A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pressure of
0.987 atm and the volume changes to 144mL?
Be sure to show all of your work, define variables, show equation and substitute variables. Report you answer in Celcius.

Answers

Answer 1

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is [tex]25.16^0C[/tex]

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 0.947 atm

[tex]P_2[/tex] = final pressure of gas = 0.987 atm

[tex]V_1[/tex] = initial volume of gas = 150 ml

[tex]V_2[/tex] = final volume of gas = 144 ml    

[tex]T_1[/tex] = initial temperature of gas = [tex]25^0C=(25+273.15)K=298.15K[/tex]

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above equation, we get:

[tex]\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}[/tex]

[tex]T_2=298.31K=(298.31-273.15)^0C=25.16^0C[/tex]

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is [tex]25.16^0C[/tex]


Related Questions

A hydrochloric acid solution contains 36 percent HCl by mass. Calculate its
molality

Answers

The Molarity M of a solute in a solution is defined as:

M=moles of solution / kilograms of solvent

Mass %= (mass solute/mass solution)x100%

Assume 100g of solution

Find moles of solute

Mass solute = (mass %/100%)mass solution

=(36%/100)100g=36 gHCL

36 gHCL 1 mol HCL/36.458 gHCL= 0.987molHCL

36% HCL by mass 100 g solution
36g HCL 0.987Mol HCL

Molarity=moles solute/kg solvent

Find kg solvent
Mass solution = mass solute + mass solvent
Mass solvent = mass solution - mass solute
= 100 g-36=64 g solvent

64 g solvent = 1 kg solvent/1000 g solvent = 0,064 kg solute

Molarity= molHCL/0.064 kg solvent

=0.987/0.064
=15.42 mHCL

PLEASE I WILL BRAINLIST YOU
1. A student predicted the reaction between hydrogen and oxygen gas would yield 125 mL of water. However, after measuring the water formed in the reaction, the student determined that only 110 mL of water was actually formed. Determine the percent yield for this reaction.
A. 75%
B. 88%
C. 100%
D. 113%
HINT: 96 yield= (actual yield/ expected yield ) X 100% ​

Answers

Answer:

B. 88%

Explanation:

percent yield is the actual yield divided by the theoretical (predicted) yield, then multiplied by 100 to get a percentage.

110/125 = 0.88

0.88 x 100 = 88%

In chemistry, the term yield also known as the reaction yield represents the measure of the quantity of the moles of a product formed in the reaction to the reactant used. The correct option is B.

What is percent yield?

The amount of the product actually made compared with the maximum calculated yield is defined as the percent yield. It can also be known as the ratio of the actual yield to the theoretical yield.

The ideal quantity of the product is called the theoretical yield and it is obtained by working a stoichiometry problem. The actual amount of the product formed gives us the actual yield.

The equation of the percent yield is given as:

%yield = Actual yield / Theoretical yield × 100

110 / 125 × 100 = 0.88 × 100 = 88%

Therefore the percent yield of the reaction is 88%.

Thus the correct option is B.

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A leader from Louisiana is claiming that it is necessary to include the effects of tornadoes in his city’s emergency plan for natural disasters. Use data from Map 1, the graphs, and what you know about tornadoes to support his claim.


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Answer:

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Answers

Answer:

Option A.

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Answers

Answer:

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Explanation:

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