a phone cord is 4.89 m long. the cord has a mass of 0.212 kg. a transverse wave pulse is produced by plucking one end of the taut cord. that pulse makes four round trips (down and back) along the cord in 0.636 s. what is the tension in the cord? hint: four round trips is a total distance of eight lengths of the cord.

Answers

Answer 1

The tension in the given phone cord is 174.3 N.

Speed of the wave

v = fλ

v = (n/t) x 2L

v = (4/0.617) x (2 x 4.89)

v = 63.4 m/s

Tension on the rope

v = √T/μ

μ  = 0.212/4.89 = 0.0434 kg/m

v² = T/μ

T = v²μ

T = (63.4)² X 0.0434

T = 174.3 N

the tension in the given  phone cord is 174.3 N.

When two opposing pressures pull on a rope, string, or wire, the force communicated through the object is known as tension. The energy is pulled equally on the bodies at the ends by the tension force, which is applied over the entire length of the wire. The International System of Units (SI) uses newtons as the unit of tension measurement for transmitted forces, action-reaction pairs of forces, and restoring forces (or pounds-force in Imperial units).

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Related Questions

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena kevin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, what can you infer?.

Answers

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena kelvin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, then Kevin’s circular path has a bigger radius than Linda’s path.

What is speed?

Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number.

Given that,

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h.

kelvin, another biker, is moving along a circular path at a constant speed of 12 km/h.

As we know,

acceleration (a) = V²/r

For Linda, a₁ = (10)²/r₁

For Kelvin, a₂ = (12)² /r₂

So, a₁/a₂ = [(10)²/r₁] × [r₂/(12)²]

or, a₁/a₂ = 0.694 r₂/r₁

or, r₁ = 0.694 r₂      [ As, acceleration is same]

Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.

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The complete question is as follows:

Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena Kevin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, what can you infer?

A) The centripetal force on Kevin is higher than that on Linda.

B) The centripetal force on Linda is higher than that on Kevin.

C) Kevin’s circular path has a bigger radius than Linda’s path.

D) Linda’s circular path has a bigger radius than Kevin’s path

the gravitational force between two very large metal spheres in outer space is 56 n. how large would this force be if the mass of each sphere were halved?

Answers

The gravitational force between two very large metal spheres in outer space if the mass of each sphere were halved is 14 N

F = G m1 m2 / r²

F = Gravitational force of attraction

G = Gravitational constant

m1, m2 = Masses of both spheres

r = Distance between the spheres

m1' = m1 / 2

m2' = m2 / 2

F' = G m1' m2' / r²

F' = G ( m1 / 2 ) ( m2 / 2 ) / r²

F' = G m1 m2 / 4 r²

F' = F / 4

F' = 56 / 4

F' = 14 N

Therefore, the force is 14 N

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How does the restoring force and the mass of the string effect the speed of a wave generated on a string?

Answers

The string will extend when the object is moved to the right, applying a restoring force to bring the weight back to its equilibrium position. The string will compress if the object is pushed to the left, and it will then exert a restoring force to bring the thing back to its starting position.

What is the impact of mass on restoring force?

The displacement diminishes as the mass comes closer to the equilibrium position, and as a result, the restoring force and acceleration both decrease. There is no restoring force once the mass has reached equilibrium.

What influences how quickly waves go down a stretched string?

The linear density of the string and the tension in the string both affect how quickly a wave moves along a string. A string's linear density is its mass per unit length. In general, a wave's speed is determined by the square root of the medium's elastic property to inertial property ratio.

How does string mass affect the wave's speed?

The speed would be higher in the low linear mass density of the string because the speed of a wave on a string is inversely proportional to the square root of the linear mass density.

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what is the distance in mm between these minima if the diffraction pattern falls on a screen 1.2 m from the slit?

Answers

The distance in mm between these minima is 0.29 ×[tex]10^{-3}[/tex] m

For first minima, m=1, Then,

[tex]a\sin \theta_1 = \lambda_1 \Rightarrow \sin\theta_1 = \frac{\lambda_1}{a} \Rightarrow \theta_1 = \sin^{-1}\left(\frac{589.1\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.2^{\circ}[/tex]

[tex]a\sin \theta_2 = \lambda_2 \Rightarrow \sin\theta_2 = \frac{\lambda_2}{a} \Rightarrow \theta_2 = \sin^{-1}\left(\frac{589.6\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.22^{\circ}[/tex]

Hence the required angle is , (14.22 - 14.2) = 0.02o

The distance between these two minima,

[tex]\Delta y = y_2 -y_1 = \frac{D}{a}\left( \lambda_2-\lambda_1\right) = \frac{1.4}{2.4\times 10^{-6}}\left(0.5\times 10^{-9} \right ) = 0.29\times 10^{-3} \hspace{2mm} m[/tex]

This distance is best measured using a microscope.

The length of a particular path taken by an object between two points is its distance, such as the distance traveled through a maze. In some cases, such as when a ball is thrown straight up or the Earth completes an orbit, this can even be a closed distance along a closed curve that begins and ends at the same location. The mathematical term for this is the curve's arc length. It is also possible to signify the distance traveled: a "ahead" distance is positive and a "backward" distance is negative.

When building vehicles or mechanical gears, it can be helpful to take circular distance—the distance covered by a

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you are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.8 × 107 m and its rotation period to be 22.3 hours. you have previously determined that the planet orbits 8.6 × 1011 m from its star with a period of 402 earth days. once on the surface you find that the acceleration due to gravity is 63.6 m/s2. what are the mass of (a) the planet and (b) the star? (g

Answers

The mass of the star of the distant solar system is 82 * 10²² kg and the mass of the planet of the distant solar system is 8.58 * 10²⁵ kg

g = G M / r

g = Acceleration due to gravity

G = Gravitational constant

M = Mass of star

r = Distance between both bodies

g = 63.6 m / s²

G = 6.67 * 10⁻¹¹ N m² / kg²

r = 8.6 * 10¹¹ m

Ms = 63.6 * 8.6 * 10¹¹ / ( 6.67 * 10⁻¹¹ )

Ms = 82 * 10²² kg

F = G M m / r²

F = m g

Equating,

m g = G M m / r²

With the above equation, we can find the mass as:

Mp = g r² / G

Mp = 63.6 * ( 1.8 * 10⁷ / 2 )² / 6.67 * 10⁻¹¹

Mass of particle = 8.58 * 10²⁵ kg

Therefore the mass will be equal to 8.58 * 10²⁵ kg

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chalkboard videos two people start at the same place and walk around a circular lake in opposite directions. one walks with an angular speed of 1.7 × 10−3 rad/s, while the other has an angular speed of 3.4 × 10−3 rad/s. how long will it be before they meet?

Answers

If two people start at the same place and walk around a circular lake in opposite directions with angular speed of 1.7 × 10−3 rad/s and 3.4 × 10−3 rad/s, they will meet after 20.5 minutes.

ω = θ / T

ω = Angular velocity

θ = Angular distance

T = Time period

ω1 = 1.7 * 10⁻³ rad / s

ω2 = 3.4 * 10⁻³ rad / s

θ = ω T

Let the angular distance covered by both person be θ1 and θ2. Since they start at same point, when they meet the sum of their total angular distances will be 360° which is 2π in radians.

θ1 + θ2 = 2 π

ω1 T + ω2 T = 2 π

T = 2 π / ( ω1 + ω2 )

T = ( 2 * 3.14 ) / ( ( 1.7 * 10⁻³ ) + ( 3.4 * 10⁻³ ) )

T = 1.2314 * 10³ s

T = 1231.4 s

T = 20.5 min

Therefore, they will meet after 20.5 minutes.

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a diffraction grating has 2,070 lines per centimeter. at what angle in degrees will the first-order maximum be for 550 nm wavelength green light?

Answers

7.87° is the first-order maximum for 550 nm.

What is diffraction?Diffraction is the spreading of waves in the presence of obstacles. Diffraction occurs with sound, electromagnetic radiation such as light, X-rays, and gamma rays, and very small moving particles with wavelike properties such as atoms, neutrons, and electrons.The locations of the interference fringes are given by the equation d sin θ = m λ d sin θ = m λ.

Using diffraction equations,

d = 0.01/Number of lines, where 0.01 m = 1 cm and d = line spacing

Therefore,

d = 0.01/2070 = 4*10^-6 m

Similarly,

d x Sin X = m x Y;

When X = Angle

m = order = 1

Y = wavelength = 550 nm =550*10^-9 m

By substituting;

Sin X = mY / d = (1*550*10^-9)/(4*10^-6) = 0.1375

X = Sin⁻¹(0.1375) = 5.97°

As a result, the first-order maximum for 550 nm will be 7.87°.

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are your results in complete agreement with the fundamental lens equation ? if not, to what to you attribute the discrepancies?

Answers

Yes, the outcomes are in perfect accordance with the basic lens equation.

What does the basic lens equation entail?

1/f = 1/s1 + 1/s2. This is the equation for the Gaussian lens. The basic relationship between the size of both the optical system and the diffraction limit of the lens is given by this equation.

What are the lens equation and formula?

For a spherical mirror, the focal length, scale factor, and object distance are all related by the lens equation, often known as the lens formula. The formula is presented as follows: Lens Equation - 1/u + 1/v = 1/f, where v is the image's distance from the lens.

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a skydiver leaps from a plane and accelerates toward the surface of the earth. earth’s acceleration toward the skydiver is: group of answer choices equal to the acceleration of the skydiver due to newton’s 3rd law much smaller than the acceleration of the skydiver zero cannot be determined

Answers

Earth’s acceleration toward the skydiver is much smaller than the acceleration of the skydiver

Define acceleration

Acceleration is the rate at which velocity, both in terms of speed and direction, varies over time. When anything moves faster or slower in a straight line, it is said to have been accelerated.

Your descent to the ground quickens as you plummet. This acceleration will keep going until the drag from her falling speed due to wind resistance equals the acceleration caused by gravity. He should keep accelerating downward because air resistance, also known as drag force, is usually far smaller than the normal force of a body. She will reach "terminal velocity" when these forces balance each other out, at which point she will stop accelerating.

He will thereafter fall at the same rate until he activates his chute, however his initial acceleration is brought on by acceleration due to gravity.

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Estimate the difference in air pressure between the top and the bottom of the Empire State building in New York City? It is 380 m tall and is located at sea level. Express as a fraction of atmospheric pressure at sea level.
Express your answer using two significant figures.

Answers

The fraction of atmospheric pressure at sea level is 0.047.

Define atmospheric pressure.

The stress present in the Earth's environment is known as atmospheric pressure, commonly referred to as barometer strain. One zero one,325 Pa, also known as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi, is the measure of stress used to describe the same old environment.

The atmospheric sea level is known as

P sea level = P atm = 1.01325 × 10^5 N/m^2

Now pressure at the bottom of empire state will be

P1 = 1.01325 × 10^5 N/m^2

Pressure at the top of empire state will be:

P2 = P1 - rho × g × h

rho = density of air = 1.29 kg/m^3

g = 9.81 m/sec^2

Given:

h = height of empire state = 380 m

P2 = 1.01325 × 10^5 - 1.29 × 9.81 × 380

P2 = 96516.138 N/m^2

So,

Delta P = P1 - P2 = 1.01325 × 10^5 - 96516.138

Delta P = 4808.862 N/m^2

So fraction will be:

N = Delta P / P sea level

N = 4808.862/1.01325 × 10^5

N = 0.04745 = 4.745 × 10^-2

Hence in two significant figures

N = 4.7 × 10^-2 = 0.047

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imura lifts a box by bending at the knees, then slowly standing up and holding the box away from her body. is this an effective and safe lifting technique?

Answers

No, as she kept the box a safe distance from her body. As closely as you can, hug the load to your body.

Which three safe lifting methods are there?

Lift gradually by extending your hips and knees (not your back). As you raise, keep your back straight and avoid twisting. Hold the load at the level of your belly button, as near to your body as you can.

Safe lifting technique?

Keep the burden as near to your body as you can, if at all possible. Perhaps this is preferable to fiercely clutching it in your hands. As opposed to either entirely flexing your back (stooping) or fully flexing your hips and knees (full/deep squatting), it is ideal to slightly bend your back, hips, and knees at the beginning of the lift.

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Ahely' brother rode beide her for everal minute. During thi time wa he moving relative o Ahley?

Answers

assuming they were moving at the same speed and started riding at the same position and time, then no, her brother was not moving relative to ashley.

a reflection nebula is described by group of answer choices a. reflection of light off the dust of the nebulae b. the explosion of hot large stars. c. the emission of light from excited hydrogen gas d. the emission of radiation from torn up material falling into black holes

Answers

A reflection nebula is described by the explosion of hot large stars. Option B.

Reflection nebulae differ from emission nebulae in that they themselves do not emit radiation. This is a cloud of dust and gas that reflects light energy from a nearby star or group of stars. They usually tend to be blue due to the way light scatters.

This nebula is a reflection nebula that glows by reflecting the light of nearby stars. In contrast to emission nebulae, which emit a reddish glow from excited gas atoms, reflection nebulae are bluish because interstellar dust particles prefer to reflect blue starlight. A cloud of gas and dust that emits no light of its own and glows by reflecting light from nearby stars.

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find the speed of the projectile when it arrives at the top of the rails if it starts at rest at the bottom of the rails

Answers

The speed of the projectile F= μο[tex]i^{2}[/tex]/2π  ㏑(1+ W/r)i^.

The projectile's path between y+dy should be considered. Equation is used to determine the magnetic force acting on the segment as well as the magnetic field of each semi-infinite wire (the top rail is known as wire 1 and the bottom rail as wire).

The field (in the region between the wires) set up by wire 1 is into the paper (the "k" direction), and that set up by wire 2 is also into the paper. The current. in rail. 1. is in the "+ i." direction, and. the current. in rail 2 is in the. " i" direction. The force element (a function of y) acting on the segment of the projectile (in which the current runs in the − j^ direction) is provided below. The coordinate. origin is  at the. bottom of the. projectile.

d F = d F1 +dF2 = idy(− j^)× B1 +dy(− j^ )× B2 =i[B 1 +B 2 ] i dy

F= μο[tex]i^{2}[/tex]/2π  ㏑(1+ W/r)i^.

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a 40 kg stone tied to a string is whirled horizontally at a speed of 2.2 m/s what is the tension in the string

Answers

The tension in the string when a 40 kg stone tied to a string is whirled horizontally at a speed of 2.2 m/s will be 488 N/m.

When two solid things come into touch with one another, tension is the force that is generated. A force of tension is the force generated by a rope, string, or chain.

When one mass is drawn vertically and another is being pulled horizontally, there is tension force acting on the string. In the absence of gravity, this gives the tension force pulling on a string.

We are aware that T = mg + ma is the formula used to compute the force of tension.

T = 40(10) + 40(2.2)

T = 488 N/m.

Given that tension is a form of force, it shares the same measurement and unit as force. The CGS unit for tension is dyne whereas the SI unit is newton (N).

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The centripetal acceleration of the stone is:

ac = v2 / r

Let us assume the radius of the string is 1m.

ac = (2.2 m/s)2 / 1

The tension in the string is:

T = m a = (40)*(2.2*2.2)

T = 40 * 2.2 * 2.2

T = 193.6 N

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By how much does the gravitational potential energy of a 50- kg pole vaulter change if her center of mass rises about 4. 0 m during the jump?.

Answers

Consequently, the acceleration due to gravity of the pole voulter is 2000J.  any object at ground surface has a potential energy = zero newtons.

What is meant when we talk about gravitational potential energy?

Gravitational potential energy is the energy that an object has due to its location within a gravitational field. The most usual use of gravitational potential energy is for a body at the surface of the Earth, where it is reasonable to assume that the gravitational pull is constant at about 9.8 m/s. 2.Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.

What is the source of gravitational potential energy?

If an object is located at a height that is higher (or lower) than the zero height, it has gravitational potential energy. If an object is situated on an elastic media in a position besides the equilibrium position, it has elastic potential energy.

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The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is _______________ the momentum of the bullet it fires.
a. less than
b. more than
c. the same as
d. not equal to

Answers

The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is the same as the momentum of the bullet it fires.

option C is the correct answer.

What is the principle of conservation of linear momentum?

The principle of conservation of linear momentum states that in an isolated system, the sum of the initial momentum of the system is equal to the sum of the final momentum of the system.

Mathematically, the principle of conservation of linear momentum is written as;

Pi = Pf

where;

Pi is the sum of the initial momentum of the systemPf is the sum of the final momentum of the system

m₁u₁ = m₂u₂

where;

m₁ is the mass of the gunu₁ is the initial speed of the gunm₂ is the mass of the bulletu₂ is the final speed of the bullet

Thus, based on the principle of conservation of linear momentum the final momentum of the gun will always be equal to the final momentum of the bullet.

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An 8.0 lb blowing ball has a diameter of 8.5 inches. When lowered into water, this ball will A. Float. B. Sink. C. Have neutral buoyancy.

Answers

An 8.0 lb blowing ball has a diameter of 8.5 inches. When lowered into water, this ball will sink.

The correct option is B.

What is density?

The measure of how densely a material is packed together is called density.

It can be defined as the mass per unit volume.

Density Symbol: D or ρ

Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Mass of the ball m=8lb

Radius of the ball r=8.5/2=4.25 inch=0.108m

Volume of the ball V=4/3[tex]\pi[/tex]r³=5.277 ×10⁻⁶m³

Density of the ball b = = 687.7 × 103 kg/m³

Density of water Pw 1 × 103 kg/m³

Since the density if the bowling ball is much larger than that of water, the ball will sink.

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When wind speeds up as it blows over the top of a hill, atmospheric pressure there.

Answers

When wind speeds up as it blows over the top of a hill, decreases atmospheric pressure there.

What is Atmospheric pressure ?

As the ratio of the force the atmosphere exerts per unit area, atmospheric pressure can be defined. Pascal can be used to both calculate and measure atmospheric pressure. 101325 pascals is what the normal atmospheric pressure is.

Your immediate environment is pressed against by the weighty air that surrounds you. It is known as air pressure or atmospheric pressure. It is the pressure from the air above a surface that pulls it toward Earth. Typically, a barometer is used to measure atmospheric pressure.

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an automobile sounds its horn while passing an observer at 25.5 m/s. the actual horn frequency is 405 hz. assume the speed of sound is 345 m/s. find its frequency heard by the observer while the car is approaching.

Answers

The frequency heard by the observer is 437.3 Hz.

What is doppler effect?

The Doppler effect or Doppler shift is the change in frequency of a wave in relation to an observer who is moving relative to the wave source. Doppler shift is frequently demonstrated by the change in pitch that occurs as a car approaches and moves away from a viewer while sounding its horn.

It is estimated by the formula:

[tex]f_o = \frac{v +v_o}{v + v_s} f_s[/tex]

where,

[tex]f_o[/tex] = observer frequency of sound

[tex]v[/tex] = speed of sound waves

[tex]v_o\\[/tex] = observer velocity

[tex]v_s[/tex] = source velocity

[tex]f_s[/tex] = actual frequency of sound waves

Given,

[tex]f_s[/tex] = 405Hz

[tex]v_s[/tex] = 25.5 m/s

[tex]v[/tex] = 345 m/s

[tex]v_o\\[/tex] = 0 m/s

[tex]f_o = \frac{v +v_o}{v + v_s} f_s[/tex]

Observer to source = Positive

Source to observer = Negative

[tex]f_o = \frac{v}{v + v_s} f_s[/tex]

[tex]f_o = \frac{345}{345 - 25.5}[/tex]  × 405

[tex]f_o[/tex] = 437.3 Hz

The frequency heard by the observer is 437.3 Hz.

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A transparent oil with index of refraction 1.24 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident red light (wavelength 700 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.=_________nm

Answers

A transparent oil with refraction index 1.24 spills on the surface of water  Assuming the maximum occurs in the first order, Then the thickness of the oil slick 271 nm

Given refraction index is 1.24

The formula to apply for find the maximum for this thin film is

2nt = mλ

(2)(1.29)t = (1)(700 X 10-9)

t = 2.71 X 10-7 m   which is 271 nm.

Light travels more slowly at higher refractive indices, changing direction within a material with a correspondingly greater degree. This means that lenses made of materials with higher refractive indices can bend light more strongly and have lower profiles. A refractive index of 1.5 applies to glass. In other words, the speed of light in glass is not independent of the color of the light and is 1.5 times slower than in a vacuum.

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Without his glasses, Isaac can see objects clearly only if they
are less than 4.2 m from his eyes.
What focal length glasses worn 2.1 cm from his eyes
will allow Isaac to see distant objects clearly?
Express your answer using two significant figures.

Answers

According to general principles, the object distance shows that the light rays coming from the object are parallel to one another, giving rise to f=-4.221.

What sort of stuff are light rays?

A small, often straight-moving light beam is called a ray. A ray is represented by the light beam of a laser or laser pointer. A ray of light travels in a straight line until it hits an object, like a mirror or perhaps the boundary between two materials, per the ray model of light.

A light ray is exactly what?

Small light beams called rays travel in a straight line as electromagnetic waves. Light always moves in a straight line, despite the fact that reflection and refraction can alter the direction of its speed.

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The right-angle link has a counterclockwise angular velocity of 3 rad/s at the instant represented, and point B has a velocity VB=2i-0.3jm/s. Determine A the velocity of using vector notation. Sketch the vector polygon which corresponds to the terms in the relative-velocity equation and estimate or measure the magnitude of VA .

Answers

The magnitude of velocity  will be  Δ=5.2 m/s.

What are vector quantities?

Any quantity which is defined by its magnitude and direction both are called as the vector quantities.

Now the data given in the question will be given as:

V(a) = 3 m/s

θ =  north of east

V(b) = 6 m/s

θ =  south of east =  360-40=320 north of east

Now we will find the x and y component of V(a)

V(ax) = V(a) cosθ

V(ax) = 2.82m/s

V(ay) = V(a)Sinθ

V(ay) = 1.03 m/s

Now we will find the x and y component of V(b)

V(bx) = V(b) cosθ

V(bx) = 4.6 m/s

V(by) = V(b) sinθ

V(by) = -3.86 m/s

Now change in velocity will be

ΔV = V(b) - V(a)

ΔV = 1.78 i - 4.89 j

The magnitude of these vectors:

ΔV = 5.2 m/s.

Therefore the magnitude of the V will be 5.2 m/s.

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light traveling in water strikes a water-air interface such that the light is incident directly along the normal to the interface. what happens to the light?

Answers

When light travels from air into water, it slows down, causing it to change direction slightly.

What is  light travels?

Light moves in waves. It does not, however, require any substance or material to transport its energy forward, unlike sound waves or water waves. This implies that light may pass through a vacuum, or an area that is entirely devoid of air. (In contrast, sound must pass through a solid, liquid, or gas.)

Light slows down and somewhat changes direction as it passes through water from air. Refraction is the name for this shift in direction. Light "bends" more in the direction of the normal line when it enters a denser material (one with a higher refractive index).

Light bends in the direction of the normal as it passes through an interface into a material having a greater index of refraction. On the other hand, light bending over a higher n to lower n contact will deviate from the usual.

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if the charge on q1 is doubled, assuming that charge of q2 and the distance of r stay the same, what will happen to the force between the two charges? (3 points)

Answers

Electromagnetic Force causes electric and magnetic effects such as the repulsion between like electrical charges or the interaction of bar magnets in a similar fashion of attraction & repulsion. It is long-ranged, but much weaker than the strong force. It can be attractive or repulsive and acts only between pieces of matter carrying electrical charge. Electricity, magnetism, and light are all produced by this force.

If the charge on q1 is doubled the force becomes 4 times its initial value.

Since, we know

F = (k×q1×q2)/r²

When the charges are doubled, we have :

F' = (k × 2q1 × 2q2)/r²

F' = 4 (k×q1×q2)/r²

Thus,

F' = 4F

Therefore, the force becomes 4 times its initial value.

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what is a condition in which there is a progressive thickening of the lens causing vision to become cloudy, opaque, and distorted?

Answers

Cataract is a condition in which there is a progressive thickening of the lens causing vision to become cloudy, opaque, and distorted.

What are the signs and symptoms of cataracts?vision that is cloudy, blurry, or dim.Nighttime eyesight is becoming more challenging.a sensitivity to glare and brightness.Brighter lighting is required for activities like reading."Halos" around lights being perceived.prescription for glasses or contacts changing frequently.colour fading or yellowing.Having double vision in just one eye.

The majority of cataracts occur when the tissue that makes up the eye's lens changes due to age or trauma.

The risk of cataracts may be increased by some hereditary genetic abnormalities that can result in other health issues. Other eye diseases, previous eye surgery, or other disorders like diabetes might also lead to cataracts. Cataracts can also form as a result of prolonged steroid drug usage.

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the distance between the eyepiece and the objective lens in a certain compound microscope is 20.0 cm. the focal length of the objective is 0.500 cm, and that of the eyepiece is 1.70 cm. find the overall magnification of the microscope.

Answers

The overall magnification of the microscope is  - 588.23 .

Magnification is the process of increasing apparent size.

It is usually done to see the object in an enlarged view by increasing its resolutions so that a more clear view of the object can be visualized.Microscopes like light, electron and compound microscopes are used to see a high resolution image of the object.Magnification can be calculated by the formula M = -(l/f₀)(25/f₁)

M = magnification

l = distance between the eyepiece and the objective lens

f₀ = focal length of the objective

f₁ = focal length of the eyepiece

l = 20 cm

f₀ = 0.500 cm

f₁ = 1.70 cm

M = - (l/f₀)(25/f₁)

M =  - (20/0.500)(25/1.70)

M = - (40)(14.70)

M = - 588.23

The overall magnification for the microscope is - 588.23.

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Assume you have a sealed jug that contains only air. If you heat the air in the jug, it will have a higher temperature. What other property of the air will also change?.

Answers

Assume you have a sealed jug that only contains air. If you heat the air in the jug it will have a higher temperature.  Air Pressure properties of air will change.

What is  Pressure?

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

The number of atoms of air in the sealed container cannot change. Assuming that the container does not expand when heated, the volume of the container cannot change when it is heated. If neither the mass nor the volume change as the can is heated, neither can the density change.

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what is the velocity of the falre when it is moving toward the ground and its position is equal to 131 feet

Answers

The velocity of the flare is -92 feet per second while it is going toward the earth, in accordance with the question.

What does physics define as velocity?

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar number. In essence, the velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

Briefing:

We determine the speed at this time after first determining t.

131 = -3t^2 + 100t  + 3

-3t^2 + 100t - 128 = 0

-(3t - 4)(t - 32) = 0

t = 4/3, 32

At 32, the flare will be released.

s'(t) = -6t + 100

s'(32) = -6(32) +100 = -92

The velocity is 92 ft/sec down.

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The complete question is-

In a scene from the Martin Matt Damon shoots a flare straight up into the sky. The height( in feet) of the flare after t seconds is given by

s(t)= -3t squared + 100t + 3

What is the velocity of the flare when it is moving toward the ground and its position is equal to 131 feet?

A bowling ball with a circumference of 27 in. weighs 14lb and has a radius of gyration of 3.28 in. If the ball is released with a velocity of 20ft/sec but with no angular velocity as it touches the alley floor, compute the distance traveled by the ball before it begins to roll without slipping. The coefficient of friction between the ball and the floor is 0.20.This is a question I would really liked answered. Thanks!!

Answers

The distance travelled by the bowling ball is 18.6566 ft

Circumference = 2πr = 27

Weight of the ball = 14 lb

Radius of gyration = 3.28

Velocity = rω = 20 ft/s

Coefficient of friction = 0.20

Total force on y axis= 0, therefore N = W

= F = μN = μW

and, ∑M = Iα

Hence,

= Fr = Iα

Total force on x axis = 0,

= F = ma = μW

= a = μg

Combining all the equations,

= Fr = Iα

= μWr = mk²α

= α = (μgr) / k²

If initial velocity = 0 then, ω = αt

=  ω = αt = [ (μgr) / k² ] t

= t = (vk²) / (μgr²)

Now, v = u + αt

= v - u = (μg) + (vk²) / (μgr²)

= u = v [ 1 +(k²/r²) ]

Distance travelled by the ball = s =

= v² = u² - 2αs

= ( u² ) / [ 1 +(k²/r²) ] ² = u² - 2μgs

= s = (u²/2μg) [1 - (1/(1 + (k²/r²))²)]

= s = 18.6566 ft

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