First Ave.
70°
300 ft
Main St.
Canal St.
Part A:
What is the distance, in feet, on Main Street between First Avenue and Canal Street? Round your answer to the nearest hundredth.

Answers

Answer 1

The distance, in feet, on Main Street between First Avenue and Canal Street, using relations in a right triangle, is of:

319.25 ft.

How to obtain the distance?

The situation is represented by a right triangle, hence the three trigonometric measures are defined as follows:

Sine of angle = length of opposite side divided by the length of the hypotenuse.Cosine of angle = length of adjacent side divided by the length of the hypotenuse.Sine of angle = length of opposite side divided by the length of the opposite side.

From the image given at the end of the answer, the parameters are given as follows:

Missing Information: Hypotenuse.The side length opposite to the angle of 70º is of 300 ft.

Hence the distance of the Main Street is found using the sine of the angle of 70º, as follows:

sin(70º) = 300/x

x = 300/sin(70º)

x = 319.25 ft.

Missing Information

The right triangle is given by the image shown at the end of the answer.

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First Ave.70300 FtMain St.Canal St.Part A:What Is The Distance, In Feet, On Main Street Between First

Related Questions

9^2/9^-4 using a single positive exponent

Answers

Answer:

9⁶

Step-by-step explanation:

[tex]\dfrac{9^2}{9^{-4}} = 9^2 9^{4} = 9 ^ {(2 + 4)} = 9^6[/tex]

Reciprocal of a number raised to exponent is the same as the number raised to the negative of the original exponent

So
[tex]\dfrac{1}{9^{-4}} \text{ becomes } 9^4[/tex]

Question-2
What is the distance between the zeros of the function defined by
6 (2x²+2-8)-2x (2x - 1)?

Answers

Answer:

(2x−1=2x−1) (mark me brainliest) <3!

A synthetic fiber used in manufacturing carpet has tensile that is normally distributed with mean 75.5 psi and standard deviation 3.5 psi. (a) Find the probability that a random sample of n = 6 fiber specimens will have a sample mean tensile strength that exceeds 75.75 psi. 75.75 - р X- р M P[X > 75.75] = P o In o Tn 75.75 – 75.5 P[X > 75.75] = P2> 3.5 va = P[Z > 0.175] = 1-0(0.175) = 0.4325 BC (b) How is the standard deviation of the sample mean changed when the sample size is increased from n = 6 to n = 49?

Answers

The probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi is 43.25%.

Given that,

The tensile strength of a synthetic fiber used to make carpet is regularly distributed, with a mean of 75.5 psi and a standard deviation of 3.5 psi. We have to determine probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi.

We know that,

The Z score is used to determine how far the raw score deviates from the mean, either above or below.

z = (score - mean) / (standard deviation ÷ √sample)

Mean 75.5 psi and standard deviation 3.5 psi. n = 6.

For > 75.75:

z = (75.75 - 75.5) / (3.5 ÷√6) = 0.17

P(z>0.17) = 1-P(z<0.17)

= 1-0.5675

= 43.25%

Therefore, The probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi is 43.25%.

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name all the corresponding sides and angles below if the polygons are congruent

not sure if i need to add more or if there’s some i missed

Answers

Answer:

Step-by-step explanation:

write all your sides and angles down

Corresponding sides:

AC≅JL

CB≅LK

AB≅JK

Corresponding angles:

∠A≅∠J

∠C≅∠L

∠B≅∠K

ms. wilson's science test scores are normally distributed with a mean score of 84 (μ) and a standard deviation of 3 (σ). using the empirical rule, about 99.7% of the scores lie between which two values?

Answers

Using the empirical rule, about 99.7% of the scores lie between 75 to 93

In this question, we have been given ms. wilson's science test scores are normally distributed with a mean score of 84 (μ) and a standard deviation of 3 (σ).

We know that the empirical rule predicts that 99.7% within the first three standard deviations (µ ± 3σ).

An empirical rule is also known as 68-95-99.7 rule.

We find the interval (µ ± 3σ)

The upper value would be,

µ + 3σ

= 84 + 3(3)

= 84 + 9

= 93

and the lower value would be,

µ - 3σ

= 84 - 3(3)

= 84 - 9

= 75

Therefore, about 99.7% of the scores lie between (75, 93)

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While playing a game with her friends, Ellen scores 12 points less than twice the lowest score. She scored 98. What was the lowest score in the game?

Answers

if she scores 98 and the lowest is 12 down the lowest is 86

(7x³ + x² + x) divided by (x² + 1)

Answers

Answer:

Q=7x+1, R=-6x-1

Step-by-step explanation:

 7x + 1

 ----‐----------------------------

 x² + 1 | 7x^3 + x^2 + x

 -) 7x^3 +7x

---‐---‐----------------------------

 x^2 -6x

 -) x^2 +1

 --------------------

 -6x-1

I am in 6th grade, can somebody answer in 6th grade skill? Here is an incomplete equation of 534 divided by 6. I only have 4 minutes left and I am stressed out!!!!

Answers

The answer would be 89 after 534 divided by 6 and applying the concept of arithmetic operation.

What is an arithmetic operation?

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that is +, -, ×, and ÷.

It is given that:

534 divided by 6

[tex]\begin{matrix}\:\:\:\:\:\:\emptyspace8\emptyspace9\:\:\:\:\:\:\:\:\:\:\:\:\\ 6\overline{|\smallspace534}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace4\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace5\emptyspace4\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace5\emptyspace4}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\emptyspace0\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}[/tex]

The A = 48

B = 54

C = 54

After applying the concept of arithmetic operation.

Thus, the answer would be 89 after 534 divided by 6 and applying the concept of arithmetic operation.

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how many integers can be represented as a difference of two distinct members of the set $\{1, 2, 3\}$?

Answers

We can represent 4 integers as a difference of two distinct members i.e.    {1, -1, 2, -2}.

What are Integers ?

The collection of positive and negative integers is known as an integer. Integers, like whole numbers, do not include the fractional portion. Integers can therefore be defined as numbers that can be positive, negative, or zero but not as fractions.

Here, we have 3 distinct positive integers which are {1, 2, 3}.

We can list down the integers as a difference of the two distinct members as follows :

1 - 2 = -1

2 - 1 = 1

2 - 3 = -1

3 - 2 = 1

1 - 3 = -2

3 - 1 = 2

So, we can see clearly it is representing only 4 integers which are {1, -1, 2, -2}.

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find the eigenvalues and associated unit eigenvectors of the symmetric matrix the smaller eigenvalue has associated unit eigenvector . the larger eigenvalue has associated unit eigenvector .

Answers

The eigenvalues and associated unit eigenvectors of the symmetric matrix the smaller eigenvalue has associated unit eigenvector is Ax = λx.

Symmetric matrix:

In algebra, symmetric matrix a square matrix that remains unaltered when its transpose is calculated.

Given,

Here we need to find the the eigenvalues and associated unit eigenvectors of the symmetric matrix the smaller eigenvalue has associated unit eigenvector and the larger eigenvalue has associated unit eigenvector.

Here the eigenvector is a vector that is associated with a set of linear equations.

And in the eigenvector of a matrix is also known as a latent vector, proper vector, or characteristic vector.

Therefore, those are defined in the reference of a square matrix.

So, the smaller eigenvalue has associated unit eigenvector is Ax is λx.

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I need HELP! I dont understand and need help!
algebra 2 please HELP

Answers

Answer:

[tex]y = 3.48(1.32)^{x}[/tex]

Step-by-step explanation:

8 = ab^3

42 = ab^9

b = 1.32

[tex]\frac{8}{(1.32)^{3} } =\frac{a(1.32)^{3} }{(1.32)^{3} }[/tex]

a = 3.48

Answer:

[tex]y = 3.48(1.32)^{x}[/tex]

Students in a fifth-grade class were given an exam. During the next 2 years, the same students were retested several times. The average score was given by the model f(t)=89−17log10(t+1),0≤t≤24 where t is the time in months.
(a) What is the average score on the original exam? (b) What was the average score after one year? (c) After how many months would it take for it to predict that the average dropped to 82? (Assume that the the model could continue past two years, if necessary)

Answers

Answer:

Step-by-step explanation:

# 3 Mia has $50 on a gift card to her favorite
coffee shop. Each time she visits the coffee
shop she spends $3.75 on her favorite drink.
Write an equation to represent the relationship
between n, the number of times she visits the
coffee shop, and b, the total balance on her
gift card.
+

Answers

The equation to represent the relationship between n, the number of times she visits the coffee shop, and b, the total balance on her gift card is b = - 3.75n + 50

How to represent a situation with equation?

Mia has $50 on a gift card to her favourite coffee shop. Each time she visits the coffee shop she spends $3.75 on her favourite drink.

The equation to represent the relationship between n, the number of times she visits the coffee shop, and b, the total balance on her gift card can be represented as follows:

Therefore,

n = number of times she visit the coffee shopb = total balance on her gift card

Hence, the equation is as follows;

b = - 3.75n + 50

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Use the appropriate normal distribution to approximate the resulting binomial distributions. A fair coin is tossed 130 times. What is the probability of obtaining between 56 and 73 tails, inclusive?.

Answers

The probability of obtaining between 56 and 73 tails, inclusive will be approximately 0.8561.

To approximate the resulting binomial distribution, we will use the normal distribution as an approximation when certain conditions are met.

The number of trials, n, is large n = 130.

The probability of success, p, is not too close to 0 or 1

Then the coin is fair, so p = 0.5.

We have to calculate the probability of obtaining between 56 and 73 tails, inclusive.

Mean (μ) = n x p = 130 x 0.5 = 65

Standard Deviation (σ) = √(np (1 - p))

(σ) = √(130 x 0.5 x 0.5) ≈ 5.7

Using a standard normal distribution, we can determine the z-scores corresponding to 56 and 73 tails:

z1 = (56 - μ) / σ ≈ (56 - 65) / 5.7

≈ -1.58

z2 = (73 - μ) / σ ≈ (73 - 65) / 5.7

≈ 1.40

P(56 ≤ x ≤ 73) ≈ P(-1.58 ≤ z ≤ 1.40)

Now we can determine these probabilities and subtract them.

P(-1.58 ≤ z ≤ 1.40) ≈ 0.9155 - 0.0594

P(-1.58 ≤ z ≤ 1.40) ≈ 0.8561

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HELP ME PLEASE!!! it’s for algebra and i really need to get this awnser right!! please literally anyone help me

Answers

Answer:

Below

Step-by-step explanation:

Start with point (3,5) slope (5/3) form:

(y-5) = 5/3 (x-3)        expand

y-5 = 5/3 x -5          re-arrange by adding 5 to both sides

y = 5/3 x                    done!

A restaurant is offering a dinner special that includes one starter and one entree. The choices are listed below. How many possible dinner special combinations are there?
Starter: breadsticks, soup, salad
Entree: beef, fish, chicken, shrimp, pork

Answers

The total number of possible dinner combinations are 15

What are Combinations?

The number of ways of selecting r objects from n unlike objects is calculated by combination. The formula for combination is

ⁿCₓ = n! / ( ( n - x )! x! )

where

n = total number of objects

x = number of choosing objects from the set

Given data ,

Let the total number of dinner combinations be = T

Now ,

The values of Starters is represented in set = A

The values of Entree is represented in set = B

The values of Set A = { bread sticks , soup , salad }

The values of Set B = { beef , fish , chicken , shrimp , pork }

Now , the total combinations of possible selection of Starters = ³C₁

The total combinations of possible selection of Entree = ⁵C₁

So , the total number of dinner combinations T = total combinations of possible selection of Starters x total combinations of selection of Entree

And , the equation is

The total number of dinner combinations T = ³C₁ x  ⁵C₁

The total number of dinner combinations T = 3 x 5

The total number of dinner combinations T = 15

Therefore , the value of T is 15

Hence , The total number of possible dinner combinations are 15

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Consider the equation xy = 0 In this equation, variables are multiplied and the result is Can the equation be true neither variable is equal to ? Can the equation be true only one variable is equal to 0If so, which one needs to be equal to Can the equation be true if both variables are equal to ? What process could you use to solve equations of the form (x + a)(x + b) = 0 In this case there are only two factors (values being multiplied ) that are being set equal to How would you solve the equation if there were more than two factors ? Explain

Answers

Answer: 1+1

Step-by-step explanation:

I not giving

Is -2/3 greater then 1 2/4

Answers

Answer: No

Step-by-step explanation:

Because 1 2/4 = 6/4 = 3/2 or 1.5

When the other one is a negative fraction which is very obviously that 1 2/4 is greater than -2/3

Answer: 1 2/4 is greater than -2/3

Step-by-step explanation: A positive number is always greater than a negative number, even when dealing with fractions

5а – 2 = 8
6
a = [?]

Answers

Answer:

5a=8+2

5a=10/:5

a=2

it is okay?

The average time it takes Greg to mown a lawn can be defined by the expression 28x + 5

Answers

The number 28 represented by the equation A = 28x + 5 is the average time it takes to mow one lawn

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be = A

Now , the equation A is given as

A = 28x + 5

where x is the number of lawns to mow

Now , A is the average time required to mow a lawn

So , the number 28 is the average time required to mow a single lawn

Therefore , the number 28  average time it takes to mow one lawn

Hence , The number 28 represented by the equation A = 28x + 5 is the average time it takes to mow one lawn

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a 8ft thick slice is cut off the top of a cube, resulting in a rectangular box that has volume 44ft . find the side length of the original cube. round your answer to two decimal places.

Answers

The side length of the original cube for the given measurements and condition is equal to 8.6ft.

As given in the question,

Let 'x' be the side of the original cube.

Volume of original cube = x³

As given 8ft thick slice is cut from the top of the cube.

Volume of the thick slice = 8x²

Volume of the resulting rectangular box = 44

⇒ x³ - 8x² = 44

⇒ x³ - 8x² -44 =0

Plot the graph of the function.

Graph is attached.

From the graph approximate value of side length 'x' = 8.6 ft.

Therefore, the side length of the original cube is equal to 8.6ft.

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Need some help, explain.

Answers

Answer:

hope this will help you

What is the slope of the black line?


What is the slope of the blue line?

Answers

Answer:

Blue line: -1/2

Black line: 3/4

Step-by-step explanation:

The slope of the blue line is a negative cause its a negative slope and the slope of the black line is positive cause its a positive slope.

Hope it helps!

Could you please give me brainiest for this? Thank you!

Using your answer from the previous question, state the value of ‘w’ if the perimeter of the rectangle is equal to 37 feet and the length is equal to 4 feet.

Answers

Answer:

16.5

Step-by-step explanation:

hence the answer is 16.5 feet

please answer this question

Answers

The correct equation is Option A which states that x+16 = 70. The reason for this is opposite angles (or vertical angles) in parallel lines are congruent.

What are opposite angles?

When two lines intersect they form a pair of opposite or vertical angles. In this case, the vertical angles are:

70° ≅  t

p ≅ s

q ≅ (x +16)°

r ≅ u

Given that lines AB and CD are parallel, and that both cut through lines EF, that means q ≅ 70°

Hence,

∡ ApE = 70° = ∡DrF

If we need to find x

Since DrF (x+16) °= 70°

x = 54°

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the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year. (a) estimate how long it takes the population to double.

Answers

As the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year and according to that it will take 63.36 years to double the population.

A population is the complete set group of individuals, whether that group comprises a nation or a group of people with a common characteristic. In statistics, a population is the pool of individuals from which a statistical sample is drawn for a study.

According to the question:

We have been given that the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year.

A) Since we know that population increases exponentially, therefore we will use our given information to form an exponential model for population increase and then we will solve for the time by which our population will be double.

P(t) = [tex](1.011)^{t}[/tex]

⇒ [tex]7.1[/tex] × [tex]2 = 7.1 (1.011^{t}[/tex]

⇒ [tex]\frac{7.1 * 2}{7.1} = 1.011^{t}[/tex]

⇒ [tex]1.011^{t}[/tex] = 2

Now let us solve for t using logarithm.

[tex]ln(2) = ln(1.011)^{t}[/tex]

⇒ ln(2) = t . ln(1.011)

⇒ 0.6931471805599 = t × 0.0109399400383

⇒ t = 0.0109399400383/ 0.6931471805599

⇒ t = 63.3593217

⇒ t ≈ 63.36

Therefore, it will take 63.36 years the population to be double.

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Which of the equations is NOT equivalent to 6x = 20? Select all that apply. 6x ÷ 6 = 20 ÷ 6 6x ÷ 6 = 20 ÷ 20 6x + 5 = 20 + 5 6x − 1 = 20 − 1 6x × 6 = 20 × 20

Answers

These three expressions

6x ÷ 6 = 20 ÷ 6

6x + 5 = 20 + 5

6x − 1 = 20 − 1

will be equal to the given expression.

What is Expression ?

Operators, constants, and variables all come together to form an expression. A value can be produced by an expression using one or more operands and zero or more operators.

We have to check which equation will be equal to 6x = 20

6x ÷ 6 = 20 ÷ 6

After Multiplying both sides by 6.

We get, 6x = 20

6x ÷ 6 = 20 ÷ 20

After simplifying we get,

x = 1

Multiplying both sides by 6

6x = 6, Hence it doesn't satisfy.

6x + 5 = 20 + 5

Subtract 5 both sides of the equation

We get, 6x = 20

6x − 1 = 20 − 1

Adding 1 both sides of the equation,

We get, 6x = 20

6x × 6 = 20 × 20

After simplifying, we get

36x = 400

Hence, only

6x ÷ 6 = 20 ÷ 6

6x + 5 = 20 + 5

6x − 1 = 20 − 1

will be equal to the given expression.

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Colin buys a car for £45500.
It depreciates at a rate of 6% per year.
How much will it be worth in 3 years?
Give your answer to the nearest penny
where appropriate.

Answers

$37310.00 is the answer

Where does the graph of y = -3x - 18 intersect with the x axis?

Answers

It crosses at x = -6.
-18 is your y intercept so you mark -18 at y.
-3x/1 is your slope, so you go left 3 cubes, up 1 cube until you cross the x axis.

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defectives ones are identified. Denote by N1the number o tsis mad un the first defectiv is identified and by N2 ihe number of additional tests until the second defective is identified. Find the joint probability mass function of N1 and N

Answers

The joint probability mass function of N1 and N2 for the given transistors is 1/15.

Explain the term selection without replacement?The total number of things available for the initial selection is one extra than the number of units available for such second option when items are chosen without replacement. Due to the fact that one object has been chosen and not returned to the pool.

For the stated question-

Six transistors total.2 transistors are faulty in total.Four non-defective transistors are present.

N1: The number of tests conducted before the first flaw is found = 2/6.

N2: The number of tests that must be performed before the second problem is found = 1/5.

If N1 = 1 and N2 = 1, then

P(N1 = 1; N2 = 1) = 2/6 x 1/5

P(N1 = 1; N2 = 1) = 2/30

P(N1 = 1; N2 = 1) = 1/15

Thus, joint probability mass function of N1 and N2 for the given transistors is 1/15.

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