When A slider is moving to the right across unpacked snow and skidding to a stop, forces act upon the slider are: Normal force, Friction force, Gravity force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: the push or pull on a mass-containing item changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
When a slider is moving to the right across unpacked snow and skidding to a stop gravitational force due to his weight, normal reaction force and frictional resistance force will act upon the slider.
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Let's assume you have a mass of 75 kg and your jeep has a mass of 1500 kg. How much greater is the force of gravity on the jeep?
A. 0.05 times
B. 20 times
C. 1500 times
Answer:
20 times
Explanation:
75kg × 20 = 1500kg
Amount of time greater is the force of gravity is 20 times
Given:
Mass of person = 75 kg
Mass of jeep = 1500 kg
Find:
Amount of time greater is the force of gravity
Computation:
Amount of time greater is the force of gravity = Mass of jeep / Mass of person
Amount of time greater is the force of gravity = 1500 / 75
Amount of time greater is the force of gravity = 20 times
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Will mark brainliest pls help
Answer: Use the x/t = v formula!!! x is distance, t is time, and v is velocity. you just need to do 40 / 5 = 8 and 100 / 15 = 6.66
A 62Kg rock climber is attached to a rope that is allowing him to hang horizontally with his feet against the wall. The tension of the rope is 7.1x10^2 N, and the rope makes an angle of 32 degrees with the horizontal. Determine the force exerted by the wall on the climber's feet? I need some help with understanding the problem through a FBD as well as how I will find the x and y components. Thank You !
Answer:
R= 602 .11 N
Explanation:
The horizontal component of tension T will give reaction of the wall and the vertical component of T will balance the weight of of the climber .
T cos32 = R
710 x .848 = R
R= 602 .11 N .
____________ is an out made when a base runner, forced to run because another teammate must run to the base being occupied, cannot reach the next base safely *
A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y= -1.0 m. Point A is on the y axis at y= +4.0 m. Determine the electric potential at point A (relative to zero at the origin).
Answer:
The potential is [tex]V_A = 9600 \ V[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]
The position of the charge is [tex]x = + 3.0 \ m[/tex]
The magnitude of the second charge is [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]
The position is [tex]y_1 = - 1.0 \ m[/tex]
The position of point A is [tex]y_2 = + 4.0 \ m[/tex]
Generally the electric potential at A due to the first charge is mathematically represented as
[tex]V_a = \frac{k * q_1 }{r_1 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_1[/tex] is the distance between first charge and a which is mathematically represented as
[tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]
=> [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]
=> [tex]r_1 = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]
[tex]V_a = 7200 \ V[/tex]
Generally the electric potential at A due to the second charge is mathematically represented as
[tex]V_b = \frac{k * q_2 }{r_2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_2[/tex] is the distance between second charge and a which is mathematically represented as
[tex]r_2 = y_2 - y[/tex]
=> [tex]r _2 = 4.0 - (-1.0)[/tex]
=> [tex]r = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]
[tex]V_a = -3600 \ V[/tex]
So the net potential difference at point A due to the charges is mathematically represented as
[tex]V_n = V_a + V_b[/tex]
=> [tex]V_n = 7200 - 3600[/tex]
=> [tex]V_n = 3600 V[/tex]
Generally the net potential difference at the origin due to both charges is mathematically represented as
[tex]V_N = V_c + V_d[/tex]
Here
[tex]V_c = \frac{k * q_1 }{x}[/tex]
=> [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]
=> [tex]V_c = 12000 V[/tex]
and
[tex]V_d= \frac{k * q_2 }{y}[/tex]
=> [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]
=> [tex]V_c =- 18000 V[/tex]
Generally the net potential difference at the origin is
[tex]V_N = 12000 - 18000[/tex]
=> [tex]V_N = -6000[/tex]
Generally the potential difference at A relative to zero at the origin is mathematically evaluated as
[tex]V_A = V_n - V_N[/tex]
=> [tex]V_A = 3600 - (-6000)[/tex]
=> [tex]V_A = 9600 \ V[/tex]
Which is a characteristic of a physical change? (1 point)
a
The chemical bonds in the substance are unchanged.
b
The change cannot be seen.
c
The molecules all move at the same speed.
d
The substance has reacted with another substance.
Between which two atoms of water are hydrogen bonds are formed?
A. between the hydrogen atom of one water molecule and the oxygen atom of another
B. between the hydrogen atoms of two water molecules
C. between the oxygen atoms of two water molecules
A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.
Answer:
Acceleration = 3m/s^2
Vf= 0 Vi =35m/s t= 13s
Explanation:
[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]
4. When energy is transformed from one form to another, what kind of energy is
always part of the transformation ? (and is usually not in a useful form)
Biomechanical Energy
O Heat Energy
Nuclear Energy
Answer:
Energy conversion also termed as the energy transformation, is the process of changing one form of energy into another.
The Law of Energy Conversion.
Scenario Energy conversions involved
In steam engine The heat energy to Mechanical Energy
In Electric heater Electric Energy to Heat
During the transformation of energy from one form to another, the kind of energy that is always part of the transformation is: C. Heat energy.
What is energy?
Energy can be defined as the ability (capacity) to do work. Thus, the standard unit of measurement of energy is Joules (J).
The various kind of energy:
Basically, there are different kind of energy and these include:
Biomechanical energyWave energySound energyNuclear energyHeat energyThe Law of Conservation of Energy:
According to the Law of Conservation of Energy, energy can neither be created nor destroyed but it can only be transformed (converted) from one form to another such as potential energy to kinetic energy.
As a general rule, heat energy is always associated with the transformation of energy from one form to another.
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Why is an important to come up with a plan for how are you to respond to negative peer pressure before the situation happens
A: it is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future
C: both a and b
Answer:
C ( is hard to refuse in the situation if you have not decided how you would handle it ahead of time
B: because it is very likely you will face these situation in the future)
please help!!!!!!!!!!
Answer:
the line b aka the option d
Explanation:
A cat rolls up a hill. It’s initial Velocity is 10 m/s.n It’s final velocity is 0 m/s. The time was five seconds. Calculate Acceleration
Answer:
[tex]\boxed {\boxed {\sf a= -2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The final velocity of the cat was 0 meters per second and the initial velocity was 10 meters per second. The time was 5 seconds.
[tex]v_f=0 \ m/s\\v_i=10 \ m/s\\t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-10 \ m/s}{5 \ s}[/tex]
Solve the numerator.
0 m/s-10 m/s= -10 m/s[tex]a=\frac{-10 \ m/s}{5 \ s}[/tex]
Divide.
[tex]a= -2 \ m/s^2[/tex]
The acceleration of the cat was -2 m/s². The negative acceleration indicates slowing down or stopping.
Numa determinada escala X, arbitrária, um termômetro marca 0°X para o ponto de fusão do gelo e 50°X para o ponto de ebulição da água, ao nível do mar. Que temperatura esse termômetro marcaria se fosse mergulhado em um líquido cuja temperatura é de 50°C?
Answer:
the temperature measured by the thermometer is 25 ° X
Explanation:
The computation of the temperature measured by the thermometer is shown below:
Here is the thermometric scale list
(X - 0) ÷ C - 0 = (50 - 0) ÷ (100 - 0)
X ÷ C = 50 ÷100
X = C ÷ 2
Now if there is 50 degrees celcius
So, the x would be
= 50 ÷ 2
= 25 ° X
Hence, the temperature measured by the thermometer is 25 ° X
The same is to be considere d
A standing wave has a frequency of 471 Hz and a wavelength of 1.9. What is the speed of the
wave? (Round to the 2nd number after the decimal)
1
I REALLY NEED HELP !
Answer:
c = 894.90 m/s
Explanation:
Given data:
Frequency of wave = 471 Hz
Wavelength of wave = 1.9 m
Speed of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
c = f×λ
c = 471 Hz × 1.9 m
Hz = s⁻¹
c = 471s⁻¹ × 1.9 m
c = 894.90 m/s
The speed of wave is 894.90 m/s.
A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What
is the speed of recoil of the gun?
Answer: -.80m/s
Explanation:
What results when energy is transformed while juggling three bowling pins?
Answer:
his is an example of the transformation of gravitational potential energy into kinetic energy
Explanation:
The game of juggling bowling is a clear example of the conservation of mechanical energy,
when the bolus is in the upper part of the path mechanical energy is potential energy; As this energy descends, it becomes kinetic energy where the lowest part of the trajectory, just before touching the hand, is totally kinetic.
At the moment of touching the hand, a relationship is applied that reverses the value of the speed, that is, now it is ascending and the cycle repeats.
Therefore this is an example of the transformation of gravitational potential energy into kinetic energy
A pyrotechnical expert needs to fire a 15 kg projectile from a launching device that has a barrel length of 2 meters. The projectile will need to be launched horizontally 1 km in 5 seconds. Calculate the force needed to launch the projectile.
Answer:
The force needed to launch the projectile is 150000 N.
Explanation:
We can find the force using the following equation:
[tex] F = ma [/tex]
Where:
m: is the mass = 15 kg
a: is the acceleration
First, we need to find the acceleration of the projectile:
[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]
Where:
[tex]v_{f}[/tex]: is the final speed
[tex]v_{0}[/tex]: is the initial speed = 0
x: is the distance = 2 m
The final speed is:
[tex]v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s[/tex]
Then, the acceleration is:
[tex]a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}[/tex]
Finally, the force is:
[tex]F = ma = 15 kg*10000 m/s^{2} = 150000 N[/tex]
Therefore, the force needed to launch the projectile is 150000 N.
I hope it helps you!
Ted Williams drops a ball from 12.7 meter to a desk that is 1.5 meter tall. What is the final speed of the ball right before it hits the desk?
Answer:
Explanation:
Using the equation of motion
V² = u²+2g∆H
v is the final velocity
u is the initial velocity = 0m/s
g = 9.8m/s²
∆H = 12.7-1.5 = 11.2m
Substitute
v² =0²+2(9.8)(11.2)
v² = 219.52
v = √219.52
v = 14.82m/s
Hence the final.speed of the ball is 14.82m/s
How far(in meters) will you travel in 3 minutes running at a rate of 6 m/s
Answer:
1080 meters is the answer
What is Newtons third law of motion?
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction
Explanation:
In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.
Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most likely do?
He reduced the number of loops in the wire.
He increased the number of loops in the wire.
He reduced the length of the wire.
He increased the length of the wire.
Answer:
Its A
Explanation:
To reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
What is electromagnetic field strength?
The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.
The strength of an induced emf in a given magnetic field is given by;
emf = NBA/t
where;
N is number of turns of the magnetB is magnetic field strengthA is area of the coilDecrease in number of turns of the wire, reduces the strength of the magnetic field.
Thus, to reduce the strength of an electromagnet, Juan must reduced the number of loops in the wire.
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A scientist is observing a eukarotic cell and a prokaryotic cell. Which structure could she only observe in the eukaryotic cell?
cytoplasm
DNA
ribosomes
a nucleus
Answer:
It's definitely Nucleus
Hope this Helps!
car sitting on a drive way is that an kinetic or potential energy
Answer:
kinetic energy..........
A boat starts moving across a river at velocity v perpendicular to the river bank.
The boat encounters a current along the river of velocity u, as shown.
u
river
Which vector diagram shows the resultant velocity r of the boat?
A
B
с
D
u
A
r
u
Question 7 (2 points)
Rachel performed an experiment testing the hours students slept with their
performance on a test. In this experiment, the hours that they slept was the_____ variable, while the grade they got on
the test was the
_____ variable.
please help!!!!!!!!!!
Answer:
B (student 1)
Explanation:
...
A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and the ball continues forward at 4.0 m/s. What was the original velocity of the ball?
The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.
We don't have external forces, so:
[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]
Where:
mb is the mass of the bowling ball mp the mass of the pin[tex]v_{0b}\quad and\quad v_{0p}[/tex] the initial velocities of the bowling ball and the pin.[tex]v_{1b}\quad and\quad v_{1p}[/tex] the final velocities of the bowling ball and the pin.Solving for v0b:
[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]
R/ The original velocity of the ball was 5.71 m/s.The original velocity of the ball is 5.71 m/s.
The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.
From the principle of conservation of momentum,
MU+mu = MV+mv.................... Equation 1
Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.
From the question,
Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.
Substitute these values into equation 1 and solve for U
7(U)+2(0) = 7(4)+2(6)
7U = 28+12
7U = 40
U = 40/7
U = 5.71 m/s.
Hence, The original velocity of the ball is 5.71 m/s.
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-)
A 1100 kg car is accelerating at 2m/s2. Find the net force acting on the car.
Answer:
2200 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1100 × 2
We have the final answer as
2200 NHope this helps you
1. What mass can be lifted by the hydraulic press if it is known that the are:
of the small piston is 48cm and that of the large piston is 1440cm, and
the force acting on the small piston can be as large as 1000N. (use g =
10m/s)
C. 3000kg
B. 30kg
D. 30,000kg
A. 300kg
Answer:
Answer: C. 3000kg
Explanation:
Hydraulic Jack
It's a device that is used to lift heavy loads by applying force via a hydraulic cylinder.
Since the internal pressure on the liquid of the jack is constant, the following relation applies:
[tex]\displaystyle \frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
Where
F1 = Force applied in one end of the jack
A1 = Area of the cylinder of the same end
F2 = Force applied in the other end of the jack
A2 = Area of the cylinder of the other end
If we assume the force is being applied on side 1, then the force on side 2 is calculated by solving for F2:
[tex]\displaystyle F_2=\frac{F_1.A_2}{A_1}[/tex]
We have F1=1000N, A1= 48~cm^2, A2= 1440~cm^2, thus:
[tex]\displaystyle F_2=\frac{1000.1440}{48}[/tex]
[tex]F_2 = 30000 ~N[/tex]
Since we need to know the mass that can be lifted by that force, we use the formula:
W = m.g
Where W is the weight of the mass and g= 10~m/s^2. Since the weight is equal to the force exerted by the jack:
[tex]\displaystyle m=\frac{W}{g}=\frac{30000}{10}[/tex]
m = 3000 Kg
Answer: C. 3000kg
Which of the following information is necessary to describe an object's motion? position, speed, direction, position, direction, and speed
Answer:
position speed and direction
Explanation:
hope that helps =)
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