A sound wave has a frequency of 250 Hz and a wavelength of 1.3 m. Calculate the speed of this waves.

Answer:

D

Explanation:

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s

Answer:

A comma.....

Explanation:

Looks like this (,), and can be used if you have run-on sentences.

I hope this helps :)

hi

what's up

wrud

hmm

hmm

Answer:

There is only a beat frequency when the frequency heard (perhaps a tuning fork) is different from the frequency from  the object in question (piano string, etc.).

The beat frequency equals the difference of the frequencies of the sources.

The piano tuner should adjust the tension in the wire to: C. decrease the amount of interference and decrease the beat frequency.

A wave can be defined as a disturbance created in a medium, which progressively transports energy from a source to another location without the transportation of matter.

Basically, some of the phenomenon and properties associated with waves include the following:

An interference refers to a phenomenon in which two (2) waves meet while traveling along the same medium and they superpose to produce a resultant wave with either a lower, greater, or the same amplitude.

In this scenario, a beat frequency is being heard by a piano tuner when using a tuning fork to tune a piano wire. Thus, the piano tuner should adjust the tension in the wire, so as to decrease the amount of interference and the beat frequency.

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Answer:

The small pebble

Explanation:

Since the potential energy, P.E lost equals kinetic energy, K.E gained,

P.E = K.E

P.E = mgh = K.E

So, K.E = mgh where g = acceleration due to gravity and h = height of drop

Since h and g are constant

K.E ∝ m

So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.

Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.

Answer:

Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.

Explanation:

Metal elements are most likely found on the left side of the periodic table. Details about periodic table can be found below.

Periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group or column.

Metallic elements are one of the group of elements found on the periodic table and they include the following:

Metallic elements are located on the left hand side of the periodic table.

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Answer: (A) Along the stairstep line

Explanation:

Answer:

According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D, the object is moving in the negative direction (i.e., has a negative velocity) and is speeding up.

Explanation:

Answer:

the answer is number 2

Explanation:

did this earlier this year

Answer:

Henry Moseley was an English physicist whose contribution to the science of physics was the justification from physical laws of the previous empirical and chemical concept of the atomic number.

Answer:

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Answer:

117.43 m

Explanation:

Eg=mgh=13x9.81xh=127.53h(N)

Ek=0.5mv^2=0.5(13)(48)^2=14,976 N

by conservation of potenial energy:

Ei=Ef

127.53h=14976

h=117.43m

Answer:

9.80 kg

Explanation:

F = ma

96 N = m(9.8 m/s^2)

m = 9.80 kg

The mass of the ball will be m= 9.8 kg

It states that the force is equal to the rate of change of momentum . For a constant mass , force is equal to mass times acceleration

given :

Force due to gravity = 96 N

g = acceleration due to gravity = 9.8 m /s^2

using Newton's second law of motion

Since , F = ma

          96 = m g

          m = 96/9.8

          m= 9.8 kg

The mass of the ball will be m= 9.8 kg

learn more about Newton's second law of motion:

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Answer:

satellite B

Explanation:

A .F= G (mM)/r²

B .F= G (2mM)/r² = 2G (Mm)r²

C .F= G (3mM)/(2r)² = ¾G (mM)/r²

D .F= G (4mM)/(2r)² = G (mM)/r²

Explanation:

the velocity of sound in air is 330m/s

and v=fh, where h is wavelength f is frequency,

h=v/f.......(1)

longer wavelength

h=330/20,h=16.5m

shorter wavelength

h=330/20000,h=1.65x10-²m

The lesser frequency was used for finding the longer wavelength since wavelength is inversely proportional to frequency,

thus an increase in frequency brings a decrease in wavelength.

and shorter wavelengths are more high and intense

hope this helps

Answer:

Assuming no air friction,

the time it takes to fall 10 m = t = √2h/g = √(20/9.8) = 1.43 s

horizontal distance = 5 m

horizontal speed = distance/time = 5/1.43 = 3.5 m/s  ANS

Explanation:

i hope this helps!

Answer:

Veterbrate

Explanation:

Answer:

(a) The gauge pressure is 4,885.3 Pa

(b) The anchoring force needed to hold the elbow in place is approximately 296.5 N

The direction of the anchoring force is approximately ≈ 134.8

Explanation:

The given parameters in the fluid dynamics question are;

Pipe elbow angle, θ = 90°

The mass flowrate of the water, [tex]\dot m[/tex] = 40 kg/s

The diameter of the elbow, D = 10 cm

The pressure at the point of discharge of the fluid = Atmospheric pressure

The elevation between the inlet and exit of the elbow, z = 50 cm

The weight of the elbow and the water = Negligible

(a) The velocity of the fluid, v₁ = v₂ = v is given as follows;

ρ·v·A = [tex]\dot m[/tex]

v = [tex]\dot m[/tex]/(ρ·A)

Where;

ρ = The density of the fluid (water) = 997 kg/m³

A = The cross-sectional area of the of the elbow = π·D²/4 = π×0.1²/4 ≈ 0.00785398163

A = 0.00785398163 m²

v = 40 kg/s/(0.00785398163 m² × 997 kg/m³) ≈ 5.1083 m/s

Bernoulli's equation for the flow of fluid is presented as follows;

[tex]\dfrac{P_1}{\rho \cdot g} +\dfrac{v_1}{2 \cdot g} + z_1 = \dfrac{P_2}{\rho \cdot g} +\dfrac{v_2}{2 \cdot g} + z_2[/tex]

v₁ = v₂ for the elbow of uniform cross section

P₁ - P₂ = ρ·g·(z₂ - z₁)

P₁ - P₂ = The gauge pressure = [tex]P_{gauge}[/tex]

z₂ - z₁ = z = 50 cm = 0.5 m

∴ [tex]P_{gauge}[/tex] = 997 kg/m³ × 9.8 m/s² × 0.5 m = 4,885.3 Pa

The gauge pressure, [tex]P_{gauge}[/tex] = 4,885.3 Pa

(b) The forces acting on the elbow are;

[tex]F_{Rx}[/tex] + [tex]P_{gauge}[/tex]·A = -β·[tex]\dot m[/tex]·v

[tex]F_{Ry}[/tex]  = β·[tex]\dot m[/tex]·v

∴ [tex]F_{Rx}[/tex]  = -β·[tex]\dot m[/tex]·v -  [tex]P_{gauge}[/tex]·A

[tex]F_{Rx}[/tex]  = -1.03 × 40 kg/s × 5.1083 m/s -  4,885.3 Pa × 0.00785398163 m² ≈ -208.83 N

[tex]F_{Ry}[/tex]  = 1.03 × 40 kg/s × 5.1083 m/s = 210.46196 N

The resultant force, [tex]F_R[/tex], is given as follows;

[tex]F_R[/tex] = √([tex]F_{Rx}[/tex]² + [tex]F_{Rz}[/tex]²)

∴ [tex]F_R[/tex] = √((-208.83)² + (210.46196)²) ≈ 296.486433934

Therefore;

The anchoring force needed to hold the elbow in place, [tex]F_R[/tex] ≈ 296.5 N

The direction of the anchoring force, θ

[tex]\theta = tan^{-1}\left( \dfrac{F_{Ry}}{F_{Rx}} \right)[/tex]

∴ θ = arctan(210.46196/(-208.83)) = -45..2230044°

θ = 180° + -45.2230044° = 134.7769956°

∴ The direction of the anchoring force is approximately, θ ≈ 134.8°

Answer:37000

Explanation:

37 x 1000= 37000

Answer:

25 m

Explanation:

The submarine dives at angle of 30 degree with the horizontal . It has travelled 50 m at this angle . So , it will have both 25 horizontal as well as vertical displacement below the surface .

vertical displacement below the surface = vertical component of displacement of 50 m

= 50 sin30

= 25 m .

Depth of submarine below the surface = 25 m.

Answer:

424.26 m/s

Explanation:

Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q

The relative speed will be calculated by using pythagorean theorem

Relative speed = sqrt(300^2 + 300^2)

Relative speed = sqrt( 180000 )

Relative speed = 424.26 m/s

Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s

Answer:

2.54 m/s

Explanation:

By conservation of energy,

work done by force due to hand = mechanical energy gained by yo-yo

So Fd = mgh + 1/2m(v₂² - v₁²)

where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown

So,  Fd = mgh + 1/2m(v₂² - v₁²)

Fd/m = gh + 1/2(v₂² - v₁²)

Fd/m - gh = 1/2(v₂² - v₁²)

2(Fd/m - gh) = (v₂² - v₁²)

(v₂² - v₁²) = 2(Fd/m - gh)

v₂²  = v₁² + 2(Fd/m - gh)

taking square-root of both sides, we have

v₂  = √[v₁² + 2(Fd/m - gh)]

Substituting the values of the variables into the equation, we have

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]

v₂  = √[(3.4 m/s)² + 2(-2.547 m²/s²)]

v₂  = √[11.56 m²/s² - 5.094 m²/s²)]

v₂  = √[6.466 m²/s²]

v₂ = 2.54 m/s

The gravitational pull of Earth is stronger in satellite A

Answer:

I would say the beaker with less water.

Explanation:

I was say this because while they are the same temperature the beaker with more water still has to fluctuate the heat or cold. They do this at the same speed but since there is less water in one beaker it finishes faster where as the beaker with more water will finish later.

Explanation:

the inability to change the position from rest to motion or motion to rest by themselves is inertia.

Answer:

Inertia is the property of a body in rest to resist motion or a body in motion to continue to its state of motion unless acted by external forces.

Answer:

1960Joules

Explanation:

Since we are not told what too find, we can as well find the Gravitational Potential Energy.

GPE = mass * acceleration due to gravity * height

GPE = 100*9.8 * 2

GPE = 980*2

GPE = 1960Joules

Hence the gravitational potential Energy is 1960Joules