A restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence that the mean level of arsenic is greater than 80 ppb, so we are testing vs , where represents the average level of arsenic in all chicken from a certain supplier. It takes money and time to test for arsenic so samples are often small. A sample of chickens from one supplier is tested, and the resulting sample mean is . Subtracting 11 from the sample data to move the mean down to the null mean of results in the following data: .
57, 64, 70, 82, 84, 123
Use StatKey or other technology to create the randomization distribution for this test. Find the p-value.

Answer:

C. 2.75P

Step-by-step explanation:

The original value was P.

It increased by 275%. That means it increased by 275% of P.

275% of P = 2.75P

The increase in value is 2.75P.

Now we add the increase to the original value of P to find today's value.

2.75P + P = 3.75P

Answer: C. 2.75P

Step-by-step explanation:

[tex]( {n}^{3} )^{2} = {n}^{6} = n \times n \times n \times n \times n \times n [/tex]

Answer:

n x n x n x n x n x n

Step-by-step explanation:

(n^3)^2 = n^6 = n x n x n x n x n x n

Answer:

a) Standard error of the mean = 1.433 mm

b) 99% confidence interval = (12.6, 22.2)

c) The precision of the estimate = 4 816

d) The assumptions that are necessary for the validity of the conidence interval constructed include

- The sample must be a random sample extracted from the population, with each variable in the sample independent from one another.

- The sample must be a normal distribution sample or approximate a normal distribution and the best way to establish this is when the population distribution where the sample was extracted from is normal or approximately normal.

Step-by-step explanation:

a) Standard error of the mean is given as

σₓ = (σ/√n)

σ = Sample standard deviation = 4.3 mm

n = sample size = 9

σₓ = (4.3/√9) = 1.433 mm

b) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 17.4 mm

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 9 - 1 = 8.

Significance level for 99% confidence interval

(100% - 99%)/2 = 0.5% = 0.005

t (0.005, 8) = 3.36 (from the t-tables)

Standard error of the mean = 1.433 mm

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 17.4 ± (3.36 × 1.433)

CI = 17.4 ± 4.816

99% CI = (12.584, 22.216)

One crate orė

99% Confidence interval = (12.584, 22.216)

c) The precision of the estimate is gven as the length of the, margin of error of the confidence interval. The precision of the estimate = 4.816

d) They include

- The sample must be a random sample extracted from the population, with each variable in the sample independent from one another.

- The sample must be a normal distribution sample or approximate a normal distribution and the best way to establish this is when the population distribution where the sample was extracted from is normal or approximately normal.

Hope this Helps!!!

Answer:

B). 3 1/2(-2) = -7

Step-by-step explanation:

Let's evaluate the expression so as to be able to get the right estimate.

3 4/7 (-2 1/12)

=3 4/7 (-25/12)

= 25/7 * -25/12

= 25/7 * -25/12

= -625/84

= -7 37/84

Approximately it's equal to ,-7

Answer:

b  

Step-by-step explanation:

got  it right on edge

Answer:

after 7 seconds the driver applied the brakes to stop the car.

Step-by-step explanation:

Given:

The position of the car s(t)=[tex]42t-3t^2[/tex]

∴Speed of the car =[tex]\frac{ds}{dt}=\frac{d(42t-3t^2)}{dt}=42-6t[/tex]

When car stopped the speed of car=0

[tex]\Rightarrow42-6t=0\\\Rightarrow6t=42\\\Rightarrow\ t=7[/tex]

Therefore, after 7 seconds the driver applied the brakes to stop the car.

Answer:

sales = $700

Step-by-step explanation:

he earned commission of 175

this is 25% of sales

if 25% = 175

what about 100%

sales = (100*175)/25

sales = $700

Answer:700

Step-by-step explanation:

Answer:

See attached

Step-by-step explanation:

Given the numbers 1,2,3,4 and 5

Let O be the event that the number is Odd

Let E be the event that the number is Prime

Then the intersection of Odd and Prime Numbers: [tex]O \cap P =\{3,5\}[/tex]

Since 4 is neither odd nor prime, we place it outside of the two circles.

See the attached diagram for the required Venn diagram.

Answer:

B

Step-by-step explanation

Complete question:

A police car is located 50 feet to the side of a straight road. A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road.

Answer:

The red car is traveling along the road at 80.356 ft/s

Step-by-step explanation:

Given

Police car is 50 feet side off the road

Red car is 130 feet up the road

Distance between them is decreasing at the rate of 75 feet per sec

Let x be how far the police is off the road.

Let y be how far the red car is up the road.  

Let h be the distance between the police and the red car.

This forms a right triangle so we can use the Pythagorean theorem, to solve for h

h² = x² + y²

h² = 50² + 130²

h² = 19400

h = √19400

h = 139.284 ft

Again;

Let dx/dt be how fast the police is traveling toward the road.

Let dy/dt  be how fast the red car is traveling along the road.

Let dh/dt be how fast the distance between the police and the car is decreasing.

Recall that, h² = x² + y² (now differentiate with respect to time, t)

2h(dh/dt) = 2x(dx/dt) + 2y(dy/dt)

divide through by 2

h(dh/dt) = x(dx/dt) + y(dy/dt)

since the police car is not, dx/dt = 0

and dy/dt is the how fast is the red car actually traveling along the road

139.284(75) = 50(0) + 130(dy/dt)

10446.3 = 0 + 130(dy/dt)

dy/dt = 10446.3 / 130

dy/dt = 80.356 ft/s

Therefore, the red car is traveling along the road at 80.356 ft/s

Answer:

0.9099

Step-by-step explanation:

1) =

=

200

800

= .25

2) Identify = . = .23

3) Find the z-value.

=

−

(1−)

=

.25−.23

.23(1−.23)

800

= 1.34

4) The probability is 0.9099.

Answer:

D. d = [tex]\sqrt{58}[/tex]

Step-by-step explanation:

Use the distance formula: d = [tex]\sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2} }[/tex]

The two points are (6, -2) and (3, -9)

Plug the values into the formula:

d = [tex]\sqrt{(3 - 6)^{2}+ (-9 + 2)^{2} }[/tex]

Simplify

d = [tex]\sqrt{(-3)^{2}+ (-7)^{2} }[/tex]

d = [tex]\sqrt{9+ 49 }[/tex]

d = [tex]\sqrt{58}[/tex]

I hope this helps :))

Answer:

Step-by-step explanation:

We will use the reduction of order to solve this equation. At first, we need a solution of the homogeneus solution.

Consider the equation [tex]y''+2y'+y=0[/tex] We will assume that the solution is of the form [tex]y=Ae^{rx}[/tex]. If we plug this in the equation, we get

[tex]Ae^{rx}(r^2+2r+1)=0[/tex]

Since the exponential function is a positive function, and A should be different to zero to have non trivial solutions, we get

[tex]r^2+2r+1=0[/tex]

By using the quadratic formula, we get the solutions

[tex]r= \frac{-2\pm \sqrt[]{4-4}}{2}=-1[/tex]

So one solution of the homogeneus equation is of the form [tex]y=Ae^{-x}[/tex]. To use the reduction of order assume that

[tex] y = v(x)y_h[/tex]

where [tex]y_h = Ae^{-x}[/tex]. We calculate the derivatives and plug it in the equation

[tex] y' = v'y_h+y_h'v[/tex]

[tex]y'' = v''y_h+v'y_h'+y_h'v'+y_h''v = v''y_h+2v'y_h+y_h''v[/tex]

[tex](v''y_h+2v'y_h'+y_h''v)+2(v'y_h+y_h'v)+vy_h = 0[/tex]

If we rearrange the equation we get

[tex]v''y_h+(2y_h'+2y_h)v'+v(y_h''+2y_h'+y_h)=0[/tex]

Since [tex]y_h[/tex] is a solution of the homogeneus equation we get

[tex]v''y_h+(2y_h'+2y_h)v'=0[/tex]

If we take w = v', then w' = v''. So, in this case the equation becomes

[tex]w'y_h+(2y_h'+2y_h)w=0[/tex]

Note that [tex]y_h' = -1y_h[/tex] so

[tex]w'y_h=0[/tex]. Since [tex]y_h[/tex] cannot be zero, this implies

w' =0. Then, w = K (a constant). Then v' = K. So v=Kx+D where D is a constant.

So, we get that the general solution is

[tex] y = vAe^{-x} = (Kx+D)Ae^{-x} = Cxe^{-x} + Fe^{-x}[/tex] where C, F are constants.

Answer:

The mass of half a liter of water is 500g, that is, 0.5kg.

Step-by-step explanation:

Density is mass divided by the volume, that is:

[tex]d = \frac{m}{v}[/tex]

Here, we have to be careful. Since the density is in grams per cm³, m has to be in grams and v in cm³.

We have that:

[tex]d = 1[/tex]

What is the mass of half a liter of water?

One liter is 1000 cm³.

So half a liter is 1000/2 = 500 cm³, which means that [tex]v = 500[/tex]

Then

[tex]d = \frac{m}{v}[/tex]

[tex]1 = \frac{m}{500}[/tex]

[tex]m = 500[/tex]

The mass of half a liter of water is 500g, that is, 0.5kg.

Answer:

x=10 and x-7 is the answer

Step-by-step explanation:

a)2x-7=13

2x=13+7

2x=20

x=20/2

x=10

b)3x+4=25

3x=25-4

3x=21

x=21/3

x=7

i hope it will help you

Answer:

a) [tex]x=10[/tex]

b) [tex]x=7[/tex]

Step-by-step explanation:

a)

2x-7=13

Add 7 to both sides

2x=20

Divide both sides by 2

x=10

b)

3x+4=25

Subtract 4 from both sides

3x=21

Divide both sides by 3

x=7

Answer:

(a) The probability that his weight is between 150 lb and 201 lb is 0.3428.

(b) The probability that the sample mean weight is between 150 lb and 201 lb is 0.011.

(c) When redesigning the ejection seat, the probability of a single pilot is more relevant as discussed in part (a).

Step-by-step explanation:

We are given that the seat was designed for pilots weighing between 130 lb and 181 lb.

The new population of pilots has normally distributed weights with a mean of 140 lb and a standard deviation of 27.3 lb.

Let [tex]\bar X[/tex] = sample mean price for a movie in the United States

SO, X ~ Normal([tex]\mu=140,\sigma^{2} =27.3^{2}[/tex])

(a) The z-score probability distribution for the normal distribution is given by;

                              Z  =  [tex]\frac{ X-\mu}{\sigma}} }[/tex]  ~ N(0,1)

where,  [tex]\mu[/tex] = population mean weights = 140 lb

            [tex]\sigma[/tex] = standard deviation = 27.3 lb

Now, the probability that his weight is between 150 lb and 201 lb is given by = P(150 lb < X < 201 lb) = P(X < 201 lb) - P(X [tex]\leq[/tex] 150 lb)

         P(X < 201 lb) = P( [tex]\frac{ X-\mu}{\sigma}} }[/tex] < [tex]\frac{ 201-140}{27.3}} }[/tex] ) = P(Z < 2.23) = 0.9871

         P(X [tex]\leq[/tex] 150 lb) = P( [tex]\frac{ X-\mu}{\sigma}} }[/tex] [tex]\leq[/tex] [tex]\frac{ 150-140}{27.3}} }[/tex] ) = P(Z [tex]\leq[/tex] 0.37) = 0.6443

The above probability is calculated by looking at the value of x = 2.23 and x = 0.37 in the z table which has an area of 0.9871 and 0.6443.

Therefore, P(150 lb < X < 201 lb) = 0.9871 - 0.6443 = 0.3428.

(b) Let [tex]\bar X[/tex] = sample mean weight

The z-score probability distribution for the sample mean is given by;

                              Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where,  [tex]\mu[/tex] = population mean weight = 140 lb

            [tex]\sigma[/tex] = standard deviation = 27.3 lb

            n = sample of pilots = 39

Now, the probability that the sample mean weight is between 150 lb and 201 lb is given by = P(150 lb < [tex]\bar X[/tex] < 201 lb) = P([tex]\bar X[/tex] < 201 lb) - P([tex]\bar X[/tex] [tex]\leq[/tex] 150 lb)

       P([tex]\bar X[/tex] < 201 lb) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{201-140}{\frac{2.73}\sqrt{39} } }[/tex] ) = P(Z < 13.95) = 0.9999

       P([tex]\bar X[/tex] [tex]\leq[/tex] 150 lb) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] [tex]\leq[/tex] [tex]\frac{150-140}{\frac{2.73}\sqrt{39} } }[/tex] ) = P(Z [tex]\leq[/tex] 2.29) = 0.9889

Therefore, P(150 lb < [tex]\bar X[/tex] < 201 lb) = 0.9999 - 0.9889 = 0.011.

(c) When redesigning the ejection seat, the probability of a single pilot is more relevant as discussed in part (a) because it is important to look after the safety of each and every pilot not of a particular sample.

Answer: £36

Step-by-step explanation:

4 Euros = £3

48 Euros (4x12) = £36 (3x12)

Answer:

£ 36.00

Step-by-step explanation:

£ 3 = € 4

Divide both sides by 4.

£ 3/4 = € 1

1 euro is 3/4 pound.

48 × 3/4 = 36

£ 36 = € 48

48 pounds is 36 euros.

Answer:

49π m² or 153.94 m²

Step-by-step explanation:

Area of a circle: A = πr²

We are given r as 7, so simply plug it in

A = π(7)^2

A = 49π m²

Answer:

i. Only X and Y kill the bird = 2/5

ii. Only two of them kill the bird= 0.11

iii. Only Z kill the bird= 5/6

iv. Only one of them kill the bird= 1/3

v. None of them kill the bird= 0

vi. All of them kill the bird​= 1

Step-by-step explanation:

Probability of x= 3/5

Probability of y = 2/3

Probability of z = 5/6

i. Only X and Y kill the bird

= 3/5 * 2/3

= 2/5

ii. Only two of them kill the bird

=Either x and y or x and z or y and z

= 2/5 or 1/2 or 5/9

= 0.111

iii. Only Z kill the bird

= 5/6

iv. Only one of them kill the bird

= 3/5 or 2/3 or 5/6

= 1/3

v. None of them kill the bird

0

vi. All of them kill the bird​

1

Answer:

Todd is 31years old.

Step-by-step explanation:

[tex]x = 28 \\ y = \\ 28 + 3 = 31[/tex]

Answer:5. 291503

Step-by-step explanation:

√28

2√7

5. 291503

Answer:

Below in bold.

Step-by-step explanation:

A).  9.9^2 is close to 10^2 = 100

Round 1.79 to 1.8

So an estimate is 1.8 * 100

= 180.

B).  √97.5 / 1.96

( I am assuming that the square root is of 97.5 only).

is approximately equal to √100 / 2

= 10/2

= 5.

Answer:

(A)$10,500

Step-by-step explanation:

Joe contributed $6000 out of a salary of $50,000.

6% of $50,000=$3000

Since his employer matches 100% of his contributions for the first 6%:

The employer adds $3000.

For the other $3000, Jose's employer matches 50%.

Therefore, the employer adds:

50% X 3000=$1500

Total Contribution by Jose's Employer = $3000+1500=$4500

Therefore, the total amount that was contributed to Jose's account last year

=Joe's Contribution + Employer's Contribution

=6000+4500

=$10,500

The correct option is A.

The correct answer is $10,500.

Answer:

  False

Step-by-step explanation:

Dilation changes the side lengths, but not the angles. The given statement is FALSE.

Answer:

They aren't wrong. The program is.

Step-by-step explanation:

The numbers you entered are the answers that matches the correct answers. It is a program error.

Answer:

65

Step-by-step explanation:

We know that,

The Sum of all angles of the triangle is 180°.

As given in the question,

Triangle PQR is similar to Triangle WXY

Therefore ,

Let the third angle be 'x'.

35° + 80° + x = 180°

115 + x = 180°

x = 180° - 115°

x = 65°.

Hence, 65° is the appropriate answer to the question.

I hope my answer helped!!

Answer:

Answer = 27.78%

Step-by-step explanation:

There are 10 outcomes with sum 9 or higher.

There the required probability is 10/36 = 5/18 = nearly 27.78% chances of getting a sum of 9 or higher on rolling two 6-sided dice.

idk if this is correct

Answer:

B, C and D

Step-by-step explanation:

Given:

Statement: "Every integer has an additive inverse"

To find: statement that is equivalent to the given statement

Solution:

For any integer x, if [tex]x+y=0[/tex] then y is the additive inverse of x.

Here, 0 is the additive identity.

Statements ''All integers have additive inverses '', '' If x is an integer, then x has an additive inverse'' and  ''Given an integer x, there exists a y such that y is the additive inverse of x'' are equivalent to the given statement "Every integer has an additive inverse".

Answer:

He has  2,772 ways

Step-by-step explanation:

Hello,

the teacher has to choose 6 students and there are 11 students in total.

When he chooses the first student he has 11 choices

if he has to choose 1 students he has 11 ways to do it

then for the second one he has 11-1=10 choices

if he has to choose 2 students he has (11*10)/2 ways to do it (we do not count the duplicate - for instance if he chooses Steve and then Nils or Nils and then Steve this is only one group (Steve, Nils) we do not care of the order)

Then for the third student he has 10-1=9 choices

if he has to choose 3 students he has (11*10*9)/(2*3) ways to do it (we do not take into account the order of ppl in the group)

and so on and so forth

...

if he has to choose 6 students he has (11*10*9*8*7*6)/(2*3*4*5)

so he has  2,772 ways

Answer:

C. 462 is correct. I did the test.

Step-by-step explanation: