavelength of a wave in a particular medium is tripled , then the frequency of the wave will become one third of its original value.

4. The time taken by sound of a clap of thunder,

                                    [tex]=\frac{2000}{340}=5.9seconds[/tex]

5. Wavelength is the ratio of speed to the frequency.

                      [tex]Wavelength=\frac{340}{392}=0.87meters[/tex]

Learn more:

https://brainly.com/question/17264163

Answer:

7 mm per year

Explanation:

It is given that :

The Pacific plate is moving towards north at = 29 mm per year

The Pacific plate is moving towards west at = 20 mm per year

We have to calculate the total relative motion towards the northwest.

So we have to find the resultant of the two motions.

Since the two movements are perpendicular, therefore the angle between the two motions is 90 degree.

Therefore, finding their resultant,

[tex]R^2=(29)^2+(20)^2[/tex]

[tex]R^2=(49)^2[/tex]

R = 7

Therefore, total relative motion towards the northwest is 7 mm per year.

Answer:

option A 4kg is your answer

Explanation:

given

mass(m)=?

velocity (v)=5m/s

we have

kinetic energy =50J

1/2 ×{m×v²)=50

m×5²=50×2

m=100/25=4 kg

Answer:

A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.

Explanation:

Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.

Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.

The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.

Hope this helps     :)

(I didn't know which type of bear so i did brown bear and grizzly bear)

Answer:

Rigorous exercise

Explanation:

For your heart rate is been around 100 bpm you should be doing a rigorous exercise . but if ain't doing any rigorous exercise and your heart rate is constantly above 100 bpm you should consult your doctor.

An average heart is between 60 bpm to 100 bpm.

Answer:343

Explanation:

Answer:

9.9 m

Explanation:

From the question given above, the following data were obtained:

Force (F) = 40 N

Workdone (Wd) = 395 J

Height (h) =?

The height can be obtained as follow:

Potential energy = mgh = Fh

395 = 40 × h

Divide both side by 40

h = 395 / 40

h = 9.9 m

Thus, the height is 9.9 m.

Answer:

A and C are correct.

A constant force of 1.25N

Explanation:

This is a kinematics problem.

First find acceleration,

then use F = ma to find force.

Given:

mass = .5kg

delta x = 20m

t = 4s

a = ?

Friction = 0

From the kinematics equations:

delta x = Vi + (1/2)at^2

Plug in terms that are given:

20m = 0 + (1/2)a(4^2)

(2*20m)/(16s^2) = a

40m/(16s^2)= 2.5m/s^2

Now use F = ma to find force exerted on object.

F = (0.5kg)*(2.5m/s^2)

F = 1.25N

Answer:

510 meters

Explanation:

That is sort of a math question but with the meters and wavelength, it's both a physical and a math question. Don't worry, i won't report (Unless you report my answer)

Answer:

Chemical energy is energy stored in the bonds of atoms and molecules. ...

Mechanical energy is energy stored in objects by tension. ...

Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together. ...

Gravitational energy is energy stored in an object's height.

Answer:

Nuclear power

Electricity

Mechanic

Gravity

Explanation:

Answer:

henry moseley was an english physicist, whose contribution to the science of physics was the justification from physical laws of the previous chemical concept of the atomic number. one of his developments were of moseley's law in x-ray spectra.

Explanation:

Answer:

a chemical reaction where electrons mix.

Explanation:

A nuclear reaction is when atomic nuclei combine, forming a new chemical element

A chemical reaction occurs when electrons from the last layer of atoms mix, forming molecules that have the same chemical elements as the reactants.

According to these definitions

           C + 2 S → CS2

in a chemical reaction where electrons mix.

Answer:

This is a chemical reaction, because only the electrons were rearranged.

Answer:

1.5 m\s Ans ......

Explanation:

Data:

f = 0.5 Hz

w = 3 m

v = ?

Formula:

v = fw

Solution:

v = (0.5)(3)

v = 1.5 m\ s Ans ........

Answer:

θ = 17.67°

Explanation:

The grating equation can be used here to find the angle. The grating equation is given as follows:

[tex]m\lambda = dSin\ \theta[/tex]

where,

m = order = 2

d = 3.88 x 10⁻⁶ m

λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m

θ = angle = ?

Therefore, using these values in the equation, we get:

[tex](2)(5.89\ x\ 10^{-7}\ m) = (3.88\ x\ 10^{-6}\ m)Sin\theta \\Sin\theta = \frac{(2)(5.89\ x\ 10^{-7}\ m)}{(3.88\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.3036)[/tex]

θ = 17.67°

Answer:17.67

Explanation:

Answer:

In an year about 6 major hurricanes and 3 minor storms occurs.

Explanation: