Answer:
3.79 m/s^2
Explanation:
We know the small part loses 0.932 MJ of gravitational potential energy during its fall.
Potential energy = mass x gravitational field strength x height
Re-arranging to solve for gravitational field strength:
g = Potential energy/(mass x height)
Plugging in the given values:
g = 0.932 MJ / (1.8kg x 140km)
= 0.932 x 10^6 J / (1.8 x 1000kg x 140 x 1000m)
= 3.79 m/s^2
Therefore, the gravitational field strength of Mars is calculated to be 3.79 m/s^2.
Question 1 of 10
What is the slope of the line plotted below?
B. 2
5
10
C. 1
O A. 0.5
о
9
OD. -0.5
5
Particles q₁ = -66.3 μC, q2 = +108 μC, and
q3 = -43.2 μC are in a line. Particles q₁ and q2 are
separated by 0.550 m and particles q2 and q3 are
separated by 0.550 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
deduce an expression, in terms of m, c, and V, for the contribution of P to the pressure exerted on W. Refer to appropriate Newton’s laws of motion.
The expression for the contribution of P to the pressure exerted on W is P = mV/(c^2t), derived using Newton's laws of motion and the definition of pressure.
In order to deduce an expression, in terms of m, c, and V, for the contribution of P to the pressure exerted on W, we can use the appropriate Newton’s laws of motion. Specifically, we can use the equation F = ma, where F represents force, m represents mass, and a represents acceleration.We know that pressure (P) is defined as force per unit area, or P = F/A. Rearranging this equation, we can solve for force: F = PA.Substituting this into the equation F = ma, we get PA = ma. Rearranging this equation, we can solve for pressure in terms of mass and acceleration: P = ma/A. Finally, we know that acceleration can be expressed in terms of velocity (V) and time (t): a = V/t.Substituting this into our equation for pressure, we get P = mV/(At). Since c represents the speed of sound, we can express A as [tex]A = c^2[/tex]. Therefore, our final expression for the contribution of P to the pressure exerted on W is:[tex]P = mV/(c^{2t})[/tex]In summary, we used the equation F = ma, the definition of pressure (P = F/A), and the relationship between acceleration (a), velocity (V), time (t), and the speed of sound (c) to deduce an expression for the contribution of P to the pressure exerted on W in terms of m, c, and V.For more questions on pressure
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The obliquity of the rotation of Uranus is over 90 degrees. Compared to the plane of the solar system, it rotates on its "side", unlike any other planet. It is surmised that this angle of rotation was caused by:
A ball is thrown vertically upward with a speed of 15.0 m/s. Find a - How high does it rise? in meters, find b - How long does it take to reach its highest point? in seconds, find c - How long does the ball take to hit the ground after it reaches its highest point? in seconds, find d - What is its velocity when it returns to the level from which it started? in m/s.
Given that the initial velocity at which the ball is thrown vertically upward is 15m/s. Let us also assume that the value of acceleration due to gravity (g) = 9.8m/s² and in this case, the value will be -9.8m/s² as the ball is moving against gravity.
a) To calculate how high the ball rises, we can use the kinematic equation:
v² = u² + 2gs......(i)
where v ⇒ final velocity
u ⇒ initial velocity
g ⇒ acceleration and,
s ⇒ displacement (the height)
The final velocity will be 0 when the ball reaches its maximum height.
Substituting the values in equation (i), we get
0² = 15² + (2*-9.8*s)
0 = 225 - 19.6s
Thus, s = 225/19.6 = 11.48 m.
Therefore, the ball rises approximately 11.48 meters.
b) To find the time taken to reach the highest point, we can use the kinematic equation,
v = u + gt......(ii)
where t = time
Substituting the values in equation (ii)
0 = 15 - 9.8*t
t = -15/ -9.8 = 1.53 seconds
Thus, the time taken to reach the highest point = 1.53 seconds.
c) To find the time taken for the ball to hit the ground after it reaches its highest point, we can use the equation,
s = ut +1/2gt².....(iii)
As the ball is moving downwards, the initial velocity, u will be 0m/s.
Thus, substituting the values in equation (iii), we get
11.48 = 0*t + 1/2*9.8*t²
11.48 = 4.9t²
t² = 2.34
Therefore t = 1.53 seconds
Thus, the time taken for the ball to hit the ground is 1.53 seconds.
d) To find the velocity at which the ball returns to the level from which it started, we can use the equation
v = u+ gt.....(iv)
v = 0 + 9.8*1.53
Thus, v = 14.99 ≅ 15 m/s
Therefore, the velocity when it returns to the level from which it started is 15m/s.
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Suppose that you're facing a straight current-carrying conductor, and the current is flowing toward you. The lines of magnetic force at any point in the magnetic field will act in
Question 17 options:
A)
a clockwise direction.
B)
a counterclockwise direction.
C)
the direction opposite to the current.
D)
the same direction as the current.
Suppose that you're facing a straight current-carrying conductor, and the current is flowing toward you. The lines of magnetic force at any point in the magnetic field will act in option c) the direction opposite to the current.
Lenz's law is the law that governs the direction of magnetic force.According to Lenz's law, magnetic fields induced by an electric current have a polarity such that the current's magnetic field opposes any change in current flow. Based on this law, the induced current must produce a magnetic field that opposes the current that produced it.
If the current is flowing towards us, the induced magnetic field must flow in the opposite direction to the current. Therefore, the direction of the lines of magnetic force at any point in the magnetic field will act in the direction opposite to the current.Hence, the correct option is C) the direction opposite to the current.
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A woman stands at the edge of a cliff and throws a pebble horizontally over the edge with a speed of v0 = 20.5 m/s. The pebble leaves her hand at a height of h = 55.0 m
above level ground at the bottom of the cliff, as shown in the figure. Note the coordinate system in the figure, where the origin is at the bottom of the cliff, directly below where the pebble leaves the hand. Answer parts a-f.
(a)The time taken for the pebble to reach the ground is approximately 2.01 seconds, and
(b) the horizontal distance traveled by the pebble is approximately 41.02 meters.
(c) The vertical distance traveled by the pebble is 55 meters.
(d) The initial vertical velocity of the pebble is 0 m/s because it is thrown horizontally.
(e) The vertical acceleration of the pebble is due to gravity and is approximately -9.8 m/s^2.
(f) The negative sign indicates that the pebble is moving downward.
a) To find the time taken for the pebble to reach the ground, we can use the equation for vertical motion:
h = (1/2)gt^2, where h is the vertical distance and g is the acceleration due to gravity.
Rearranging the equation, we have:
t = √((2h) / g), where t is the time taken.
Substituting the given values, we get:
t = √((2 * 55) / 9.8) ≈ 2.01 seconds.
b) The horizontal speed of the pebble remains constant throughout its motion. Therefore, the horizontal distance traveled by the pebble can be found by multiplying the horizontal speed by the time taken:
d = v0 * t, where d is the horizontal distance and v0 is the initial horizontal speed.
Substituting the given values, we have:
d = 20.5 * 2.01 ≈ 41.02 meters.
c) The vertical distance traveled by the pebble is given as 55 meters.
d) The initial vertical velocity of the pebble is 0 m/s because it is thrown horizontally.
e) The vertical acceleration of the pebble is due to gravity and is approximately -9.8 m/s^2.
f) The final vertical velocity of the pebble when it reaches the ground can be found using the equation:
v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
Since the initial vertical velocity is 0 m/s and the acceleration due to gravity is -9.8 m/s^2, we have:
v = 0 + (-9.8) * 2.01 ≈ -19.8 m/s.
The negative sign indicates that the pebble is moving downward.
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Look at this graphic organizer of requirements to apply to become an astronaut.
Requirements for Astronauts
What does the graphic organizer most suggest about the job of an astronaut?
It is technical and potentially tedious.
It is detailed and potentially exhausting.
It is confidential and potentially exciting.
○ It is complex, demanding, and involves flight.
Save and Exit
Next
The graphic organizer suggests that the job of an astronaut is complex, demanding, and involves flight.
This conclusion can be drawn by examining the nature of the requirements listed in the graphic organizer. Firstly, the requirements listed in the organizer are numerous and encompass various aspects. They include educational qualifications, such as having a bachelor's degree in a relevant field, as well as specific experience, like piloting an aircraft.
These requirements highlight the complexity of the job and indicate that astronauts need to possess a diverse set of skills and knowledge. Additionally, the requirements for physical fitness and health demonstrate the demanding nature of the job.
Astronauts are expected to undergo rigorous physical training to ensure they can handle the physical stresses associated with space travel and the conditions they will encounter in space. This indicates that the job can be physically exhausting and requires individuals to be in excellent health.
Lastly, the inclusion of flight-related requirements, such as the need to pass a long-duration spaceflight physical and participate in aircraft flights, implies that the job of an astronaut involves actual flight experiences. This indicates that astronauts are directly involved in piloting spacecraft and are expected to have practical experience in flying.
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D 4.8
This is a harder question based on the Law of Conservation of Momentum. Take the time to work
your way through it. Start with a diagram.
A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the
east with a velocity of 150 m s². A 100 kg piece moves off with a velocity of 200 m s at a direction of
south 60° west. What is the velocity of the third piece?
It is possible
The velocity of the third piece is v₃ = -12500 kg·m/s / m₃
How do we calculate?The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.
velocity of the third piece = v₃.
The total initial momentum before the explosion = 0
The total final momentum after the explosion= 0
Initial momentum = 0 kg·m/s (since the bomb is at rest)
Final momentum = m₁v₁ + m₂v₂ + m₃v₃
m₁ = mass of the first piece = 150 kg
v₁ = velocity of the first piece = 150 m/s (to the east)
m₂ = mass of the second piece = 100 kg
v₂ = velocity of the second piece = 200 m/s (south 60° west)
m₃ = mass of the third piece = unknown
v₃ = velocity of the third piece = unknown
0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)
final momentum = 0 and hence v₃ is found as :
0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)
-12500 kg·m/s = (m₃)(v₃)
v₃ = -12500 kg·m/s / m₃
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Explain the function of power supply, readout, peripheral, microcomputer, transducer and processor
The function of the power supply is to provide electrical energy to the device or system that needs it. The power supply converts the incoming voltage from the power source into a form that is usable by the device, such as DC voltage.
The readout is a device or component that displays data or information to the user. The readout could be a simple LED display or a complex graphical display.
A peripheral is a device or component that connects to a computer or other electronic device to provide additional functionality. Examples of peripherals include printers, scanners, and external hard drives.
A microcomputer is a type of computer that is designed to fit on a single microchip. Microcomputers are found in a wide range of devices, including smart phones, tablets, and embedded systems.
A transducer is a device that converts one form of energy to another. In electronics, transducers are commonly used to convert electrical energy into mechanical energy, or vice versa.
The processor is the central component of a computer or electronic device. The processor is responsible for executing instructions and controlling the other components of the system. The performance and capabilities of a device are largely determined by the speed and power of the processor.
A person walks 3.30 km south and then 2.00 km east, all in 3.20 hours. Answer parts a-c.
(a) the magnitude of the displacement is approximately 3.85 km, and the direction is approximately 59.04° south of east.
(b) Magnitude of average velocity ≈ 3.85 km and Direction of average velocity ≈ -59.04° (south of east)
(c) the average speed during the given time interval is approximately 1.66 km/h.
(a) To find the magnitude and direction of the person's displacement, we can use the Pythagorean theorem and trigonometry.
Displacement in the x-direction = 2.00 km east
Displacement in the y-direction = -3.30 km south (negative because it is in the opposite direction of the positive y-axis)
Using the Pythagorean theorem:
Magnitude of displacement = √((2.00 km)^2 + (-3.30 km)^2)
Magnitude of displacement ≈ 3.85 km
To find the direction, we can use trigonometry:
θ = tan^(-1)(opposite/adjacent)
θ = tan^(-1)(-3.30 km / 2.00 km)
θ ≈ -59.04° (measured counterclockwise from the positive x-axis)
Therefore, the magnitude of the displacement is approximately 3.85 km, and the direction is approximately 59.04° south of east.
(b) Average velocity is defined as displacement divided by time. The magnitude and direction of average velocity will be the same as the magnitude and direction of displacement.
Magnitude of average velocity ≈ 3.85 km
Direction of average velocity ≈ -59.04° (south of east)
(c) Average speed is defined as total distance traveled divided by time. The total distance traveled is the sum of the magnitudes of the individual displacements.
Total distance = 3.30 km + 2.00 km = 5.30 km
Average speed = Total distance / Time
Average speed ≈ 5.30 km / 3.20 hours
Average speed ≈ 1.66 km/h
Therefore, the average speed during the given time interval is approximately 1.66 km/h.
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Which statement best describes the refraction of light as it moves from air to glass?
A. Light bends due to the difference in the speed of light in air and glass.
B. Although the light bends, its speed remains the same as before.
C. Although the light changes speed, it continues in the same direction as before.
D. Light undergoes diffraction due to the difference in the speed of light in air and glass.
WHOEVER ANSWERS IS THE BRAINLIEST!!! PLS HELP!!
Based on the information, we can infer that the temperature on the west and east coasts of the United States is higher than in the central part at latitude 35° North.
What do we see in the image?In the image you can see the map of the United States and two latitudinal lines of 35° and 45° North. Additionally we see the different temperatures that exist in various cities or locations in the United States.
Based on this information, we can infer that the temperatures on the east and west coasts are higher than the temperatures recorded in the central part. For example, at 35° latitude, the coasts register temperatures of more than 60°F while the central zone registers lower temperatures between 36 and 59°F.
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.An electron of charge 1.6 x 10-19is situated in a uniform electric filed strength of 120 vm-1 Calculate the force acting on it
The force acting on the electron is 1.92 x 10^-17 N.
The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.
We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.
The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.
Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.
F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.
Therefore, the force acting on the electron is 1.92 x 10^-17 N.
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7. Name the type of mirror used:-
(i) as a reflector in search light (iii) by the dentist
(ii) as side view mirror in vehicles. (iv) as a shaving mirror
Answer:
1. Concave mirror
2. Convex mirror
3. Concave mirror
4. Concave mirror
Explanation:
Concave mirror is placed near on an object it displays a virtual image
Two blocks, M1 and M2, are connected by a massless string that passes over a massless pulley as shown in the figure. M2, which has a mass of 19.0 kg,
rests on a long ramp of angle theta=25.0∘.
Ignore friction, and let up the ramp define the positive direction.
If the actual mass of M1 is 5.00 kg and the system is allowed to move, what is the acceleration of the two blocks?
What distance does block M2 move in 2.00 s?
The acceleration of the two blocks is[tex]2.14 m/s^{2[/tex]} and the distance does block M2 move in 2.00 s is 4.27 m.
Now we need to find the acceleration of the two blocks and the distance does block M2 move in 2.00 s.
We know that: mass of M1, m1 = 5.00 kg mass of M2, m2 = 19.0 kgθ = 25.0°Taking upward direction as positive for block M1 and downwards as positive for block M2.
Therefore, we can write the following equation of motion for the two blocks:
For M2: m2g - T = m2a ...(1)
For M1: T - m1g = m1a ...(2)
We can see from the figure that M2 is on an inclined plane making an angle θ with the horizontal.
We can resolve the weight of M2 into two components:
Perpendicular to the plane = m2gcosθParallel to the plane = m2gsinθ
The component parallel to the plane will tend to make the block move downwards.
Therefore, the effective weight will be:
mg = m2gsinθ ...(3)
From equation (1) we can write:
T = m2g - m2a ...(4)
Substituting equation (4) in equation (2), we get:
m2g - m2a - m1g = m1a ...(5)
On solving equation (5), we get the acceleration as:
a = g(m2sinθ - m1) / (m1 + m2)
On substituting the given values, we get:
[tex]a = 2.14 m/s^{2}[/tex]
The distance moved by M2 in 2 seconds can be found out using the formula:[tex]s = ut + \frac{1}{2} at^{2}[/tex]
Here, initial velocity, u = 0m/s Time, t = 2s Acceleration, [tex]a = 2.14 m/s^{2}[/tex]
On substituting these values, we get the distance travelled by M2 as: s = 4.27 m
Therefore, the acceleration of the two blocks is [tex]2.14 m/s^{2}[/tex]. And the distance does block M2 move in 2.00 s is 4.27 m.
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One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching that snowball, you throw a second one at a low angle timed to arrive before or at the same time as the first one. Assume both snowballs are thrown with a speed of 26.5 m/s. The first one is thrown at an angle of 58.0° with respect to the horizontal. Find a - At what angle should the second snowball be thrown to arrive at the same point as the first?, find b - How many seconds later should the second snowball be thrown after the first in order for both to arrive at the same time?
The second snowball should be thrown at an angle of approximately 48.196° with respect to the horizontal to arrive at the same point as the first snowball.
the second snowball should be thrown 4.582 seconds later in order for both to arrive at the same time.
To find the angle at which the second snowball should be thrown, we can use the fact that the horizontal displacement of both snowballs must be the same.
Let's first find the horizontal and vertical components of the velocity for the first snowball. The initial speed is 26.5 m/s, and the angle is 58.0° with respect to the horizontal.
The horizontal component of the velocity for the first snowball is given by:
V1x = V1 * cos(angle1)
= 26.5 m/s * cos(58.0°)
= 26.5 m/s * 0.530
= 14.045 m/s
Now, let's find the vertical component of the velocity for the first snowball:
V1y = V1 * sin(angle1)
= 26.5 m/s * sin(58.0°)
= 26.5 m/s * 0.848
= 22.472 m/s
Since the vertical acceleration is the same for both snowballs (gravity), the time it takes for both to arrive at the same point is the same. Therefore, we can use the time of flight of the first snowball to calculate the vertical displacement for the second snowball.
The time of flight for the first snowball can be calculated using the vertical component of velocity and the acceleration due to gravity:
t = (2 * V1y) / g
= (2 * 22.472 m/s) / 9.8 m/s²
≈ 4.582 s
Now, let's find the vertical displacement for the second snowball:
Δy = V1y * t - (0.5 * g * t²)
= 22.472 m/s * 4.582 s - (0.5 * 9.8 m/s² * (4.582 s)²)
≈ 103.049 m
To find the angle at which the second snowball should be thrown, we can use the horizontal displacement and the vertical displacement:
tan(angle2) = Δy / Δx
= 103.049 m / (2 * 14.045 m/s * t)
= 103.049 m / (2 * 14.045 m/s * 4.582 s)
≈ 1.085
Now, we can find the angle2 by taking the arctan of both sides:
angle2 ≈ arctan(1.085)
angle2 ≈ 48.196°
Therefore,
To find how many seconds later the second snowball should be thrown, we can simply use the time of flight of the first snowball, which is approximately 4.582 seconds.
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An object of mass M = 14.0 kg is attached to a cord that is wrapped around a wheel of radius r = 12.0 cm (see figure). The acceleration of the object down the frictionless incline is measured to be a = 2.00 m/s2 and the incline makes an angle = 37.0° with the horizontal. Assume the axle of the wheel to be frictionless. Answer parts a-c.
a. the tension in the rope is 91.5 N.
b. the moment of inertia of the wheel is 0.1008 kg⋅m².
c. the angular speed of the wheel 2.30 s after it begins rotating is 38.34 rad/s.
How do we calculate?(a)
The tension in the rope can be found by considering the forces acting on the object.
ma = mg*sin(θ) - T
(14.0 kg)(2.00 m/s²)
= (14.0 kg)(9.8 m/s²)*sin(37°) - T
T = (14.0 kg)(9.8 m/s²)*sin(37°) - (14.0 kg)(2.00 m/s²)
T = 91.5 N
(b)
The moment of inertia of a wheel:
I = (1/2)MR²
I = (1/2)(14.0 kg)(0.12 m)²
I = 0.1008 kg⋅m²
(c)
The angular acceleration of the wheel:
α = a/R
α = angular acceleration,
a = linear acceleration of the object,
R = radius of the wheel.
α = (2.00 m/s²)/(0.12 m)
α = 16.67 rad/s²
The angular speed (ω) of the wheel after time t is :
ω = ω₀ + αt
ω = 0 + (16.67 rad/s²)(2.30 s)
ω = 38.34 rad/s
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