Answer:
Approximately [tex]2.1 \times 10^{3}\; {\rm m}[/tex] ([tex]2.1\; {\rm km}[/tex]) assuming that the speed of sound in the water is [tex]1482\; {\rm m\cdot s^{-1}}[/tex] ([tex]20\; ^{\circ}{\rm C}[/tex].)
Explanation:
Multiply speed [tex]v[/tex] by time [tex]t[/tex] to find the distance [tex]s[/tex] travelled.
The sound wave in this question has travelled a distance of at least:
[tex]\begin{aligned}s &= v\, t\\ &= (1482\; {\rm m\cdot s^{-1}})\, (2.8\; {\rm s}})\\ &\approx 4.15\times 10^{3}\; {\rm m}\end{aligned}[/tex].
Note that this distance is for a round trip- from the ship to the ocean floor and back. The depth of the ocean at this location will be one-half the distance of a round trip:
[tex]\begin{aligned} \frac{4.15\times 10^{3}\; {\rm m}}{2} \approx 2.1\times 10^{3}\; {\rm m} = 2.1\; {\rm km}\end{aligned}[/tex].
in the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in case 2 as in case 1. 1)how are the maximum velocities in the two cases related?
The maximum velocities in the two cases related are Vmax,2 = 2 Vmax,1
Simple harmonic motion :
In physics, simple harmonic motion is the repeated back-and-forth motion through an equilibrium, or center, position so that the maximum displacement on one side of this position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.
Complete question:
In the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in Case 2 as in Case 1.
1)How are the maximum velocities in the two cases related?
Vmax,2 = Vmax,1
Vmax,2 = 2 Vmax,1
Vmax,2 = 4 Vmax,1
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g two pool balls, each moving at 2 m/s, roll toward each other and collide. suppose after bouncing apart, each moves at 2 m/s. assume the positive direction is to the right. this collision violates conservation of group of answer choices kinetic energy momentum both kinetic and momentum none of the above
This collision violates conservation of both energy and momentum i.e, third option is correct.
According to the law of conservation of momentum, when two bodies collide their total momentum and energy before and after collision are equal.
According to the law of conservation of energy, energy can neither be created nor destroyed. However, it can be transformed from one form to another. It is also known as the first law of thermodynamics.
Given that, the two bodies move with same velocities after collision, means that the law has not been violated since, momentum = mass*velocity (where mass is said to be constant)
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a 0.030-kg bullet is fired vertically at 200 m/s into a 0.15-kg baseball that is initially at rest. how high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?
If a 0.030-kg bullet is shot vertically at 200 m/s into a 0.15-kg baseball, the combined height of the bullet and baseball following the collision is at most 56.6 m, provided the bullet embeds itself in the ball.
This phase will begin immediately prior to the collision and conclude immediately following the impact (when the two objects are on the verge to move up as a single unit). Note that we are assuming the ball will initially be moving at a speed of 200 m/s when the bullet then collision with it. At this point, we define the system as the ball plus the bullet. We are ignoring any outside factors, such as air resistance or even gravitational force, that can affect this system. As a result, the final velocity of the system immediately following the impact can be determined using the conservation of momentum principle, p=0. The gravitational potential energy is being ignored because we assume that the ball and the bullet were at the same level just before (and just after) colliding.
Yf = v1^2*2*9.8
Yf = 33.3^2*2*9.8
Yf = 56.6 metres.
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suppose that an object is dropped, not from the earth's surface, but from a height rearth above the earth's surface. with what acceleration will it start to fall? give your answers as a fraction of gearth
The acceleration of the object when it will start falling from the height above the earth is ( 1/9 ) gₓ.
Acceleration due to gravity from the height = gₙ
Acceleration due to gravity on earth = gₓ
Distance between the core of earth and the point at a height above earth = h
Radius of the earth = rₓ
Now, for h = rₓ
= Using the gravitational formula
= gₙ = gₓ ( rₓ / (rₓ + rₓ))²
= gₙ = ( 1/4 ) gₓ
Similarly for h = 2rₓ,
= gₙ = gₓ ( rₓ / (rₓ + rₓ))²
= gₙ = ( 1/9 ) gₓ
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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?
The kinetic energy of the bullet when it left the gun barrel is 1000J.
We know that ,
K.E. = F d
where, K.E. = kinetic energy
F = force
d = distance
Given, F = 1* 10^4 N
d = 10cm = 0.1 m
Putting these values in above equation we get,
K.E. = 1000J
So the kinetic energy of the bullet when it left the gun barrel is 1000J.
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a fluid flows through a horizontal pipe of radius 1.5 cm at a speed of 5.0 m/s. the density of the fluid is 900 kg/m3 and the pressure is 1.30 x 105 n/m2. when the fluid flows into a connecting pipe of radius 1.0 cm, the speed is increases to 11.0 m/s. what is the pressure in the connecting pipe in pa?
The pressure in the connecting pipe is 88 pa.
Stress is the pressure applied perpendicular to the floor of an object according to unit place over which that force is sent. Gauge strain is the strain relative to the ambient pressure. diverse gadgets are used to explicit strain.
Calculation:-
radius of pipe = 1.5 cm
speed = 5 m/s
The speed is increases to 11.0 m/s
density of the fluid = 900 kg kg/m³
Pressure = 1.30 × 10⁵ N/m²
The pressure in the connecting pipe in pa = ρdv/dl
= 88 pa.
Stress is defined because the bodily pressure exerted on an item. The force applied is perpendicular to the surface of objects in step with unit place. The primary components for strain is F/A (force in keeping with unit location). Unit of pressure is Pascals (Pa). forms of Pressures are Absolute, Atmospheric, Differential, and Gauge pressure.
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you shoot a 51 g pebble straight up with a catapult whose spring constant is 320 n/m. the catapult is initially stretched by 0.20 m. how high above the starting point does the pebble fly? ignore air resistance
Applying the Conservation of Energy, the point above the starting point of the pebble will fly is 12.8 m
Given Parameters:
Mass of the pebble (m) = 51 g
Spring Constant (k) = 320 N/m
Extension (x) = 0.20 m
Law Of Conservation Of Energy:
According to the rule of conservation of energy, energy cannot be created or destroyed. Energy doesn't evaporate when it is used by people.
Within a specific frame of reference, the total energy of an isolated system either remains constant or is conserved.
According to the law of conservation of energy
Kinetic Energy is equal to potential Energy,
[tex](1/2)kx^2 = mgh\\\\h = (kx^2) / (2mg)= [(320 N/m)(0.20m)^2] / [2(0.051kg)(9.8 m/s^2)]= 12.8 m[/tex]
Thus, The point above the starting point of the pebble will fly is 12.8 m.
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in the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. suppose the background signal level is 13 mv, the signal is 91 mv with no attenuator and is 25 mv with an attenuator in place. calculate pt/pi including the background correction. round your answer to 3 digits after the decimal point.
15.38 % is pt/pi including the background correction.
What is the definition of an amplitude simple?The greatest deviation from equilibrium of a point on either a vibrating body or wave in terms of displacement or distance traveled. It is similar to the half-length of the vibration path.
Briefing :
Background [tex]=13mv[/tex]
corrected signal [tex]= 91mv - 13 mv = 78mv[/tex]
with attenuator[tex]=25mv - 13mv = 12 mv[/tex]
[tex]\frac{P_{t} }{P_{i} } = \frac{12}{78} . 100[/tex]
[tex]= 15.38 %[/tex] %
Therefore , the pt/pi is 15.38 %
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if quasars are at the distances most astronomers believe they are, then (for the most luminous ones) their luminosities must be:
If quasars are located at the distances that the majority of astronomers think they are, then their luminosities must equal the sum of one hundred trillion (1014) Suns.
What kind of brilliance is that?Something's luminosity is determined by how much light it emits or reflects. A big, sparkling diamond's brightness is its most distinguishing feature. You might talk about the luminosity of an energetic and vibrant oil painting or be in awe of the luminosity of a spectacular sunset.
Does light improve intelligence?Small (2–3 point) training benefits are obtained via lumosity training. If you exercise for 12 and a half hours over several weeks, you can enhance your IQ, working memory, and other cognitive abilities by about 2-3 points.
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Light having a wavelength in vacuum of 600 nm enters a liquid of refractive index 2. 0. In this liquid, its wavelength will be
The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10 m/s and the wavelength is
4 x 10^-7 m
Given that,
Wavelength X = 600 nm
Refractive index n = 1.5
We know that,
The frequency is the ratio of the speed of light and wavelength of the light.
f = c/λ
f = 3 x 10^8/600 × 10^-9
f = 5 x 10^14 Hz
The speed in the medium is the ratio of the speed of the light in the vacuum and the refractive index.
n = c/v
1.5 = 3 x 10^8/υ
v = 2 × 10^8 m/s
The wave length is the ratio of the speed of the light in the medium and frequency.
λ = v/f
λ = 2 × 10^8/5 x 10^14
λ = 4 × 10^-7 m
Hence, The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10^8 m/s and the wavelength is 4 x 10^-7 m
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In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 x 107 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 x 1027 kg). Part A What is the value of g on this large, but low-density, world? Express your answer with the appropriate units. НА ? g= Value Units Submit Request Answer Provide Feedback
3.86 m/s^2 is the value of gravity on this large, but low-density, world.
given :
Kepler-12b
diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),
mass = 0.43 Jupiter (M_Jupiter = 1.90 × 10^27 kg ).
g = GM/r^2
g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2
g = 3.859 ~ 3.86 m/s^2
Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.
On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.
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metallic bonding occurs when a. a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction b. positive metallic ions are bonded with delocalized free electrons. c. the negative side of one molecule bonds with the positive side of a neighboring molecule d. two metallic atoms share electrons in their outer valence shells
The answer is A. Metallic bonding occurs when a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction
Metallic bonds are formed when the charge is spread over a larger distance than the size of single atoms in solids. Metallic bonding is a chemical bonding that arises from the attractive electrostatic force between conduction electrons (in the form of an electron cloud of delocalized electrons) and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions (cations). Metallic bonding is not the only type of chemical bonding a metal can exhibit, even as a pure substance.
Metallic bonding occurs when you have a metal in a solid or liquid state. The s and p valence electrons of metals are loosely held. They leave their “own” metal atoms. This forms a "sea" of electrons that surrounds the metal cations. The electrons are free to move throughout this electron sea. A strong metallic bond will be the result of more delocalized electrons, which causes the effective nuclear charge on electrons on the cation to increase, in effect making the size of the cation smaller.
Metallic bonds are strong and require a great deal of energy to break, and therefore metals have high melting and boiling points. A metallic bonding theory must explain how so much bonding can occur with such few electrons (since metals are located on the left side of the periodic table and do not have many electrons in their valence shells). The theory must also account for all of a metal's unique chemical and physical properties.
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a 6.0 v ideal battery is being used to charge a 5.0 x 10-6 f capacitor through a resistor r. the capacitor attains a potential difference of 3.6 v in 1.0 s after the charging begins. the value of the resistance r is
The value of the resistance R in the above case is 120000 Ohms.
In this case
Charge is given by
Q=CV
=6*5*10^-6
=30*10^-6 C
Then the current through the resistor, R is
I=Q/t
=(30*10^-6)/1
=30*10^-6 A
From Ohm's law
R=V/I
=3.6/(30*10^-6)
=120000 Ohms
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what is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at 8.00 cm? take the lens-to-retina distance to be 2.00 cm.
Given details :
a) For this exercise we use the equation for thin lenses
1 / f = 1 / p + 1 / q
where f is the focal length, p the distance to the object and q the distance to the image
In this case q is the distance from the lens to the retina q = 2.00 cmThe distance p is the distance from the object to the lens p = 8.00 cm1 / f = 1 / 8.00 + 1/2
1 / f = 0.625 cm⁻¹
power is the inverse of the focal length in meters
P = 1 / f [m]
P = 0.625
P = 62.5 diopter
b) the size of the image
m = - p / q
m = - 2 / 8.00
m = -0.25 X
if we assume that the object is right
m = h´ / h
h´ = m h
h´ = -0.25 x 2
h´ = -0.5 mm
if the height of the object h is straight the image and inverted
c) if the object were at p = 25.0 cm
m = - 2/25
m = -0.08
h´ = -0.08 x 2
h´ = -0.16 mm
the image would be much smaller
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Keiko is riding a skateboard 2 m/s, west. How long will it take her to reach a velocity of 8 m/s, west if her acceleration is 2 m/s2?By definition, acceleration is the measure of a velocity change in time. In a particular case when the acceleration is constant, the velocity of an object is changed uniformly (linearly) with time.
If we denote the initial velocity as V_0, the constant acceleration as a and the time since the initial moment as t, then the new speed V at time t will be
V=V_0+at.
In our problem the velocities and the acceleration are given, and we need to solve the above equation for t. It is simple:
t=(V-V_0)/a=(8-2)/2=3(s).This is the answer. Note that it is important that the initial velocity and the final velocity have the same direction (west). If they would have opposite direction, one of them should be taken with a minus sign, and the acceleration might be negative.
The time taken to reach a velocity of 8 m/s, west if her acceleration is 2 m/s is 3 seconds
Given,
Velocity of Keiko's skateboard = 2 m/s
Velocity to reach = 8 m/s
Acceleration = 2 m/s²
Velocity is known to be the total displacement that occurred in a particular given time.
It is a vector quantity that has both magnitude and direction.
By the 1st equation of motion regarding velocities,
v = u + at ...........(1)
where,
v = final velocity = 8 m/s
u = initial velocity = 2 m/s
t = time = ?
a = acceleration = 2 m/s²
Now put all the given values in the above equation 1, we get:
8 m/s = 2m/s + (2 m/s²)t
t = 3 seconds
Therefore, using the velocities, we got the the time taken will be 3 seconds.
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An elastic cord is 61 cm long when a weight of 75 N hangs from it but is 85 cm long when a weight of 210 N hangs from it. What is the "spring" constant k of this elastic cord? also, find the frequency of the motion with the 210N object hanging on it (Physics 'Algebra base')
The spring constant of this elastic cord is 562.64 Nm.The frequency of the motion with the 210 N is 0.817Hz.
Elastic cord is a fairly versatile stretchy rope. it is small diameter makes it ideal for indoor craft makes use of and light duty strapping. Use this elastic string for sewing initiatives, scrapbooking, and kids' crafts.
Calculation:-
Spring constant K = f/x
= 75/0.61 - L
= 75/0.61 - 0.4767
= 562.64 Nm
Frequency when 210 N is hanging is
extension X = 0.85 -L
= 0.87 - 0.4767
= 0.3733
Frequency = 1/2π√g/X
= 1/2π √9.8/0.3733
= 0.816 Hz.
The free movement of a frame with appreciate to time is called motion. for example-the fan, the dirt falling from the carpet, the water that flows from the tap, a ball rolling around, a shifting car etc. Even the universe is in chronic motion.
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To practice Problem-Solving Strategy 24.1 Magnetic field problems.
The element niobium, which is a metal, is a superconductor at temperatures below 9 K . This means that at such low temperatures a niobium wire has no electrical resistance. The superconductivity of the wire, however, is destroyed if the magnetic field at the surface of the wire exceeds 0.10 T . What is the maximum current in a straightsuperconducting niobium wire of radius 1.5 mm ? You may assume that all the current flows in the center of the wire.
Prepare
Create a visual representation of the problem. First choose the best orientation for the wire, then draw the magnetic field created by the current. You can then determine your known variables and identify those that you must find.
Recall that you are to treat the current as if it all runs through the center of the wire, and you are interested in the value of the magnetic field at the surface of the wire. Sort the following variables as known or unknown: the magnitude of the magnetic field B, the current I, and the distance r between the current and the point at which the magnetic field has a value of B.
u0= 4pi*10^-7
r=1.5mm= 1.5*10^-3m
substitute these values
The answer is 750 A
Long straight wire :B =µ01/2πr = Icrit==(2π)*(r=D/2)(Bcrit))/µ0
An electron is accelerated from rest through a potential difference V. Its final speed is proportional to???
Answer:
E = V q energy attained by charge q thru potential energy V
E = 1/2 m v^2 kinetic energy of charge q
1/2 m v^2 = V q equating energy attained
v^2 = 2 V q / m
v = (2 V q / m)^1/2
The final speed is proportional to the square roots of V, q, and inverse of square root of m.
v high - speed stroboscopic photographs show that the head of a 2.00 3 102 - g golf club is traveling at 55.0 m/s just before it strikes a 46.0 - g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40.0 m/s. find the speed of the golf ball just after impact.
Velocity of golf ball after collision with golf club using law of conservation of momentum is 65.21 m/s
What is momentum ?
Momentum seem to be directly dependent on the value of mass as well as velocity of the object in the direction of motion. it is quantified by "mass velocity". Since mass is a scalar quantity but velocity is a vector, momentum is a vector quantity.
From the given information-
mass of golf club = 200 g
mass golf ball = 46 g
velocity of club before collision = 55 m/s
velocity club after collision =40 m/s
velocity of golf ball before collision = 0 m/s
You need to use conservation of momentum here.
momentum = mass x velocity
Prior to impact, the golf club has a momentum of 0.200 kg * 55 m/s = 11.00 kg m/s.
The ball's not moving before impact, so it has a momentum of zero. Therefore the total momentum before impact will be 11.00 kg m/s. Conservation of momentum dictates the total momentum of the two objects after impact will also be 11.00 kg m/s.
We know the speed of the club after the impact, so the momentum of the club after impqact is 0.200 kg * 40 m/s =8 kg m/s.
So the momentum of the ball must be 11.00 kg m/s - 8 kg m/s = 3 kg m/s, and dividing by the mass of the ball (0.046 kg) gives the speed of the ball, 65.217 m/s
Velocity of golf ball after collision wit golf club is 65.21 m/s
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which planet(s) will experience an increase in gravitational force and an increase in orbital speed from this added mass? explain your reasoning.
Saturn, Uranus, and Neptune
The reason is that more mass is added interior to those planets' orbits. With a greater interior mass, Saturn, Uranus, and Neptune will experience a larger gravitational force and an increased orbital speed.
A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.
As seen in the equation v = SQRT(G * Mcentral / R), the mass of the central body (earth) and the radius of the orbit affect orbital speed.
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a 100 meter long copper wire has a resistance of 100 ω. another copper wire has the same mass but is 10 meters long. find the resistance of the second wire. group of answer choices 1 ω 10 ω 100 ω 1,000 ω
The resistance of the second wire will be 10 ω.
What is resistance?
Electrical resistance, or resistance to electricity, is a force that opposes the flow of current. It acts as a gauge for the difficulty of current flow in this way. Ohms (Ω) are used to express resistance values. Electricity would then flow from high to low when two terminals have an electron differential. That flow is countered by resistance. The current decreases as resistance increases. On the other hand, the current increases as the resistance decreases. Resistance could be calculated as a number using the circuit's voltage and current.
The resistance of a wire is inversely proportional to its length, so the second wire, which is 10 meters long, will have a resistance that is 10 times less than the first wire, which is 100 meters long. The resistance of the second wire will be 100 ω ÷ 10 = 10 ω.
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a machine works with an efficiency of 18%. the energy input is 500 joules/second. how much useful energy will the machine generate in 15 minutes?(1 point)
The useful energy the machine will generate in 15minutes is 81000J
What is efficiency of a machine?The efficiency of a machine indicates how well its input energy is converted to useful output energy or work. It is a major factor in the usefulness of a machine and is the fraction or percentage of the output divided by the input.
Therefore the efficiency of a machine is given as Energy output/ energy input ×100 or power output/ power input ×100
let the power output be x
therefore 18=( x/500)×100
100x = 18×500
x= 18×500/100= 90J/s
Energy = power ×time
in 15minutes = 15×60s, the machine will generate energy of 90×15×60= 81000J
Therefore the machine will generate a useful energy of 81000J
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using newton law of gravity calculate the lenghth of the year. consider the orbit of earth is a circule
Using Newton's Law of gravity, the length of the year is 364.24 days.
According to Newton's law, there exist a force of gravitation between the sun and the earth, The gravitational force is responsible for the revolution of earth around the sun,
So, we can write,
MW²/R = GMm/R²
Where,
M is the mass of earth,
m is the mass of the sun,
R is the distance between the sun and the earth,
G is the universal Gravitational constant.
Solving the relation,
W² = Gm/R
W = √(Gm/R)
The time period of revolution is given by,
T = 2π/W
So, we can write,
T = 2π√(R/Gm)
Bow, putting all the values,
T = 2π(147 x 10⁶/2 x 10³⁰ x 6 x 10⁻¹¹)
T = 364.24 Days.
So, the length of the year is 364.24 years.
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A lever requires an energy input of 10,000 J to move a 35 kg box up a distance of 18 m. What is the efficiency of this lever?
The efficiency of the lever will be 62%
What is Efficiency?Efficiency is the ratio of the work performed by a machine to the total energy expended or heat consumed.
Efficiency refers to how close we can get to a particular outcome of the given input with as much less wastage as possible. Efficiency is the ability to minimise wasting materials, efforts, energy and time in performing something or producing the desired result.
The ratio of energy transferred to a useful form compared to the total energy supplied initially is called the efficiency of the device.
Efficiency (%) = (work output/work input) x 100%
work output = mgh
work input = 10,000J
Efficiency (%) = (35 x 18 x 9.8/10,000) x 100
Efficiency (%) = 0.62 x 100
Efficiency (%) = 62%
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Nuclear decay occurs according to first-order kinetics. A nuclide decays in 23. 0 minutes from 12. 9 g to 2. 04 g. What is the rate constant for the nuclide?.
The rate constant for the nuclide is 0.08.
We know that rate of first order reaction is given by: [tex]kt = 2.303 * log(R'/R)[/tex]
where k = rate of reaction
t = time = 23 minutes
R' = initial mass = 12.9 grams
R = final mass = 2.04 grams
Putting these values in above equation we get k = 0.08.
i.e. the rate constant for the nuclide is 0.08.
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A wooden loop and a wire loop, both with the same shape and size, are placed next to the north poles of identical magnets. Then, the loops are moved closer to and farther from the magnets in exactly the same way. The emf generated around the wooden loop is zero. O less than the emf generated around the wire loop. equal to the emf generated around the wire loop. O greater than the emf generated around the wire loop.
The emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.
Give an explanation about EMF.
The electric potential created by either modifying the magnetic field or by an electrochemical cell is known as electromotive force (emf).
Due to the fact that Faraday's law is independent of the material and only considers how the flux is changing, the emf produced around the wooden loop is equivalent to the emf produced around the wire loop. Due to the fact that the loop material moves close to the end of the bar magnet, modifying the magnetic flux through the loop, even though it is not a part of the magnetic flux expression, an emf is nevertheless produced.
Hence, the answer is the emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.
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if a pendulum-driven clock gains 7.2 s/day, what fractional change in pendulum length must be made for it to keep perfect time?
Pendulum length must be made for it to keep perfect time of 100 or 0.0167 % or 0.017 % nearly.
What is time?Time is the measure of to non-stop, consistent change by in our surroundings, or it is usually from a specific to viewpoint.
Total number of seconds in a normal day is 24×60×60 = 86400 seconds
We know that time period of pendulum is
T= 2π √l/g
Then we use fractional error method
∆T/T = 1/2 ( ∆l /l )
Here l is length of pendulum string
So 7.2/86400 = 1/2 ( ∆l/l)
∆l/l = 0.000167
So percentage change is
∆l/l *100 or 0.0167 % or 0.017 % nearly.
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your friend is 1.7 m tall. (a) when she stands 3.2 m from you, what is the height of her image formed on the retina of your eye? (consider the eye to consist of a thin lens 2.5 cm from the retina.) (b) what is the height of her image when she is 4.2 m from you?
(a) Formulae for magnification (m) = distance of image/image of object
=.025/3.2 = 0.00781
so, magnification of eye = 0.00781
now. m = image size / actual size
so, image size = actual size x m
= 1.7 x 0.00781
= 0.0132 m
(b) similarly, in this case the size of the image can be calculated as follows:
m = distance of image/image of object = 0.00595
image size = actual size x m = 0.0101
What is magnification?
Magnification in physics can be defined as the ratio of size of the image to the size of the object. Magnification in simple terms means enlargement in the size of the image of an object.
It can be denoted by the formulae:
[tex]magnification = \frac{size of the image}{size of the object}[/tex]
It has no SI unit.
Why Magnification has no SI unit?
It has no SI unit because it is a ratio of length.
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What is the maximum speed at which a car can safely travel around a circular track of radius 55. 0 m if the coefficient of friction between the tire and road is 0. 350?.
The maximum speed at which a car can safely travel around a circular track of radius 55. 0 m is 10.84 m/s
What does it imply to speak of centripetal forces?Any object is drawn toward the center of a curved surface by a centripetal force. Imagine that you are a yo-yo being spun. The yo-yo is set in motion by your arm movement, and as you twirl it, the tension of the string keeps it spinning.
Given : r=30 m
μ=0.4
g=9.8m/s
2The maximum speed
v max =μgr= 0.4×9.8×30 =10.84 m/s
How would you describe centripetal force to a young person?A force known as centripetal force keeps things moving in a circular motion. The object will keep rotating in a circle as long as the centripetal force persists and all other forces are equally balanced. One object that moves in a circle as a result of centripetal force is a yo-yo.
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the magnitude of the magnetic field 50 cm from a long, thin, straight wire is 8.0 μt. what is the current through the long wire?
The current through the long wire is 20A.
What is a magnetic field in simple terms?
The magnetic field is the area around a magnet in which the effect of magnetism is felt. We use the magnetic field as a tool to describe how the magnetic force is distributed in the space around and within something magnetic in nature.
What causes a magnetic field?
Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the nucleus, or core, of an atom.
How do you find current in a wire in a magnetic field?
The strength of a magnetic field, , some distance away from a straight wire carrying a current, , can be found using the equation = 2 , where is a constant known as “the permeability of free space”
What happens when a wire with a current is placed in a magnetic field?
The wire will bend away from the poles of the magnet.
[tex]i=\frac{2\pi RB}{m_{0}}[/tex]
Given : [tex]R=0.50m, B=8*10^{-6}[/tex]
[tex]i=\frac{2\pi *0.50*8*10^{-6}}{4\pi *10^{-7}}[/tex]
[tex]i=20A[/tex]
Thus, the current flowing in the wire is 20A.
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