A school raised $4,589 in a magazine sale. Mr. Simmon's class raised 1 of the school's total. 100 How much money, in dollars, did Mr. Simmon's class raise? Enter the number in the box.​

Answer:

C

Step-by-step explanation:

slope intercept is y=mx+b

The y-intercept is at 2 so b=2.

The slope is rise/run, equaling -3

so y= -3x+2

Answer:

answers are 1 and 9

Step-by-step explanation:

x² - 10x = -9

x² - 10x + 9 = 0

(x - 9)(x - 1) = 0

x = 9, x = 1

Answer:

Replace key words with variables, numbers, and operations. “A number squared” is a power where the base is the variable and the exponent is 2. “Decreased by ten” means you must subtract 10 from the squared number.

Step-by-step explanation:

hope this helps

Ok ill answer the question but do you want me to evaluate it or find it to the simplest form ?

Answer:

No, because the number of trials is not fixed.

Step-by-step explanation:

a. pe. x

Answer:B

Step-by-step explanation: khan - There is no fixed number of trials , so D is not a binomial variable.

Answer: The best choice from the provided options is the "Cube".

Step-by-step explanation: The cube is also called "rectangular hexahedron," because it has 6 congruent (meaning figures that are identical in form) faces.

Answer:

The slope would be x/y so really the b value could be anything if you leave the slope the same. Hope this helps!

Step-by-step explanation:

x - 7y = 7

-7y = -x + 7

7y = x - 7

y = x/7 - 1

Answer:

The distance is 5.4.

Step-by-step explanation:

Hope this helps!! Have an Amazing day!!

Answer:

5.385

Step-by-step explanation:

Use the distance formula with (-6,2) (-4,7)

[tex]\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2 }[/tex]

[tex]\sqrt{(-4--6)^2 + (7-2)^2 }[/tex]

[tex]\sqrt{(2^2) + (5^2)}[/tex]

[tex]\sqrt{4+25}[/tex]

[tex]\sqrt{29}[/tex]

= 5.385

Answer:

$3.25 per gallon

Step-by-step explanation:

Answer: he paid 3.25 for each gallon

Step-by-step explanation:

Divide the money (16.25) by the gallon (5) and get 1 gallon for 3.25

Answer:friday

Step-by-step explanation:

On Monday  of the week does he arrive just 15 seconds late​.

Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

The white rabbit has an appointment to see the red queen at 4pm every day of the week except weekends

Each day after that he hurries more and more and so manages to halve the amount of time that he arrives late by each day.

On Monday he arrives 16 minutes late.

On Tuesday he arrives 8 minutes late.

On wednesday he arrives 4 minutes late.

On Thursday he arrives 2 minutes late.

On Friday he arrives 1 minutes late.

On Saturday he arrives 30 seconds late.

Sunday is a weekend.

On Monday  he arrives 15 seconds late.

Hence, On Monday  of the week does he arrive just 15 seconds late​.

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Answer:

Step-by-step explanation:

Answer:

3 1/2 units cubed.

1 3/4 · 1 · 2 = 3 1/2

Answer:

f(g(4))​=34

Step-by-step explanation:

g(x)=2x

g(4)=2(4)

      =8

f(x)=4x+2

f(8)=4(8)+2

    =32+2

    =34

f(g(4))​=34

Answer:

Step-by-step explanation:

Moving a coordinate left will subtract from the x coordinate (left 3 means subtract 3 from x coordinate)

Moving a coordinate right will add to the x coordinate (right 3 means add 3 to x coordinate)

Moving a coordinate down will subtract from the y coordinate (down 3 means subtract 3 from y coordinate)

Moving a coordinate up will add to the y coordinate (up 3 means add 3 to y coordinate)

Reflect means flip the sign of the corresponding coordinate

reflect over x axis flip the sign of x coordinate

reflect over y axis flip the sign of y coordinate

Answer:

A) Airplane A has a lesser median

Step-by-step explanation:

If you look at the photo you see both airplane A and airplane B and if you were to line them up

airplane A=3

airplane B=4 ½  

so clearly airplane A would have a lesser median than airplane B

Answer:

expanded version of 4(q+6) should be 4q+24

Step-by-step explanation:

just multiply 4 and q, 4 and 6. and add it.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{4(p + 6)}[/tex]

[tex]\huge\text{DISTRIBUTE 4 WITHIN the PARENTHESES}[/tex]

[tex]\huge\textsf{4(p) + 4(6)}[/tex]

[tex]\huge\textsf{4(p) = \boxed{\bf 4p}}\huge\checkmark[/tex]

[tex]\huge\textsf{4(6) = \boxed{\bf 24}}\huge\checkmark[/tex]

[tex]\huge\checkmark\boxed{\huge\textsf{\bf 4p + 24}}\huge\checkmark[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf 4p + 24}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

all of these

0 does not equal 1

4 does not equal 7

2 does not equal -2

-3 does not equal 3

All of the given equations have no solution.

        ax + by + c = 0

        dx + ey + f = 0

We have the given system of linear equations that has no solutions.

For no solutions, the final equation should be of the form -

α = β

where [α] and [β] are constant integers.

So all the equations result in no solution.

Therefore, all of the given equations have no solution.

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Answer

$199.8

Explanation:

Find the total amount of money he had in the begining. It says that he can spend $18 on each student. He has 18 students so you would multiply that by the $18 he can spend which gives a total of $324 then you subtract the total cost of the calculators from it which then gives you $199.8

Answer:

C

Step-by-step explanation:

Answer:

jus trynna get points

Step-by-step explanation:

Answer:

90 degre i cant wright the small o thing but is 90

Step-by-step explanation:

Answer:

what exactly are we solving

Step-by-step explanation:

Answer:

Answer to what exactly?

Answer:

c

Step-by-step explanation:

Answer:

1) 49 degrees

2) It is a trapezoid

Step-by-step explanation:

1) the angles of a quadrilateral are 360 degrees, 78 + 102 + 132 + ? = 360

312 + ? = 360

? = 48

The graph that represents a function is graph X

For a graph to represent a function, then the graph must pass the vertical line test.

This means that, no two output values of the graph must have the same input value.

The above statement can be interpreted as:

For every x value, there must be exactly one corresponding y value.

From the given graphs, only graph X passes the vertical line test, because every x value has exactly one corresponding y value.

Hence, the graph X represents a function

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Answer:

the answer is x ! hope this helps

Step-by-step explanation:

i took the test

Answer:

P=5

Step-by-step explanation:

-6(2p + 1) = -7p - 31

Expand -6(2p+1)

Apply distributive law;

a=-6, b=2p, c=1

=-6*2p+(-6)*1

=-6*2p-6*1

Simplify; -6*2p-6*1

=-12p-6

-12p-6=-7p-31

Add 6 to both sides;

-12p-6+6=-7p-31+6

simplify;

-12p=-7p-25

Add 7p to both sides;

-12p+7p=-7p-25+7p

Simplify;

-5p=-25

Divide both sides by -5

-5p/-5=-25/-5

Simplify:

p=5

Answered by the One and Only #DrippQueenMo

Answer:

p=5

Step-by-step explanation:

first you want to get rid of the parentheses in -6(2p+1) so take -6 and times it by 2p and 1 to get -12p-6. You can do this because of the distributive property. Now you have the equation -12p - 6 = -7p - 31. So now you want to get the p values on one side. Adding 7p to both sides of the equations get rid of the -7p. -12p + 7p equals -5p so now you have the equation -5p - 6 = -31. so now you need to get the whole numbers on one side. So add 6 to both sides so you can get rid of the -6. this leaves you with the equation -5p= -25. Now to find the value of p you divide both sides by -5. This gives you p = 5.

Answer:

C

Step-by-step explanation:

different size wedges would be the most visibly different

Answer:

26

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\[/tex]

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

[tex]= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y[/tex]

Answer:

3 • (4y + 15)

-----------------  

      40  

Step-by-step explanation:

Long explanation get ready

STEP

1

:

           7

Simplify   —

           8

Equation at the end of step

1

:

   1   9      3     7

 ((—+(——•y))-(—•y))+—

   4  10      5     8

STEP

2

:

           3

Simplify   —

           5

Equation at the end of step

2

:

   1   9      3     7

 ((—+(——•y))-(—•y))+—

   4  10      5     8

STEP

3

:

            9

Simplify   ——

           10

Equation at the end of step

3

:

   1      9          3y     7

 ((— +  (—— • y)) -  ——) +  —

   4     10          5      8

STEP

4

:

           1

Simplify   —

           4

Equation at the end of step

4

:

   1    9y     3y     7

 ((— +  ——) -  ——) +  —

   4    10     5      8

STEP

5

:

Calculating the Least Common Multiple :

5.1    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       10

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 1 2

5 0 1 1

Product of all

Prime Factors  4 10 20

     Least Common Multiple:

     20

Calculating Multipliers :

5.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

5.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.       5

  ——————————————————  =   ——

        L.C.M             20

  R. Mult. • R. Num.      9y • 2

  ——————————————————  =   ——————

        L.C.M               20  

Adding fractions that have a common denominator :

5.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5 + 9y • 2     18y + 5

——————————  =  ———————

    20           20  

Equation at the end of step

5

:

  (18y + 5)    3y     7

 (————————— -  ——) +  —

     20        5      8

STEP

6

:

Calculating the Least Common Multiple :

6.1    Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       5

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

5 1 1 1

Product of all

Prime Factors  20 5 20

     Least Common Multiple:

     20

Calculating Multipliers :

6.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

6.3      Rewrite the two fractions into equivalent fractions

  L. Mult. • L. Num.      (18y+5)

  ——————————————————  =   ———————

        L.C.M               20  

  R. Mult. • R. Num.      3y • 4

  ——————————————————  =   ——————

        L.C.M               20  

Adding fractions that have a common denominator :

6.4       Adding up the two equivalent fractions

(18y+5) - (3y • 4)     6y + 5

——————————————————  =  ——————

        20               20  

Equation at the end of step

6

:

 (6y + 5)    7

 ———————— +  —

    20       8

STEP

7

:

Calculating the Least Common Multiple :

7.1    Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       8

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 3 3

5 1 0 1

Product of all

Prime Factors  20 8 40

     Least Common Multiple:

     40

Calculating Multipliers :

7.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 2

  Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

7.3      Rewrite the two fractions into equivalent fractions

  L. Mult. • L. Num.      (6y+5) • 2

  ——————————————————  =   ——————————

        L.C.M                 40    

  R. Mult. • R. Num.      7 • 5

  ——————————————————  =   —————

        L.C.M              40  

Adding fractions that have a common denominator :

7.4       Adding up the two equivalent fractions

(6y+5) • 2 + 7 • 5     12y + 45

——————————————————  =  ————————

        40                40  

STEP

8

:

Pulling out like terms :

8.1     Pull out like factors :

  12y + 45  =   3 • (4y + 15)