A recipe calls for 1/3 cup of sugar for every 1/2 cup of flour. In cups, how much sugar is needed per one cup of flour?

The amount of interest that's owed by Darius after 6 months will be $14

Principal = $500

Rate = 5.6%

Time = 6 months.

Based on the information given, the simple interest will be calculated as:

Simple Interest = PRT/100

Simple Interest = ($500 × 5.6 × 1/2) / 100

Simple Interest = $1400/100

Simple Interest = $14

Therefore, the amount of interest that's owed by Darius after 6 months will be $14

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Answer:

You know that 5 g of sugar form 12%. Let x g be the amount of water needed. The total amount of syrup will be x+5 g. Then

5 g - 12%,

x+5 g - 100%.

mathematically you can write a proportion;

5/x+5=12/100

=>500=12(x+5)

,500=12x+60

,12x=400,

x=440/12

=110/3

36.66 grams of water is added  to make 12% sugar syrup using 5g sugar.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Let the amount of water is added be 'x'.

Amount of sugar = 5 g

We need to make 12% of sugar syrup.

x grams of water is added to 5 g of sugar, to 12% of sugar syrup.

5/5+x=12/100

Apply cross multiplication

5×100=12(5+x)

500=60+12x

Subtract 60 from both sides

440=12x

Divide both sides by 12

x=36.66

Hence, 36.66 grams of water is added  to make 12% sugar syrup using 5g sugar.

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Answer:

y=-3x-13

Step-by-step explanation:

Answer:

1 .  

Step-by-step explanation:        

Answer:

y = -2x + 6

Step-by-step explanation:

This has sort of the same concept as your earlier question

Use the equation y = mx + b

To find the slope, take the second y value and subtract the first y value. Then take the second x value and subtract the first x value. Divide the answers. You'd get -2 in this case. -2 would be your slope (m).

The substitute any set of x and y values (either (1, 4) or (-2, 10)) and the slope into y = mx + b. You'd get 6 as your y-intercept (b).

Answer:

B

Step-by-step explanation:

Because the the contract will be in verbal form. no matter if it is videotaped or recorded or both a "videoed verbal contract" not just written. so like paper thst is notarized or not this is still the same bc the the same rules apply the contract is still valid. the rest of the options are more like what they call gentlemens agreements which would be the handshake type of thing. and no matter what any agreement someone has to witness the transaction or contract. so definitely the answer is B

Answer:

(d+5)^2

Step-by-step explanation:

Answer:

the answer would be 6...

Answer:

Perpendicular

Answer:

The equation is y = (2/3)x + (4/3).

Step-by-step explanation:

First, you have to change the equation into slope-intecept formula to find its gradient (slope) :

[tex]3x + 2y = 12[/tex]

[tex]2y = - 3x + 12[/tex]

[tex]y = - \frac{3}{2}x + 6[/tex]

Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :

[tex]m1 \times m2 = - 1[/tex]

[tex] - \frac{3}{2} \times m2 = - 1[/tex]

[tex]m2 = - 1 \div - \frac{3}{2} [/tex]

[tex]m2 = \frac{2}{3} [/tex]

Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :

[tex]y = \frac{2}{3}x + b[/tex]

[tex]let \: x = 1,y = 2[/tex]

[tex]2 = \frac{2}{3} (1) + b[/tex]

[tex]b = 2 - \frac{2}{3} [/tex]

[tex]b = \frac{4}{3} [/tex]

[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]

I think it is A)2 because 3^2 = 9 and 9×4 = 36

Answer:

8:3

Step-by-step explanation:

The GCF of each of them is 8. Divide both of them by it you'll get the ratio

in equivalence the answer is 8 3

Answer:

my teacher has cancer please help her at #snowmanchallenge

Step-by-step explanation:

try to spread the help every snowman is ten dollars for her

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}} : [/tex]

[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

~ Plug the value of x and then multiply !

⇾ [tex] \tt{6x = 6 \times 6 \times = \boxed{36}}[/tex]

[tex] \red{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \tt{36}}}}}}[/tex]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

x [tex]\geq[/tex] 5

Step-by-step explanation:

step 1: subtract 6 from both sides

step 2: divide both sides by 7

answer: x [tex]\geq[/tex] 5

interval notation: [5,∞)

Answer:

El lado del cuadrado es de 20 my el área del cuadrado es de 400 metros cuadrados. Paso a paso ... El perímetro de un cuadrado es 80 m. ¿Cuál es la longitud de cada lado del cuadrado ... Para celosía & lt; L, * & gt; si a, b, ce L thena + (a e b) = a se llama.

Step-by-step explanation:

Answer:

r1 and r2 are the radii of two concentric circles

To find:

The length of the chord of the larger circle.

Solution:

We have given the two concentric circles which means both the circles have the same centre.

The chord of the larger circle toches the inner circle so the chord of the larger circle will be the tangent of the smaller circle.

And we know that the radius of the circle is perpendicular to the tangent of the circle.

Let 2x be the length of the chord of the circle.

r1 is the radius of the larger circle.

r2 is the radius of the smaller circle.

So by the Pythagoras theorem,

The length of the half of the chord is given by:

r1² = x² + r2²

x² = r1² - r2²

x = √r1² - r2²

So,

The length of the chord will be 2x = 2√r1² - r2² units

Step-by-step explanation:

Answer:

a) x ≤ -8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

-3 + x ≤ -11

Step 2: Solve for x

Here we see that any value x smaller than or equal to -8 would work as a solution to the inequality.

Answer:

a. Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [P(x,y)]  ∨ ∃x ∃y ¬ [Q(x,y)]

Step-by-step explanation:

a.∃x ∀y(P(x,y) → Q(x,y))

Negation = ¬ [ ∃x ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ¬ [ ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [ (P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [  ¬P(x,y)  ∨ Q(x,y) ]

                = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. ∃x ∀y(P(x,y) → P(y,x))

Negation = ¬ [ ∃x ∀y(P(x,y) → P(y,x)) ]

               = ∀x ¬ [ ∀y(P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ (P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ ( P(x,y) ∧ P(y,x) ) ∨ ( ¬P(x,y) ∧ ¬P(y,x) )]

               = ∀x ∃y ¬ [ P(x,y) ∧ P(y,x) ] ∧ ¬[ ¬P(x,y) ∧ ¬P(y,x) ]

               = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [ P(x,y) ∨ P(y,x) ]

∴ we get

Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y)

Negation = ¬ [ ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) ]

                = ¬ [ ∃x ∃y P(x,y) ]  ∨ ¬ [ ∀x ∀y Q(x,y) ]

                = ∀x¬ [  ∃y P(x,y) ]  ∨ ∃x ¬ [ ∀y Q(x,y) ]

                = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

∴ we get

Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

Answer:

Let x be your first alloy

2/5x+7/10(30-x)=1/2(30)

4x+210-7x=150

3x=60

x=20

So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy

Answer:

20 pounds for first 10 for second.

Step-by-step explanation:

First, let's write what we know.

We can represent the number of students in the play from each class as L, G, and C. We know that L = 7, and if Gardener has 4 more students than Cho, then G = C + 4.

Then, taking the third line, we can write an inequality:

C < L < G

C < 7 < C + 4

C - 4 < 3 < C

3 < C < 7

If C is greater than 3 and less than 7 and is an integer, than means C is 4, 5, or 6.

Then, we need to find how many students are in the play.

C + L + G

C + 7 + C + 4

2C + 11

So we have our expression for the number of students in the play. Then, we need to find the total number of students. We know that 2C + 11 will be 30% of the total, so if T is the total, we can find T.

0.3T = 2C + 11

(Divide by 3/10 or multiply by 10/3 on both sides)

T = 20/3 C + 110/3

We know from before that C is 4, 5 or 6. We can plug these into our equation here to find which one produces a whole number.

T = 20/3 * 4 + 110/3

T = 190/3

T = 20/3 * 5 + 110/3

T = 210/3

T = 70

T = 20/3 * 6 + 110/3

T = 230/3

We can see here that only when C is 5 will the total be a whole number. That means Mrs. Cho has 5 students in the play. If Mrs. Gardner has 4 more than that, she has 9 students in the play in her class.  We now need to figure out the number of student in her class.

The total students are Cho's, Logan's, and Gardner's classes added together. We know that Logan's class is 23 students, so if we subtract that from the total, we can see that Cho's and Gardner's class have 47 students. If Mrs. Cho has 24 students in her class, we can subtract that from the 47, so we know that Mrs. Gardner has 23 students in her class.

Answer:

x = 3

Step-by-step explanation:

MN is exactly half of 6x + 2 (midpoint theorem)

2(2x + 4) = 6x + 2

4x + 8 = 6x + 2

-2x + 8 = 2

-2x = -6

x = 3

Answer: She invested $5000 in an account that pays 6% interest and $10000 in an account that pays 7% interest.

Step-by-step explanation:

Let P be the initial amount she invested in an account that pays 6% interest.

Then, amount invested in other account = 2P

Simple interest = Principal x rate x time

After one year, for the first account,

Interest = P(0.06)(1)  = 0.06P

For second account,

Interest = (2P)(0.07)(1)=0.14P

Total interest = [tex]0.06P+0.14P=1000[/tex]

[tex]\Rightarrow\ 0.20P=1000\\\\\Rightarrow\ P=\dfrac{1000}{0.20}\\\\\Rightarrow\ P=5000[/tex]

2P = 2(5000)=10000

Hence, She invested $5000 in an account that pays 6% interest and $10000 in an account that pays 7% interest.

At the interest rate of 6%, amount invested is; $5000

At interest rate of 7%, amount invested is; $10000

Let P be the initial amount that Ms. Hagan invested in the 6% interest account that

Since she invested twice as much in the 7% interest account as in the 6% interest account, then;

Initial amount invested in the 7% interest account = 2P

Formula for Simple interest is;

I = Principal × rate × time

Interest after 1 year for the 6% interest account is,

I_1 = P × 0.06 × 1

I_1 = 0.06P

Interest after 1 year for the 7% interest account is,

I_2 = 2P × 0.07 × 1

I_2 = 0.14P

Total investment pays her $1000 after a year. Thus;

0.06P + 0.14P = 1000

0.2P = 1000

P = 1000/0.2

P = $5000

Then amount initially invested in the 7% interest account = 2P = $10000

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Answer:

-10

Step-by-step explanation:

Answer:

= -10

Step-by-step explanation:

-7 + (-3)

=

-7 - 3

-10

Answer:

[tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Step-by-step explanation:

Given:

[tex](x+2)^2+(y-3)^2=16\\x+y-1=0[/tex]

To find: value of [tex]x,y[/tex]

Solution:

[tex](x+2)^2+(y-3)^2=16\,\,\,...(i)\\x+y-1=0\,\,\,(ii)[/tex]

From (ii),

[tex]x=1-y[/tex]

Put this value of [tex]x[/tex] in (i)

[tex](1-y+2)^2+(y-3)^2=16\\(3-y)^2+(y-3)^2=16\\(y-3)^2+(y-3)^2=16\\2(y-3)^2=16\\(y-3)^2=8[/tex]

[tex]y-3=[/tex] ± [tex]\sqrt{8}[/tex] = ± [tex]2\sqrt{2}[/tex]

[tex]y=3[/tex] ± [tex]2\sqrt{2}[/tex]

At [tex]y=3[/tex] + [tex]2\sqrt{2}[/tex] ,

[tex]x=1-(3+2\sqrt{2})=1-3-2\sqrt{2}=-2-2\sqrt{2}[/tex]

At [tex]y=3-2\sqrt{2}[/tex] ,

[tex]x=1-(3-2\sqrt{2})=1-3+2\sqrt{2}=-2+2\sqrt{2}[/tex]

Solutions are [tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Answer: 12≠6

False

Step-by-step explanation:

Answer:

volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( [tex]\frac{-b}{a}[/tex]x + b )² dx

Step-by-step explanation:

Given the data in the question and as illustrated in the image below;

R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)

from the image;

the equation of AB will be;

y-b / b-0 = x-0 / 0-a

(y-b)(0-a) = (b-0)(x-0)

0 - ay -0 + ba = bx - 0 - 0 + 0

-ay + ba = bx  

ay = -bx + ba

divide through by a

y = [tex]\frac{-b}{a}[/tex]x + ba/a

y = [tex]\frac{-b}{a}[/tex]x + b

so R is bounded by  y = [tex]\frac{-b}{a}[/tex]x + b and y =0, 0 ≤ x ≤ a

The volume of the solid revolving R about x axis is;

dv = Area × thickness

= π( Radius)² dx

= π ( [tex]\frac{-b}{a}[/tex]x + b )² dx

V = π ₀∫^a ( [tex]\frac{-b}{a}[/tex]x + b )² dx

Therefore,  volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( [tex]\frac{-b}{a}[/tex]x + b )² dx

The volume of the solid generated when region R is revolved about the x-axis is [tex]\frac{b^{5} }{3a^{2} }[/tex].

Equation of the line AB

[tex]y-0 = \frac{b-0}{0-a} (x-a)[/tex]

[tex]y = \frac{-b}{a} (x-a)[/tex]

The volume generated when a curve f(x) is rotated about the x-axis in x∈(c,d) is given by:

[tex]V=\int\limits^d_c {y^2} \, dx[/tex]

So, the volume generated when line AB is rotated about the x-axis will be [tex]V=\int\limits^b_0 ({\frac{-b}{a} (x-a))^2} \, dx[/tex]

[tex]V=\frac{b^{5} }{3a^{2} }[/tex]

Therefore, the volume of the solid generated when region R is revolved about the x-axis is [tex]\frac{b^{5} }{3a^{2} }[/tex].

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Answer:

60 divided by 8

Step-by-step explanation:

60 divided by 8

Answer:

what do you mean?

Step-by-step explanation: