A semicircle with diameter 8 inches is connected to a triangle with a base length of 8 inches. The height of the triangle is 3 inches. What is the area of the composite figure? (8π + 6) in.2 (8π + 12) in.2 (8π + 18) in.2 (8π + 24) in.2

Answers

Answer 1

Answer:

B or (8π + 12) in.2

Step-by-step explanation:

A Semicircle With Diameter 8 Inches Is Connected To A Triangle With A Base Length Of 8 Inches. The Height
Answer 2

The area of the composite figure = (8π + 12) [tex]inch^{2}[/tex].

How to estimate the area of the composite figure?

The composite figure is made up of a semicircle and an isosceles triangle.

The area of a semicircle = (1/2)π[tex]r^{2}[/tex]

radius =  4 inch

When we substitute, the area of the semicircle is

= (1/2)π[tex]\times[/tex]16

= 8π [tex]$inch^{2}[/tex]

Area of the isosceles triangle = (1/2)bh

= (1/2)(4+4)[tex]\times[/tex]3

= 12 [tex]inch^{2}[/tex]

We add the two areas to acquire the area of the composite figure to be: (8π + 12) [tex]inch^{2}[/tex]

The area of the composite figure = (8π + 12) [tex]inch^{2}[/tex].

Therefore, the correct answer is option b. (8π + 12) in.2

To learn more about the area of semicircle

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99 % of the trees in our neighborhood are eucalyptus trees. The town planning commission wants to get rid of some of these trees because they spread too quickly. However, the people in my neighborhood like the trees. The commission argues that their new eucalyptus tree removal plan will cut down so few eucalyptus trees that 98% of the trees in our neighborhood will be eucalyptus trees. If the plan only involves removing eucalyptus trees, what percent of the existing trees in my neighborhood would the plan remove

Answers

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50%

Step-by-step explanation:

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Suppose we reduce the number of eucalyptus trees by some amount x and that the remaining number of eucalyptus trees are now 98% of the total trees.

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So we end up removing a little over half of the eucalyptus trees. EDIT: Forgot to mention - removing 50.505050...% of the eucalyptus trees means that we are removing 0.50505050....×0.99T which is 0.5T or half the trees in the neighborhood.

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Answer:

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Answers

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Step-by-step explanation:

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