Answer:
The probability of randomly selecting someone who does not believe that Marilyn Monroe had an affair with JFK is P=0.3061.
Step-by-step explanation:
The probability of randomly selecting someone who does not believe that Marilyn Monroe had an affair with JFK is calculated as the complement of the probability of randomly selecting someone who does believe that Marilyn Monroe had an affair with JFK. This last value is the one estimated from the poll: 0.6939.
Then, the probability of randomly selecting someone who does not believe that Marilyn Monroe had an affair with JFK is:
[tex]P=1-0.6939=0.3061[/tex]
What is the product -3 1/3of -8 7/10 and ?
Answer:
Brainliest!!!
Step-by-step explanation:
See picture!!
Answer:
29
Step-by-step explanation:
Fraud detection has become an indispensable tool for banks and credit card companies to combat fraudulent credit card transactions. A fraud detection firm has detected some form of fraudulent activities in 2%, and serious fraudulent activities in 0.75% of transactions. Assume that fraudulent transactions remain stable.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
Answer:
a) 35.17% probability that fewer than 2 out of 110 transactions are fraudulent
b) 81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
Step-by-step explanation:
For each transaction, there are only two possible outcomes. Either they are fradulent(or seriously fraudulent), or they are not. Transactions are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
2% are fraudulent, so [tex]p = 0.02[/tex]
110 transactions, so [tex]n = 110[/tex]
This is
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{110,0}.(0.02)^{0}.(0.98)^{110} = 0.1084[/tex]
[tex]P(X = 1) = C_{110,1}.(0.02)^{1}.(0.98)^{109} = 0.2433[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.1084 + 0.2433 = 0.3517[/tex]
35.17% probability that fewer than 2 out of 110 transactions are fraudulent.
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
0.75% are seriously fraudulent, so [tex]p = 0.0075[/tex]
105 transactions, so [tex]n = 105[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
[tex]P(X = 0) = C_{105,0}.(0.0075)^{0}.(0.9925)^{105} = 0.4536[/tex]
[tex]P(X = 1) = C_{105,1}.(0.0075)^{1}.(0.9925)^{104} = 0.3599[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.4536 + 0.3599 = 0.8135[/tex]
81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes. What is the probability that the mail arrival time is more than 25 minutes on a given day? Answer: (Round to 2 decimal places.)
Answer:
0.5
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X higher than x is given by the following formula.
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes.
This means that [tex]a = 5, b = 45[/tex].
What is the probability that the mail arrival time is more than 25 minutes on a given day?
[tex]P(X > 25) = \frac{45 - 25}{45 - 5} = 0.5[/tex]
So the probability that the mail arrival time is more than 25 minutes on a given day is 0.5.
Three support beams for a bridge form a pair of complementary angles. Find the measure of each angle. If (3x+3) (5x-9)
Answer:
39 degrees and 51 degrees respectively.
Step-by-step explanation:
Two angles are complementary if their sum adds up to 90 degrees.
Given the pair of complementary angles formed by the three support beams:
3x+3 and 5x-9
Then:
3x+3+5x-9=90 degrees
Collect like terms
3x+5x=90+9-3
8x=96
Divide both sides by 8
x=12
Therefore, the measure of each angle is:
[tex](3x+3)=3(12)+3=36+3=39^\circ\\(5x-9)=5(12)-9=60-9=51^\circ[/tex]
The measure of each angle is 39 degrees and 51 degrees respectively.
Answer:
39 and 51 degrees
Step-by-step explanation:
Once a fire is reported to a fire insurance company, the company makes an initial estimate, X, of the amount it will pay to the claimant for the fire loss. When the claim is finally settled, the company pays an amount, Y, to the claimant. The comapny has determined that X and Y have the joint density functionf(x,y) = Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
Answer:
The probability that the final settlement amount is between 1 and 3 given that the initial claim is 2 = (2/9) = 0.2222
Step-by-step explanation:
The complete question is presented in the attached image to this solution
The joint probability distribution is given as
f(x, y) = {2/[x²(x - 1)} × y^-[(2x-1)/(x-1)] for x>1 And y>1
Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
That is, x = 2, and y ranges from 1 to 3
Inserting x = 2 into the expression, we obtain
f(y) = (1/2) × y⁻³ = (y⁻³/2)
The required probability would then be
P(1 < y ≤ 3) = ∫³₁ f(y) dy
= ∫³₁ (y⁻³/2) dy
= [y⁻²/-4]³₁
= [3⁻²/-4] - [1⁻²/-4]
= (-1/36) - (-1/4)
= (1/4) - (1/36)
= (8/36)
= (2/9) = 0.2222
Hope this Helps!!!
Suppose we want to study the weekly rate of alcohol drinking among USF undergraduate students. Which of the following would be the LEAST preferred method of randomly selecting participants?
A. Selecting a random sample of students from each residence hall
B. Selecting a random sample of students from the list of all undergraduate students from the university's registrar office
C. Selecting a random sample of students who have used the university health services in the past month
D. Selecting a random sample of students from each college
Answer:
Option D
Step-by-step explanation:
I think the least preferred method the researcher would like is to select a random sample of students from each college. This means the researcher would have to go to every college and randomly selects participants which is very exhausting. Thus, this would be the least prefer method over the others...
Google I would like to purchase 10 bags of chicken wings the store is selling three bags for $51.00 what is the cost of 10 bags of chicken wings
a. 61.00
b. 71.00
c. 170.00
d. 130.00
Answer:
A 61.00
Step-by-step explanation:
51 Added to 10 Equals 61.00 which is the Cost of 10 Bags of chicken Wings. Your Welcome.
Information about five planets is shown in the table below.
Planet Diameter (km) Mass (kg)
Mercury 4.88 x 10 3.3 x 1023
Jupiter 1.43 x 10 1.898 x 1027
Earth
1.28 104 5.97 x 1024
Mars
6.78 x 103 6.42 x 1023
Saturn
1.21 10% 5.68 x 1026
a) Write down the name of the planet with the greatest mass.
b) Work out the radius of Mercury giving your answer as an ordinary number.
c) Work out the difference between the masses of Jupiter and Saturn.
Give your answer in standard form.
Answer:
(a)Jupiter
(b)24.4 km
(c)[tex]1.33 \times 10^{27}$ kg[/tex]
Step-by-step explanation:
Part A
The planet with the greatest ma.ss is Jupiter.
It has a ma.ss of [tex]1.898 X 10^{27}$ kg[/tex]
Part B
The diameter of Mercury = 4.88 X 10
Radius = Diameter/2
Therefore:
Radius of Mercury
[tex]=\dfrac{4.88 X 10}{2}\\ =2.44 X 10\\=24.4$ km[/tex]
Part C
[tex]M$a.ss of Saturn = 5.68 X 10^{26}\\$Mass of Jupiter = 1.898 X 10^{27}\\$Difference in their ma.ss =(1.898 X 10^{27})-(5.68 X 10^{26})\\=1.33 \times 10^{27}$ kg[/tex]
Please answer this correctly
Answer:
33.3%
Step-by-step explanation:
The numbers greater than 6 from the spinner are 7 and 8.
2 numbers out of total 6 numbers.
2/6 = 1/3
= 0.333
= 33.3%
Write an equation for a polynomial function that has the given roots
-2. 3i , and 5
Answer:
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
Step-by-step explanation:
If 3i is one root then another is -3i.
In factor form we have:
(x + 2)(x - 5)(x - 3i)(x + 3i) = 0
(x^2 - 3x - 10)(x^2 -9i^2) = 0
(x^2 - 3x - 10)(x^2 + 9) = 0
x^4 + 9x^2 - 3x^3 - 27x - 10x^2 - 90 = 0
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
Please answer this correctly
Answer:
# of plants # of gardens
10-14 2
15-19 2
20-24 5
25-29 3
30-34 3
35-39 5
40-44 4
Step-by-step explanation:
10-14: 10, 12 (2 numbers)
15-19: 18, 19 (2 numbers)
20-24: 20, 22, 23, 24, 24 (5 numbers)
25-29: 25, 27, 38 (3 numbers)
30-34: 31, 33, 33 (3 numbers)
35-39: 36, 36, 36, 37, 38 (5 numbers)
40-44: 40, 44, 44, 44 (4 numbers)
Answer:
10-14 ⇒ 2
15-19 ⇒ 2
20-24 ⇒ 5
25-29 ⇒ 3
30-34 ⇒ 3
35-39 ⇒ 5
40-44 ⇒ 4
A regression model involved 18 independent variables and 200 observations. The critical value of t for testing the significance of each of the independent variable's coefficients will have:__________. a) 18 degrees of freedom b) 200 degrees of freedom c) 199 degrees of freedom d) 181 degrees of freedom
Answer:
The correct answer to the following question will be Option d (181 degrees of freedom).
Step-by-step explanation:
The given values are:
Regression model,
n = 200
Observations,
p = 18
Now,
⇒ [tex]n-p-1[/tex]
On putting the estimated values, we get
⇒ [tex]200-18-1[/tex]
⇒ [tex]181[/tex]
So that the correct choice will be "181 degrees of freedom".
A television network, Network A, is scheduling its fall lineup of shows. For the Tuesday night 8 p.m. slot, Network A has selected its top show. If its rival network, Network B, schedules its top show during the same time slot, Network A estimates that it will get 1.1 million viewers. However, if Network B schedules a different show during that time slot, Network A estimates that it will get 1.9 million viewers. Network A believes that the probability that Network B will air their top show is 0.7 and the probability that Network B will air another show is 0.3. Determine the expected number of viewers for Network A's top show.
Answer:
1,280,000 (1.28 million.)
Step-by-step explanation:
If Network B schedules its top show (with a probability of 0.7), Network A will get 1.1 million viewers.
If Network B schedules a different show during that time slot, (with a probability of 0.3), Network A will get 1.9 million viewers.
Therefore, the probability distribution table of number of viewers of Network A is:
[tex]\left|\begin{array}{c|c|c}$Number of Viewers, x&1.1$ million&$1.7 million\\P(x)&0.7&0.3\end{array}\right|[/tex]
Therefore, the expected number of viewers for Network A's top show
= (1100000 X 0.7) + (1700000 X 0.3)
=1,280,000
The expected number of viewers for Network A's top show is 1.28 million.
The valve was tested on 270 engines and the mean pressure was 6.6 lbs/square inch. Assume the variance is known to be 0.49. If the valve was designed to produce a mean pressure of 6.5 lbs/square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications
Answer:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
Step-by-step explanation:
Information given
[tex]\bar X=6.6[/tex] represent the sample mean
[tex]s=\sqrt{0.49}= 0.7[/tex] represent the population deviation
[tex]n=270[/tex] sample size
[tex]\mu_o =6.5[/tex] represent the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level
z would represent the statistic
[tex]p_v[/tex] represent the p value for the test
Hypothesis to verify
We want to verify if the true mean for this case is equal to 6.5 lbs/square inch or not , the system of hypothesis would be:
Null hypothesis:[tex]\mu= 6.5[/tex]
Alternative hypothesis:[tex]\mu \neq 6.5[/tex]
The statistic for this case is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
State whether the decay is linear or exponential, and answer the associated question. The value of a car is decreasing by 9% per year. If the car is worth $11 comma 000 today, what will it be worth in two years? g
Answer:
ExponentialA(2)=$9109.10Step-by-step explanation:
Since the value of the car decreases by a common factor each year, the decay is exponential.
An exponential decay function is of the form
[tex]A(t)=A_0(1-r)^t$ where:\\Initial Value, A_0=\$11,000\\$Decay Factor, r=9%=0.09[/tex]
Therefore, the function modeling the car's decay is:
[tex]A(t)=11000(1-0.09)^t[/tex]
We want to determine the car's value in two years.
When t=2
[tex]A(2)=11000(1-0.09)^2\\A(2)=\$9109.10[/tex]
The value of the car in 2 years will be A(t)=$9109.10
Final value of the car after 2 years will be $9109.10
Value of the car decay by 9%.
Since, 9% is a common factor by which the value of car is decreasing,
Therefore, decay will be exponential.
Expression for the exponential decay is given by,
[tex]P=P_0(1-\frac{r}{100} )^t[/tex]
Here, [tex]P=[/tex] Final price
[tex]P_0=[/tex] Initial price
[tex]r=[/tex] Rate of decay
[tex]t=[/tex] time
If initial price of the car [tex]P_0=11000[/tex], rate of decay [tex]r=0.09[/tex] and [tex]t=[/tex] Number of years
By substituting the values in the expression,
P = [tex]11000(1-0.09)^2[/tex]
= 11000(0.91)²
= $9109.10
Therefore, final value of the car after 2 years will be $9109.10
Learn more,
https://brainly.com/question/24515212
Please answer this correctly
Answer:
First box is 4This is because 2 is the stem and the leaves are 1, 2, 4, and 5
so the numbers are 21, 22, 24, and, 25
Second box is 3This is because 2 is the stem for the leaves 6 and 7
3 is the stem for the leaf 0
So the numbers are 26, 27, and 30
Hope this helped
Answer:
As you know about the stem and leaf plot
1 |7 7 7 8 => 17, 17, 17, 18
2|1 2 4 5 6 7 => 21, 22, 24, 25, 26, 27
3|0 2 5 5 6 7 7 8 9 => 30, 32, 35, 35, 36, 37, 37, 38, 39
4|1 2 => 41, 42
Now we count to complete the table:
16-20 | 4 {17, 17, 17, 18}
21-25 | 4 {21, 22, 24, 25}
26-30 | 3 {26, 27, 30}
31-35 | 3 {32, 35, 35}
36-40 | 5 {36, 37, 37, 38, 39}
41-45 | 2 {41, 42}
Hope this helps!
Factor 5x4 - 30x2 - 135.
Answer:
20 - 60 - 135
95
Step-by-step explanation:
All you have to do is add/subtract the factors together
Answer:
5(x - 3)(x + 3)(x^2 + 3)
Step-by-step explanation:
First take out the GCF of the 3 numbers (5):-
= 5(x^4 - 6x^2 - 27)
= 5(x^2 - 9)(x^2 + 3)
= 5(x - 3)(x + 3)(x^2 + 3).
(a) Explain what is wrong with the following ‘proof’:Statement:IfRis symmetric and transitive, thenRis reflexive."Proof":SupposeRis symmetric and transitive. Symmetric means thatx R yimpliesy R x. We apply transitivity tox R yandy R xto givex R x. Therefore,Ris reflexive.(b) Give an example of a relation on a set that is both symmetric and tran-sitive, but not reflexive
Answer:
Step-by-step explanation:
Recall that, in this case, the subset of X for which R is defined is called the domain of R. The mistake occurs when we assume that the domain R is the whole set X, but it could happen that R is not defined for some elements of X.
Recall the following example:
X = {2,4,6}.
We can define R as follows {(2,2), (4,4), (2,4), (4,2)}. We can easily check that this is a transitive and symmetric relation, but since we don't have the element (6,6) it fails to be reflexive.
Write the number six hundred and forty-
nine thousand and six in figures
Answer:
649,006
Step-by-step explanation:
Six hundred and forty nine thousand= 649,000
and six so we have
649006
THE ANSWER IS 649,006 HOPE IT HELPS
A rectangular bin is going to be made with a volume of 492 in3. The base of the bin will be a square and the top will be open. The cost of the material for the base is 0.8 cents per square inch, and the cost of the material for the sides is 0.6 cents per square inch. Determine the dimensions of the bin that will minimize the cost of manufacturing it. What is the minimum cost
Answer:
base side = 9.037 inches
height = 6.024 inches
Minimum cost = 196 cents
Step-by-step explanation:
The volume of the bin is given by:
[tex]Volume = side^2 * height[/tex]
and the surface area of the bin is given by:
[tex]Surface\ area = side^2 + 4*side*height[/tex]
The cost of the bin will be:
[tex]Cost = 0.8*side^2 + 0.6*4*side*height[/tex]
[tex]Cost = 0.8*side^2 + 2.4*side*height[/tex]
From the volume equation, we have:
[tex]height = 492 / side^2[/tex]
Now the cost will be:
[tex]Cost = 0.8*side^2 + 2.4*side*492/side^2[/tex]
[tex]Cost = 0.8*side^2 + 1180.8/side[/tex]
To find the side that gives the minimum cost, we can find the derivative of Cost in relation to side and then make it equal zero:
Abbreviating Cost as C and side as s, we have:
[tex]dC/ds = 0.8*2*s - 1180.8/s^2[/tex]
[tex]1.6s - 1180.8/s^2 = 0[/tex]
[tex]1.6s = 1180.8/s^2[/tex]
[tex]1.6s^3 = 1180.8[/tex]
[tex]s^3 = 738[/tex]
[tex]s = 9.037\ in[/tex]
Finding the height of the bin, we have:
[tex]height = 492 / 9.037^2[/tex]
[tex]height = 6.024\ in[/tex]
The minimum cost is:
[tex]Cost = 0.8*9.037^2 + 1180.8/9.037 = 196\ cents[/tex]
Jamie is investing $47,000 in an account paying 9.26% interest compounded continuously. What will Jamie's account balance be in 17 years?
9514 1404 393
Answer:
$226,863.29
Step-by-step explanation:
The amount is given by ...
A = Pe^(rt)
where principal P is invested at annual rate r for t years.
A = $47,000×e^(0.0926×17) ≈ $226,863.29
Answer:
the answer is $226,863.29
The sum of the ages of ahsan and his mother is 61 years.The difference in their ages is 29 years.By forming a pair of simultaneous linear equations,find (i)ahsan's present age (ii)the age of ahsan's mother when ahsan is 21 years old
Answer:
a. 16 years
b. 50 years
Step-by-step explanation:
Let us assume the age of Ahsan be X
And, the age of his mother be Y
It is mentioned in the question that the sum of the both ages to be 61 years and their difference is 29 years
So now the equation is as follows
X + Y = 61 .............................. (1)
-X + Y = 29 .............................. (2)
Now solve this
We get
2Y = 90
Y = 45 = Ahsan mother age age
Now put the value of Y in any of the above equation
So X would be
X = 61 - 45
= 16 i.e ahsan age
The mother age is
= 45 years + 5 years
= 50 years
The 5 years come from
= 21 years - 16 years
= 5 years
I sell hot dogs at a football game. I can make a hot dog for $0.65 and sell it for $1.00. If i sell 50 hot dogs, what is my profit? show your work
Answer:
17.50
Step-by-step explanation:
The profit on one hotdog is
1 - .65 = .35
Multiply by the number of hotdogs sold
.35 * 50 =17.50
If f(x) = x^2 is reflected over the x-axis and the shifted 4 units down, what is the equation of the new function, g(x)?
Answer:
g(x) = -x² - 4
Step-by-step explanation:
In this case, we are only changing a (reflection and vertical shrink/stretch) and k (vertical movement)
k = -4 because we are moving 4 units down
a = -1 because we are just reflecting over the x-axis
At a cell phone assembly plant, 75% of the cell phone keypads pass inspection. A random sample of 110 keypads is analyzed. Find the probability that more than 78% of the sample keypads pass inspection. Use at least five decimal places for the denominator.
Answer:
23.27%
Step-by-step explanation:
From the statement we know that random sample n is 110 and that p is 75% and x the percentage to evaluate is 78%
We have that the probability would be equal:
P (x > 0.78) = [tex]P(z <\frac{x-p}{\sqrt{\frac{p*(1-p)}{n} }})[/tex]
Replacing we have:
[tex]P(z <\frac{0.78-0.75}{\sqrt{\frac{0.75*(1-0.75)}{110} }})[/tex]
P ( z < 0.73) = 1 - P ( z => 0.73)
= 1 - 0.7673
= 0.2327
Therefore the probability is 23.27%
Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's helght. He needs to rewrite the formula A = 2#r(+h)
to find the cylinder's height (h) In terms of the cylinder's surface area (A) and its radius (7). Which is the correct formula?
Answer:
h= pi(r)2/A or h= 3.14 times 7 times 2 divided by A
Step-by-step explanation:
u need to do the opposite of multiplication which is division to find the height
hope this helps
correct me if this is wrong
find the equation of the line that is perpendicular to y= -1/5x-3 and contains the point (1,2) answer all boxes please
Answer:
Y = 5x -3
Step-by-step explanation:
Let's look for the gradient to solve this question for.
We are given y= -1/5x-3
Any line perpendicular to the above line will have a graient of m'.
Where mm'= -1
m = -1/5 from the line equation
So
mm'= -1
-1/5m'= -1
m' =5
For the equation of point (1,2)
(Y-y1)/(x-x1) = m'
(Y-2)/(x-1)= 5
Y-2= 5x -5
Y = 5x -3
Can advise on the solution?
Answer:
340
Step-by-step explanation:
If x is the amount of pages in the book we can write:
1/4x + 5 + 3/5(x - (1/4x + 5)) + 10 + 12 + 24 = x
1/4x + 51 + 3/5(3/4x - 5) = x
1/4x + 51 + 9/20x - 3 = x
7/10x + 48 = x
3/10x = 48
x = 160
Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the estimated product?
Answer: first box is 20 (1/2)
Second box is 10
Answer:
Answer: first box is 20 (1/2)
Second box is 10
Step-by-step explanation:
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 442 gram setting. It is believed that the machine is underfilling the bags. A 44 bag sample had a mean of 438 grams. Assume the population variance is known to be 576. A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Answer:
p value is 0.1343
Step-by-step explanation:
Null: u>= 442
Alternative: u < 442
Using the formula for z score:
(x - u)/sd/√n
Where x is 438, u = 442 sd can be determined from the variance = √variance =√576 = 24 and n = 44
z score = 438-442 / (24/√44)
z score = -4/(24/6.6332)
z = -4/3.6182
z =-1.1055
Now let's find the p value at 0.1 significance level using a z score of -1.1055, using a p value calculator, p value is 0.1343 which greatest than 0.1 meaning the day is not sufficient enough to conclude that the machine is underfilling the bags.