Answer:
No. At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the average number of sick days a worker takes per year is significantly less than 5.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=5\\\\H_a:\mu< 5[/tex]
The significance level is 0.01.
The sample has a size n=30.
The sample mean is M=4.8.
The standard deviation of the population is known and has a value of σ=1.2.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.2}{\sqrt{30}}=0.219[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{4.8-5}{0.219}=\dfrac{-0.2}{0.219}=-0.913[/tex]
This test is a left-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z<-0.913)=0.181[/tex]
As the P-value (0.181) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.
Using the z-distribution, it is found that since the test statistic is greater then the critical value for the left-tailed test, this is not enough evidence to support the claim at [tex]\alpja = 0.01[/tex].
At the null hypothesis, it is tested if the number of sick days is of at least 5, that is:
[tex]H_0: \mu \geq 5[/tex]
At the alternative hypothesis, we test if it is less than 5, that is:
[tex]H_1: \mu < 5[/tex]
We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
The parameters are:
[tex]\overline{x}[/tex] is the sample mean. [tex]\mu[/tex] is the value tested at the null hypothesis. [tex]\sigma[/tex] is the standard deviation of the sample. n is the sample size.For this problem, the values of the parameters are: [tex]\overline{x} = 4.8, \mu = 5, \sigma = 1.2, n = 30[/tex]
Hence, the value of the test statistic is:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{4.8 - 5}{\frac{1.2}{\sqrt{30}}}[/tex]
[tex]z = -0.91[/tex]
The critical value for a left-tailed test, as we are testing if the mean is less than a value, with a significance level of 0.01 is of [tex]z^{-\ast} = -2.327[/tex].
Since the test statistic is greater then the critical value for the left-tailed test, this is not enough evidence to support the claim at [tex]\alpja = 0.01[/tex].
A similar problem is given at https://brainly.com/question/16194574
What is the angle of rotation from figure A to figure A’? Assume that the center of rotation is the origin. A. 180° clockwise B. 90° counterclockwise C. 180° counterclockwise D. 270° counterclockwise
Answer:
B.90°counterclockwise
Answer: B
Step-by-step explanation:
A. If you rotate a figure in the first quadrant 180 degrees clockwise it will end up in the third quadrant so the answer can't be A.
B. If you rotate a figure in the first quadrant 90 degrees counterclockwise it will end up in the second quadrant because you will rotate it backwards and as you could see A prime is in the second quadrant.
C.If you rotate a figure in the first quadrant 180 counterclockwise it will end up in the third quadrant. SO the answer can't be it C.
D.If your rotate a figure in the first quadrant 270 counterclockwise it will end up in the fourth quadrant. So the answer can't be D.
Please answer this correctly
Answer:
1/2
Step-by-step explanation:
The numbers 3 or odd are 1, 3, 5, and 7.
4 numbers out of 8.
4/8 = 1/2
P(3 or odd) = 1/2
PLEASE HELP ME FOR BRAINLIEST Reduce to simplest form. 6/3+(-1/6)
Answer: 1 5/6, or 11/6, or 1.83333333
Step-by-step explanation:
[tex]\frac{6}{3} + -\frac{1}{6}[/tex]
6/3 is 2.
Thus, the answer is 2 - 1/6 or 1 5/6
Answer:
11/6
Step-by-step explanation:
First, we need to find a common denominator for the 2 fractions.
A common denominator for 3 and 6 is 6.
Let’s get the fraction 6/3 to a denominator of 6.
Multiply by 2/2
6/3 * 2/2
(6*2) / (3*2)
12/6
Now the fractions have common denominators and can be added.
12/6 + (-1/6)
When adding negative fractions, you can simply subtract.
12/6 - 1/6
Subtract across the numerator and leave the denominator as is
11/6
This fraction can be written as: 2 1/6, 11/6, or 1.83333
If (x) = 3x - 5 and g(x) = x + 3, find (f - g)(x).
O A. 8 - 2x
O B. 2x-2
O c. 2x-8
O D. 4x-2
Answer:
C
Step-by-step explanation:
(f-g)(x)=(3x-5)-(x+3) = 3x-5-x-3 = 2x-8
Answer:
2x -8
Step-by-step explanation:
f (x) = 3x - 5
g(x) = x + 3,
(f - g)(x) = 3x - 5 - ( x+3)
Distribute the minus sign
= 3x-5 -x-3
Combine like terms
= 2x -8
Find all solutions of the equation in the interval , 02π. =4cosx+−sin2x4 Write your answer in radians in terms of π. If there is more than one solution, separate them with commas.
Answer:
The answer is "2nπ".
Step-by-step explanation:
Given:
[tex]4 \cos x= -\sin^2x+4.......(1)[/tex]
We know:
[tex]\Rightarrow \sin^2 x+\cos^2 x=1\\\\\Rightarrow \sin^2 x= 1 -\cos^2 x\\[/tex]
put the value of [tex]\sin^2 x[/tex] value in the above equation:
[tex]\Rightarrow 4 \cos x= - (1-\cos^2 x)+4\\\\\Rightarrow 4 \cos x= - 1+\cos^2 x+4\\\\\Rightarrow 4 \cos x= \cos^2 x+3\\\\\Rightarrow \cos^2 x-4 \cos x+3=0\\\\[/tex]
Let [tex]\cos x= A[/tex]
[tex]\Rightarrow A^2-4A+3=0 \\ \Rightarrow A^2-(3A+A)+3=0 \\\Rightarrow A^2-3A-A+3=0\\\Rightarrow A(A-3)-1(A-3)=0\\\Rightarrow (A-3)(A-1)=0 \\[/tex]
[tex]\Rightarrow A- 3=0 \ \ \ \ \ \ \ \ \ \ \ \Rightarrow A -1 =0 \\\\[/tex]
[tex]\Rightarrow A= 3\ \ \ \ \ \ \ \ \ \ \ \Rightarrow A =1 \\\\\Rightarrow \cos x = 3\ \ \ \ \ \ \ \Rightarrow \cos x =1\\\\\Rightarrow x = \cos^{-1} 3\ \ \ \ \ \ \ \Rightarrow \cos x =\cos 0\\\\\Rightarrow x = \cos^{-1} 3\ \ \ \ \ \ \ \Rightarrow x = 0\\\\[/tex]
The value of x is [tex]2n\pi\ \ \ _{where} \ \ \ \ \ \ \ n=1, 2, 3......[/tex]
[tex]\boxed{\bold{x=2 n \pi}}[/tex]
What is the product of (2p + 7)(3p2 + 4p – 3)?
6p3 + 29p2 – 34p + 21
6p3 + 29p2 – 22p + 21
6p3 + 29p2 + 22p – 21
6p3 + 29p2 + 34p – 21'
Answer: 6p^3+29p^2+22p-21
Use the following data to compute a 98% upper confidence bound for μ1 − μ2:
m = 41
x = 42,700
s1 = 2030
n = 41
y = 36,275
s2 = 1360.
Answer:
[tex] (42700- 36275) -2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}= 5519.071[/tex]
[tex] (42700- 36275) +2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}=7330.929[/tex]
Step-by-step explanation:
For this case we have the following info given:
[tex]n_1 = 41 , \bar X_1 =42700 , s_1 = 2030[/tex]
[tex]n_2 = 41 , \bar X_2 =36375 , s_2 = 1360[/tex]
And for this case we want a 98% confidence interval. The significance would be:
[tex] \alpha= 1-0.98=0.02[/tex]
The degrees of freedom are:
[tex] df = n_1 +n_2 -2= 41+41 -2= 80[/tex]
And the critical value for this case is:
[tex] t_{\alpha/2}= 2.374[/tex]
And the confidence interval would be given by:
[tex](\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}[/tex]
And replacing we got:
[tex] (42700- 36275) -2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}= 5519.071[/tex]
[tex] (42700- 36275) +2.374 \sqrt{\frac{2030^2}{41} +\frac{1360^2}{41}}=7330.929[/tex]
Identify the slope and y-intercept of the line whose equation is given. Write the y-intercept as an ordered pair s=3/4 t+ 2
Answer:
b
Step-by-step explanation:
The slope is 3/4 and the y-intercept is y(0,2)
The slope is what we multiply by the variable ( here t) and the y-intercept is the number we add
How can you find f(2) f(x) = - 3x ^ 2 - 7
Answer:
-19Step-by-step explanation:
Plug in 2 for x.
f(2) = -3(2)² - 7
f(2) = -3(4) - 7
f(2) = -12 - 7
f(2) = -19
Choose the correct simplification of the expression (7x - 3)
(4x2 – 3x - 6). (1 point)
Answer:
Step-by-step explanation:
hello,
I assume that you want to develop the expression
[tex](7x-3)(4x^2-3x-6)=7x(4x^2-3x-6)-3(4x^2-3x-6)\\= 28x^3-21x^2-42x-12x^2+9x+18\\\\=28x^3-33x^2-33x+18[/tex]
hope this helps
I NEED HELP PLEASE, THANKS! :)
Take a look at the attachment below. It proves that the inverse of matrix P does exists, as option c,
Hope that helps!
Answer: C
Step-by-step explanation:
Given a b
c d
Multiply the reciprocal of the determinant by d -b
-c a
Determinant = ad - bc = 2(-3) - 4(1)
= -6 - 4
= -10
[tex]-\dfrac{1}{10}\left[\begin{array}{cc}-3&-4\\-1&2\end{array}\right] \\\\\\\\=\left[\begin{array}{cc}\dfrac{-3}{-10}&\dfrac{-4}{-10}\\\\\dfrac{-1}{-10}&\dfrac{2}{-10}\end{array}\right]\\\\\\\\=\left[\begin{array}{cc}\dfrac{3}{10}&\dfrac{2}{5}\\\\\dfrac{1}{10}&-\dfrac{1}{5}\end{array}\right][/tex]
A bag contains 17 counters all of different colours. Colin chooses one counter and gives it to Obi, and another counter and gives it to Zeema. In how many ways can Colin do this?
Answer:
Colin can do this is 272 ways.
Step-by-step explanation:
The first counter goes to Obi and the second to Zeema, so the order is important. This means that we use the permutations formula to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this question:
Two counters from a set of 17. So
[tex]P_{(17,2)} = \frac{17!}{(17-2)!} = 272[/tex]
Colin can do this is 272 ways.
What is the value of x to the power of 3 times y to the power of 4 when x =3 and y =0 what answer and coorect
Answer:
0
Step-by-step explanation:
The value of x to the power of 3 times y to the power of 4:
x³× y⁴when x =3 and y =0, we get below:
x³× y⁴= 3³ × 0⁴ = 0The result is zero because:
1. Any power of zero makes it zero
2. The product of numbers equal to zero if one of multiples is zero
Which list orders the sides of triangle abc from longest to shortest length?
Answer:
B
Step-by-step explanation:
the hotpotuse is always the biggest
the rest is pretty easy to determine
The orders that the sides of the triangle ABC from longest to shortest length will be AB, BC, and AC.
What is a right-angled triangle?A triangle is a polygon that has three sides and three vertices. It is one of the basic figures in geometry. A right-angled triangle is a triangle having one of its angles with a measure of 90°. The slanted side of that triangle is called Hypotenuse and it is the longest side in that triangle.
If one of the angle is of 90° then the triangle is right angled triangle.
We can see that the Hypotenuse is always the biggest side among all the sides.
Then the perpendicular side BC is the second biggest and then the base of the triangle.
Therefore, the order must be AB > BC > AC.
The orders that the sides of the triangle ABC from longest to shortest length will be AB, BC, and AC.
Learn more about right angled triangle here:
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A teacher based in California calculated a particular date in the calendar and named it Square Root Day. Try and find out why the day was named so. Can you find more such days? When was last square root day and when is next square root day
Answer:
may 5 the is squareroot day and it is when the day and the month has the first two digits in the date are the square root of the last two digits. examples 2nd February,2004 3rd March 2009 and the last time we had one was April 4th 2016. The next square root day is May 5th 2025
Please help me answer my question
Answer:
All angles in any quadrilateral adds up to 360°
Step-by-step explanation:
We can prove this by using 180(n - 2)
n = 4 for a quadrilateral
180(4 - 2)
180(2)
360°
So, 360 - (125 + 67 + 80) = 88°
Answer:
See below
Step-by-step explanation:
The interior angles of a quadrilateral (having 4 sides) add up to 360 degrees.
=> So, to find x, we'll simply subtract the rest if the angles from 360
So,
=> x = 360-125-67-80
=> x = 88 degrees
A low calorie dinner has 480 calories in an 9 ounce serving. What is the unit rate in simplest form?
Answer: 53.333333, 53 1/3
Step-by-step explanation:
The unit rate in this question means how many calories for one ounce. Thus, you can simply divide 480 by 9 to get 53.3333333
Answer:
53.33 caloriesStep-by-step explanation:
Calories in a low calorie dinner = 480 calories
Serving at one time = 9 ounce
then,
Unit rate = Amount of calories in one serving
So,
Amount of calorie in 9 serving = 480
Amount of calorie in 1 serving = 480/9
In simple form : 160/3
= 53.33 calories
Hope this helps...
Good luck on your assignment..
I NEED HELP PLEASE THANKS!
Answer: A) 0.5
Step-by-step explanation:
The denominator should be in the form 1 + e sin θ
Currently the denominator is: 2 + 1 sin θ
Divide the denominator by 2 to get: 1 + 0.5 sin θ
Thus, e = 0.5
(9-6)+12 what’s is the answer?
Answer:
15
Step-by-step explanation:
Answer: 15
Step-by-step explanation: (9-6) + 12
(3) + 12
15
What numeral is in the 100th decimal place in the decimal representation of $\frac{6}{7}$?
Answer:
5
Step-by-step explanation:
[tex]\frac{6}{7}=0.857142857142857142857142...[/tex]
Or 0.857142 with "857142" recurring.
The hundredths place is the second decimal place of a number. In this case, it would be 5.
After adding up all your expenses for the month you spent $465.36. your total budget for the month is$529.What percentage are under budget?(Round to the nearest whole percentage).Do not include symbol
Answer:
12%.
Step-by-step explanation:
It is given that, after adding up all your expenses for the month you spent $465.36. your total budget for the month is $529.
Total budget = $529
Total expenditure = $465.36
Under budget = $529 - $465.36 = $63.64
We need to find the percentage of under budget.
[tex]\%=\dfrac{\text{Under budget}}{\text{Total budget}}\times 100[/tex]
[tex]\%=\dfrac{63.64}{529}\times 100[/tex]
[tex]\%=0.12030\times 100[/tex]
[tex]\%=12.030\%[/tex]
[tex]\%\approx 12\%[/tex]
Therefore, the required percentage is 12%.
The number of people who voted in the most recent local election was up from the last local election by about 24%. Therefore the number of people who voted in this election was how many times the number who voted in the last election
Answer:
The number of people who voted in this election was 1.24 times the number who voted in the last election
Step-by-step explanation:
The multiplier for a increase of a% is 1 + a/100.
The multiplier for a decrease of b% is 1 - b/100.
In this question:
Up by about 24%, so we want the multiplier for a increase of 24%.
So
1 + (24/100) = 1 + 0.24 = 1.24
The number of people who voted in this election was 1.24 times the number who voted in the last election
Matías and José want to distribute 4.5 kilograms of lemons in 3/4 kilogram bags. How many bags will they be able to complete?
Answer:
6 bags
Step-by-step explanation:
3/4 = .75
4.5/.75 = 6 =
6 BAGS
a vertical pole stands on an horizontal ground. a student position due west of the pole observes that the angle of elevation of the top of the pole is 40 degree. when the the students moves 10 m due South. he observes that the angle of elevation of the top of the pole is 35 degrees. what is the height of the pole.
Step-by-step explanation:
|S450(2)
(3)
(4)1m3+1AB is a vertical pole with B at the ground level
and A at the top. A man finds that the angle of
elevation of the point A from a certain point C600.He moves away from the pole along the lineCD- 7m
.From D the angle of elevation of the point Aon the ground isBC to a point D such that.Then the height of the pole is (1)7/3
7/3
7/3
7/3V33+1m
i hope this help
A car is driving at 100 kilometers per hour. How far, in meters, does it travel in 3 seconds?
Answer:
The car travels 83 1/3 meters in 3 seconds.
Step-by-step explanation:
Speed of car = 100 KM/ hour
1 km= 1000m
1 hour = 3600 seconds
Lets find speed of car in Meters/second
speed of car in m/sec = 100*1000 m/3600 second
here we have taken 1000 for km and 3600 for hour
speed of car in m/sec = 100*1000 m/3600 second = 500/18 m/second
speed of car in m/sec = 250/9 m per sec
We know that
distance = speed*time
speed = 250/9 m per sec
time =3 second
distance = 250/9 * 3 meters = 250/3 meters = 83 1/3 meters.
Thus, car travels 83 1/3 meters in 3 seconds.
Hawkins Manufacturing Company produces connecting rods for 4- and 6-cylinder auto-mobile engines using the same production line. The cost required to set up the production line to produce the 4-cylinder connecting rods is $2,000, and the cost required to set up the production line for the 6-cylinder connecting rods is $3,500. Manufacturing costs are $15 for each 4-cylinder connecting rod and $18 for each 6-cylinder connecting rod. There is no production on weekends, so on Friday the line is diassembled and cleaned. On Monday, the line must be set up to run whichever product will be produced that week. Once the line has been set up, the weekly production capacities are 6000 6-cylinder connecting rods and 8000 4-cylinder connecting rods. Letx4 5 the number of 4-cylinder connecting rods produced next week x6 5 the number of 6-cylinder connecting rods produced next week s4 5 1 if the production line is set up to produce the 4-cylinder connecting rods; 0 if otherwise s6 5 1 if the production line is set up to produce the 6-cylinder connecting rods; 0 if otherwise Using the decision variables x4 and s4, write a constraint that sets next week
Complete question:
Hawkins Manufacturing Company produces connecting rods for 4- and 6-cylinder auto-mobile engines using the same production line. The cost required to set up the production line to produce the 4-cylinder connecting rods is $2,000, and the cost required to set up the production line for the 6-cylinder connecting rods is $3,500. Manufacturing costs are $15 for each 4-cylinder connecting rod and $18 for each 6-cylinder connecting rod. There is no production on weekends, so on Friday the line is diassembled and cleaned. On Monday, the line must be set up to run whichever product will be produced that week. Once the line has been set up, the weekly production capacities are 6000 6-cylinder connecting rods and 8000 4-cylinder connecting rods. Letx4 5 the number of 4-cylinder connecting rods produced next week x6 5 the number of 6-cylinder connecting rods produced next week s4 5 1 if the production line is set up to produce the 4-cylinder connecting rods; 0 if otherwise s6 5 1 if the production line is set up to produce the 6-cylinder connecting rods; 0 if otherwise
a) Using the decision variables x4 and s4, write a constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 8000 units
b) Using the decision variables x6 and s6, write a constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 6000 units
c) Write a constraint that requires that production be setup for exactly one of the two rods
d) Write the cost function to be minimized
Answer:
a) x₄ ≤ 8000s₄
b) x₆ ≤ 8000s₆
c) s₄ + s₆ = 1
d) MIN 15x₄ + 18x₆ + 2000s₄ + 3500s₆
Explanation:
a) The constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 8000 units, is written as:
x₄ ≤ 8000s₄
b) The constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 6000 units is written as:
x₆ ≤ 8000s₆
c) The constraint that requires that production be setup for exactly one of the two rods:
Since we have:
x₄ ≤ 8000s₄ ; x₆ ≤ 8000s₆
The constraint that requires that production be setup for exactly one of the two rods will be:
s₄ + s₆ = 1
d) Write the cost function to be minimized:
Since we are to find the cost function to be minimized, we take the function below:
MIN 15x₄ + 18x₆ + 2000s₄ + 3500s₆
798/8×41 rounded to one significant figure
Answer:
2.5
Step-by-step explanation:
the other persons answer is wrong
The number after rounding to the one significant figure is 4000.
What is significant figure?
The term significant figures refers to the number of important single digits (0 through 9 inclusive) in the coefficient of an expression in scientific notation
What is round off?Rounding off means a number is made simpler by keeping its value intact but closer to the next number
According to the given question we have an expression.
[tex]\frac{798}{8} (41)[/tex]
When we evaluate this expression we get
[tex]\frac{798}{8} (41)[/tex]
[tex]=99.75(41)[/tex]
[tex]= 4089.75[/tex]
Here, the first significant figure is 4 and the second one is 0 which is less than 5.
Hence, the number after rounding to the one significant figure is 4000.
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The function graphed is reflected across the x-axis to create a new function. Which is true about the domain and range of each function? Both the domain and range change. Both the range and domain stay the same. The domain stays the same, but the range changes. The range stays the same, but the domain changes.
Answer:
Domain stays the same while the range changes
Step-by-step explanation:
While reflecting cross x-axis, the x coordinates remains the same while the y-coordinate changes to its opposite.
=> x- coordinate = Domain
=> y-coordinate = Range
The domain stays the same, but the range changes. is true about the domain and range of each function. Option C is correct.
What is the domain and range of a function?Domain is the set of values for which the given function is defined.Range is the set of all values which the given function can output.
When reflecting across the x-axis, the x coordinates remain constant, but the y coordinate changes to its inverse.
The Domain represent as x-coordinate and the range as y-coordinate
The domain stays the same, but the range changes. is true about the domain and range of each function. Option C is correct.
Hence, option C is correct.
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[tex] 3 {x}^{2} - 15x = 15[/tex]
[tex]3x^2-15x= 15\\\\x^2 -5x = 5\\\\x^2-5x-5=0\\\\\Delta = 25+20\\\\\Delta = 45\\\\\\x = \dfrac{5\pm \sqrt{\Delta}}{2}\\\\\\x = \dfrac{5\pm \sqrt{45}}{2}\\\\\\x = \dfrac{5\pm 3\sqrt{5}}{2}\\\\\\[/tex]
In a basketball shooting competition there are ten balls from 1-10. The number of points earned is based on the number on the ball (I.e shoots a 7 gets 7 points), if a person misses 2 shots what number is not possible
52
44
41
38
35
The answer is 41 because all of the them are in the 7 times table .so I deducted 2 from each one of them and 41 was not part