A professional employee in a large corporation receives an average of μ = 39.8 e-mails per day. Most of these e-mails are from other employees in the company. Because of the large number of e-mails, employees find themselves distracted and are unable to concentrate when they return to their tasks. In an effort to reduce distraction caused by such interruptions, one company established a priority list that all employees were to use before sending an e-mail. One month after the new priority list was put into place, a random sample of 38 employees showed that they were receiving an average of x = 33.1 e-mails per day. The computer server through which the e-mails are routed showed that σ = 16.2. Has the new policy had any effect? Use a 10% level of significance to test the claim that there has been a change (either way) in the average number of e-mails received per day per employee.

Answer:

The length of the short side is 14.5 units, the length of the other short side is 18.5 units, and the length of the longest side is 23.5 units.

Step-by-step explanation:

The Pythagorean Theorem

If a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse, then the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse.

This relationship is represented by the formula:

                                                     [tex]a^2+b^2=c^2[/tex]

Applying the Pythagorean Theorem  to find the lengths of the three sides we get:

[tex](x)^2+(x+4)^2=(x+9)^2\\\\2x^2+8x+16=x^2+18x+81\\\\2x^2+8x-65=x^2+18x\\\\2x^2-10x-65=x^2\\\\x^2-10x-65=0[/tex]

Solve with the quadratic formula

[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}[/tex]

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]\mathrm{For\:}\quad a=1,\:b=-10,\:c=-65:\quad x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}\\\\x_{1}=\frac{-\left(-10\right)+ \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5+3\sqrt{10}\\\\x_{2}=\frac{-\left(-10\right)- \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5-3\sqrt{10}[/tex]

Because a length can only be positive, the only solution is

[tex]x=5+3\sqrt{10}\approx 14.5[/tex]

The length of the short side is 14.5, the length of the other short side is [tex]14.5+4=18.5[/tex], and the length of the longest side is [tex]14.5+9=23.5[/tex].

Answer:

a) The volume of the wooden block is 240 cm^3.

b) The density of the wooden block is 0.7 g/cm^3.

Step-by-step explanation:

The volume of the rectangular wooden block can be calculated as the multiplication of the length in each dimension: length, wide and height.

With dimensions 10 cm x 3 cm x 8 cm, the volume is:

[tex]V=L\cdot W\cdot H = 10\cdot 3\cdot 8=240[/tex]

The volume of the wooden block is 240 cm^3.

If we know that the mass of the wooden block is 168 g, we can calculate the density as:

[tex]\rho = \dfrac{M}{V}=\dfrac{168}{240}=0.7[/tex]

The density of the wooden block is 0.7 g/cm^3.

Step-by-step explanation:

can u give image PlZzzzz ....

Answer:

Hey!

Your answer should be Y=2x+4

Step-by-step explanation:

Hope this helps!

Answer:

[tex]\boxed{\df\ \dfrac{-19}{2}}[/tex]

Step-by-step explanation:

Hi,

x=-2

it gives

9*(-2)-4y=20

<=> -18-4y=20

<=> 18-18-4y=20+18=38

<=> -4y=38

<=> y = -38/4=-19/2

hope this helps

Step-by-step explanation:

solve f(x) by supposing it has y and and then interchange it with x .

hope this is helpful

Answer:

The answer is given below

Step-by-step explanation:

1) Find the possible ones place digit in the square root of the following

a) 2039184

The number 2039184 ends with 4, therefore the square root of the number can either end in 2 or 8

2² = 4, √4 = 2

8² = 64, √64 = 8

b) 10,004,569

The number 10,004,569 ends with 9, therefore the square root is the number will end in 3

3² = 9, √9 = 3

2) How many natural numbers lie between the squares of 41 and 42

42² = 1764 and 41² = 1681

Therefore the numbers that lie between 1764 and 1681 = (1764 - 1681) - 1 = 83 - 1 = 82

3) What will be the value of ‘ x’ in Pythagorean triplet (41, 9, x)

Pythagorean consist of three positive numbers a, b, c such that a² + b² = c². Therefore: x² + 9² = 41²

x² = 41² - 9² = 1681 - 81

x² = 1600

x = √1600 = 40

4) Check whether 15028 is a perfect square

15028 = 2 × 2 × 13 × 17 × 17

15028 = 2² × 13 × 17²

It is not a perfect square. If it is divided by 13 it becomes a perfect square, that is:

15028/13 = 2² × 17²

15028/13 = (2 × 17)² = 34²

34² = 15028/13

34² = 1156

The square root of the new number formed is 34 (i.e √1156)

5) A gardener has 5190 plants. He wants to plant in such a way that the number of rows and columns remains the same.

let the number if rows be x. Since the rows and columns are the same, the number of columns = x.

x² = 5190

x = √5190 = 72² + 6.

Therefore at least six plant would be left out

Answer:

It is a probability sample because it utilizes some form of random selection. It is not a simple random sample because there is not an equal possibility of A, B, or C.

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

You can remove one or more of the other color marbles to increase the probability of drawing a green marble

or

You can add  one or more green marbles to have more green marbles in the bag

Answer:

a. 0.4772 = 47.72 %

b. 0.7605 = 76.05 %

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

a. ind the least proportion of data falls between 70 and 80 If the histogram is bell shaped:

So for 70 copies we have:

z = (70 - 70) / (5)

z = 0

and this value represents 0.5

So for 80 copies we have:

z = (80 - 70) / (5)

z = 2

and this value represents 0.9772

p (70 > x > 80) = 0.9772 - 0.5

p (70 > x > 80) = 0.4772 = 47.72 %

b.  Find the proportion of data between 65 and 77

So for 65 copies we have:

z = (65 - 70) / (5)

z = -1

and this value represents 0.1587

So for 77 copies we have:

z = (77 - 70) / (5)

z = 1.4

and this value represents 0.9192

p (65 > x > 77) = 0.9192 - 0.1587

p (65 > x > 77)  = 0.7605 = 76.05 %

Answer:

C.

Step-by-step explanation:

Perpendicular ⇒ So the slope will be the negative reciprocal to this slope

Slope = m = 2

Point = (x,y) = (4,-8)

So, x = 4, y = -8

Putting in the slope-intercept form

[tex]y = mx+b[/tex]

-8 = (2)(4) + b

b = -8-8

b = -16

Now we'll put it in the slope-intercept form

y = 2x-16

=> y = 2x-8-8

=> y+8 = 2(x-4)

Answer:

Option B

Step-by-step explanation:

The number that had never been married will vary in each sample due to the random selection of adults.

This number will vary in each sample to the random selection process but they might or might not be as close as possible to one another after sampling.

Answer:

The answer is A) -9.7 > -18.2

Step-by-step explanation:

This is because, when you are thinking about negative numbers, the closer they are to 0, the greater they are. So, it is warmer in Minnesota.

Answer:

A and A

Step-by-step explanation:

Answer:

a. p=0.562

b. E = 0.0253

c. The 90% confidence interval for the population proportion is (0.537, 0.587).

d. We have 90% confidence that the interval (0.537, 0.587) contains the true value of the population proportion.

Step-by-step explanation:

We have to calculate a 90% confidence interval for the proportion.

The sample proportion is p=0.562.

[tex]p=X/n=583/1038=0.562[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.562*0.438}{1038}}\\\\\\ \sigma_p=\sqrt{0.000237}=0.0154[/tex]

The critical z-value for a 90% confidence interval is z=1.645.

The margin of error (MOE) can be calculated as:

[tex]MOE=z\cdot \sigma_p=1.645 \cdot 0.0154=0.0253[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=p-z \cdot \sigma_p = 0.562-0.0253=0.537\\\\UL=p+z \cdot \sigma_p = 0.562+0.0253=0.587[/tex]

The 90% confidence interval for the population proportion is (0.537, 0.587).

We have 90% confidence that the interval contains the true value of the population proportion.

Answer:

-45/2 - 12/2 = -57/2

Step-by-step explanation:

Substitute 15 for x in the given equation:  y = (-3/2)x - 6 becomes

y = (-3/2)(15) - 6 = -45/2  -  6 when x = 15.  This is equivalent to -57/2

Answer:

a = T - 4

Step-by-step explanation:

Simply just subtract 4 on both sides to get the answer!

Answer:

a=T-4

Step-by-step explanation:

subtract 4

Answer:

367.75

Step-by-step explanation:

21+23.3+323.45

Add the three terms.

= 367.75

The sum of theses numbers is 367.75.

Answer:

[tex]= 367.75 \\ [/tex]

Step-by-step explanation:

[tex] \: \: \: \: \: \: \: \: \: 21 \\ + \: \: \: \: 23.3 \\ = \: \: 44.3 \\ + 323.45 \\ = 367.75[/tex]

Step-by-step explanation:

y=7x-10

Answer:

[tex]\huge \boxed{y=7x-10}[/tex]

Step-by-step explanation:

[tex]-7x+y=-10[/tex]

[tex]\sf Add \ 7x \ on \ both \ sides.[/tex]

[tex]-7x+y+7x=-10+7x[/tex]

[tex]y=7x-10[/tex]

Answer: 41 candles

Step-by-step explanation:

Multiply the dimensions of the candle first.

V = l*w*h

7 * 2 = 14

14 * 10 = 140

Now, divide the total amount of wax used by the amount of wax used for one candle.

5,740 / 140 = 41

Answer:

The probability that at exactly one of them does exactly two language classes is 0.32.

Step-by-step explanation:

We can model this variable as a binomial random variable with sample size n=2.

The probability of success, meaning the probability that a student is in exactly two language classes can be calculated as the division between the number of students that are taking exactly two classes and the total number of students.

The number of students that are taking exactly two classes is equal to the sum of the number of students that are taking two classes, minus the number of students that are taking the three classes:

[tex]N_2=F\&S+S\&G+F\&G-F\&S\&G=12+4+6-2=20[/tex]

Then, the probabilty of success p is:

[tex]p=20/100=0.2[/tex]

The probability that k students are in exactly two classes can be calcualted as:

[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{2}{k} 0.2^{k} 0.8^{2-k}\\\\\\[/tex]

Then, the probability that at exactly one of them does exactly two language classes is:

[tex]P(x=1) = \dbinom{2}{1} p^{1}(1-p)^{1}=2*0.2*0.8=0.32\\\\\\[/tex]

Answer:

a) [tex]t = 1\,s[/tex], [tex]\dot A \approx 22619.467\,\frac{cm^{2}}{s}[/tex], b) [tex]t = 3\,s[/tex], [tex]\dot A \approx 67858.401\,\frac{cm^{2}}{s}[/tex], c) [tex]t = 5\,s[/tex], [tex]\dot A \approx 113097.336\,\frac{cm^{2}}{s}[/tex]. The rate at which the area within the circle is increasing linearly inasmuch as time passes by.

Step-by-step explanation:

The area of a circle is described by the following formula:

[tex]A = \pi \cdot r^{2}[/tex]

Where:

[tex]A[/tex] - Area, measured in square centimeters.

[tex]r[/tex] - Radius, measured in centimeters.

Since circular ripple is travelling outward at constant speed, radius can be described by the following equation of motion:

[tex]r (t) = \dot r \cdot t[/tex]

Where:

[tex]\dot r[/tex] - Speed of the circular ripple, measured in centimeters per second.

[tex]t[/tex] - Time, measured in seconds.

The rate of change of the circle is determined by deriving the equation of area and replacing radius with the function in terms of the speed of the circular ripple and time. That is to say:

[tex]\dot A = 2\cdot \pi \cdot r \cdot \dot r[/tex]

[tex]\dot A = 2 \cdot \pi \cdot \dot r^{2}\cdot t[/tex]

Where:

[tex]\dot A[/tex] - Rate of change of the circular area, measured in square centimeters per second.

[tex]\dot r[/tex] - Speed of the circular ripple, measured in centimeters per second.

[tex]t[/tex] - Time, measured in seconds.

If [tex]\dot r = 60\,\frac{cm}{s}[/tex], then:

a) [tex]t = 1\,s[/tex]

[tex]\dot A = 2\cdot \pi \cdot \left(60\,\frac{cm}{s} \right)^{2}\cdot (1\,s)[/tex]

[tex]\dot A \approx 22619.467\,\frac{cm^{2}}{s}[/tex]

b) [tex]t = 3\,s[/tex]

[tex]\dot A = 2\cdot \pi \cdot \left(60\,\frac{cm}{s} \right)^{2}\cdot (3\,s)[/tex]

[tex]\dot A \approx 67858.401\,\frac{cm^{2}}{s}[/tex]

c) [tex]t = 5\,s[/tex]

[tex]\dot A = 2\cdot \pi \cdot \left(60\,\frac{cm}{s} \right)^{2}\cdot (5\,s)[/tex]

[tex]\dot A \approx 113097.336\,\frac{cm^{2}}{s}[/tex]

The rate at which the area within the circle is increasing linearly inasmuch as time passes by.

Answer:

30

Step-by-step explanation:

Answer:

It would decrease by 9.

Step-by-step explanation:

52 is the original mean or the initial mean.

43 is the final mean.  

52-43 = 9

So 9 is the difference.

Hope this helped!

Answer:

t = 0

Before it starts rushing that's when it will be fastest

Step-by-step explanation:

For the water ib the tank to flow very fast it means that there is a big volume of water present.

And for volume of water to be present that much it means that the water must

have not leaked much or at all.

And for that it signifies large volume of water.

If we do the calculation we'd see that time will be actually equal to zero for the pressure and the volume of the water to be biggest.

V = 4500 (1 − 1 /50 t )^2

V = 4500

4500 = 4500(1- 1/50t)²

1 = 1- 1/50t

0 = -1/50t

t = 0

Answer:

Considering the audience helps a writer identify the types of details and language needed in the writing. Considering the audience helps the writer identify what is important to him or her. Considering the audience allows the writer to write about what he or she wants. Knowing the audience for a particular essay is important because it determines the content that will appear in the writing. If you are arguing for a change to occur, identifying the level at which you want this change to occur and/or the people you want to persuade to help create this change (audience) is important step by step

Answer:

m∠AOC= 120°

, m∠BOD = 130°

m∠COE = 110°

m∠COD.= 60°

Step-by-step explanation:

Let's note that

AOF = COD= 60°

BOC = FOE= 70°

AOB = DOE= 50°

Given: m∠AOB=50°, m∠FOE=70°. m∠AOC

, m∠BOD,

m∠COE

m∠COD. = AOF = (360-(2(70)+2(50)))/2

AOF = (360-240)/2

AOF = 120/2

AOF = 60°= COD

COE = COD+DOE= 60+50= 110°

BOD = BOC + COD = 70+60= 130°

AOC = AOB + BOC = 50+70 = 120°

Answer:

See explanation below.

Step-by-step explanation:

Let's take P as the proportion of new candidates between 30 years and 50 years

A) The null and alternative hypotheses:

H0 : p = 0.5

H1: p < 0.5

b) Type I error, is an error whereby the null hypothesis, H0 is rejected although it is true. Here, the type I error will be to conclude that there was age discrimination in the hiring process, whereas it was fair and random.

ie, H0: p = 0.5, then H0 is rejected.

f(x) = 6-5x

y = 6-5x .... replace f(x) with y

x = 6-5y .... swap x and y; solve for y

x+5y = 6

5y = 6-x

y = (6-x)/5

[tex]f^{-1}(x) = \frac{6-x}{5}[/tex] ... replace y with the inverse function notation

The missing part in the question;

and the payoff is $2.20 won for every dollar bet. (As the player’s probability of winning in this case is [tex]\dfrac{1}{4}[/tex]........

Also:

For such a bet, the casino pays off as shown in the following table.

The table can be shown as:

Keno Payoffs in 10 Number bets

Number of matches        Dollars won for each $1 bet

0  -   4                                        -1

5                                                  1

6                                                  17

7                                                  179

8                                                 1299

9                                                 2599

10                                               24999

Answer:

Step-by-step explanation:

Given that:

Twenty numbers are selected at random by the casino from the set of numbers 1 through 80

A player can select from 1 to 15 numbers; a win occurs if some fraction of the player’s chosen subset matches any of the 20 numbers drawn by the house

Let assume X to represent the numbers of player chooses which are in the Casino-selected-set of 20.

Let assume the random variable X has a hypergeometric distribution with parameters  N= 80 and m =20.

Then, the probability mass function of a hypergeometric distribution can be defined as:

[tex]P(X=k)=\dfrac{(^m_k)(^{N-m}_{n-k})}{(^N_n)}, k =1,2,3 ... n[/tex]

Now; the probability that i out of  n numbers chosen by the player among 20  can be expressed as:

[tex]P(X=k)=\dfrac{(^{20}_k)(^{60}_{n-k})}{(^{80}_n)}, k =1,2,3 ... n[/tex]

Also; given that ; When the player selects 2 numbers, a payoff (of odds) of $12 won for every $1 bet is made when both numbers are among the 20

So; n= 2; k= 2

Then :

Probability P ( Both number in the set 20)  [tex]=\dfrac{(^{20}_2)(^{60}_{2-2})}{(^{80}_2)}[/tex]

Probability P ( Both number in the set 20) [tex]= \dfrac{20*19}{80*79}[/tex]

Probability P ( Both number in the set 20) [tex]=\dfrac{19}{316}[/tex]

Probability P ( Both number in the set 20) [tex]=\dfrac{1}{16.63}[/tex]

Thus; the payoff odd for [tex]=\dfrac{1}{16.63}[/tex] is 16.63:1 ,as such fair payoff in this case is $16.63

Again;

Let assume X to represent the numbers of player chooses which are in the Casino-selected-set of 20.

Let assume the random variable X has a hypergeometric distribution with parameters  N= 80 and m =20.

The probability mass function of the hypergeometric distribution can be defined as :

[tex]P(X=k)=\dfrac{(^m_k)(^{N-m}_{n-k})}{(^N_n)}, k =1,2,3 ... n[/tex]

Now; the probability that i out of  n numbers chosen by the player among 20  can be expressed as:

[tex]P(n,k)=\dfrac{(^{20}_k)(^{60}_{n-k})}{(^{80}_n)}, k =1,2,3 ... n[/tex]

From the table able ; the expected payoff can be computed as shown in the attached diagram below. Thanks.

Answer:

The formula is 1/2h(a+b)

h stands for the perpendicular height

a and b stand for the two horizontal lengths which are parallel to each other

Answer:x>-1

Step-by-step explanation:

Step 1: Subtract 3 from both sides.

-3x+3-3<6-3

-3x<3

Step 2: Divide both sides by -3.

-3x/-3<3/3

X>-1

Answer:

See the answers below.

Step-by-step explanation:

[tex]a.\:\frac{f\left(x\right)-f\left(a\right)}{x-a}=\frac{2x^2-x-5-\left(2a^2-a-5\right)}{x-a}\\\\=\frac{2x^2-x+a-2a^2}{x-a}\\\\=\frac{2\left(x+a\right)\left(x-a\right)-1\left(x-a\right)}{x-a}\\\\=\frac{\left(x-a\right)\left[2\left(x+a\right)-1\right]}{x-a}\\\\=2x+2a-1\\\\\\b.\:\frac{f\left(x+h\right)-f\left(x\right)}{h}=\frac{2\left(x+h\right)^2-\left(x+h\right)-5-\left(2x^2-x-5\right)}{h}\\\\=\frac{2\left(x^2+2xh+h^2\right)-\left(x+h\right)-5-\left(2x^2-x-5\right)}{h}\\[/tex]

Expand and simplify to get:

[tex]=\frac{2h^2+4xh-h}{h}\\\\=\frac{h\left(2h+4x-1\right)}{h}\\\\=2h+4x-1[/tex]

Best Regards!